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Narayana: Cpt-03 (CDF) Objective

This document contains a test with multiple choice questions from various subjects like physics, chemistry, maths and biology. It provides the questions, answers and brief explanations for some of the questions. The test was conducted on 11th July 2022 for class 9 students as part of an objective based class by Narayana IIT/NEET Foundation Academy.

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Swaraj Tarte
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0% found this document useful (0 votes)
727 views3 pages

Narayana: Cpt-03 (CDF) Objective

This document contains a test with multiple choice questions from various subjects like physics, chemistry, maths and biology. It provides the questions, answers and brief explanations for some of the questions. The test was conducted on 11th July 2022 for class 9 students as part of an objective based class by Narayana IIT/NEET Foundation Academy.

Uploaded by

Swaraj Tarte
Copyright
© © All Rights Reserved
We take content rights seriously. If you suspect this is your content, claim it here.
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Download as PDF, TXT or read online on Scribd
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NARAYANA

IIT/NEET FOUNDATION ACADEMY

CPT- 03 (CDF)OBJECTIVE
CLASS – IX - DATE: 11-07-22

PHYSICS CHEMISTRY MATHS BIOLOGY

1. B 11. C 21. A 31. B

2. A 12. D 22. B 32. D

3. D 13. B 23. D 33. B

4. C 14. A 24. B 34. A

5. C 15. B 25. B 35. D

6. B 16. A 26. B 36. A

7. D 17. B 27. A 37. C

8. A 18. A 28. C 38. A

9. D 19. A 29. C 39. B

10. A 20. B 30. D 40. C

PHYSICS
1. Rest and motion are relative terms; path, velocity, acceleration etc depends on frame of reference.
2. Distance is always positive but displacement being vector quantity can be positive, negative or zero.
3. |Displacement| ≤ Distance, equality holds if body moves in a straight line without changing direction.

Displaceme nt 2 R 2
4.  
Dis tan ce R 
5. ( 40) 2  (30) 2  50
6. Rest and motion are relative terms; path, velocity, acceleration etc depends on frame of reference.
7. Random motion is defined as the motion of an object with no specific path and sudden changes in its
motion.
8. Since body have moved, distance travelled cannot be zero. Also, since initial point and final point are
not the same, therefore displacement is non-zero.
CPT-03 IX
9. Here distance travelled is zero, it means body is at rest. Since location doesn’t change displacement
is zero.
10. Distance = 0 if body is at rest. Distance ≠ 0 if body returns to its initial location.

CHEMISTRY

11. Due to evaporation surface water is converted into gas.


12. Evaporation is affected by temperature, surface area and humidity.
13. Kelvin temperature = 273 + Celsius temperature
280 = 273 + Celsius temperature
Celsius temperature = 280 – 273 = 7 0C
14. At sea-shore boiling point of water is 1000C. B.P. decrease with altitude.
15. K = C + 273
K = 78 + 273
K = 351 K
16. Evaporation is the changes of liquid into vapour below its B.P.
17. M.P. of water on Celsius and Kelvin scale respectively is 0 0C and 273 K.
18. Evaporation decreases with increase in humidity.
19. Evaporation is a surface phenomenon as the particles at the surface have sufficient energy to break
through the forces of attraction between them.
20. Evaporation causes cooling effect.

MATHS
1 / 5 1 / 6
 5   5
1 / 30
6
1 / 30

21.       
 6   6 5
3 2 3 2 ( 3  2 )2
22. x  = = 3  2  2 6 =5  2 6
3 2 3 2 3 2
3 2 3  2 ( 3  2 )2
y  = = 3 2 2 6 =5  2 6
3 2 3 2 32
x 2  y 2  ( x  y)2  2 xy  (5  2 6  5  2 6 )2  2(5  2 6 )(5  2 6 )
 (10)2  2(25  24)  100  2  98.
1
4  2
( 25 ) 2 / 5  ( 2 2 ) 1 / 2  ( 23 )1 / 3 2
23.  4
1 1 1

4 4
24. We have, x  3  2 2
1 1 1 3 2 2 3 2 2 3 2 2
     2   3 2 2
x 3  2 2 3  2 2 3  2 2 3  (2 2 ) 2
98
1
Thus, x 2  2
 (3  2 2 ) 2  (3  2 2 ) 2
x
1
 x2   9  8  12 2  9  8  12 2  34
x2
25. L.C.M. of 2, 4, 5 = 20
(5)1 / 4 , (4)1 / 5 , (4)1 / 2 , (3)1 / 2
2
CPT-03 IX

(5)5 / 20 , (4) 4 / 20 , (4)10 / 20 , (3)10 / 20


20
55 , 20 44 , 20 410 , 20 310
Since, 44 is smallest amongst 55, 44, 410, 310
5
So, 4 is smallest.
26. (mn)  (mn)2/6  (mn)2/3  (mn)K
4/2

4 2 2
 
(mn) 2 6 3
 (mn) K
(mn)3  (mn)K
K = 3.
27. p( x)  5x  p
4 4
p   5   p  4  p
5 5
28. p(2) = 0
k (2)4  11(2)3  k (2)2  13  2  2  0
16k – 88 + 4k + 26 + 2 = 0  20k = 60  k = 3
2
1 1 1 1 3
29. p   2     3   5    5  4
2 2 2 2 2
x3  x 4  x6
30. 2
 x  x2  x4
x
i.e., degree of the polynomial is 4.

BIOLOGY
31. Electron transport system is present in the mitochondria (inner membrane infoldings of
Mitochondria).
32. The mitochondria is the seat of respiration as it produces energy in the form of ATP through electron
transport.
33. Because it has a specialized membrane called tonoplast which helps in osmoregulation in plant cell.
34. Food vacuoles found in Amoeba
35. Amyloplast and Elaioplast are two of the three possible forms of leucoplast which is a colourless
plastid.
36. Thylakoids are number of flattened sacs inside a chloroplast where the light reaction of
photosyntehsis takes place.
37. Stroma refers to the colourless fluid surrounding the grana and thylakoids present within the
chloroplast.
38. Eukaryotes have two types of cell division, mitosis and meiosis. Meiosis is reduction division.
Mitosis is equational division where the number of chromosomes in parent and daughter cells remain
same.
39. Metaphase is a stage of cell division in which chromosomes align in the equator of the cell before
separated into each of the two daughter cell.
40. During reduction division one cell divides to form four daughter cells having half the number of
chromosomes of the parent cell and are called haploid. Reduction division produces sex cells or
gamete cells.
*****

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