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What is forecasting?
+ Forecasting is a a tool used for predicting
future demand based on past and
current demand information.
+ Common variables that are forecasted
include demand levels, supply levels,
and prices.What is forecasting?
+ Forecasting is an integral part of almost all
business enterprises including
Manufacturing firms that forecast demand for their
products
Service organizations that forecast customer
artival patterns to maintain adequate customer!
service,
Secutity analysts who forecast revenues, profits,
and debt ratios, to make investment
recommendations. +
Firms that consider economic forecasts of
indicators (housing starts, changes in gross
national profit) before deciding on capital
investments.fa)
a is a a
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rs | I What is hotel
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ee 'youtube.comiwatc! )-WLFSC-](a) ofl
Why is forecasting important?
Demand for products and services is usually uncertain.
Forecasting can be used for
+ Strategic planning (long range planning)
+ Finance and accounting (budgets and cost
controls)
+ Marketing (future sales, new products)
+ Production and operations pusness ——
researct
Sefa)
What is forecasting all about?
Demand for Mercedes E Class Dieteaaeca as
sina oentae te
Baan
er ace
Cone)
ee)
Peetind
a
Jan Feb Mar Apr May Jun Jul Aug
@ | Actual demand (past sales)
@ Predicted demanda 2
Short Term Forecasting: Needs and Uses
Scheduling existing resources
+ How many employees do we need and when?
* How much product should we make in
anticipation of demand?
nal resources
* When are we going to run out of capacity?
+ How many more people will we need?
* How large will our back-orders be?
six months one year
five years
Determining what resources are needed
* What kind of machines will we require?
* Which services are growing in demand?
declining?
+ What kind of people should we be hiring?Example: Mercedes E-class vs. M-class Sales
Month | E-classSales | M-class
Sales
Jan 23,345 =
Feb 22,034 =
Mar 21,453 =
Apr 24,897 =
May 23,561 =
Jun) 22,684 =
Jul ? ?
Question: Can we predict the new model M-class sales based on
CUTERCP Tmt item e Hemel) Cor
PASC eam VCO Co oct ROMO EST om Cena Mme)
PLEAS LEN Kea LU MCcepTLEA OE14
Forecast Types
Organizations often need to forecast variables other than demand. The most common forecast
types are: demand, supply, and price forecasts.
Demand Forecasts BAN
NX
Q)
yy
Supply Forecasts =
Price Forecasts5
Fundamental Principles of ForecastingMain Steps in Forecasting Process
See cae nee
eo nearer
Ce ene eu eit)
Step 3 Select a forecasting technique
Reason eu ce)
Re Pc iey tec ke dee tdMajor Categories of Forecasts
__|Quantitative Qualitative
avercast
https:/www.youtube.com/watch?\
|_9mLIbe&t=2sMajor Categories of Forecasts
Qualitative methods — judgmental methods
+ Forecasts generated subjectively by the forecaster
+ Educated guesses
Quantitative methods — based on mathematical modeling:
| + Forecasts generated through mathematical modelingfa)
_ Major Categories of Forecasts
|__ Forecasting methods are classified into two groups
41. Characteristics Based on human judgment, Based on mathematics;
|.) ‘opinions; subjective and quantitative in nature.
I nonmathematical.
2. Strengths Can incorporate latest Consistent and objective;
changes in the environment —_able to consider much
and “inside information.” ‘information and data at
i) ‘one time.
3. Weaknesses Can bias the forecast and Often quantifiable data are
reduce forecast accuracy. not available. Only as good
as the data on which they
are based.fa)
20 ff
Qualitative Methods
Executive
opinion
Market
research
Delphi
method
A group of managers Good for strategic or One person's opinion
meet & come up with new-product can dominate the
a forecast forecasting forecast
Uses surveys & Good determinant of It can be difficult to
interviews to identify customer preferences develop a good
customer preferences questionnaire
Seeks to developa = Excellent for Time consuming to
consensus among a forecasting long-term develop
group of experts product demand,
technologicala ai
Qualitative forecasting methods
JNAVADHI
‘wwnavedhcom
1. Market Surveys: are generally structured
questionnaires submitted to potential customers
in the market. They solicit opinions about
products or potential products, and also often
attempt to get an understanding of the likelihood
of customer demand for products or services.
od
& 6 STEPS OF
SUCCESSFUL
Strength: If structured well and administered to a MARKET RESEARCH,
representative sample of the defined population, PROCESS. ©
market surveys can be quite effective.
Weakness: A major drawback is that they are
expensive and time-consuming to perform."2. Panel Consensus: A qualitative forecasting technique
that brings experts together to discuss and develop a
forecast.
| 3. Delphi Method: A qualitative forecasting technique in
which experts work individually to develop forecasts. The
individual forecasts are shared among the group, and then
each participant is allowed to modify his or her forecast
| based on information from the other experts.
| This process is repeated until consensus is reached.
Advantages:
The advantage is that when done correctly,
i ney do tend to be quite accurate.
Disadvantages:
These two methods tend to be quite expensive, primarily
due to the time requirements from a group of experts in the
“field. Such experts often charge fairly high fees for their
ime and observations.
‘Steps of Delphi Method4. Life cycle analogy method is a forecasting technique that attempts to identify the time frames and demand
levels for the introduction, growth, maturity, and deciine Ife cycle stages of a new product or service based on the
observation that many products and services have a fairly well-defined lite cycle.
‘The major questions that arise include the follo 4
+ How long will each stage last?
+ How rapid will the growth be? How rapid will the decline be?
+ How large will the overall demand be, especially during
the maturity phase?
£ Sales
‘invest
Introduction] Growth
~ Effective if the new product or service is essentially replacing another in the market and targeted to the same
population.
Disadvantages:
Not accurate, but a good starting point when no product demand history is available.Qualitative forecasting methods
5. Informed judgment is among the most common forecasting
methods used, but unfortunately is also among the worst methods
lo use.
Example: A sales manager to ask each salesperson to develop a
projection of sales for their area for some defined time period in
the future. The sales manager then combines the individual sales
projections into an overall sales forecast for the company.
This method tend to be so poor due to several things that will
| Potentially alter the judgment ofthe incividual, sometimes without
them being consciously aware. For example:
- Being optimistic
- Being pessimistic
Being affected by recent eventsfa)
Quantitative forecasting methods
25a 26 fl
Causal Models
Causal models use statistical techniques to establish
relationships between various items and demand
Some of the key characteristics of these methods include:
+ This method is based on the concept of relationship
between variables, or the assumption that one
measurable variable "causes" the other to change in a
predictable fashion.
+ The causal variable can be accurately measured.
+ The developers will gain additional significant market
Knowledge during the process of developing the models.
» These methods are seldom used for product, but more
commonly used for entire markets or industries.
+ The methods are often time-consuming and very
expensive to develop, primarily because of developing the
relationships and obtaining the causal data.
eCeC SC!
Gausal Forecastingfa)
27
Causal Relationship:
Some of the more common methods of causal forecasting are given as:
input =y
Input-output models
om Simulation models
G output
Econometric models
Regression_ Time Series
+ Time Series models predict future demand
based on past history trends
Itis the process of analyzing time series data
using statistics and modeling to make.
predictions and inform strategic decision-
making.
It's not always an exact prediction, when
dealing with the commonly fluctuating
variables in time series data as well as
2 factors outside our control.
Examples of time series forecasting
___- Forecasting the closing price of a stock
_ each day
/__ - Forecasting product sales in units sold each
day for a store
10 fie Frecean on New Date
‘ooo! aval
= predicted
2200
3
E 2000
‘ays an 212-Dec 2016)Time Series Patterns
. Random pattern (Horizontal Pattern)
A horizontal pattern exists when the data
fluctuate randomly around a constant mean ovel
time.
Changes in a condition often result in a time
series with a horizontal pattern to shift to a new
level at some point in time
Demand
endo seges
ation30
resriceaire rar desea
‘wend a
|\
rane
ocean werd ‘enioesr
PX lerecaing versTime Series Patterns
'3. Seasonal pattern oe ‘Sarpie seasonal
{opal pater
+ It occurs when a time series is affected by
seasonal factors such as the time of the year
or the day of the week.
“he
‘Seasonality is always of a fixed and known
frequency.Time Series Patterns
. Cyclic pattern
It occurs when the data exhibit rises and falls g «»-
that are not of a fixed frequency.
gow.
5
The duration of these fluctuations is usually of be
at least 2 years.33 |
|
Time Series Patterns
If we were to put a random pattern together with a trend and a seasonal pattern, we could obtain
a demand pattern that would look similar to the pattern experienced by many companies for their
products or services.
For example, a random, seasonal pattern with a linear increasing trend might look something like
the figure below
Demand
Time| Time Series Forecasting Models
1. Naive (Last Period) Models
_ The simplest time series model is a last period model, which uses demand for the current period
“as a forecast for the next period. Stated formally:
Fy =D,
where:
Fy, = forecast for the next period, t + 1
D, = demand for the current period, t"Consider the time series listed in below table and graphed. Suppose the director of the emergency
care facility decides to use Naive(last period) forecasting model to predict the number of patients
each week.
2
3
4
|
yg
7 27 108
8 17 27
9 27 7
0 103 127
Zz 36 ie ae a
i 12 36 36 ‘Week
3 26 %
14 101 36 As the results suggest, the main problem with a Naive
13 103 101 model is that it is based on only one observation. This
| 109 makes it overly susceptible to unusually high or low values
Naive (Last Period) Forecasting for an Emergency Care FacilityiE ‘Time Series Forecasting Models
__ 2, Simple Moving Average (SMA) Model
+ It derives a forecast by taking an average of a set of recent demand values.
By basing the forecast on more than one observed demand value, the moving average model is
less susceptible to random swings in demand.
The model is stated as follows:
2
Drei
Aa
F..1 = forecast for time period t + 1
Drst-i ctual demand for period t + 1 — i
n = number of most recent demand observations used to develop the forecastQ) For example, using the data in the table, what is
the forecast for week 16 using four-period simple
| moving average (4 period-SMA) and two-period
__ simple moving average (2 period-SMA)?
Four-period simple moving average: The forecast
for 16 is derived from the demand figures for the *:
previous four weeks (weeks 12-15): .
8 8
| Two-period simple moving average: The forecast
for 16 is derived from the demand figures for the
previous two weeks (weeks 14-15):
=105
3
|
‘Number of patients| Time Series Forecasting Models
3. Weighted Moving Average (WMA) Model
| A variation of the moving average model is the weighted moving average model. In this case,
he actual weights applied to past observations are allowed to differ:
.
Ra = Win iDear-
W,41-i = weight assigned to the demand in period t + 1 — i
"
DM =1
a
As the formulas suggest, the only real restriction is that the weights must add to 1.Q) Suppose we want to use a three-period weighted moving average (3
period- WMA) model with the following weights:
| Weight given to the current time period = Wt = 0.5
Weight given to the last time period = Wt- 1 = 0.3
Weight given to the time period two periods earlier = W-2 = 0.2
/ The different weights will place more emphasis on the most recent
| observations. Using the data in the table, the three-period weighted
moving average forecast for week 16 would be:
4
Fis = YWre-Dio-i = WisDis + WuaDiy + WD
a
= 0.5*109 + 0.3*101 + 0.2*86 = 102
pos co
es}
84
aI
29
90
93
106
a7
n7
a7
103
96
96
a6
101
109Flavio’s Pizza has recorded the following demand history for each Friday night for the past
5 weeks. Develop forecasts for week 6 using a two-period moving average and a three period
_ weighted moving average. The weights for the three-period moving average model
are 0.4, 0.35, and 0.25, starting with the most recent observation.
ia
Solution:
1
. 2
The two-period moving average forecast would be: -
Fez (60 + 73)/2 = 66.5 pizzas a
The three-period moving average forecast would be: _
_ Fe= 0.4*60 + 0.35*73 + 0.25*55 = 63.3 pizzas —| Time Series Forecasting Models
_ 4, Exponential Smoothing Model
_The exponential smoothing model is @ special form ofthe moving average model in which the
forecast for the next period is calculated as the weighted average of the current period’s actual
_ value and forecast. The formula for the exponential smoothing model is:
cy F,.1 = forecast for time periodt + 1 (e., the new forecast)
R
D, = actual value for time period t
smoothing constant used to weight D,and F,(0 = a@ = 1)
forecast for time period t (ic., the current forecast)
R
I42
Example
Suppose the Emerald Pool Company has just started
selling aboveground pools. In the first month, the
company forecasted demand of 40 pools, while actual
demand tured out to be 50. If we select an_ value of
0.3, the exponential smoothing forecast for period 2
becomes:
Period Demand Forecast
Fe= 0.3*D: + (1 - 0.3)Fi ' 5 0
= 0.3°50 + 0.7*40 = 15 + 28 = 43 pools 2 a 0.3 °50+(1-0.3)*40=43
/ 52 0.3 * 46+ (1-0.3)* 43 = 43.9
Now suppose period 2 demand turns out to be 46 pools.
The forecast for period 3 can now be calculated as: 4 03+s2+(1-03)"439
5 ay 03% 48+ (1-03)" 4633 =
Fi
.3*Ds+ (1 - 0.3)Fe
.3*46 + 0.7°43 = 13.8 + 13.0 = 43.9 pools
6 03°47 +(1-03)* 46.83 =_ Example
| Using the time series data the table, calculate an
exponential smoothing forecast for periods 2 through 20,
using a smoothing constant value of 0.8.
The detailed calculations for F2 through F7 are as follows:
F2 = 0.8°D1 +0.2*F1 = 0.810 + 0.210 = 10
F3 = 0.8°D2 + 0.2*F2 = 0.8°11 +0.2"10 = 10.8
F4 = 0.8°D3 + 0.2*F3 = 0.8*9 + 0.2°10.8 = 9.36
| F5 = 0.8°D4 + 0.2*F4 = 0.8°11 + 0.2*9.36 = 10.67
| F6 = 0.8°DS + 0.2*F5 = 0.810 + 0.2°10.67 = 10.13
FT = 0.8*D6 + 0.2*F6 = 0.8*8 + 0.2°10.13 = 8.43
"Forecasts for periods 8 through 20 are completed in a
similar manner.
13 IB 21.t e-
% 20 19.68
wo 1974
192075
200 tas
mo om var
“ose he res ld a5 10.ee
oman graze elect poted wast
Figures show the complete set of forecast values and graph. Because of the high value, the exponential
|
“smoothing model now reacts quickly to the increase in demand levels.ll
Linear Regression
+ An approach to forecasting when there is a
trend in the data is linear regression.
+ Linear regression is a statistical technique
that expresses the forecast variable as a
linear function of some independent
variable.
+ In the case of a time series model, the
independent variable is the time period
itself.Linear Regression
" Linear regression works by using past data to estimate the intercept term and slope coefficient for
the followingline: . . , ¢ “)
j=at bx
R .
oe
forecast for dependent variable y
independent variable x, used to forecasty
estimated intercept term forthe line
B = estimated slope coefficient forthe line
| __ Gand Bare estimated wsing the raw time series data for variable» he dependent variable)
+ and variable he idepeen variable
where:
| (5.9) = matched pais of observed (x.
numberof paired observations
“ Once the line in Equation (has been estimated, the forecaster can then plug
in values for x, the independent variable, to generate the forecast values, .Mike Clem, owner of Clem’s Competition
Clutches, designs and manufactures heavy-duty
car clutches for use in drag racing. In his first 10
|_| months of business, Mike has experienced the
demand as shown in the Table and Figure
Using the month as the independent variable (x)
to forecast demand (y), Mike wants to develop a
| linear regression forecasting model and use the
|__| model to forecast demand for months 11, 12,
and 13.
40
Demand (y)
8
3
12
25
40
50
65
36
61
88
63The first step is to set up columns to calculate the average x and y values, as well as the sums of
the x, y, x, and xy values for the first 10 months:
| ca)
| , 5 2
1 8 1 8
2 12 4 24
3 25 9 75
4 40 16 160
5 50 25 250
6 65 36 390
| 7 36 49 252
| 8 61 64 488
9 88 81 792
10 63 100 630
sum. 55 448 385 3,069
5.50 44.80Plugging these values into the equations gives the estimate of the slope coefficient, b:
3,069 — 2548
7 10 3,069 — 2,464
32 «3RS OLS
385 — —
10
and the intercept term, a:
— bx = 44.80 — 7.33*5.50 = 4.49
The resulting regression line is:
§ = 449 + 7.33x
By plugging in 11, 12, and 13 for x, we can generate forecasts for months 11, 12, and 13:
Month 11 forecast: 4.49 + 7.33*11 = 85.12 clutches
Month 12 forecast: 4.49 + 7.33*12 = 92.45 clutches
Month 13 forecast: 4.49 + 7.3313 = 99.78 clutchesThe beside Figure plots the
regression line forecasts _ for
months 1 through 13 and the first
410 months of demand.
The graph shows how the
regression line captures the
upward trend in the data and
projects it out into the future.
Of course, these future forecasts
are good’ only as long as_the
upward trend of around 7.33
additional sales each month
continues.
Demandy)
3
3
Bs € 8
o
1
2345 67 8 910 1112 13
‘Month (x)51 ff
How should we pick our forecasting model?
The amount & type of available data
* Some methods require more data than others
Degree of accuracy required
* Increasing accuracy means more data
Length of forecast horizon
* Different models for 3 month vs. 10 years
Presence of data patterns
¢ Lagging will occur when a forecasting model meant for a level
pattern is applied with a trend52
Selecting a Forecasting Method
a
|Forecast Errors
+ Forecasts are never perfect
+ Need to know how much we should rely on our chosen forecasting method
+ Measuring forecast error:
Forecast error for period jis Ei= Di F,
+ Note that over-forecasts = negative errors and under-forecasts = positive errorsfa)
Measuring Forecasting Accuracy
Mean Absolute Deviation (MAD) measures
the total error in a forecast without
regard to sign
Cumulative Forecast Error (CFE) Measures
any bias in the forecast
Mean Square Error (MSE) Penalizes larger
errors
Tracking Signal Measures if your model is
working
MAD =
CFE = y (actual— forecast)
MSE =
TS
CFE
_ D jactual — forecast |
¥ (actual - forecast )*
MAD
5455
Forecast error for period i( E) = D, ~ F,
Mean forecast error (MFE)
‘Mean absolute deviation (MAD) =
Mean absolute percentage error (MAPE)
ad
Tracking signal = AD
where:
‘D; = Demand for time period
Forecast for time period i
S & = sum of the forecast errors for periods 1 through m
a56
Several measures of forecasting accuracy follow —
* Mean absolute deviation (MAD)- a MAD of 0 indicates the forecast
exactly predicted demand
* Mean absolute percentage error (MAPE)- provides a perspective of the
true magnitude of the forecast error
* Mean squared error (MSE)- analogous to variance, large forecast errors
are heavily penalizedGea ACY
fT
Py
EY
rt
5
c
7
r
9
ct
1
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rr
ro
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ry
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rc
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ries)
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rary
5.94
eae
ED
pea
MAD =
4.85fa)
58
Tracking signal
Determines it torecast is within acceptable control limits. If the
tracking signal falls outside the pre-set control limits, there is a bias
problem with the forecasting method and an evaluation of the way
forecasts are generated is warranted.Sumof — MAD
RSFE Abs.Dev. Abs.Dev. (%Erront TS = REE
1 1,000 950 -50 -50 50 50 50 (5.26%) eal
2 1,000 1,070 +70 +20 70 120 60 (5.61%) 33
3 1,000 1,100 +100 +120 100 220 73.3 (6.67%) 1.64
4 1000 960-40 «18040. 260 65(677%) 1.2
5 1000 1,090 +490 +170 90 350 70(642%) 2.4
6 1,000 1,050 +50 +220 50 400 66.7 (6.35%) 33
“Overall, MAD = 400 + 6 = 66.7. MAPE = (5.26 + 5.61 + 6.67 +6.77 + 6.42 + 6.35)6= 6.18%
‘Tocking
4
3
2
1
sign gValue forecast. error —_ertor®2 Month
‘a)MSE?
forecast for month 10 2
b)MSE ?
forecast for month 10 ?
c) Which method appears better?
Value forecast error error’?
1 2
2 Fy R 2144
3 2B 6 36
4 23? 16 7 49
5 1a" 1775 3.75 14.0625
6 wo ° °o
7 wa 7 49
8 ww
° a7. 25 625
using the most recent value as forecast
using the avg of available data as forecasta ol
i
Week _ Snes 10005 of USD) Exponential fneast (a= 0.1) enor __ABS(encs) enor'2_Sverror_ ABS ene)
7 2
a m0 100 100100435
6 10 410 410681 22.78% 22.78%
is ne 369 3691362 20508 20508
2 a2 168168282708 7.30%
2 nas 049 odd 028-2 2K
0 na 4a dak 39.71 262% 262%
2 no 200 «20402 TIN
2 7120080 080065 365% su
2 72a 00720523298 3.29%
ias3 5938 0%
[Weck _ Sales (10005 of USD) i frecast(a=02) eror _ABS(enoe) cor’? _% cor eo
2
» mo 1 L.A ASK
1s mm 40 © 420 «sk 2K ARN.
18 213-2 2351129 1K ON.
B 20s 231 2a 5.35 105% 105K.
a1 2s ais ats, om OK ON.
"7 mn 42 42 1698 2am DEH.
2 2030270270731 176% ML T6N.
2 post 116116138208 SDD
207 oss ass os 4K ADIN
1998 6180 amrWeek _ Snes 10005 of USD) Exponential fneast (a= 0.1) enor __ABS(encs) enor'2_Sverror_ ABS ene)
2
rt ee
— a at
a ois i Mik l=
3 ———
t= ———
#4 —— eo
— ——
3 a
—e ale
Be ae ue, at
——— ————
==
t—# ————
rt % a
t—$ ae
= ae ee
+ —# Se
aa a
z eee
“ ~ ea,Qa ef
Moving Average Forecasts Weighted Moving Average Forecasts
Period) Sales Moving Average Forecasts Weighted Moving Average Forecasts | Error Absolute Deviation Squared Eror| Error Absolute Devitlon ‘Squared Eror
130
2
208
47 30.33383533 30.83533333 3.333338 3.333399833 11.a1n1i111|-3.833833 3.833385333 14 69eaaaas
5s 48 2933333333 29.16666667 43466667 14.66666657 215.1111131|24.833333 1483332333 2200277778
6 oa 34.66666667 365 -13,66667 12.66666667 186.7777778| -15 155 240.25,
79 30.66665667 29.65656667 8.333333 8339333333 69.4adaaaaa]|9.3393333 9.333339333 @7.11111111
8 34.66665667 338322333 9.566667 e.6se666667 75.11111131|-7.923333 7.932332323 6136111111
soa 28,66666667 295 7.866667 7.666666667 58.77777778| 85 as 7225
Pomme 28.66565667 25.65656667 2.333333 2339333333 S.anaqaaaaa|5.3333333 9.333333333 2aaqaaaaae
uoo3 26 26.83333333 7 7 49 |6.1666667 6.166656667 3802777778
pv 2 2,33333333 30.33333333 0.666667 o,6s6666657 o.asacasaga|-1.333333 | 1.3333333331.777797778
aon 3 30.65556667
cre map mse | cre Map se
YY
Compare the accuracy ofthe forecasts using MAD. Please indicate whch forecast appears tobe most accurate.
Compare the accuracy ofthe forecast sing MSE lease indicate which forecast appears tobe mos accurate,
Compare the accuracy ofthe forecasts srg the cumulative error. Pleas ndcate which forecast appears tobe most accurate,64 |
COMPUTER-BASED ORECASTING PACKAGES
Spreadsheets
* Microsoft Excel, Quattro Pro, Lotus 1-2-3
+ Limited statistical analysis of forecast data
Statistical packages
* SPSS, SAS, NCSS, Minitab
* Forecasting plus statistical and graphics
Specialty forecasting packages
* Forecast Master, Forecast Pro, Autobox, SCAfa)
| COLLABORATIVE PLANNING, FORECASTING, AND REPLENISHMENT (CPFR)
- CPR is a set of business processes, backed up by information
technology, in which supply chain partners agree to
+ mutual business objectives and measures,
+ develop joint sales and operational plans,
+ and collaborate to generate and update sales forecasts and
replenishment plans.
What distinguishes CPFR from traditional planning and
forecasting approaches is the emphasis on collaboration.
- The increased communication among partners means that when
demand, promotions, or policies change, managers can adjust
jointly managed forecasts and plans immediately, minimizing or
even eliminating costly after-the-fact corrections.66
SUMMARY
+ Forecasting is a critical business process for nearly every organization.
+ There are four basic patterns of data: level or horizontal, trend, seasonality, and cycles.
+ Forecasting methods can be classified into two groups: qualitative and quantitative
+ Different measures of forecast error, such as MAD, MSE, MAPE, MFE and TS.
+ There are four factors to consider when selecting a forecastng model: amount and type of data
available, degree of accuracy required, length of forecast horizon, and patterns present in the
data.o7 i
Exercises68 ff
Problem #1
Below are monthly sales of light bulbs from the lighting store.
‘Month Sales
gen 258:
Fe 298
Mar 357
Aor 319
May 360
dune
Forecast sales for June using the following
1. Naive method
2.Three- month simple moving average:
3. Three-month weighted moving average using weights of 5, 3 and 2
4, Exponential smoothing using an alpha of 2 and a May forecast of 350.1.360
2. (397 +519 + 560)/3=3453
3.360 x 5-319 x3 +357 x.2=3471
4,350 + 2(860 - 350) = 35270 ff
Problem #2
Demand for aqua fit classes at a large Community Centre are as follows for the first six
‘weeks of this year.
Week Demand
1 162
2 18
3 we
4 190
5 162
6 m
7
‘You have been asked to experiment with several forecasting methods. Calculate the follow-
ing values:
1a) Forecast for weeks 3 through week 7 using a two-period simple moving average
2.b) Forecast for weeks 4 through week 7 using a three-period weighted moving average:
with weights of 6, Sand 1
3.¢) Forecast for weeks 4 through week 7 using exponential smoothing. Begin with a
‘wook 3 forecast of 130 and use an alpha of 3al
(962 +158) /2=
160
(osa.+ 138) /2
148
(938 +190) /2 =
164
(990 + 162) /2=
ras
992.4177) /2=
195
138 x.6+ 198% 5 +162x
121464
190x 6+ 158 x.3~ 158 x
a=1m2
162.6 + 190x.3 + 38x
3=180
17.6 + 182% 3+190x
i
8)
130
150 + 3x (138-150)
124
152.4 = 3 x (190 182.4)
=497
V9.7 + 3x (182-
14997) = 159.4
1594 + 3x (177-1894)
2166.7
32179872 ff
‘Demand for aqua fit classes at a large Community Centre are as follows for the first six
weeks of this year.
162
188
we
190
vez
wr
You have been asked to experiment with several forecasting methods, Calculate the follow-
ing values:
1. a) Forecast for weoks 3 through week 7 using a two-period simple moving average
2. b) Forecast for wooks 4 through woek 7 using a three-peried weighted moving average
with weights of 6, 3 and 1
3.) Forecast for weeks 4 through week 7 using exponential smoething. Begin with a
‘week 5 forecast of 180 and use an alpha of 3182
7
(062 +158) /2
160
(058 +138) /2
148
(138 +990) /
166
(090+ 182) /
186.
e249) /2=
1795
>)
138 x 6+ 158.3 +162
121464
190 x 6 +138 x 3+ 158x
yea
182.6 + 190%.3 4188x
1=180
W7x 6+ 182x 3 +190x
11798
130
130 + 3x (138-130) =
124
152.4 + 3% (190-1524)
=497
497 + 3x 1a2~
1497) =159.4
1994 + 3x (177-189.4)
166.7
73 |74 ff
Problem #3
Sales of a new shed has grown steacily rom the large farm supply store. Below are the sales
from the past five years. Forecast the sales for 2018 and 2019 using exponential smoothing
h an alpha of 4 In 2015, the forecast was 360. Calculate a forecast for 2016 through te
Year Sales Forecast
2015 348 $60
2016 372
2017 3
2018 371Forecast
Year
2015
2016
2007
2018
2019
2020
3583 + 4x (365-3533) = 3580
Sales
348,
a
m
365
360
360+ 4 « (348-360) = 355.2
3552+ 4 x(872-3552)= 3619
3619 + 4x (SM 3619) = S416
ALG + 4x (571-3416) = 3533
7576 ff
Problem #4
Bolow is the actual demand for X-rays at a medical clinic. Two methods of forecasting were
sed. Calculate a mean absolute deviation for each forecast method. Which one is more
accurate?
“Week Actual Demand Forecast #1 Forecast #2.
50
56
5s
es
Beas
saasForecast #1 letron Forecast #2 lertort
50 2 60 2
55 wo 86 9
60 2 55 3
70 9 65 6
Mean Abs Mean Abs
Deviati 575 Deviation: .