PROBLEMS TA 12 13 14 18 16 mW 18 19 Using the vapor pressure-temperature relationships for CaF iq), CaFacgy, and liquid CaF, calculate: a. The temperatures and pressures of the triple points for the equilibria CaF xq) — CaF xg) — CaF x.) and CaF yg) — CaFxn — CaF x4) b. The normal boiling temperature of CaF, cc. The molar latent heat of the transformation CaF 2.q) —> CaF apy d. The molar latent heat of melting of Carp) Calculate the approximate pressure required to distilf' mercury at 100°C. One mole of SiCl, vapor is contained at 1 atm pressure and 350 K in a rigid container of fixed volume. The temperature of the container and its contents is cooled to 280 K. At what temperature does condensation of the SiCl, vapor begin, and what fraction of the vapor has condensed when the temperature is 280 K? The vapor pressures of zinc have been written as In p (atm) = 1520 _ oss in7 + 19.25 “ and In p (atm) = 1.255 In T + 21.79 Gi) Which of the two equations is for solid zinc? At the normal boiling temperature of iron, T;, = 3330 K, the rate of change of the vapor pressure of liquid iron with temperature is 3.72 X 107? auw/K. Cal- culate the molar latent heat of boiling of iron at 3330 K. Below the triple point (~56.2°C) the vapor pressure of solid CO; is given as 3116 Inp (atm) = 7 + 1601 ‘The molar latent heat of melting of CO, is 8330 joules. Calculate the vapor pressure exerted by liquid CO, at 25°C and explain why solid CO, is referred to as “dry ice” The molar volumes of solid and liquid lead at the normal melting temperature of lead are, respectively, 18.92 and 19.47 cm*. Calculate the pressure which ‘must be applied to lead in order to increase its melting temperature by 20 centi- grade degrees. Nitrogen has a triple point at P = 4650 atm and T = 44.5 K. at which state the allotropes a, [8, and y coexist in equilibrium with one another. At the tripie point Vp — V,. = 0.043 cm*/mole and V,, — V, = 0.165 cm*/mole. Also at the tiple point Sj, — S, = 4.59 WK and S, — S, = 1.25 JK. The state of P = 1 atm, T = 36 K lies on the boundary between the fields of stability of the « and B phases, and at this state, for the transformation of a —> B. AS = 6.52 J/K and AV = 0.22 cm’/mole. Sketch the phase diagram for nitrogen at low tempera- tures. Measurements of the saturated vapor pressure of liquid NdCI give 0.3045 atm. at 478 K and 0.9310 atm at 520 K. Calculate the normal boiling temperature of NaCls.ay Ve cok) t bs p col) = ~ 54350 — ASS eT + 56.57 T Cot, (2! Poe Goin) = ~ sag - asashot + S60F Tv GR Ur Map Cam) = on, gent 4 3M | T @) At tuple pat d-p-y (by (ey Ds POA = Daecey 54350 — 45S MT 456.97 = - SOO — 45a 4 Shor T Tt Ts 13 P= 25x19 am ae AM Tipe wit prey a) = Dap (2) =O = 4.525 ba T + S608 = -Hn0d ~ 4525 QT +53. t T Tr Ves ez 8.35K10 at ermal boiling paint P= qalm L Ru C19 + Chun fap = A Mea Usey su = ~Sytod = 4.525 L.T + $7.6 7 = Ob ok f+ tht te au, = ~AR + BRT = ? = (54350 C831) + (4.5259 (E300 246. ), = 34730 3 wel = (53980) C31 C~ 45289 CHIT C275)aM = dae Ho 4 He wy 29 Map = Mey DM ay ¢ = C5.arats cw) = ¢.4 252010 = 3 AN Za. : “al bh ay . } . Hey = Mg on + Mery i : Ae * : Moet => Mesy - Heay as Mose > Greorcenay + Cassese CT — G BB Sy = C5000) P34) + 459 RHE CTY LD ©-@ = 29164 Za bes ; . . : . oe : ‘ 22h 7 ; ‘ ayby @2 Hace) anim vo Yepprapongdovio4 : dae =~ Pl = OAS MT + 17. — Ss TBM & onas hs G73) + (DE = ag Po= 385 wot afm Aus S 1-3 Viz mer . soe Cam _ 199 L © 4 fun Sly ov Dap > 3 + Wab T C-Be s aa Pre P+ ah) = mer 2 1 Caosen) C7) v 28, T7 3 Ke es qu) 1+ 180 <3i 104 pe Om TY met 2 mn Caezaei yc 2m WH. n> Ott 2. aN ae om. 08s mt 2 5% Ayere G1 Dap = 157 OTF ISS + due tse + oasy = alia at = <7 “ert DHiy = yOTOCRY - onss(eT? oy (mp = TZ asst f DITA T dive = SSO pas = _ bin A in “er Mi = 152 (Ry — 255 (ET). @) on Is7HR @ INI Tee ® “aw 5 sav 7 Meg + My gy 4,dime = OM dy mt tae o> eH et ay, ae = 3 & OF OF mm = 32 xIo > & cory 32410” (831) (33307* mo MDP TOD 1s SOV Qe = - 3b 4 thot uw 7 Mos Aho 8 zub ee & a Od > BW CRD = 25843 D. S22: os e350 mae Oey 2 Mey 4 OMe 25843 = 830 + ODM, ‘tov 5 PHY = tts SF. +é = - ns soo — 4) ean T E A rrie gow: Censetey NP Mk gy = La ee Sa ate Can-se4) gn be CS = ITED 4¢ 4 4 nag (EAN CI- 8:2)YY vem ae ‘ f | SA —— j 4 —— | v i Pak. ae Savin eet alm o = 3 tel ge yay, T FP eran alors Saas Vo wht 11 ™ ae. BH on TAV ae > fet dt ee OT thy BY a ah Fy Tes De OH MCRy ov ~ ae 7 C@.47- 982 Vi? i) = weTIT oN > 2867 atm— 7 = —~ Pe Otte or ay av OB 5 ps 454 T 44, —— 0) 0.064 xia" Boh 5 Pa ue = 4, oy 0.5 x10 i Si Frege pot Re AGond de TH as ke. ay A008 nv s Me 4 Mag de b= ~ H8SIHt0 0.84% vig? as sens . eo 1s 2 4 HSV $d ee at who O.165 x0 . ‘ s -2 MF P= MbI KW T — 4zesxio ‘ @) = PE Aste + eyo oy12 GO) P= o3eas @ P= 04310 Te Sw G) p= dole Tem a. as ~~ o> Pe setae 3 oO 35 03045 Mo = £3 Cay 4 ay Q@y y Dame ee = BC su) +6 Nv . s ()-@) 5 -.ba ae = 4a as av os 2 a (an. @ =n be2 Tb 5 Pr otne = 1492 (1) — 687M TO = sat kf