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Lift Well Pressurisation Design

The document contains calculations to determine the air supply needed to maintain a 12.5 Pa differential between lift lobbies and wells for a residential building with 1 lift and 25 doors. It is determined that: 1) The total air flow needed is 6,340 L/s or 6.34 m3/s including a 10% safety factor. 2) For the service lift, the total air flow needed is 6,400 L/s or 6.4 m3/s including a 10% safety factor. 3) The effective relief area for pressure relief dampers is 1.08 m2 and 1.09 m2 respectively based on the total air flow and a residue pressure of 50 Pa

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0% found this document useful (0 votes)
418 views2 pages

Lift Well Pressurisation Design

The document contains calculations to determine the air supply needed to maintain a 12.5 Pa differential between lift lobbies and wells for a residential building with 1 lift and 25 doors. It is determined that: 1) The total air flow needed is 6,340 L/s or 6.34 m3/s including a 10% safety factor. 2) For the service lift, the total air flow needed is 6,400 L/s or 6.4 m3/s including a 10% safety factor. 3) The effective relief area for pressure relief dampers is 1.08 m2 and 1.09 m2 respectively based on the total air flow and a residue pressure of 50 Pa

Uploaded by

jibin
Copyright
© © All Rights Reserved
We take content rights seriously. If you suspect this is your content, claim it here.
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Download as XLSX, PDF, TXT or read online on Scribd
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Lift Well Pressurisation 1 to4

Project: G+4P+19 RESIDENTIAL BUILDING JBL Author: JM


Project No: Date: 13/05/2020
System: Checked:
Date:
Design criteria

below Calculation done based on BS EN 12101 6:2005


Lift well pressurisation based on 12.5 Pa differential between lobbies and the well.
Calculation of air supply to maintain 12.5 Pa in the lift lobby relative to the tenants demise,
when all doors Leakages are through following elements:
Leakages through lift shafts & Vent
Perimeter of the internal walls where leakage = 10.8 m2
Height of the lift shaft = 84.21 m
No. of lifts = 1
Leakage area through lift shafts = 909.47 m2
The leakage area ratio for an "tight construction" lift well wall Refer Table A.3 of BS EN
0.00018
is: 12101-6:2005
Effective leakage Area = 0.16 m2
Vent at the head of the shaft = 0.3 m2
Leakages through lift doors
Refer Table A.3 of BS EN
Crackage area around the lift doors = 0.06 m2
12101-6:2005
No. of lifts in the shaft = 1
No. of lift doors = 25
Total area around lift doors = 1.5 m2
Total flow

Q=(0.83 x Ae x P1\N) = 5.76 m³/s


(value of N taken as 2 as recommended in BS EN 12101-6:2005)

10% SAFETY = 6.34 m³/s


Total Flow = 6340 L/s
Pressure Relief Damper
Total flow (Q) = 6.34 m³/s
Residue Pressure(P) = 50 Pa Refer to BS EN 12101-
Effective Relief Area 6:2005
Ae = Q/(0.83*SQRT(P)) = 1.08 m2
Lift Well Pressurisation Service Lift

Project: G+4P+19 RESIDENTIAL BUILDING JBL Author: JM


Project No: Date: 13/05/2020
System: Checked:
Date:
Design criteria

below Calculation done based on BS EN 12101 6:2005


Lift well pressurisation based on 12.5 Pa differential between lobbies and the well.
Calculation of air supply to maintain 12.5 Pa in the lift lobby relative to the tenants demise,
when all doors Leakages are through following elements:
Leakages through lift shafts & Vent
Perimeter of the internal walls where leakage = 11.8 m2
Height of the lift shaft = 84.21 m
No. of lifts = 1
Leakage area through lift shafts = 993.68 m2
The leakage area ratio for an "tight construction" lift well wall Refer Table A.3 of BS EN
0.00018
is: 12101-6:2005
Effective leakage Area = 0.18 m2
Vent at the head of the shaft = 0.3 m2
Leakages through lift doors
Refer Table A.3 of BS EN
Crackage area around the lift doors = 0.06 m2
12101-6:2005
No. of lifts in the shaft = 1
No. of lift doors = 25
Total area around lift doors = 1.5 m2
Total flow

Q=(0.83 x Ae x P1\N) = 5.81 m³/s


(value of N taken as 2 as recommended in BS EN 12101-6:2005)
10% SAFETY 6.39 m³/s
Total Flow = 6400 L/s

Pressure Relief Damper


Total flow (Q) = 6.40 m³/s
Residue Pressure(P) = 50 Pa Refer to BS EN 12101-
Effective Relief Area 6:2005
Ae = Q/(0.83*SQRT(P)) = 1.09 m2

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