2 3 6 3 5 2
f ( x )=( x −8 x+ 4) =x −512 x +64=6 x −1536 x
−3 −1 −30−3
f ( x )=(5 x −x+1) =−3 ( 5 x −x +1 )
2 −3 2
∗( 10 x +1 )= 4
( 5 x 2−x +1 )
x x ( x ¿¿ 8−1)−x ( 8 x 7 ) x 8−1−8 x 8 −8
f ( x )= 2 4
= 8
= 8 2
= 16
= 16 ¿
( x −1) x −1 (x −1) x −1 x
1 1
1 −1 10 x−1 10 x−1 10 x−
f ( x )= √ 5 x 2−x+ 4=(5 x 2−x + 4) 3 = (5 x 2−x +4 ) 3 ∗( 10 x−1 )=
3
= =
3 √(15 x 2−3
2 2
3 ( 5 x −x +4 )
2 3
15 x 2−3 x +12 3
1
2 3 −1 1
2 4∗3 2+4∗3 x 2+ 4∗√ 3 x 2
f ( x )= √ x +4 √ x =x +4∗x = x +
3 2 3 3 2 3 2
x = =
3 2 1
√3 x∗2
3 x ∗2
2
1 −2 2 2
1 24 x 24 x
f ( x )= √ 8 x +27=(8 x +27) 3 = ( 8 x +27) 3 ∗24 x =
3 3 3 3 2
=
3
√
2 3 2
3∗ ( 8 x +27 )
3
3∗( 8 x + 27 )
3 3
−5 −6 −40
f ( x )=(8 x−7) =−5 ( 8 x−7 ) ∗8=
( 8 x−7 )6
1 −2
3∗1 3 10 x +3 10 x+ 3
f ( x )=10 √ x + 3 √ 7=10 x+3∗( 7 ) =10 x +
3 3 3 3
(7 ) = =
3
3∗7
2
3 3∗√3 2
7
1 1 1 1
f ( x )= = = =
√( x +7 x )
4 2 3
4
(x + 7 x )
3
2 2 3 4
1
2 2 3
( x +7 x ) ∗( 4 x +14 x)
3
√ 4 2 3
(x +7 x )∗(4 x + 14 x)
2 2
1
1 1
1 (2 x )2 √2 x
f ( x )= √2 x=(2 x) = (2 x ) =
2
= 2
2 2 2
Jose Barrera 143261393