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Quadratic Equation Practice Questions 2021
1. In the following questions two equations Ax<y
numbered I and II are given. You have to solve
Bx>y
both the equations and choose the correct
option. Cx≤y
I. x2 -15x +36 = 0 Dx≥y
II. 10y2 +31y -63 = 0 E x = y or relationship cannot be established
Ax<y Correct Answers: B. x > y
Bx>y From equation I:
Cx≤y x2 -20x +96 = (x -12)(x -8)= 0
Dx≥y => x = 12, 8
E x = y or relationship cannot be established From equation II:
Correct Answers: B. x > y y2 +y -6 = (y -2)(y + 3) = 0
From equation I: => y = 2, -3
x2 -15x +36 = (x -12)(x -3)= 0 So, x > y
=> x = 12, 3 3. In the following questions two equations
numbered I and II are given. You have to solve
From equation II: both the equations and choose the correct
option.
10y2 +31y -63 = (5y -7)(2y + 9) = 0
=> y = 7/5, -9/2 I. x2 +16x -161 = 0
So, x > y II. y2 -31y +210 = 0
2. In the following questions two equations Ax<y
numbered I and II are given. You have to solve
Bx>y
both the equations and choose the correct
option. Cx≤y
I. x2 -20x +96 = 0 Dx≥y
II. y2 +y -6 = 0 E x = y or relationship cannot be established
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Correct Answers: A. x < y => y = 7/2, -9/5
From equation I: So, x > y
x2 +16x -161 = (x + 23)(x -7)= 0 5. In the following questions two equations
numbered I and II are given. You have to solve
=> x = -23, 7
both the equations and choose the correct
From equation II: option.
y2 -31y +210 = (y -10)(y -21) = 0 I. x2 -x -42 = 0
=> y = 10, 21 II. y2 -24y +128 = 0
So, x < y Ax<y
4. In the following questions two equations Bx>y
numbered I and II are given. You have to solve
both the equations and choose the correct Cx≤y
option.
Dx≥y
I. x2 -44x +483 = 0 E x = y or relationship cannot be established
II. 10y2 -17y -63 = 0 Correct Answers: A. x < y
Ax<y From equation I:
Bx>y x2 -x -42 = (x + 6)(x -7)= 0
Cx≤y => x = -6, 7
Dx≥y From equation II:
E x = y or relationship cannot be established y2 -24y +128 = (y -8)(y -16) = 0
Correct Answers: B. x > y => y = 8, 16
From equation I: So, x < y
x2 -44x +483 = (x -21)(x -23)= 0 6. In the following questions two equations
numbered I and II are given. You have to solve
=> x = 21, 23
both the equations and choose the correct
From equation II: option.
10y2 -17y -63 = (2y -7)(5y + 9) = 0 I. 9x2 -9x +2 = 0
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II. y2 -28y +187 = 0 Correct Answers: B. x > y
Ax<y From equation I:
Bx>y x2 -11x -126 = (x -18)(x + 7)= 0
Cx≤y => x = 18, -7
Dx≥y From equation II:
E x = y or relationship cannot be established y2 +30y +224 = (y + 16)(y + 14) = 0
Correct Answers: A. x < y => y = -16, -14
From equation I: So, x > y
9x2 -9x +2 = (3x -1)(3x -2)= 0 8. In the following questions two equations
numbered I and II are given. You have to solve
=> x = 1/3, 2/3 both the equations and choose the correct
From equation II: option.
y2 -28y +187 = (y -17)(y -11) = 0 I. x2 -15x +36 = 0
=> y = 17, 11 II. 10y2 +43y -9 = 0
So, x < y Ax<y
7. In the following questions two equations Bx>y
numbered I and II are given. You have to solve
both the equations and choose the correct Cx≤y
option. Dx≥y
I. x2 -11x -126 = 0 E x = y or relationship cannot be established
II. y2 +30y +224 = 0 Correct Answers: D. x > y
Ax<y From equation I:
Bx>y x2 -15x +36 = (x -3)(x -12)= 0
Cx≤y => x = 3, 12
Dx≥y From equation II:
E x = y or relationship cannot be established 10y2 +43y -9 = (2y + 9)(5y -1) = 0
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=> y = -9/2, 1/5 II. y2 -33y +270 = 0
So, x > y Ax<y
9. In the following questions two equations Bx>y
numbered I and II are given. You have to solve
Cx≤y
both the equations and choose the correct
option. Dx≥y
I. x2 +15x +54 = 0 E x = y or relationship cannot be established
II. y2 -5y -66 = 0 Correct Answers: A. x < y
Ax<y From equation I:
Bx>y x2 +9x -22 = (x -2)(x + 11)= 0
Cx≤y => x = 2, -11
Dx≥y From equation II:
E x = y or relationship cannot be established y2 -33y +270 = (y -15)(y -18) = 0
Correct Answers: C. x ≤ y => y = 15, 18
From equation I: So, x < y
x2 +15x +54 = (x + 9)(x + 6)= 0 11. In the following questions two equations
numbered I and II are given. You have to solve
=> x = -9, -6 both the equations and choose the correct
option.
From equation II:
y2 -5y -66 = (y -11)(y + 6) = 0 I. 6x2 +41x +70 = 0
=> y = 11, -6 II. y2 +16y -17 = 0
So, x ≤ y Ax<y
10. In the following questions two equations Bx>y
numbered I and II are given. You have to solve
Cx≤y
both the equations and choose the correct
option. Dx≥y
I. x2 +9x -22 = 0 E x = y or relationship cannot be established
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Correct Answers: E. x = y or relationship cannot y2 +9y -112 = (y -7)(y + 16) = 0
be established
=> y = 7, -16
From equation I: So, x > y
6x2 +41x +70 = (2x + 7)(3x + 10)= 0 13. In the following questions two equations
=> x = -7/2, -10/3 numbered I and II are given. You have to solve
both the equations and choose the correct
From equation II: option.
y2 +16y -17 = (y -1)(y + 17) = 0
I. x2 +12x -45 = 0
=> y = 1, -17
So, relationship cannot be established between x II. y2 -16y +55 = 0
and y
Ax<y
12. In the following questions two equations Bx>y
numbered I and II are given. You have to solve
both the equations and choose the correct Cx≤y
option. Dx≥y
I. x2 -17x +72 = 0 E x = y or relationship cannot be established
II. y2 +9y -112 = 0 Correct Answers: A. x < y
Ax<y From equation I:
Bx>y x2 +12x -45 = (x + 15)(x -3)= 0
Cx≤y => x = -15, 3
Dx≥y From equation II:
E x = y or relationship cannot be established y2 -16y +55 = (y -5)(y -11) = 0
Correct Answers: B. x > y => y = 5, 11
From equation I: So, x < y
x2 -17x +72 = (x -9)(x -8)= 0 14. In the following questions two equations
numbered I and II are given. You have to solve
=> x = 9, 8 both the equations and choose the correct
From equation II: option.
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I. x2 +18x +77 = 0 E x = y or relationship cannot be established
II. y2 -14y -147 = 0 Correct Answers: B. x > y
Ax<y From equation I:
Bx>y x2 -42x +440 = (x -20)(x -22)= 0
Cx≤y => x = 20, 22
Dx≥y From equation II:
E x = y or relationship cannot be established y2 -19y +88 = (y -8)(y -11) = 0
Correct Answers: C. x ≤ y => y = 8, 11
From equation I: So, x > y
x2 +18x +77 = (x + 7)(x + 11)= 0 16. In the following questions two equations
numbered I and II are given. You have to solve both
=> x = -7, -11 the equations and choose the correct option.
From equation II: I. 15x2 -2x -24 = 0
y2 -14y -147 = (y + 7)(y -21) = 0 II. y2 -20y +84 = 0
=> y = -7, 21
Ax<y
So, x ≤ y
Bx>y
15. In the following questions two equations
Cx≤y
numbered I and II are given. You have to solve
both the equations and choose the correct Dx≥y
option.
E x = y or relationship cannot be established
I. x2 -42x +440 = 0 Correct Answers: A. x < y
II. y2 -19y +88 = 0 From equation I:
Ax<y 15x2 -2x -24 = (5x + 6)(3x -4)= 0
Bx>y => x = -6/5, 4/3
Cx≤y From equation II:
Dx≥y y2 -20y +84 = (y -14)(y -6) = 0
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=> y = 14, 6 II. y2 -37y +330 = 0
So, x < y Ax<y
17. In the following questions two equations Bx>y
numbered I and II are given. You have to solve
both the equations and choose the correct Cx≤y
option.
Dx≥y
I. x2 +21x +110 = 0 E x = y or relationship cannot be established
II. y2 +15y +56 = 0 Correct Answers: A. x < y
Ax<y From equation I:
Bx>y x2 +8x -65 = (x -5)(x + 13)= 0
Cx≤y => x = 5, -13
Dx≥y From equation II:
y2 -37y +330 = (y -15)(y -22) = 0
E x = y or relationship cannot be established
=> y = 15, 22
Correct Answers: A. x < y
So, x < y
From equation I:
19. In the following questions two equations
x2 +21x +110 = (x + 10)(x + 11)= 0
numbered I and II are given. You have to solve
=> x = -10, -11 both the equations and choose the correct
option.
From equation II:
y2 +15y +56 = (y + 8)(y + 7) = 0 I. x2 +x -306 = 0
=> y = -8, -7 II. y2 -12y -28 = 0
So, x < y Ax<y
18. In the following questions two equations Bx>y
numbered I and II are given. You have to solve
both the equations and choose the correct Cx≤y
option.
Dx≥y
I. x2 +8x -65 = 0 E x = y or relationship cannot be established
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Correct Answers: E. x = y or relationship cannot => y = 4, -3
be established
So, x > y
From equation I:
21. In the following questions two equations
x2 +x -306 = (x -17)(x + 18)= 0 numbered I and II are given. You have to solve
both the equations and choose the correct
=> x = 17, -18
option.
From equation II:
I. 9x2 -64 = 0
y2 -12y -28 = (y -14)(y + 2) = 0
II. y2 +28y +147 = 0
=> y = 14, -2
Ax<y
20. In the following questions two equations
numbered I and II are given. You have to solve Bx>y
both the equations and choose the correct
Cx≤y
option.
Dx≥y
I. x2 -40x +399 = 0
E x = y or relationship cannot be established
II. y2 -y -12 = 0
Correct Answers: B. x > y
Ax<y
From equation I:
Bx>y
9x2 -64 = (3x + 8)(3x -8)= 0
Cx≤y
=> x = -8/3, 8/3
Dx≥y
From equation II:
E x = y or relationship cannot be established
y2 +28y +147 = (y + 21)(y + 7) = 0
Correct Answers: B. x > y
=> y = -21, -7
From equation I:
So, x > y
x2 -40x +399 = (x -21)(x -19)= 0
22. In the following questions two equations
=> x = 21, 19
numbered I and II are given. You have to solve
From equation II: both the equations and choose the correct
option.
y2 -y -12 = (y -4)(y + 3) = 0
I. x2 +11x +30 = 0
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II. y2 -5y -50 = 0 Correct Answers: A. x < y
Ax<y From equation I:
Bx>y x2 +30x +209 = (x + 11)(x + 19)= 0
Cx≤y => x = -11, -19
Dx≥y From equation II:
E x = y or relationship cannot be established 10y2 -27y -81 = (2y -9)(5y + 9) = 0
Correct Answers: C. x ≤ y => y = 9/2, -9/5
From equation I: So, x < y
x2 +11x +30 = (x + 6)(x + 5)= 0 24. In the following questions two equations
numbered I and II are given. You have to solve
=> x = -6, -5 both the equations and choose the correct
From equation II: option.
y2 -5y -50 = (y -10)(y + 5) = 0 I. x2 -40x +396 = 0
=> y = 10, -5 II. y2 -7y +6 = 0
So, x ≤ y Ax<y
23. In the following questions two equations Bx>y
numbered I and II are given. You have to solve
both the equations and choose the correct Cx≤y
option. Dx≥y
I. x2 +30x +209 = 0 E x = y or relationship cannot be established
II. 10y2 -27y -81 = 0 Correct Answers: B. x > y
Ax<y From equation I:
Bx>y x2 -40x +396 = (x -22)(x -18)= 0
Cx≤y => x = 22, 18
Dx≥y From equation II:
E x = y or relationship cannot be established y2 -7y +6 = (y -1)(y -6) = 0
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=> y = 1, 6 II. y2 +28y +115 = 0
So, x > y Ax<y
25. In the following questions two equations Bx>y
numbered I and II are given. You have to solve
both the equations and choose the correct Cx≤y
option. Dx≥y
I. x2 -x -132 = 0 E x = y or relationship cannot be established
II. y2 -31y +234 = 0 Correct Answers: B. x > y
Ax<y From equation I:
Bx>y 15x2 +4x -3 = (3x -1)(5x + 3)= 0
Cx≤y => x = 1/3, -3/5
Dx≥y From equation II:
E x = y or relationship cannot be established y2 +28y +115 = (y + 5)(y + 23) = 0
Correct Answers: A. x < y => y = -5, -23
From equation I: So, x > y
x2 -x -132 = (x + 11)(x -12)= 0 27. In the following questions two equations
numbered I and II are given. You have to solve
=> x = -11, 12 both the equations and choose the correct
option.
From equation II:
y2 -31y +234 = (y -18)(y -13) = 0 I. 6x2 -7x -24 = 0
=> y = 18, 13 II. y2 +31y +238 = 0
So, x < y Ax<y
26. In the following questions two equations Bx>y
numbered I and II are given. You have to solve
both the equations and choose the correct Cx≤y
option. Dx≥y
I. 15x2 +4x -3 = 0 E x = y or relationship cannot be established
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Correct Answers: B. x > y => y = -21, -14
From equation I: So, x > y
6x2 -7x -24 = (3x -8)(2x + 3)= 0 29. In the following questions two equations
numbered I and II are given. You have to solve
=> x = 8/3, -3/2
both the equations and choose the correct
From equation II: option.
y2 +31y +238 = (y + 14)(y + 17) = 0 I. x2 -17x -38 = 0
=> y = -14, -17 II. y2 -39y +380 = 0
So, x > y Ax<y
28. In the following questions two equations Bx>y
numbered I and II are given. You have to solve
both the equations and choose the correct Cx≤y
option.
Dx≥y
I. x2 -15x -100 = 0 E x = y or relationship cannot be established
II. y2 +35y +294 = 0 Correct Answers: C. x ≤ y
Ax<y From equation I:
Bx>y x2 -17x -38 = (x -19)(x + 2)= 0
Cx≤y => x = 19, -2
Dx≥y From equation II:
E x = y or relationship cannot be established y2 -39y +380 = (y -20)(y -19) = 0
Correct Answers: B. x > y => y = 20, 19
From equation I: So, x ≤ y
x2 -15x -100 = (x + 5)(x -20)= 0 30. In the following questions two equations
numbered I and II are given. You have to solve
=> x = -5, 20
both the equations and choose the correct
From equation II: option.
y2 +35y +294 = (y + 21)(y + 14) = 0 I. x2 +14x +40 = 0
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II. y2 +28y +192 = 0 From equation I:
Ax<y x2 +14x +40 = (x + 4)(x + 10)= 0
Bx>y => x = -4, -10
Cx≤y From equation II:
Dx≥y y2 +28y +192 = (y + 16)(y + 12) = 0
E x = y or relationship cannot be established => y = -16, -12
Correct Answers: B. x > y So, x > y
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