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Lecture 2

This document contains lecture notes on belt friction and examples of related problems. It discusses how the tensions on either side of a belt wrapped around a pulley will differ due to friction. Problem 1 involves calculating the force needed to produce a breaking torque of 12,000 N-mm on a drum braked by a belt. Problem 2 asks for the largest mass that can be supported on a drum using a pulling force of 20 N. Problem 3 provides examples for calculating the minimum and required forces to support or move a box using cables over fixed round supports.

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Jonie Matienzo
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66 views1 page

Lecture 2

This document contains lecture notes on belt friction and examples of related problems. It discusses how the tensions on either side of a belt wrapped around a pulley will differ due to friction. Problem 1 involves calculating the force needed to produce a breaking torque of 12,000 N-mm on a drum braked by a belt. Problem 2 asks for the largest mass that can be supported on a drum using a pulling force of 20 N. Problem 3 provides examples for calculating the minimum and required forces to support or move a box using cables over fixed round supports.

Uploaded by

Jonie Matienzo
Copyright
© © All Rights Reserved
We take content rights seriously. If you suspect this is your content, claim it here.
Available Formats
Download as DOCX, PDF, TXT or read online on Scribd
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ES 3 STATICS OF RIGID BODIES CHAPTER 5 LECTURE 2 (BELT FRICTION) 1ST SEMESTER 2022-23

BELT FRICTION – When a belt or band passes over a rough pulley, PROBLEM 2
the tensions in the belt or band on the two sides of the Determine the largest mass of cylinder A that can be supported
pullewill be different. from the drum if a force P = 20 N is applied to the handle of the
lever. The coefficient of static friction between the belt and the
wheel is 0.3. The drum is pin supported at its center, B.

PROBLEM 3
The box B weighs 50 lb. The coefficients of friction between the
cable and the fixed round supports are fs = 0.40 (static) and fk
PROBLEM 1 = 0.30 (kinetic).
As shown a flexible belt placed around a rotating drum of 120 a. What is the minimum force F required to support the box?
μβ mm radius acts as a brake when the arm ABCD is pulled down
T 1 =T 2 e b. What force F is required to move the box upward at a
by the force P. The coefficient of kinetic friction between the constant rate?
Where: belt and the drum is 0.2.
T1 – Larger tension (tight side) μ = coefficient of friction a. Determine the force P that would result in a breaking
T2 – Smaller tension (slack side) β = angle of contact, in torque of 12000 N- mm assuming that the drum is
radians. rotating counterclockwise.
e = 2.71828… b.

PREPARED BY:

ENGR. MELVYN MCARTHUR R. TATING


Assistant Professor 2

CATANDUANES STATE UNIVERSITY COLLEGE OF ENGINEERING AND ARCHITECTURE Lecture Notes by : ENGR. MELVYN MCARTHUR R. TATING

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