A N A LY T I C
GEOM 2
DISCUSSIONS                                      ANALYTIC
                                                 GEOM 2
  CONICS
  Four ways of knowing conics (conic sections)
  1.   By cutting plane
  2.   By discriminant
  3.   By eccentricity
  4.   By equation
DISCUSSIONS                                      ANALYTIC
                                                 GEOM 2
  By Cutting Plane
  •   Parallel to the base: Circle
  •   Parallel to the element: Parabola
  •   Parallel to the axis: Hyperbola,
  •   Any angle provided not parallel to base,
      element, and axis: Ellipse
DISCUSSIONS                                                                      ANALYTIC
                                                                                 GEOM 2
  General Equation of a Conic
          Ax2 + Bxy + Cy2 + Dx + Ey + F = 0
  The invariant B2-4AC can be used to test the type of conics represented by the equations
  above. Thus,
  1.Ellipse if B2 – 4AC < 0
  2.Parabola if B2 – 4AC = 0
  3.Hyperbola if B2 – 4AC > 0
DISCUSSIONS                                                       ANALYTIC
                                                                  GEOM 2
  Eccentricity                                 Conics       Eccentricity
  Measurement of how “uncircle” the conic      Circle            0
  is
                                               Ellipse          <1
             𝑓𝑜𝑐𝑢𝑠                           Parabola            1
  𝑒=
     𝑝𝑒𝑟𝑝𝑒𝑛𝑑𝑖𝑐𝑢𝑙𝑎𝑟 𝑑𝑖𝑠𝑡𝑎𝑛𝑐𝑒
                                             Hyperbola          >1
                                            Straight Line       ∞
DISCUSSIONS                                              ANALYTIC
                                                         GEOM 2
  By Equation
                     Ax2 + Bxy + Cy2 + Dx + Ey + F = 0
  A=C :                         CIRCLE
  A≠C, same sign                ELLIPSE
  A≠C, opposite sign            HYPERBOLA
  Either A or C is present      PARABOLA
DISCUSSIONS                                                                ANALYTIC
                                                                           GEOM 2
  Principal Axis
  Line or segment that divides conics into two equal parts through focus
  Circle                :::           Diameter
  Parabola              :::           Axis of Symmetry
  Hyperbola             :::           Transverse Axis
  Ellipse               :::           Major Axis
PROBLEM NO. 1                                        ANALYTIC
                                                     GEOM 2
  What is the conic section formed by the equation
  16x2-24xy+9y2-144x+8y=244?
  A.   Hyperbola
  B.   Parabola
  C.   Ellipse
  D.   Circle
DISCUSSIONS                                                                          ANALYTIC
                                                                                     GEOM 2
  Circles
  Circle is the locus of point such that it moves equidistant from the fixed point called the
  center.
                                 General Equation of a Circle
                                  Ax2 + Cy2 + Dx + Ey + F = 0
                                    x2 + y2 + Dx + Ey + F = 0
                                Standard Equation of a Circle
                                     (x – h)2 + (y – k)2 = r2
                                         Center : (h, k)
DISCUSSIONS                                                                          ANALYTIC
                                                                                     GEOM 2
  The two circles C1 and C2 are said to be orthogonal (they intersect at right angles) if and
  only if
  D1D2 + E1E2 = 2(F1 + F2)
DISCUSSIONS                                                                 ANALYTIC
                                                                            GEOM 2
                                                    Radical axis
  Radical Axis
  Let the equation of the two intersecting
  circles be as follows
  C1 : x2 + y2 + D1x + E1y + F1 = 0                    Line of Centers
  C2 : x2 + y2 + D2x + E2y + F2 = 0            Radical axis
  The line through the points of
  intersection of C1 and C2 is called the
                                                                         Line of Centers
  radical axis of the circles and its
  equations is
     (D1 – D2)x + (E1 – E2)y + (F1 – F2) = 0
PROBLEM NO. 2                                                      ANALYTIC
                                                                   GEOM 2
  Find the equation of the radical axis of the following circles
  C1 :   x2 + y2 – 5x + 3y – 2 = 0
  C2 :   x2 + y2 + 4x – y – 7 = 0
  A.   9x + 4y + 5 = 0
  B.   9x – 4y + 5 = 0
  C.   9x – 4y – 5 = 0
  D.   9x + 4y – 5 = 0
PROBLEM NO. 3                                                                         ANALYTIC
                                                                                      GEOM 2
  Find the equation of the circle which has the line joining (4, 7) and (2, -3) as diameter.
  A. (x-3)2+(y-2)2=26
  B. (x+3)2+(y-2)2=26
  C. (x+3)2+(y+2)2=26
  D. (x-3)2+(y+2)2=26
PROBLEM NO. 4                                                                      ANALYTIC
                                                                                   GEOM 2
  Find the radius and the equation of the line tangent to a circle whose center is (5,3) and
  at the point (10, 15)
  A.   13, 5x-12y=230
  B.   13, 5x+12y=230
  C.   15, 5x+12y=-230
  D.   15, 5x-12y=-230
PROBLEM NO. 5                                                                      ANALYTIC
                                                                                   GEOM 2
  Determine the equation of the circle whose radius is 5, center on the line x = 2 and
  tangent to the line 3x – 4y + 11 = 0
  A. (x-2)2+(y-2)2=5
  B. (x-2)2+(y+2)2=25
  C. (x-2)2+(y+2)2=5
  D. (x-2)2+(y-2)2=25
DISCUSSIONS                                                                         ANALYTIC
                                                                                    GEOM 2
  Parabola
  locus of a point which moves so that it is always equidistant from fixed point called focus
  and a fixed line called directrix.
                               General Equation of a Parabola
                         Ax2 + Dx + Ey + F = 0 ::: Cy2 + Dx + Ey + F = 0
DISCUSSIONS                                                      ANALYTIC
                                                                 GEOM 2
                      Standard Equation of a Parabola
      (x – h)2 = ± 4a(y – k)                 (y – k)2 = ± 4a(x – h)
DISCUSSIONS                                                                    ANALYTIC
                                                                               GEOM 2
  1.Distance from vertex to focus : a = VF
  2.Length of the Latus Rectum : LR = 4a
  3.Eccentricity          :e=1
                            D
              directrix                        Parabola (opens to the right)
                                     L
                                         2a        Axis of the parabola
                                     a
                                 V       F
                                              Latus Rectum
                                     R
                            D’
PROBLEM NO. 6                                                            ANALYTIC
                                                                         GEOM 2
  Find the directrix of the parabola from the equation y-1=0.25 (x+2)2
  A.   y=2
  B.   y=0
  C.   x+y=0
  D.   x-y=0
PROBLEM NO. 7                                        ANALYTIC
                                                     GEOM 2
  The parabola y = 3x2 – 6x + 5 has its vertex at.
  A.   (1, 2)
  B.   (1, 5)
  C.   (3, 2)
  D.   (3, 5)
PROBLEM NO. 8                                                                 ANALYTIC
                                                                              GEOM 2
  A parabolic arch, 18 meters high has a beam, 64 meters long placed along the arch 8
  meters from the top. A beam is to be placed on the bottom. How long should this beam
  be?
  A.   48
  B.   24
  C.   69
  D.   96
DISCUSSIONS                                                                       ANALYTIC
                                                                                  GEOM 2
  Ellipse
  locus of point which moves so that the sum of its distance from two fixed points is
  constant and is equal to the length of the major axis (2a).
  General Equation of a Ellipse
  Ax2 + Cy2 + Dx + Ey + F = 0
DISCUSSIONS                                                                                         ANALYTIC
                                                                                                    GEOM 2
                                       Standard Equation of a Ellipse
      ( x − h) 2 ( y − k ) 2                                   ( x − h) 2 ( y − k ) 2
   1.       2
                +      2
                             =1   Center    : (h, k)        2.       2
                                                                         +      2
                                                                                      =1   Center      : (h, k)
          a          b                                             b          a
                                  Major Axis : Horizontal                                  Major Axis : vertical
DISCUSSIONS                                                                                              ANALYTIC
                                                                                                         GEOM 2
                                                                                      2𝑏2
                                                                               LR =
directrix
                                               a                   directrix           𝑎
                                                                               e = c/a=a/d < 1
                                      B1
                   L1
                                                    L2                         A = π ab
                                                               b
                                                         V2
                             c
                                                                               a > b ::: a2 = b2 + c2
              V1        F1                         F2
                   R1
                                 B2                R2                                                  𝑎−𝑏
                                           c                  Ellipse Flatness              :::   𝑓=
                                                                                                        𝑎
                                                                                                   ′    𝑎−𝑏
                                                   d          Second Flatness               :::   𝑓 =
                                                                                                         𝑏
                                                                                                       𝑐
                                                              Second Eccentricity           :::   𝑒′ =
                                                                                                       𝑏
PROBLEM NO. 9                                                           ANALYTIC
                                                                        GEOM 2
                                                     𝑥2     𝑦2
  Find the values of a, b, c and e for the ellipse        +      = 1?
                                                     25     16
            3
  A. 5,4,3,
            5
            5
  B. 3,4,5,
            3
            4
  C. 4,3,5,
            5
            1
  D. 1,2,3,
            3
PROBLEM NO. 10                                                                    ANALYTIC
                                                                                  GEOM 2
  Find the equation of the ellipse whose foci are the point (±2, 0), and one of whose
  vertices is the point (3,0).
    𝑥2  𝑦2
  A. +       =1
     9   5
    𝑥 2 𝑦2
  B. +       =1
     3   5
    𝑥 2 𝑦2
  C. +       =1
     9  25
    𝑥 2 𝑦2
  D. −       =1
     9   5
PROBLEM NO. 11                                                                            ANALYTIC
                                                                                          GEOM 2
  An ellipse has its vertices at (-2, -3) and (8, -3). If one of the minor axis is at (3, -7), how
  far is the nearest focus to the left of the directrix?
  A.   4.33
  B.   5.33
  C.   6.33
  D.   7.33
DISCUSSIONS                                      ANALYTIC
                                                 GEOM 2
 Hyperbola
 locus of a point which moves so that the
 difference of the distances from two fixed
 points (foci) is constant and is equal to the
 length of the transverse axis (2a).
 EQUILATERAL/ RECTANGULAR HYPERBOLA
 Transverse axis and conjugate axis have the
 same length and asymptotes are
 perpendicular to each other.
 General Equation of a Hyperbola
 ±Ax2 + ∓ Cy2 + Dx + Ey + F = 0
DISCUSSIONS                                      ANALYTIC
                                                 GEOM 2
              Standard Equation of a Hyperbola
DISCUSSIONS                                                                                              ANALYTIC
                                                                                                         GEOM 2
                      asymptotes
                                                                  1.a = semi transverse axis CV1 = CV2
                                                                  2.b = semi conjugate axis CB1 = CB2
                           B1                            L2       3.c = distance from center to focus = CF1 = CF2
   L1
                                                                  4.2a = transverse axis = V1V2
                                                              b
                                                                  5.2b = conjugate axis B1B2
   R1      V1                                  V2   F2            6.2c = distance from focus to focus = F1F2
                         C
                                                                  7.a < b, a = b, or a > b
   R1
                           B2                       R2
                                                                  8.a2 + b2 = c2
                                   d                              9.eccentricity : e = c/a > 1
        directrices
                                       a                          10.Distance from center to directrix : d = a/e
                                                                  11.LR = 2b2/a = length of latus rectum
                                           c
PROBLEM NO. 12                                            ANALYTIC
                                                          GEOM 2
  What are the coordinates of the foci of the hyperbola
  𝑥 2 -4𝑦 2 =4
  A. (±5,0)
  B. (±2,0)
  C. (±3,0)
  D. (±√5,0)
PROBLEM NO. 13                                           ANALYTIC
                                                         GEOM 2
  Find the equation of the asymptotes of the hyperbola
  𝑥 2 -4𝑦 2 =4
  A. 2𝑦 ±x=0
  B. 2𝑦 ±x=4
  C. 2𝑦 ±x=1
  D. 2𝑦 ±x=2
PROBLEM NO. 14                                                                ANALYTIC
                                                                              GEOM 2
  The eccentricity of the hyperbola 6(y – 6)2 – 9(x – 7)2 = 144 is equal to
  A.   6/7
  B.   5/3
  C.   9/7
  D.   6/9
DISCUSSIONS                                                         ANALYTIC
                                                                    GEOM 2
  Translation of Axis
  Wherein (x,y) is the original point and (h,k) is the new origin
                                             x’ = x-h
                                             y ’=y-k
DISCUSSIONS               ANALYTIC
                          GEOM 2
  Rotation of Axis
  x’ = xcos 𝜃 + y sin 𝜃
  y’=-xsin 𝜃 +ycos 𝜃
DISCUSSIONS            ANALYTIC
                       GEOM 2
  Reflection of Axis
PROBLEM NO. 15                                                                      ANALYTIC
                                                                                    GEOM 2
  Find the coordinates of the points (2,3), (-5,7) and (0,2) in a system of coordinates
  whose origin is the point (1,3).
  A. (1,0), (-6,4), (-1,-1)
  B. (1,0), (-6,4), (1,-1)
  C. (1,1), (-6,4), (-1,-1)
  D. (-1,0), (-6,4), (-1,-1)
PROBLEM NO. 16                                                                      ANALYTIC
                                                                                    GEOM 2
  Find the coordinates the points (1,0), (2,2) and (-3,4) referred to a system of rectangular
  coordinates obtained by turning the coordinate axes through an angle of 450.
        2 − 2                      2 7 2
  A.      ,          , 2 2, 0 , ( , )
       2     2                    2    2
        2 − 2                  2 7 2
  B.      ,          , 0,0 , ( , )
       2    2                 2   2
        2 2                      2 7 2
  C.      ,      ,    2 2, 0 , ( , )
       2 2                      2    2
       − 2 2                        2 7 2
  D.        ,         , 2 2, 0 , ( , )
         2     2                   2    2
DISCUSSIONS                                                     ANALYTIC
                                                                GEOM 2
                                                POLAR TO RECTANGULAR
  Polar Coordinates                              𝑥 = 𝑟𝑐𝑜𝑠𝜃 𝑦 = 𝑟𝑠𝑖𝑛𝜃
  •θ is positive if measured counterclockwise   RECTANGULAR TO POLAR
  •θ is negative if measured clockwise
                                                𝑟=   𝑥2 + 𝑦2
                                                                  𝑦
                                                           𝑡𝑎𝑛𝜃 =
                                                                  𝑥
                              Radius vector
DISCUSSIONS                                                                        ANALYTIC
                                                                                   GEOM 2
  The distance between two points (r1, θ1) and (r2, θ2) can be found using cosine law.
              𝑑=                2           2
                            𝑟1 + 𝑟2 − 2𝑟1 𝑟2 𝑐𝑜𝑠𝜃
PROBLEM NO. 17                                           ANALYTIC
                                                         GEOM 2
  Calculate the distance between (3,60∘) and (5,145∘).
  A.   6.90
  B.   5.60
  C.   4.70
  D.   3.90
PROBLEM NO. 18                                            ANALYTIC
                                                          GEOM 2
  Convert r(-2 sin𝜃+ 3 cos𝜃) = 2 into rectangular form.
  A. -2y + 3x = 2
  B. -2y - 3x = 2
  C. -3y + 2x = 2
  D. 3y - 2x = 2
PROBLEM NO. 19                                 ANALYTIC
                                               GEOM 2
  Convert 𝜃 + 𝜋/4 = 0 into rectangular form.
  A.   y=x
  B.   y=-x
  C.   y+1=x
  D.   y-1=x
PROBLEM NO. 20                                                                    ANALYTIC
                                                                                  GEOM 2
  Given the polar equation r = sin 𝜃. Determine the rectangular coordinates (x,y) of a
  point in the curve when 𝜃 is 30 degrees
  A.   (2.17, 1.25)
  B.   (3.08, 1.5)
  C.   (2.51, 4.12)
  D.   (6, 3)