Thinking Time: Equal Matrices
Thinking Time: Equal Matrices
Time
1.	 Write down a 3  3 square matrix.
2.	 Write down a 1  2 zero matrix and a 2  3 zero matrix.
3.	 Is (0) equal to 0? Explain.
      Equal Matrices
      Two matrices A and B are equal if and only if                    AT
                                                                            TE
                                                                                 NTI
                                                                                       ON
      (a)	 both matrices have the same order, and
      (b)	their corresponding elements are equal.                 The corresponding elements of
                                                                  two matrices refer to the elements
                           1 2           1 2                  in the same position of both
      For example, if A =       and B =       , then A = B.   matrices.
                           3 4           3 4 
              Thinking
              	Time
         2       2 0 
1.	 Are     and       equal? Explain.
         3       3 0 
                     0 0 0 
         0 0               
2.	 Are       and  0 0 0  equal? Explain.
         0 0       0 0 0 
        1 2       1 3 
3.	Are       and       equal? Explain.
        3 4       2 4 
Solution:
           20 b     4a a + 3 
A = B, so        =           .
           c 16     d−4  d 
From (1),
       20
∴ 	a	=
        4
		   =5
From (2),
	b = 5 + 3
 	 =8
1.	 Write down the order of each of the following         3.	   The table below shows the number of students in a
	matrices.                                                	     class and the type of fruits that they like best among
     −1 3                                               	     the fruits given (i.e. they can only choose one type
                                                        	     of fruit among the fruits given).
     0 2  	
	(a)	
     5 6 
                                                          	                 Apple    Orange Banana Durian
         1                                                      Boys        4         0          5         6
     7 6
	(b)	       −8 
         2                                                                  8         7          5         3
                                                                  Girls
                                                          	
     −8 −1 7 
                                                          	(i)	 Represent the data in the table by using
               
     3 0 4.3  	
	(c)	                                                     		a matrix F.
     5 −9 12 
                                                          	(ii)	 Which is the type of fruit that is liked best by an
     5                                                  		     equal number of boys and girls?
	(d)	
        		                                              	(iii)	 Find the sum of the elements in the first row
     0 
                                                          		of F. What does this sum represent?
    ( −13 ) 	
	(e)	                                                     	(iv)	 How do you use the elements of F to find the
                                                          		 number of students who like durian best?
      0 0 
	(f)	                                                   		     What is the answer?
      0 0 
                                                          4.	 Which of the following pairs of matrices are equal?
2.	 Which of the following pairs of matrices are equal?   	   If they are not equal, state the reason.
	   If they are not equal, state the reason.
                                                                  6 
        −4      −4                                        P= 
                                                          	(a)	        , Q = (0)
    A=                                                           −3 
	(a)	       ,B=     
        5       5 
                                                                          0      0 
        7 8       7 −8                                	     (b)	 X =    ,Y=    
    C=                                                                   0      0 
	(b)	         ,D=       
        −8 2      8 2 
        −2 
    P= 
	(c)	
        7 
            ,Q=            (   −2 7   )
        0 6         6 
    X= 
	(d)	          , Y=     
        0 −3        −3 
        5 
	   Q=    
        7 
            3 5 b   a 5 13 
	(b)	               =        
            7 −3 c   d − a 6 
       2 x 18   14 2 k 
	(c)	  3 y 36  =  15 6 h  		
                         
	(d)	      (   2x − 3 y + 4   )=(   7 6   )
       1                  
         x          x+4       3    h 
	(e)	  2                    =
                             k − 9 27  	
                               
       5            3 y 
       2x − 5 y − 4  
                          0 0 
	(f)	               =      
       z+3     5k   0 0 
          4.2                        Subtraction of
                                     Matrices
                             Class
                             Discussion
Addition of Matrices
Let us return to the context of the matrix for Table 4.1 in the class discussion on
                 16 7 69 
page 129: M =                
                 58 64 76 
Suppose the boss of the stationery shops receives a new stock of 100 pens of each
brand. How should he distribute them? Should he give equal number of pens of each
brand to each of the two shops, or more pens to the shops with less stock?
      86   ____ ____ 
			=                 
      ____ ____ ____ 
	         Hence when we add two matrices, we get a new matrix whose elements are the
	         sum of the corresponding elements of the two matrices.
2.	 Can you add two matrices of different orders, e.g.
                                 16 7 69   70 80 
                                           +      ?
                                 58 64 76   30 20 
	Explain.
3. 	 How about adding the following two matrices?
                                16 7 69   70 80 0 
                                          +        
                                58 64 76   30 20 0 
	Explain.
               p q           w x                        p+w q+x        
       if A =       and B =       , then A + B =                       .
               r s           y z                        r + y s + z   
                       Class
                       Discussion
Subtraction of Matrices
The final stock for the two stationery shops for the previous class discussion is now
                                  86 87 119 
represented by the matrix X =                  .
                                  88 84 126 
After one month,    the boss finds that the stock of pens left is given by
      30 24 98     
Y=                 .
      61 67 117    
1.	 How do you subtract matrix Y from matrix X to give the quantity of the pens of
	   each brand that were sold?
                         119   30            98 
	X − Y =  86        87
                                −
                                          24
          88        84   126   61    67   117 
     86 − 30              87 − 24   119 − ___ 
			
  =                                           
     88 − ___             ______     _______ 
     56   ____ ____ 
			
  =                 
     ____ ____ ____ 
	   Hence when we subtract one matrix from another, we get a new matrix whose
	   elements are the difference of the corresponding elements of the two matrices.
2. 	 Do you think you can find the difference of two matrices if their orders are
	different?
In general, if two matrices A and B have the same order, then A – B is obtained by
subtracting the corresponding elements of B from A, e.g.
               p q               w x                    p−w q−x        
                                                                       
       if A =  r s  and B =      y z  , then A – B =    r − y s− z     .
               t u             a b                  t − a u − b   
                                              −1 3       
                                                         
                                     and D =  6 −2        , evaluate each of the following if
                                              0 8       
                                     possible. If it is not possible, explain why.
                                     (a)	 A + B	(b)	 A – B + C	                (c)	 C – D
Solution:
              6 3   4 −2 
(a)	 A + B	=       +     
              5 8   0 7 
      10 1 
		 =                                                                                                   P
      5 15                                                                                           So roblem
                                                                                                         lvin
                                                                                                              g T
                                                                                                                  ip
                  6             3   4 −2    −9 0 
(b)	 A – B + C	=                    −     +                                               For (b), we can also evaluate
                   5           8   0 7    10 −1                                         A – B + C straightaway, e.g. the
                                                                                                  first element is equal to
                  2             5   −9 0                                                      6 – 4 + (–9) = –7.
			=                               +      
                  5             1   10 −1 
      −7 5 
			=       
      15 0 
2.	 The marks of a Mathematics test and a Science test for three students are shown
	   in matrix P. The total possible score for each test is 50 marks.
                                  Raj       Ethan      Farhan
                                 49         28          39       Mathematics
                        P=                                      
                                 47         45          21       Science
	 In the second test for Mathematics and for Science, Raj scores 46 marks for
	 Mathematics and 42 marks for Science, Ethan scores 40 marks for
	 Mathematics and 38 marks for Science, and Farhan scores 31 marks for
	 Mathematics and 35 marks for Science.
	(i)	 Express the marks for the second test by using the matrix Q with the same
		order as P.
	(ii)	 Find the matrix P + Q.
	(iii)	 Explain what the numbers in the matrix in (ii) represent.
              Exercise
                      4B
1.	 Evaluate each of the following if possible. If it is      2.	 Evaluate each of the following if possible. If it is
	   not possible, explain why.                                	   not possible, explain why.
                  
	(a)  3 4  +  4 6                                                3   −1   6 
      8 −5   3 0                                          	(a)	     +    −  
                                                                     4   5   7 
              
	(b)  7  +  5                                                    4 −1   3 2   −6 4 
      −8   −9                                             	(b)	        +     −     
                                                                     3 2   −5 4   2 1 
	(c)    (   2 8 −3    )+(    −4 7 0   )
                                                              	(c)	       (   1 3    )−(   3 4   )+(   −2 6   )
       5 
	(d)      +   (   5 −2    )                                    3 1 5   2 −1 0   7 5 8 
       −2                                                   	(d)	
                                                                            −        +        
                                                                   −7 8 −2   5 −2 6   −2 4 −9 
      2 −3 8   5 6 7 
	(e)          −                                                2                 5 
      10 5 4   −3 0 12                                                                  2 
      12         8                                             3
                                                              	(e)	                  +  6  −  −8 
                                                                   −5               0       
                       
	(f)  −8.3      −  1.7 
      4         0                                            4 −3                −3 2         4 5       
                                                                                                                
      8 9   4 
                                                              	(f)	  2 5                −  7 −1      +  0 −6    
                                                                     −8 9               6 −3       2 8     
	(g)        +  
      −7 6   8  	
                                                                     2 5   −5 0   −8 6 0 
      8 9   4 0                                           	(g)	        +     −       
	(h)        +                                                    −3 6   8 9   2 8 0 
      −7 6   8 0 
                                                                  ( 5 ) − ( −6 ) + ( 3 )
                                                              	(h)	
            3 1       4 −1 
5.	 If A =       ,B=        and
            4 −2      3 −4 
              0 1 
	         C=        , evaluate
              −1 0 
	(i)	A – B,	(ii)	
                B – A,	
      B – C,	(iv)	
	(iii)	          A – (B – C),
    (A – B) – C.
	(v)	
                        Class
                        Discussion
Multiplying a Matrix by a Scalar
In the previous class discussion on page 136, the number of pens sold after one
                                                56 63 21 
month is represented by the matrix P = X – Y =            .
                                                27 17 9 
Suppose the boss decides to order two times the number of pens sold in the previous
month.
1.	 How do you multiply matrix P by a constant number to give the quantity of the
	   pens of each brand ordered by the boss for each shop?
         56 63 21 
	2P = 2 
         27 17 9 
           2 × 56      2 × 63   2 × ___ 
			     =                               
           2 × ___    ______    ______ 
                              p q               kp kq 
                      if A =       , then kA =        .
                              r s               kr ks 
                            	   evaluate 2A + 3B.
                            (b)	 Find the value of a and of b in the following:
                            	     −2   (   a b   )+(   −5 8   )=(   7 3   ).
Solution:
                   5 −3      −2 7 
(a)	 2A + 3B =	 2        + 3      
                   1 6       −4 0 
       10 −6   −6 21 
			=	         +      
       2 12   −12 0 
        4 15 
		 	=	         
        −10 12 
(b)		 −2   (    ) + ( −5 8 ) 	= (
               a b                     7 3   )
	
  ( −2 a −2b ) + ( −5 8 ) = (          7 3   )
		
        ( −2 a − 5 −2b + 8 ) 	= (      7 3   )
	 Equating the corresponding elements, we have
	–2a – 5 = 7	       and	–2b + 8	= 3
		–2a	= 7 + 5		               –2b	= 3 – 8
			= 12			= –5
            12                       −5
		 a	=         		               b	=
            −2                      −2
                                      1
			= –6			= 2
                                      2
                  1
	 ∴ a = –6, b = 2
                  2
	(i)	 3A + 2B,		
               (ii)	 4B – 3A.
                                            Passenger Cargo
                                              Ships   Ships
                                               8       3    Dock 1
                                      A=                   
                                               7       5    Dock 2
                                            Passenger   Cargo
                                              Ships     Ships
                                               11         2      Dock 1
                                      B=                        
                                               12         1      Dock 2
Solution:
(i) 	 Total number of ships of each type arriving at each of the docks from Monday to
	     Friday is given in the matrix 5A.
             
	5A = 5  8 3 
         7 5 
    40 15 
	=        
    35 25 
                40 15      11 2 
(ii)	5A + 2B =         + 2      
                35 25      12 1 
      40 15   22 4 
			=         +     
      35 25   24 2 
      62 19 
			=        
      59 27 
(iii)	 The elements of 5A + 2B represent the number of each type of ships arriving at
	      each of the docks from Monday to Sunday.
A chartered bus carries passengers daily from Monday to Friday. The number of Exercise 4C Question 5
adults and children it carries each morning and afternoon is given in the matrix D.
                                 Adults    Children
                                 15          25     Morning
                        D=                         
                                  21          8     Afternoon
(i) 	 Find the total number of adults and children carried by the bus from Monday to
	     Friday in the mornings and afternoons, expressing your results in matrix form.
(ii)	 The bus carries a total of 14 adults and 10 children every Saturday morning, and
	     18 adults and 7 children every Saturday afternoon. Represent this information
	     using the matrix E.
(iii)	 Evaluate the matrix 5D + E and explain what this matrix represents.
                         Class
                         Discussion
Multiplying a Matrix with another Matrix
In the class discussion on page 136, the number of pens sold is represented by the
matrix:
                                   A      B     C
                                 56      63   21    Shop 1
                          P=                       
                                 27      17   9     Shop 2
Suppose the selling price of each pen of brands A, B and C is $1.50, $2 and $1.80
                                                         1.5  A
                                                               
respectively, and this is represented by the matrix Q =  2  B .
                                                         1.8  C
                      A         B      C                       A
                                                        1.5            ( 56 × 1.5) + ( 63 × 2 ) + ( 21 × __ )      Shop 1
 Shop 1          56            63     21   
                                                         2
                                                               
                                                              B =                                             
 Shop 2          27            17     9                             ( 27 × __ ) + ( __ × __ ) + ( __ × __ )    Shop 2
                                                       1.8     C
                                                                        ____  Shop 1
                                P                       Q
                                                                    =           
                                                                        ____  Shop 2
                                                                             R
Order of matrix: 2  3                                 31                  21
2.	 Look at the orders of P, Q and the product R. Can you explain the relationship
	   between the orders?
3. 	 By looking at their orders, state the conditions for multiplication of two matrices
	    to be possible.
In general, for any two matrices A and B, the product A  B (or simply AB) is only
possible if
                               number of columns of A = number of rows of B.
In other words,
                                            A                  B       =       C
                                       mn                     np           mp
                                                     must be
                                                      equal
                          Thinking
                          	Time
Justify if the following two matrices can be multiplied together by checking their
orders. If it is possible, write down the order of the product.
                  4 −9                                         4 −9                
       2 −3 5                                                                      2 −3 5 
(a) 	           −5 10                              			(b) 	  −5 10                 −7 0 8 
       −7 0 8   21 6                                        21 6                       
                 
(c)	   (   2 3        )    7 8           7 8 
                                    				(d)	
                              −9 4                                                  (       2 −3     )
                                             −9 4 
      7                                                                                       7     
     
(e)	  8
                 
                     (       −7 2 3   ) 				(f)	( −7                             2 3      )   
                                                                                                8
                                                                                                       
                                                                                                       
      −5                                                                                    −5   
                                                                           Old New
                                    A             B            C           Price Price
                                                                           1.5   1.9 
                Shop 1         56               63        21        
                                                                             2
                                                                                         
                                                                                  2.4  =             a       b      
                                                                                                                   
                Shop 2         27               17        9                                        c       d      
                                                                           1.8   2.2 
                                                  P                            Q                         R
                Order:                           23                          32                       22
                                                               equal
Fig. 4.1
    Since the orders of the two matrices P and Q are 2 by 3 and 3 by 2 respectively, the
    order of the product R must be 2 by 2, as shown in Fig. 4.1.
    To obtain a (element in first row, first column of R) we multiply the corresponding
    elements in the first row of P and the first column of Q as shown in Fig. 4.2, before
    adding the three products to obtain 247.8.
                                                        1.5       1.9      
          56        63        21                                                  56(1.5) + 63( 2 ) + 21(1.8 )       b   
                                                       2        2.4       =                                              
          27        17        9                      1.8       2.2                          c                      d   
                                                                                      247.8       b    
                                                                               =                       
                                                                                        c         d    
                                                                     Fig. 4.2
                                                  1.5         1.9        
                                                                                247.8     56(1.9 ) + 63( 2.4 ) + 21( 2.2 )   
      56        63        21                        2          2.4
      27        17        9
                                                                         =                                                   
                                                                                                                                  
                                               1.8         2.2                 c                        d
                                                                                    247.8     303.8       
                                                                            =                             
                                                                                      c         d         
                                                                     Fig. 4.3
    Since Q has no third column, then we move on to the second row of P.
                              1.5    1.9   
                                                           247.8                    303.8 
   56   63     21          2     2.4    =                                               
    27   17     9                            ( 27 )(1.5) + (17 )( 2 ) + ( 9 )(1.8 )   d   
                               1.8    2.2
                                           
                                                    247.8 303.8 
                                              =  90.7       d
                                                                 
                                                                
Fig. 4.4
                              1.5    1.9   
                                              247.8                303.8                        
     56   63     21
                           2     2.4    =                                                    
                                                                                                     
    27   17     9           1.8    2.2        90.7 ( 27 )(1.9 ) + (17 )( 2.4 ) + ( 9 )( 2.2 )   
                                           
                                                  247.8 303.8 
                                              =              
                                                  90.7 111.9 
                                        Fig. 4.5
                                                    247.8 303.8 
Therefore, we obtain the product R, i.e. PQ = R =               .
                                                    90.7 111.9 
                                                 −2          3 −1         
                                          (c)	                         
                                                 1            1 −4         
Solution:
                                                                                                               AT
                                                                                                                    TE
       −2 5            9 2            (− 2 )( 9 ) + (5)(1)              (− 2 )( 2 ) + (5)( − 2 ) 
                                                                                                                         NTI
                                                                                                                               ON
(a)	                              =                                                          
       1 −6              1 −2          (1)( 9 ) + ( − 6 )(1)           (1)( 2 ) + ( − 6 )( − 2 )    (a)	 Product exists as number of
                                                                                                          	 columns of first matrix
    −13 −14                                                                                             	 = number of rows of second
	=                                                                                                      	      matrix
    3   14                                                                                              	= 2
= ( −23 )
                    −2              
(c)	 The order of                   is 2  1.
                    1                
                                 −2                  
	         Number of columns of                       = 1
                                 1                    
                              3 −1                   
	         Number of rows of                          = 2
                              1 −4                    
                                                                   
	         Since number of columns of  2  ≠ number of rows of  3 −1  , then matrix
                                        1                     1 −4 
	         multiplication is not possible.
Evaluate all the matrix multiplication in Thinking Time Questions 1(a) – (f) on                           Exercise 4C Questions 6(a)-(h),
page 144, if it is possible.                                                                              7-9, 11
              Exercise
                  4C
                                                       2.	 Simplify each of the following.
                                                                               
1.	 Simplify each of the following.                    	   (a) 	 2  −1  + 3 4  	
                                                                    5       −3 
          (
    2 1 −2 3
	(a)	                 )	
      −2 
                                                       	   (b) 	 2   (3   1 5   ) − 4(   −1 3 2     )
    4
	(b)	     
      1                                                    1 3       −3 −1 
                                                           5
                                                       	(c)	        − 2       
        6                                                  −4 6      4 2 
     1          
	(c)	 4         	                                          0 4 1       −1 3 0 
     2
        −8                                             3
                                                       	(d)	          − 4         
                                                             5 0 −1      −2 1 −1 
     1         
	(d)	 6 15 
     3  21 −24                                                   4 4        1 2            1 4 
                                                       3.	 If A =         ,B=       and C =       ,
        −1 0.5 3                                                 2 7        −1 3           3 −5 
    −2 
	(e)	               	
        −0.8 2 1.2                                   	   find the following.
        1 5                                          	(i)	 A + B	                         (ii)	 A + 2B
                                                     	(iii)	 A – B – C	                   (iv)	 2A – 2C + 3B
	(f)	5  −4 3 
        −1 2 
        1                 
      6    1              
        2                                            4.	 Find the values of the unknowns in each of the
           1                                         	following.
    3 0 2
	(g)	                      
             3
                                                           2      2   0 
      5 −4 − 2                                           a
                          
                                                       	(a)	     + b     =  
                                                           2      −2   8 
                                                             2x      x   18 
                                                           3
                                                       	(b)	      + 3      =   
                                                             y       3 y   36 
                                                             1 2   3 5   a b 
                                                           2
                                                       	(c)	       −     =    
                                                             3 4   c 6   7 d 
                                                                                      9 12 6 
                                                       	   (d) 	 2  5 3 2  +  a b c  =       
                                                                    1 6 3   −2 −4 5   d e f 
Worked
                   6
                                     (Application of Matrices in Calculating Costs)
                                     A bakery produces 3 different types of bread:
Example                              white bread (W), wholemeal bread (M) and multi-grain
                                     bread (G). Delivery is made to 2 distribution outlets in
                                     the following way:
Solution:
                            2.1 
               60 50 30           348 
(a)	(i)	 PQ =             2.7  =      
               40 70 20   2.9     331 
                                
     PQ gives the costs of the bread delivered to Outlets A and B respectively.
	(ii)	                                                                                                         AT
                                                                                                                    TE
                                                                                                                         NTI
                                                                                                                               ON
                        348 
(b)	   (   27 25   )         =   (   17 671   )                                                  For (b), an alternative method is
                         331                                                                                                          
                                                                                                     (       348     331        )   27 
                                                                                                                                         
	      ∴ The total cost of bread delivered to the 2 outlets is $17 671.                                                              25 
                                                                                                     =   (    17 671           ).
1. Huixian and Lixin take a multiple choice test. The matrices X and Y show the Exercise 4D Questions 1-8
2.	 An otah factory produces four types of seafood otahs, namely fish (F), prawn (P),
	   squid (S) and mixed seafood otah (M), for distribution to its five outlets across
	Singapore.
Part A:
A simple method of encoding a message is to use the encoding key shown in Fig. 4.6.
                                       AèD
                                       BèE
                                       CèF
                                          ⋮
                                       WèZ
                                       XèA
                                       YèB
                                       ZèC
                                       Fig. 4.6
Usually, we write the encoded message in blocks of 4 letters.
The first 3 blocks are:   VHFU   HWUR   RPLQ
If your enemies intercept this encoded message, they can break it easily by using
frequency analysis. In English, the 3 most frequent letters used are E, followed by T
and then A.
2. 	 Which letter occurs the most often in the above encoded message? Does it
	    correspond to E, T or A in the original message?
Your enemies will try H → E (i.e. I → F, J → G, etc.) and decode the entire message.
If it does not make sense, they will try H → T (i.e. I → U, J → V, etc.), and so forth,
until the decoded message makes sense. Therefore there is a need for a more secure
coding system.
                                        Aè1
                                        Bè2
                                        Cè3
                                           ⋮
                                       Z è 26
Fig. 4.7
You can encode all the letters at one go. The following shows the encoding of the
first 6 letters. You must fill the second matrix column by column, not row by row.
          3 1   19 3 5      62 27 35      10 1 9 
                         =             è          
          5 2   5 18 20     105 51 65     1 25 13 
                                                              J A I   
	 	 	 	                          	 	 	                    è          
                                                                       
                                                              A Y M   
                                                                                          INF
                                                                                                OR
                                                                                                     MA
                                                                                                          TIO N
So, SECRET is encoded as JAAYIM.
                                                                                     Although it is harder to decode
4. 	 Can you use frequency analysis to break the code? For example, what letter(s)   matrix encoding, we can still
	    in the original message does the letter A in the encoded message represent?     analyse the frequency of blocks
                                                                                     of 2 letters using a computer
5.	 Encode the rest of the message using the above matrix encoding key.              software in order to try to break
                                                                                     the code.
	   Then write down the entire encoded message in blocks of 4 letters.
Hint: If you get a negative number, e.g. –11, you add 26 continuously until you reach
	     a number between 1 and 26 inclusive, e.g. –11 + 26 = 15 → O.
        Journal
         Writing
We can use matrices to rotate a point on the Cartesian plane.
For example, Fig. 4.8 shows a point P(2, 3). We want to rotate P 90° anti-clockwise
about the origin to give the image Pʹ.
                                                y
                                                    P(2, 3)
                                            3
                             P'(−3, 2)
                                            2
                                          90°
                                                              x
                              −3            0          2
                                         Fig. 4.8
A 90° anti-clockwise rotation about the origin O can be represented by the matrix
 0 −1 
        .
 1 0 
                           0 −1   2     −3 
By matrix multiplication,            =     .
                           1 0  3       2 
                      Exercise
                           4D
1.	 In a soccer tournament, 4 teams play against one               2.	 The price of tickets to a musical at Marina Bay
	 another twice. The matrices P and Q show the                     	   Sands Theatre is as follows:
	 results of the matches and the points awarded
                                                                   	 	 VIP Reserve: $130	              A Reserve: $115
	respectively.
                                                                   		B Reserve: $90	                   C Reserve: $75
                       Win      Draw     Lose                      	   The number of tickets sold for three nightly
                       5        1        6         Team A        	   performances are as follows:
                                               
                        8        4        0          Team B
               P=                              
                       2        3        7         Team C                          VIP      A       B       C
                      3        4        5        Team D
		                                                                                 Reserve Reserve Reserve Reserve
                                                                       Friday        220         430         555         355
                                Points
                                3  Win                               Saturday      245         485         520         310
                                    
                           Q =  1  Draw                              Sunday        280         430         515         375
                                                                   
                                0  Lose
	
                                                                   	   Write down two matrices only such that the
	(i)	How many matches does each team play
                                                                   	   elements of their product will give the total amount
		   during the tournament?
                                                                   	   of ticket sales for the three nightly performances.
	(ii)	Evaluate PQ.
                                                                   	   Hence, calculate the total amount collected for
	(iii)	 Explain what your answer to (ii) represents.               	   the three nightly performances.
	(i)	Write down two matrices only such that the                                  Extra
                                                                     Size                    Large     Medium       Small
		 product will give the total takings of each                                   -large
		   outlet and hence, calculate the takings for the           Men                220         240          180          85
		   day, for each of the outlets.                                                 50          60          210        135
                                                               Women
	(ii)	 Hence, calculate the total takings for the pie                              10          40          200        250
                                                               Children
		company.
                                                              	 The cost of an extra-large, large, medium and
4.	 The table below shows the number of cups of               	 small T-shirt is $15, $13.50, $12 and $10
	 tea, tea with milk, coffee, and coffee with milk,           	 respectively. Evaluate the product.
	   sold during breakfast hours by 3 drinks stalls in a       	(i)	         Write down two matrices only such that the
	neighbourbood.                                               		            elements of their product under matrix
                                                              		            multiplication give the total cost of the T-shirts
                             Tea                 Coffee       		            ordered for the men, women and children
                  Tea        with     Coffee      with
                                                              		            respectively. Evaluate the product.
                             milk                 milk
                                                              	(ii)	
                                                                   Evaluate the matrix product
 Albert            22         32         42         28                                          
 Drink Stall                                                        220 240 180 85  1
                                                                                                
                                                                                           1 
 Best                                                                50    60   210  135  
                   18         26         36         32
 Drink Stall                                                        10 40 200 250   1 
                                                                                              1 
                                                              		
 Chandra           27         24         52         25        		   and explain what the elements in the product
 Drink Stall                                                  		represent.
	(i)	If the price is $0.90 for a cup of tea, $1.00 for        	(iii)	
                                                                    Evaluate the matrix product
		 a cup of tea with milk, $1.10 for a cup of                                220 240 180 85 
                                                                                                  
		coffee and $1.20 for a cup of coffee with milk,
		   form two matrices only such that the product
                                                                            (           )
                                                                   1 1 1  50 60 210 135 
                                                                             10 40 200 250 
		   will give the total amount of money collected            		                                  
		   by the three different stalls from the sales of          		 and explain what the elements in the product
		   these drinks during the breakfast hours.                 		represent.
                                                              	(iv)	Write down two matrices such that the
                                                              		 elements of their product under matrix
                                                              		 multiplication will give the total cost of the
                                                              	 	   T-shirts ordered. Hence, find the total cost.