Hagaja: Important Instructions
Hagaja: Important Instructions
No. :
HAGAJA
M3 This Booklet contains 28 pages.
Do not open this Test Booklet until you are asked to do so.
Important Instructions :
1. The Answer Sheet is inside this Test Booklet. When you are directed to open the Test Booklet, take out the
Answer Sheet and fill in the particulars on OFFICE Copy carefully with blue/black ball point pen only.
2. The test is of 3 hours duration and the Test Booklet contains 200 multiple-choice questions (four options
with a single correct answer) from Physics, Chemistry and Biology (Botany and Zoology). 50 questions
in each subject are divided into two Sections (A and B) as per details given below :
(a) Section A shall consist of 35 (Thirty-five) Questions in each subject (Question Nos – 1 to 35,
51 to 85, 101 to 135 and 151 to 185). All questions are compulsory.
(b) Section B shall consist of 15 (Fifteen) questions in each subject (Question Nos – 36 to 50, 86 to 100,
136 to 150 and 186 to 200). In Section B, a candidate needs to attempt any 10 (Ten) questions out
of 15 (Fifteen) in each subject.
Candidates are advised to read all 15 questions in each subject of Section B before they start
attempting the question paper. In the event of a candidate attempting more than ten questions, the first
ten questions answered by the candidate shall be evaluated.
3. Each question carries 4 marks. For each correct response, the candidate will get 4 marks. For each
incorrect response, one mark will be deducted from the total scores. The maximum marks are 720.
4. Use Blue/Black Ball Point Pen only for writing particulars on this page/marking responses on Answer
Sheet.
5. Rough work is to be done in the space provided for this purpose in the Test Booklet only.
6. On completion of the test, the candidate must hand over the Answer Sheet (ORIGINAL and OFFICE
Copy) to the Invigilator before leaving the Room/Hall. The candidates are allowed to take away this Test
Booklet with them.
7. The CODE for this Booklet is M3. Make sure that the CODE printed on the Original Copy of
the Answer Sheet is the same as that on this Test Booklet. In case of discrepancy, the candidate should
immediately report the matter to the Invigilator for replacement of both the Test Booklet and the Answer Sheet.
8. The candidates should ensure that the Answer Sheet is not folded. Do not make any stray marks on the
Answer Sheet. Do not write your Roll No. anywhere else except in the specified space in the Test Booklet/
Answer Sheet.
9. Use of white fluid for correction is NOT permissible on the Answer Sheet.
10. Each candidate must show on-demand his/her Admit Card to the Invigilator.
11. No candidate, without special permission of the centre Superintendent or Invigilator, would leave his/her seat.
12. The candidates should not leave the Examination Hall without handing over their Answer Sheet to the
Invigilator on duty and sign (with time) the Attendance Sheet twice. Cases, where a candidate has not
signed the Attendance Sheet second time, will be deemed not to have handed over the Answer
Sheet and dealt with as an Unfair Means case.
13. Use of Electronic/Manual Calculator is prohibited.
14. The candidates are governed by all Rules and Regulations of the examination with regard to their conduct in
the Examination Room/Hall. All cases of unfair means will be dealt with as per the Rules and Regulations
of this examination.
15. No part of the Test Booklet and Answer Sheet shall be detached under any circumstances.
16. The candidates will write the Correct Test Booklet Code as given in the Test Booklet/Answer Sheet in the
Attendance Sheet.
: in words
(1) 4 2 Ω
(2) 5 2 Ω
(1) 4×10−20 N
(3) 4Ω
(2) 8π×10−20 N
(4) 5Ω
(3) 4π×10−20 N
∧ ∧ ∧ ∧
(2) − j+k, − j−k
∧ ∧ ∧ ∧
(3) j +k, − j−k
∧ ∧ ∧ ∧
(4) − j+k, − j+k
(2) towards the right as its potential energy will (1) a large aperture contributes to the quality
decrease. and visibility of the images.
13. A cup of coffee cools from 908C to 808C in t minutes, (4) 908
when the room temperature is 208C. The time
taken by a similar cup of coffee to cool from 808C 17. A small block slides down on a smooth inclined
to 608C at a room temperature same at 208C is : plane, starting from rest at time t=0. Let Sn be
the distance travelled by the block in the interval
13 Sn
(1) t
10 t=n−1 to t=n. Then, the ratio is :
Sn+1
13 2n−1
(2) t
5 (1)
2n
10
(3) t 2n−1
13 (2) 2n+1
5
(4) t 2n+1
13
(3) 2n−1
14. The equivalent capacitance of the combination
shown in the figure is : 2n
(4) 2n−1
(1) 3C (1) v
(2) 2C (2) 2v
(3) C/2 (3) 3v
(4) 3C/2 (4) 4v
5 M3
19. The half-life of a radioactive nuclide is 100 hours. 23. Match Column - I and Column - II and choose
The fraction of original activity that will remain the correct match from the given choices.
after 150 hours would be : Column - I Column - II
(1) 1/2 1
(A) Root mean square (P) nm v 2
3
1 speed of gas molecules
(2)
2 2 3 RT
(B) Pressure exerted (Q)
M
by ideal gas
2
(3) 5
3 (C) Average kinetic energy (R) RT
2
of a molecule
2
(4) 3
3 2 (D) Total internal energy (S) kBT
2
of 1 mole of a
diatomic gas
20. In a potentiometer circuit a cell of EMF 1.5 V gives
balance point at 36 cm length of wire. If another (1) (A) - (R), (B) - (P), (C) - (S), (D) - (Q)
cell of EMF 2.5 V replaces the first cell, then at (2) (A) - (Q), (B) - (R), (C) - (S), (D) - (P)
what length of the wire, the balance point occurs ? (3) (A) - (Q), (B) - (P), (C) - (S), (D) - (R)
(1) 60 cm (4) (A) - (R), (B) - (Q), (C) - (P), (D) - (S)
1
−1
gT2 2
(1) θ=cos (1) 20 cm from the lens, it would be a real
π2 R
image.
1
(2) 30 cm from the lens, it would be a real
π R 2 2 image.
(2) θ=cos−1 (3) 30 cm from the plane mirror, it would be a
gT2
virtual image.
(4) 20 cm from the plane mirror, it would be a
1
π2 R 2 virtual image.
(3) θ=sin−1 42. Twenty seven drops of same size are charged at
gT2
220 V each. They combine to form a bigger drop.
Calculate the potential of the bigger drop.
1
−1
2gT2 2 (1) 660 V
(4) θ=sin (2) 1320 V
π2 R
(3) 1520 V
(4) 1980 V
39. A particle of mass ‘m’ is projected with a velocity 43. In the product
v=kVe(k < 1) from the surface of the earth.
(Ve=escape velocity)
→
(
F =q v × B
→ →
)
The maximum height above the surface reached
→
( ∧
=q v × B i +B j +B0 k
∧ ∧
)
by the particle is : ∧ ∧ ∧
→
2
For q=1 and v =2 i +4 j+6 k and
k → ∧ ∧ ∧
(1) R
1−k F=4 i −20 j +12 k
→
2 What will be the complete expression for B ?
k
(2) R ∧ ∧ ∧
1+k (1) −8 i −8 j −6 k
∧ ∧ ∧
R2 k (2) −6 i −6 j −8 k
(3)
1+k ∧ ∧ ∧
(3) 8 i +8 j−6 k
Rk2 ∧ ∧ ∧
(4) (4) 6 i +6 j−8 k
1−k2
M3 8
44. For the given circuit, the input digital signals are 46. A uniform conducting wire of length 12a and
applied at the terminals A, B and C. What would resistance ‘R’ is wound up as a current carrying
be the output at the terminal y ? coil in the shape of,
R1
(1) R2
(1) R2
(2) R1
(2) 2
R1
(3) (3)
R2
(4) 2
R2
45. A uniform rod of length 200 cm and mass 500 g is (4)
R1
balanced on a wedge placed at 40 cm mark. A
mass of 2 kg is suspended from the rod at 20 cm
and another unknown mass ‘m’ is suspended from 48. From a circular ring of mass ‘M’ and radius ‘R’ an
the rod at 160 cm mark as shown in the figure.
arc corresponding to a 908 sector is removed. The
Find the value of ‘m’ such that the rod is in
equilibrium. (g=10 m/s2) moment of inertia of the remaining part of the ring
about an axis passing through the centre of the
ring and perpendicular to the plane of the ring is
‘K’ times ‘MR2’. Then the value of ‘K’ is :
3
(1)
4
1 7
(1) kg
2 (2)
8
1
(2) kg
3 1
(3)
1 4
(3) kg
6
1
1 (4)
(4) kg 8
12
9 M3
49. Three resistors having resistances r1, r2 and r3 53. Which one among the following is the correct option
are connected as shown in the given circuit. The for right relationship between CP and CV for one
i mole of ideal gas ?
ratio 3 of currents in terms of resistances used
i1 (1) CP+CV=R
in the circuit is :
(2) CP−CV=R
(3) CP=RCV
(4) CV=RCP
60. BF3 is planar and electron deficient compound. 66. An organic compound contains 78% (by wt.) carbon
Hybridization and number of electrons around the and remaining percentage of hydrogen. The right
central atom, respectively are : option for the empirical formula of this compound
is : [Atomic wt. of C is 12, H is 1]
(1) sp3 and 4
(1) CH
(2) sp3 and 6
(2) CH2
(3) sp2 and 6 (3) CH3
(4) sp2 and 8 (4) CH4
11 M3
67. The molar conductance of NaCl, HCl and 71. Identify the compound that will react with Hinsberg’s
CH3COONa at infinite dilution are 126.45, 426.16 reagent to give a solid which dissolves in alkali.
and 91.0 S cm2 mol−1 respectively. The molar
conductance of CH3COOH at infinite dilution is.
Choose the right option for your answer. (1)
(1)
(1)
(2)
(3) (2)
(4)
(b) hν
HOCl(g) (ii) Smog
Choose the correct answer from the options given →
i i
below. OH+C l
(1) (a)-(iv), (b)-(i), (c)-(ii), (d)-(iii) (c) CaCO3+H2SO4→ (iii) Ozone
(2) (a)-(iii), (b)-(ii), (c)-(i), (d)-(iv) CaSO4+H2O+CO2 depletion
119. Which of the following is not an application of PCR 125. The factor that leads to Founder effect in a
(Polymerase Chain Reaction) ? population is :
(1) Natural selection
(1) Molecular diagnosis
(2) Genetic recombination
(2) Gene amplification
(3) Mutation
(3) Purification of isolated protein
(4) Genetic drift
(4) Detection of gene mutation
126. When the centromere is situated in the middle of
120. The amount of nutrients, such as carbon, nitrogen, two equal arms of chromosomes, the chromosome
phosphorus and calcium present in the soil at any is referred as :
given time, is referred as :
(1) Metacentric
(1) Climax
(2) Telocentric
(2) Climax community (3) Sub-metacentric
(3) Standing state (4) Acrocentric
(4) Standing crop
127. Genera like Selaginella and Salvinia produce two
121. The term used for transfer of pollen grains from kinds of spores. Such plants are known as :
anthers of one plant to stigma of a different plant (1) Homosorus
which, during pollination, brings genetically
(2) Heterosorus
different types of pollen grains to stigma, is :
(3) Homosporous
(1) Xenogamy
(4) Heterosporous
(2) Geitonogamy
(3) Chasmogamy 128. Match List - I with List - II.
(4) Cleistogamy List - I List - II
More attraction in
122. The production of gametes by the parents, (a) Cohesion (i)
liquid phase
formation of zygotes, the F1 and F2 plants, can be Mutual attraction
understood from a diagram called : (b) Adhesion (ii) among water
(1) Bullet square molecules
(2) Punch square Water loss in liquid
(c) Surface tension (iii)
phase
(3) Punnett square Attraction towards
(d) Guttation (iv)
(4) Net square polar surfaces
Choose the correct answer from the options given
123. In the equation GPP−R=NPP below.
R represents : (a) (b) (c) (d)
(1) Radiant energy (1) (ii) (iv) (i) (iii)
(2) Retardation factor (2) (iv) (iii) (ii) (i)
(3) Environment factor (3) (iii) (i) (iv) (ii)
(4) Respiration losses (4) (ii) (i) (iv) (iii)
M3 18
129. Gemmae are present in : 135. Match List - I with List - II.
(1) Mosses
(2) Pteridophytes List - I List - II
(3) Some Gymnosperms Cells with active cell Vascular
(a) (i)
(4) Some Liverworts division capacity tissues
Tissue having all cells
130. Which of the following algae produce Carrageen ? Meristematic
(b) similar in structure (ii)
(1) Green algae tissue
and function
(2) Brown algae Tissue having
(c) (iii) Sclereids
(3) Red algae different types of cells
(4) Blue-green algae Dead cells with highly
(d) thickened walls and (iv) Simple tissue
131. Complete the flow chart on central dogma. narrow lumen
149. Identify the correct statement. 154. The fruit fly has 8 chromosomes (2n) in each cell.
(1) In capping, methyl guanosine triphosphate During interphase of Mitosis if the number of
is added to the 39 end of hnRNA. chromosomes at G1 phase is 8, what would be the
number of chromosomes after S phase ?
(2) RNA polymerase binds with Rho factor to
terminate the process of transcription in (1) 8
bacteria. (2) 16
(3) The coding strand in a transcription unit is (3) 4
copied to an mRNA. (4) 32
(4) Split gene arrangement is characteristic of
prokaryotes. 155. Persons with ‘AB’ blood group are called as
“Universal recipients”. This is due to :
150. In some members of which of the following pairs (1) Absence of antigens A and B on the surface
of families, pollen grains retain their viability for of RBCs
months after release ? (2) Absence of antigens A and B in plasma
(1) Poaceae ; Rosaceae (3) Presence of antibodies, anti-A and anti-B,
(2) Poaceae ; Leguminosae on RBCs
(3) Poaceae ; Solanaceae (4) Absence of antibodies, anti-A and anti-B, in
(4) Rosaceae ; Leguminosae plasma
21 M3
156. Which of the following statements wrongly 162. The partial pressures (in mm Hg) of oxygen (O2)
represents the nature of smooth muscle ? and carbon dioxide (CO2) at alveoli (the site of
(1) These muscle have no striations diffusion) are :
(1) pO2=104 and pCO2=40
(2) They are involuntary muscles
(2) pO2=40 and pCO2=45
(3) Communication among the cells is
(3) pO2=95 and pCO2=40
performed by intercalated discs
(4) pO2=159 and pCO2=0.3
(4) These muscles are present in the wall of
blood vessels 163. In a cross between a male and female, both
heterozygous for sickle cell anaemia gene, what
157. Which one of the following belongs to the family percentage of the progeny will be diseased ?
Muscidae ? (1) 50%
(1) Fire fly (2) 75%
(2) Grasshopper (3) 25%
(3) Cockroach (4) 100%