CHAPTER 2 METHOD OF BUILDING ESTIMATE Example 1. — Estimate the quantities of brickwork and plastering required in a wall 4m long, 3mhigh and 30cm thick. Calculate also the cost if the rate of brickwork is Rs. 320.00 per cu mand of plastering is Rs. 8.50 per sq m. Quantity of brickwork = LB x H = 4mx3 mx 30 = 3.6 cum, Quantity of plastering (two faces) = 2x Lx H = 2x 4m x3 m= 24.sq m. Cost of brickwork = 3.6 x 320,00 Rs, 1152.00. Cost of plastering = 24 x 8.50 = Rs. 204.00. Total cost = 1152.00 + Rs. 204.00 = Rs. 1356.00. Example 2. — Prepare a detailed estimate of part of a wall of a building from the given plan and section and general specifications (Figs. 2-1 and 2-2). GENERAL SPECIFICATIONS : (1) Foundation concrete shall be of lime concrete. (2) Foundation and plinth shall be of Ist class brickwork in lime mortar. (3) Damp Proof Course — 2.5 mm c.c. |: 1% : 3 with water proofing compound. (4) Superstructure — Ist class brickwork in lime mortar. (5) Wall finishing — Inside wall [2 mm Cement plastered I : 6 and white washed 3 coats. Outside wall 12 mm cement plastered I : 6 including 10 cm below ground level and finished with two coats of colour wash over one coat of white washing. RATES : Assume local current rates. Note: — Fig. 2-1 and Fig. 22 are plan and cross-section of the wall with standard modular brick and with traditional brick respectively. For simplicity only a portion of a wall has been taken and licnce there are no footings at the ends.ESTIMATING OF WALL Pi nd Section Plana Fig. 2-1 WALL WITH STANDARD MODULAR BRICKS. Inside ‘Super Structure Wall 2.5m D.P.c, Plinth Level 2nd. Footing Ist. Footing «Lime Cone CROSS SECTION Fig. 2-2 WALL WITH TRADITIONAL BRICKS. 800m. 4 CROSS SECTION a) ———I eee COUT PLAN AT PLINTH. With Standard Bricks, Fig. 2-1 — 45.7 om, Dimensions sagem | k}-———_ 600m. ———— PLAN AT PLINTH. DETAILS OF MEASUREMENT AND CALCULATION OF QUANTITIES (Ex. 2) T | Quantities! tem! Description of items of work | No. }— i | ot Total No Length Breadth) Ht, or | Contents. |yuansities Depth | 1 iiesanenre ation in foun- | | arthwork in excavation in eee | dation : 00m] 80 | 90m 4.32 eum 2. | Lime conerete in foundation ..,| 1 |6.00m) .80.m om) 14d [LAs cum 2. | fst elass brickwork in lime mortar | | in foundation and plinth | : | Ist footing 1 |6.00.m | 60 m 20m | 72 | Ind footing 1 |6.00m| 50m | 20m 60 || | Plinth wall up to GL “| 1 [6.00:m| 40m | 20m) AK F324 crm Plinth wall above G1 + [6.00 m] 40m | 60m) 44? | deontd, | SS i STIMATING AND COSTING ] Dimensions Quantities fem) Deseription of items of work No. — — or | Total No. Length [Breadth] Ht. or | Contents | quantitiey | | Depth 4. | 2.5m Damp proof course(D.P.C.) | fo i a jee 3 e| 1 {6.00 me} 40 m ae 2dunas| 5. | First. class Brickwork in lime | ao | mortar for superstructure +-| 1 [600m 30m /3.50m| 63 | 63cum 6. 12 mm plaster of Cement sand | | \* 16 | Inside | 1 |6.00m Outside including 10 em below | 46.294 m GL. | j 1 |6.00m 25, 7. | White 3 coats (inside) 1 {6.00 m 21.0 | 21.0 sqm %. Colour washing 2 coats over one} | | coat of white washing (outside| | | above Gb) ea | 1 |6.00.m 24.6 |24.6 sqm ABSTRACT OF ESTIMATED COST (Ex. 2) . i. 2re | Amount Item Description of Items of Work (Quantity) Unit Per z No. | em eee _ I { . | Rs. |. | Earthwork in excavation in Foundation} 4.32 | cum | 350.00 [eum | 15.12 2. | Lime concrete in foundation with white | lime, surkhi and brick ballast 1.44 | cum | 220.00 | percum 316.89 3. | Ist class brickwork with white lime and | | | |surkni mortar 1; 2 in foundation and | plinth 3.24 | cum | 300.00 |percum 972.00 4. | 2.5 em thick cc. 1 : 14 : 3 Damp proof 1 | course with water proofing compound | 24 | sqm | 20.00 | persqm) 48.00 5. | Ist class Brickwork with white lime and | surkhi |: 2 mortar in super-structure | 6.3. | cum | 320.00 | Per eum] 2016.00 6. |12 mm cement and local sand plaster | 1:6 46.2 | sqm 8.50 | persym) 392.70 7. | White washing 3 coats 21.0 | sqm | 0.75 |persqm, 15.75 8. | Colour washing 2 coats over one cout of | | white washing [246 | sam | 082 |persqm| 20.17 a Total .., 3796.54 Add for Contingencies 3% : 113.90 Add for Workcharged Establishment 20% | 75.93 Grand Total... | 3986.37 wall have not been taken into consideration: and the outer plinth offset of Sem has Note : — For the items of plastering and white washing or colour washing the end faces of the been neglected.METHOD OF BUILDING ESTIMATE, Trench Filling. — Earthwork in trench filli i I ed fe ae ee ke usually not taken into account. If require Quantity of earthwork in trench filling = Quantit i antity of concrete + Y yy in excavation — Quantity of concrete Quantity of brickwork upto G.L. = 4.32 — (1.44 + 1.80) = 1.08 cu m > For simplicity the earthwork in trench filling may be taken as I /5 of earthwork in excavation. Example 2 — ional Bricks, Fig. 2.2 — _. With traditional bricks, the items of foundation concrete, Plastering, White washing and Colour washing are same as for above. The earthwork, Brickwork in foundation and plinth, Brickwork in superstructure, and D.P.C. differ and are as calculated below :— Item 1. — Earthwork in excavation in founda- tion v1 6,00 m x .80 m x.75 m= 3.69 cum Item 3. — Ist class brickwork in lime mortar in foundation and plinth — Ist footing v1 6,00 m x 686 m x 15 m = 0.62 cum 2nd footing 1 6.00 m x .571 mx .15 m= 0.52 Plinth wall above footing ve 1% 6.00 m x .457 m x .75 m = 2.06 Toial = 3.20 cum Item 4, — 2.5 cm thick D.P.C.1:1%:3 0... 1* 6.00 mx 457 m = 2.74 sqm irst class brickwork in lime mortar in superstructure a 1 x 6.00 m * 343 m x 3.5 m= 7.20 cum Abstract of cost may be prepared accordingly. Item S. - METHODS OF BUILDING ESTIMATE The dimensions, length, breadth and height or depth are to be taken out from the drawing — plan, elevation and section. From the study of the drawings, the building is to be imagined and pictured in the mind and the dimensions are to be taken out correctly. Thereis no hard and fast rule for finding out dimensions from the drawing but the dimensions are to be taken out accurately. ‘Junctions of wall at the corners and at the meeting points of walls require special attent For symmetrical foundation which is the usual case, earthwork in excavation in foundation, foundation conerete, brickwork in foundation and plinth, and brickwork in superstructure may be estimated by either of the following two methods. METHOD I Separate or individual wall method. — In this method, measure or find out the external length of walle running in the longitudinal direction generally the long walls out-to-out, and the internal lengths of walls running in the transverse direction in-to-in i.e. of cross or short walls in-to-in, and calculate quantities multiplying the length by the breadth and the height of wall. The same rule applies to the excavation in foundation, to concrete in foundation and to masonry. Care should be taken to note the difference in dimensions at different height due to offset, or footings. It is convenient to imagine plans at different level of heights as foundation trench plan, foundation concrete plins of each footing, etc. and dealing each plan or part separately.~ 30 ESTIMATING AND COSTING [The simple methodis o take the long walls and short or cross walls separately and to find ou the centre to centre lengths of long walls and short walls from the plan, Foreseoreen footing on either sides, the centre line remains same for superstructure and for foundation and plinth." For fong walls add to the centre length one breadth of wall, which out-to-out, multiply this length by the breadth and the height and (Long wail length out-to-out = centre to centre length y + half breadth on one side + half breadth on the other side = centre to centre length + one breadth). For short or cross walls subtract (instead of adding) from the centre length one breadth of wall, Which gives the length in-to-in, and repeat the same process as for che long walls, subtracting one breadth instead of adding. (Short wall length in-to-in = centre fo centre length — one breadth). Thatis, in case of long wall add one breadth and in case of short w: all subtiact one breadth from the centre length to get the corresponding lengths, zn foundation the offset of concrete on either side may be 10 em to 20 em depending on the (hickness of concrete (usually less thgn the thickness of conerete). The offset once of brick wall of standard bricks is 5 cm, and of traditional bricks is 5.7 em, This method can also be worked out in a quicker way. For long walls find the length of the foundation trench of the long wall out-to-out in the same manner ae explained above, the length of {he foundation concrete is the same, for the length of the first footing or first step of brick wall subtract two offsets in foundation conerete from the length of the trench or concrete: for tre eens footing subtract from the length of Ist footingtwo offsets in footing ie.25- len oney eins cm for traditional bricks), for the third footing subtract from the length of the 2nd footing two olfsets i.e. 10 em (11.4 cm for traditional bricks) in this way deal the long walls up to the cnpersiTucture. [For 25.4 em x 12.7 em x 7.6 cm (10" x 5" 314") bricks, one offset in footing - 6.35, cm and two offsets = 12.7 em]. For short wall follow the same method but instead of subtracting, add two offsets to get the corresponding lenyih in-to-in. twill be noticed that by taking dimensions in this way, the long walls are gradually decreasing in length from foundation to superstructure, while the short walls are increasing in length. It may also be noted that the wall which is taken first is to be treated as lot ng wall though its length may be lesser, and the other wall be treated as short wall. This method is simple and accurate and there is no chance of any mistake. This method may b naried as Long wall and short wall method, or general method.METHOD OF BUILDING ESTIMATE a The following examples (Exs. 3a, 4a, and 5a) illustrate this method :— Example 3(a). — Fig. 2- building of Sm x 4m, and § Estimate the quantities of — the plan represents the plan of superstructure wall of asingle room ections represent the cross-sections of the walls with foundat'o (1) Earthwork in excavation in foundation, (2) Concrete in foundation, (3) Brickwork in foundation and plinth and (4) Brickwork in superstructure ‘The length of long wall centre to centre = 5.00 + 14% .30 + 4 x.30=5.30m. The length of short wall centre to centre = 4.00 + 4 x .30 + 4 x 30 = 4.30 m. SECTION ON AB 2 | 30.em. PLAN OF SUPERSTRUCTURE WALL.—r | > 8 eM esmonng 2 4JedNg 10 UBid TENA Ute} $0 UBled +t Bd [2 ory 22 woer— 1 ue 4q 2u0 yeep aq Aru pied yore Jo Uror-ur jem Lys ayy pur urorur yem Fuop 21 wry] PC Big Ur UaAI se pourteur’ oq Aew jjen jo sdois 46 sdunooy yoeajo ued ay7 ‘a1a19 -uo9 uonepunoy pur yous ‘2409 spuno: uonepunoy jo urd 241 ‘89a fe pune yo eg -huenb 2y) ovens op i 29 WOES ——e bing o11n6 Wem buoy A ‘S13A37 LN3Y33410 LY SNVId ONILSOS GNV ONILVWILSS weMETHOD C# BUIT. DING ESTIMATE 3 DETAILS OF MEASUREMENT AND CALCULATION OF QUANTITIES (Ex. 3a) Item| Particulars of 7 Height a No. | Items No.|Length Breadth] or |Quantity| Explanatory note oo Depth 1. | Earthwork in | - ceoe —_ |excavation in| foundation — | Long walls 6.20 m Length = 5.30 + 90 Breadth = 4.30 - .90 Re Short walls... 3540: 2. | Conerete in | foundation — i i Long walls 6.20m| 90m | 30m] 3.35 | Length same as for excavati | Short walls 3.40 m| 90m | 30m | 1.83 | Quantity = '/; of excavate Total | 5.18 cum 3. | Brickwork in foundation and plinth — Long walls — Ist footing 2 |5.90m| .60m | 30m | 2.13 | Length = 5.30 + .60 and footing ...| 2 |5.80m| .50m4.30m | 1.74 | Length = 5.30 +5 Plinth walls -- 2 |5.70m| 40m | 60m 2.74 | Length = 5.30 + 4 Short walls — Ist footing ...| 2 |3.70m| 60m) 30m] 1.33 Length = 4.30 ~ .60 = 3.70 m 2nd footing ...| 2 3.80 m| 50m | 30m 1,14 | Length = 4.30 - 50 = 3.80 m Plinth walls ... | 2 |3.90m 40m | 60m 1,87. | Length = 4.30 - 40 = 3.90m Total | 10.95 cum 4. | Brickwork in superstructure Long walls... 2 |5.60m)| 30m 2.50 m| 11.76 | Length = 5.30 + .30 = 5.60 m | Short walls | 2 |4.00m| .30m |3.50m| 840 | Length = 4.30 206 4.00 m Total | 20.16 cum Note: The door openings, superstructure as usual. See next page (page 34) for further ch Tt may be noted that in the case of long wall, the lengths of the 2nd footing, 3rd foc differ by 10 cm and each is shorter than the previous one by 10 em,Similarly for short wall the length is longer than the previous footing by 10 cm, Thus the lengths can be obtained by subtracting 0: ‘ndding 10 cm as the case may be. For traditional bricks (22.9 cm x 11.2 cm » 7.6 cm) the length can be obtained by subtracting or adding 11.2 em, (For 25.4 cm ¥ 12.7 cm * 7.6 em bricks ada or subtract 12.7 cm). window openings, lintels, etc. shall have to be deducted trom ete,4 ESTIMATING AND COSTING As study of the plans and elevations (Fig. 2-5) will make it clear. The plan (i) shows the foundation footings. The long walls and short walls may be imagined to be constructed Separately, first the long walls and then the short walls, From the elevation (iii) and (v) it will be clear that the length of each successive footing of long walls is reduced in length and that of the short walls each successive footing is increased in length, The corresponding breadth and height can be obtained from the cross-section of wall PLAN AND ELEVATION OF WALLS (EARTH REMOVED). Super structure } t E g 3 + Plinth wall ¥ 40cm = 2nd. Footing Xen Ist Footing Foundation Cone. -| (v) PLAN OF SHORT WALL (DETACHED) 5s0moe | Fig. 2-5 ()) PLAN OF FOUNDATION & FOOTING i in fir ind footins ith traditional bricks, the breadth of wall in first footing, seco it et Exar ee ire wall will ‘be 68.6cm, 57.1 cm, 45.7 cm and 34.3 cm respectively. Th oe aay Sib ‘problem having walls with traditional bricks. studentMETHOD OF BUILDING ESTIMATE 35 Example 4(a). — Estimate the quantities of the following items of a two roomed building from the given plan and section (Fig. 2-6) :— (1) Earthwork in excavation in foundation, (2) Lime concrete in foundation, (3) Ist class brickwork in cement mortar I: 6 in foundation and plinth, (4) 2.5 cmc.c. damp proof course, and (5) Ist class brickwork in lime mortar in superstrueturé. TWO ROOMED BUILDING 7.5.om L.C. Terrace Over 13 em A.C.C. ‘All Walls are of same section Lintels over Doors. Windows and ‘Shelves ar@ 15 om thick R.B. Doors D-1.20 m x 2.10m Windows W-1.00 x 1.50 m ‘Shelves S-1.00 m x 1.50 m GROSS SECTION OF WALL ON AA. Fig. 2-6 Note : — No beanrhas been shown in the plan as the object of this example is to explain the metknd of estimating the walls only.36 DETAILS OF MEASUREMENT AND CALCULATION OF QUAN ESTIMATING AND COSTING TITIES (Ex, 4a) Ttem] Particulars of “| THeight] ~ —— No. | Items No. |Length|Breadth} or |Quantity| Explanatory note _| Depth a ! Long wall, c/c. length = 44 7 6+ 30+2%%0 = 10.60 m Short and Inter walls, c/c. 1, | Earthwork in length = 6 + 2x 0 = 6.30 m excavation in foundation — Long walls ...! 2 {11.70 m| 1.10 m} 1.00 m] 25.74 | L = 10.60 + 1.10 = 11.70 m Short walls ...] 3. | 5.20.m]1.10m|1.00m]| 17.16 | L = 6.30-1.10=5.20m Total | 42.90 cum 2. | Lime concrete in foundation — Long walls ...} 2 |11.70 m| 1.10 m| 30m | 7.72 | Length same for excavation Short walls ...] 3 | 5.20 m}1.10m| .30m | 5.15 — | Quantity=3/10 of excavation Total | 12.87 3. | Ist class brick- cum work in I : 6 cement mortar in foundation and plinth — Long walls — \ Ist footing ...| 2 [11.40 m] 80m] 20m] 3.65 | L = 10.60 + .80= 11.40 m 2nd footing...| 2 |11.30m] .70m] 10m] 1.58 | L= 10.60 + .70¢ 11.30m 3rd footing ...| 2 |11.20m] .60m] .10m| 1.34 | L= 10.60 + .60=11.20m 4th footing ...| 2 [11.10 m} 50m] 10m] 1.11 | L= 10.60 +.50= 11.10 m Plinth wall above footing | 2 |11.00m] .40m| .80m| 7.04 | L = 10.60 + .40= 11,00 m Short walls — = Ist footing ...| 3 | 550m) .80m] 20m] 2.64 | L=6.30~.80=5.50m ‘and footing...| 3 | 560m] .70m] 10m] 1.18 |L=6.30-.70= 560m _ be obtained Not 1 simply by deducting 10 cm fro! 1 : — Length of subsequent footings of long walls after Ist footing may um first footing.METHOD OF BUILDING ESTIMATE n Item] Particui J (Ex 4a Contd.) tem] Particulars of ; - Height ena No. |Length|Breadth) or —|Quantity| Explanatory note = ie Depth 3rd footing ...| 3] 5.70m) 60m] .10m| 1.03 [L=6.30-.60=5.70m 4th footing ..| 3 | 5.80m| 50m] .10m| 0.87 | L=6.30-.50= 5.80 m’ Plinth wall above footing | 3 | 5.90m| 40m |_.80m| 5.66 | L~=6.30-.40=5.90m Total | 26.10 cum 4. | Damp proof course 2.5 em thick ce. — Long walls ...] 2 {11.00m| 40m] — | 8.80 | Lengths same as for plinth Short walls ..] 3 | 5.90m| 40m|_— | 7.08 | wallinitem3. Total | 15.88 Deduct door : sills 2 | 120m) 4om| — |" 096 Net | Total | 14.92 sqm 5. | 1st class brick- work in lime mortar in superstructure Long walls ...| 2 |10.90:m| 30m [4.20m| 27.47 | L= 10.60 +.30= 10.90m Short walls ..| 3 | 6.00 m| .30m [4.20 m| 22.68 | L=6.30-.30=6.00m Total | 50.15 cum Deduct — Door openings | 2 [120m] .30m 210m) 151 Window eens 4 {1.00 m! 30m |1.50m| 1.80 Shelves 2 |1.00m) .20_m |1.50.m] 0.60 | Back of eves 10 om thick ee ; Lintels over |» |1.50m| .30m'| .15m| 0.14 | Bearing 15 em Lintels over : wwindows 4 [130m] 30m] 15m} 0.23 | Bearing 15 em intels over . - Shelves 2 [1.30 m| 30m | .15m| 0.12 | Bearing 15em Total off deduc-| tion | 4.40 |cum Net_| Total | 45.75 jcum - obtained simply Note = by adding 10 cm from first footing. — Length of subsequent. footing of short walls ai Ist footing: ‘may be:ESTIMATING AND COSTING RESIDENTIAL BUILDING 1.20 mie— 38 & = a] g g g 8 ‘W,/cw = 2.00 m ver. A. PLAN 10cm L. C. Over 120m A.C. 7.5. cm. L.C. Over 10cm R.C.C. Yr som 4— 15cm R.C.C. Lintel 20cm Pillar 300m x 150m 7 q— 2.00m—4 Dycw Doors:- D, = 120. cm x 210 cm (1.20m x 2.10) D,— 100 emx 200 em (1.00 m x 2.00 m) D, - 75 cm x 180 cm (.75 m x 1.80 m), Windows:- W, ~ 100 em x 150m (1.0m x 1.50) W, ~ 200 om x 150 em (2.00 m x 1.50) W,-75.¢m x 120m (.75m x 1.20m) CW. = 75 om x 60 cm (.75.m x 60°) Shelves: S100 om x 150 cm (1.00 m x 1.50 Lintel Over Doors, Windows Etc. 150mRB. 2.5emC.C. Over. 2.5m D.P.C. (T 7.5cm. LC. FLOOR G pal > + 30cm ped Bon 20cm 20cm zuem 200m G2s)- Ie— 500m =e ons Aq cmk> Yocm : CROSS SECTIONOF MAIN WALLS CROSS SECTION AB OF VERWALL _Alfwalls of Drawing Rooms and Bath Roc walls have similar ed Rooms have same section _ Section, Note—No beam has been shown in the plan. Fig. 2-7METHOD OF BUILDING ESTIMATE. 39 Example 5(a). — Estimate the quantities of the following items of a residential building from the given drawings (Fig. 2-7) :— (1) Earthwork in excavation in foundation, (2) Lime concrete in foundation, (3) First class brickwork in I: 6 cement sand mortar in foundation and plinth, (4) 2.5 cm Damp proof course, and (5) First class brickwork in lime mortar in superstructure. e Centre to centre lengths of wall — For estimating it is convenient to find the centre to centre lengths of different walls first. The centre to centte lengths of different walls have been worked put below :— Drawing and left hand side bed room combined — c. to c. long walls = 6.00 + 4.00 + .30 + 2x .15 = 10.60 m. c. to c. short walls = 5.00 + 2 x .15 = 5.30 m. Bed rooms right side (both combined) c. to c. long walls = 5.00 + 4.00 + .30 + 2x .15 = 9.60 m. c. to c. short walls = 4.50 + 2x .15 = 4.80 m. Front verandah — Front wall c. to c. length = 5.00 + 4.00 + 2 x .30 +9020. 9.65 m. Side wall c. to c. length = 2.00 +32 20. 37 2.25 m. Back verandah including bath room — c. to c. long wall (rear wall including bath room) 9.65 m same as front ver. wall. ¢. 10, length of side wall of bath room: = 2,50 +=32.+20.= 2.75 m.40 ESTIMATING AND COSTING DETAILS OF MEASUREMENT AND CALCULATION OF QUANTITIES (Ex. 5a) Item) Height . No. No. |Length|Breadth] or |Quantity| Explanatory note Depth Earthwork in exca- | vation in foundation — Drawing room and left bed room — Long walls 2 {11.50 m) .90 m |-1.00 m| 20.70 0.60 + .90 = 11.50 m Short walls 3 | 4.40 m| 90m | 1.00 m| 11.88 30 - .90 = 4.40 m Bed rooms right side (both) — Long walls 2 | 9.60 m| 90 m [1.00 m} 17.28 Short walls ...| 2 [3.90m) .90m|1.00m| 7.02 Front verandah a 1 | 950m] 60m} .5om| 2.85 Side short wall 1 | 150m] 60m | som| 0.45 Back verandah including bath room —Long wall (rear wall including bath) 1 | 9.50m| 60m} .som| 285 6: Short walls (remaining walls of bath) “| 2 | 200m) 60m | 50m] 1.20 | fa2.7s 20-9 00m 2. | Lime conerete in foundation —Draw- Total | 64.23 ing and left bed cum room Long walls...) 2 |11.50m} 90m] 30m} 6.21 | Lsame as for earthwork in excavation Short walls ...! 3 | 4.40m|.90m| 30m] 3.56 Bed, room right side (both) — Long walls ...| 2 | 9.60 m| .90m| 30m 5.18 | L same as for earthwork in excavation. Short walls ...| 2 | 390m] .90m| 30m] 211 |. : Front verandah Front long wall’. 9.70 m| 60m] 20m] 1.16 | L=9.65 - 50 +: Side short wall ...| 1.70 m| .60 m | .20m 0.20 | L=2.25METHOD OF BUILDING ESTIMATE ‘articulars of Ttems | Back verandah, including bath room Long wall including bath Short wall (remaining walls of bath) Ist class brickwork in foundation and plinth in | : 6 cement mortar bed room Long walls — Ist footing 2nd footing Plinth wall above footing Short walls — Ist footing 2nd footing Plinth wall above Drawing and left |— Length 1 | 9.70 m| 2.20 m| 11.20 m) 11.10 m| 11.00 m| 4.70 m 4.80 my footing Bed rooms right side (both) — Long walls — Ist footing 2nd footing Plinth wall above footing 9.60 m| 9.60 m| 9.60 m| 4.90 m | | Breadth] 60m 60m 60m 50m 40m 60m 50m atm 60m 50m 40m *| Height or Depth 20m 20m 20m 90m 20m 20m 90m 20m 20m Quantity 1.16 0.53 cum 2.69 2.22 7.92 1.69 1.44 5.29 2.31 1,92 6.91 41 (Ex. Sa Contd.) Explanatory note L=9.65 50 + 0. 2 2 70m 7 50 60 4 4 122.75 5 -=2.90m L = 10.60 + .60 = 11.20 m L = 11.20 - 2x.05 = 11.10m. L= 11.10 -.10= 11.00 m L = 5.30 - .60 = 4.70 m L= 4.70 + 2x 05 = 4.80 m L= 4.80 + 10 = 4.90 m42 ESTIMATING AND COSTING Item] Particularsof = || ~— | Height - — No. | Items No. |Length Breadth] or |Quantity| Explanatory note Depth Short walls a Ist footing 2 | 420m) 60m] .20m| 1.01 | L=4.80~ 60 = 4.20 m 2nd footing 2 | 430m) 50m | 20m] 0.86 |L=4.20+2x 05= 4.0m Plinth wall above footing _ ao 2 | 4.40 m| .40m | .90m 3.17 L = 4.30 + 10= 4.40 m Front verandah — Front wall — Footing | 1 |9.65m| .49 | 20m} 0.77 |L=9.65 - a + 965m Plinth wall above footing 1 1 | 960m] 30m] .70m| 2.02 |1=9.65 - or + des, 60m Side short wall Footing | 1 | 185m} 40m | 20m} 0.15 |L=225- 49-4 185m | 1 | 190m) 20m} .70m| 0.40 j1-2.25 4} -30-1.90m including bath room — Lorig wall — Footing we{ 1 | 9.65 m} 40m | 20m | 0.77 |) Length same as for fron ‘ verandah long wall Plinth wall above footing —...| 1 | 9.60.m| 30m] .70m| 2.02 Short walls (remaining walls of bath) Footing | 2 | 235m) 40m | 20m] 0.38 Plinth wall 0 above footing =| 2 | 2.40m| 30m | .70m| 1.01 Sac ‘ Total | 44.95 “Note — It may be noted that for length of long walls of right side bed rooms. hall brea " the left side has been deducted, and half breadth on the right side has been added. For long walls of front and back verandah, half breadth of main walls on the lef hander, thesame level, has been deducted, and half breadth of the verandah wall on the right han! been added to get lengths. no For cross walls of the rooms and side wall of front verandah. half nw educted same level has been deducted for inner side, and half breadth of veran for the outer side to get the lengths. ‘breadth of main dah wall has beenMETHOD OF BUILUING ESTIMATE a3 _ _ (Ex. Sa Contd.) Item| Particulars of Height ~ _ No. | Items No. |Length [Breadth] or |Quantity| Explanatory note _ Depth 2.5 cm Damp proof ~ OO course Drawing and left bed rooms — Long walls 2 [11.00 m| 40m] — | 8.80 | L same as plinth wall. Short walls 3 | 4.90 m| 40m - 5.88 | L same as plinth wall. Bed rooms inner side — . | Long walls 2 | 9.60m| .40m| — | 7.68 |Lsame as plinth wall. Short walls 2 | 4.40 m| 40m] — | 3.52 | Lsameas plinth wall. Verandah Pillars ...] 4 | 0.50m| 30m] — oko 5 om extra on all sides. Bath room — 7 Rear wall | 1 | 2.50m) 30m] — | 0.75 {L=2.20+2%.15=2.50m Side and inter walls w| 2 | 240m) 30m] — | 144 Total | 28.67 sqm Deduct — Door sills Di ...| 6 | 1.20m) 40m] —-| 2.88 Door sills D2... | 2 | 100m) 40m) — 0.80 Door sillsD; ...| 1 | 0.75m| 30m | — 0.23 [Total of] deduction 3.91 sqm | Net | Total | 24.76 sqm 5. | Ist class brick-work in superstructure in lime mortar—Draw- ing and left bed | room — | Longwalls | 2 |10.90.m/ .30m | 4.00 m} 26.16 | L.= 10.60 + 30 = 10.90 m | Short walls 3 | 5.00 m} .30 m | 4.00 m} 18.00 | L = 5.30 30 = 5.00 mESTIMATING AND COSTING 44 |Particulars of |e No. | Length [Breadth Bed room right side — Long walls 2 | 9.60 m} 30m Short walls 2 | 450m) .30 Front verandah Front wall as od 1 | 9.60 m) .20m Side wall as solid 1 | 2.00 m| .20 m Back verandah including bath room — Back long wall as solid 1 | 9.60 m) .20m Side and inter walls of bath 2 | 2.50 m) .20m Deduct — Door openings D. openings D, 6 | 1.20 m| 30m D. openings Dz 2 | 1.00 m] 30m D. openings Ds || 1 | 0.75 m} 20m Window openings W. openings W, 11] 1.00 m| 30m |W. openings Wo 1 | 2.00 m} 30 m 'W. openings W3 2 | 0.75 m) 20m Clerestory window (C.W.) opening | 18 | 0.75 m| 30m Shelves opening ... | 5 | 1.00 m| .20m Front verandah opening in between pillars =| 1 | 8.40 :m) .20m Front verandah opening side 1 | 2.00 m} .20 m Back verandah opening 1 | 6.80 m| .20 m Height or {Quantity Depth 4.00 m| 23.04 4.00 m| 10.80 3.05m) 5.86 3.05m} 1.22 3.05m| 5.86 3.05m) 3.05 Total | 93.99 cum 210m) 4.54 200m) 1.20 180m) 0.27 150m] 4.95 150m] 0.90 120m] 0.36 0.60m| 2.43 1.50 m 1.50 240m} 4.03 240m] 0,96 2.40m| 3.26 Explanatory note L=9.60 - 30. 5 60m L=480-30= 450m L=9.65 - x + 20-9.60m L same as front verandah. Back of shelves 10 cm thick wall. L = 9.60 - 3x .40= 840m L=9,60 - 2.40 - 40 = 6.80"METHOD OF BUILDING ESTIMATE 45 a _ (Ex. Sa Contd.) Item| Details of Height No. | Items No. |Length|Breadth| or —|Quantity| Explanatory note Depth _{|—_ —j—} _ | " frert — Lintels Over doors D. doors Di s+ | 6 | 150m} 30m | 15m | 0.405 | Bearing 15 cm ID doors D2 2 | 1.30 m) 30m | 15m] 0.117 | Bearing 15 cm D. doors Ds 1 | 95m) 20m .15m| 0.029 | Bearing 10 cm Over windows W. windows Wi... | 11] 1.30 m| 30m] .15m] 0.644 | Bearing 15 cm W.windows W2 ...} 1 | 2.30m) 30m] .15m] 0.103 | Bearing 15 cm ©. windows Wy) ...| 2 | 95m) .20m| .15m| 0.087 | Bearing 10 em Over C.W. aes 18| 95m) 30m] .1Sm| 0.770 | Bearing 10 cm Over shelves... | 5 | 1.30) .30m| .15m| 0.293 | Bearing 15 em Verandah lintels Front we| 1 {975m} 20m] 15m} 0.293 | L=9.60+.15=9.75 m Side we| 1 | 215m) 20m | 15m} 0.065 | L= 2.00 + .15= 2.15 m | Back ..| 1 | 7.50m} 20m} 15m} 0.225 |L=9.60-2.40+2x 15 = 7.50 m Total off deduction 27.401 | cum | Net | Total | 66.59 |cum Note:— Verandah walls above lintel, verandah pillars, and bath room walls may be taken separately and no deduction for verandah openings need be made. ABSTRACT OF QUANTITIES (Ex. 5a) 1. Earthwork in excavation in foundation 64.23 cu m. 2. Lime concrete in foundation 20.22 cu m. 3. Ist class brickwork in foundation and plinth in 1:6 cement.mortar ... 44.95 cum. 4, 2.5 cm damp proof course 24.76 sq m. 5. Ist class brickwork in superstructure in lime mortar wee 66,59 cum. Note:— Steps have not been taken into consideration as the object of this example is to illustrate the method of estimating of walls only.ESTIMATING AND COSTING 46 METHOD I . 5 hod sum-total length of, Method. — In this method known as centre line met length of cente eee and short, has to be found out. Find the total length of centre lines of walls, of . d short having same type of foundations and footings and then fing th suantities | ee multiplying the total centre length by the respective breadth and the height. In he method, the length will remain same for excavation in foundation, for concrete in foundation, for all footings and for superstructure (with slight difference when there are cross walls or numberof junctions). This method is quick but requires special attention and consideration at the junction, meeting points of partition or cross walls, etc. For rectangular, circular polygonal (hexagonal, octagonal, etc.) buildings having no inter o, cross walls, this method is quite simple. For buildings having cross or partition walls, for every junction of partition or cross walls with main walls, special consideration shall have to be made to find the correct quantity. For each junction half breadth of the respective item or footing is tobe deducted from the total centre length. Thus in the case of a building with one partition wall or cros wall having two junctions, for earthwork in foundation trench and foundation concrete deduct one breadth of trench or concrete from the total centre length (half breadth for one junction and one breadth (2 x 4 = one for two junctions). For footings, similary deduct one breadth of footing for two junctions from the total centre length, and so on. If two walls come from opposite directions and meet a wall at the same point, then there will be two junctions. For building having different types of walls, each set of walls shall have to be dealt separately Find the total centre length of all walls of one type and proceed in the same manner as. described above. Similarly find the total centre length of walls of second type and deal this separately, andso on. In the case of a building having different type of walls, suppose the outer (main) walls are of type and inter cross walls are of B type, then all A type walls shall be taken jointly first, and thenall Btype walls shall be taken together separately. In such cases no deduction of any kind need be made for A type walls, but when B type walls are taken, for each junction deduction of half breadth of A type wall (main wall) shall have to be made from the total centre length of walls. It may be noted that at corners of the building where two walls are meeting no substraction or addition is required. When there are number of footings, the length of the first footing is to be determined by deducting half breadth of footing per ‘junction from the total centre line length and then the length of the subsequent footing can be obtained simply by adding one offset of footing i.e. cm forever) Junction to the length of the previous footing. The examples 3(a), 4(a) and 5(a) which have been solved by method I in the previous pages. have been solved again under examples 3(b), 4(b) and 5(b) in the following pages, by method Il0 illustrate this method. These illustrations will make this method quite clear. Note.— Student should practice method J first and when they have become sufficica'! acquainted with method 1, then only they should take up the method I Example 3(b).— Estimate by centre line method the quantities of the following items of * single room building Fig. 2-3 of example 3a (page 31)— (1) Earthwork in excavation in foundalo™ (2) Concrete in foundation, (3) Brickwork in foundation and plinth, and (4) Brickwork i* superstructure.METHOD OF BUILDING ESTIMATE 47 Total centre length of walls = AB + BC +CD + DA = 5.30 + 4.30 + 5.30 + 4.30 = 19.20 m Fig, 2-8 represents the foundation trench plan. If the total centre length is multiplied by the breadth and the depth we get the quantity of earthwork in excavation. By doing so we take certain portion twice and leave an equal portion but this does not affect the quantity The quantity of excavation = ABx 90cm x90. cm + BCX 90cm x 90 cm + CD x 90. cm * 90 em + DA x 90 cm x 90 cm. It may be noticed that the portions P,QR and S marked with double hatch lines come twice while the portions K,L,M,N left blank do not come at all, but these portions being equal in ‘magnitude, we get the correct quantity. ‘The same principle applies to foundation con- ¥——_8.0m.cle., ———— crete, footings, plinth wall and superstructue wall. DETAILS OF MEASUREMENT AND CALCULATION OF QUANTITIES (Ex. 3b) Item] Description of Height No. | Items No. |Length Breadth} or _|Quantity| Explanatory notes | Depth 1. | Earthwork in excavation in foun- dation | 1 {19.20 m) 90m] 90m| 15.55 | Total centre length of all | cum | walls = 19.20m 2. | Conerete in founda- tion | 1 {19.20 m| 90m) 30m) 5.18 cum 3. | Brickwork in foundation and plinth rioting | 1 (19.20m| .60m| 30m) 3.46 ee eh Plinth wall 7 1 {19.20 m| .40m| .60m 4.61 Total | 10.95 | | cum 4. | Brickwork in super- | structure | 1 |19.20 ml .30m|3.50m| 20.16 | Door and window open- | | cum. | ings, lintels, ete. to be | deducted. Note. The above may be compared with the solution by method I given in page 33.— 48 ESTIMATING AND COSTING Example 4(b).— Estimate by centre line method the quantities of the following items of atwo roomed building Fig. 2-6 Example 4a (page 35)— (1) Earthwork in excavation in foundation, (2) Lime concrete in foundation, (3) Ist class brickwork in cement mortar 1:6 in foundation and plinth, (4) 2.5 em c.c. damp proof course, and (5) Ist class brickwork in lime mortar in superstructure, In this problem there are two junctions of the inter wall with the main wall. 2x. to. ¢. of long wall + 3 * c. toc. of short wall. Total centre length of wal 2x 10.60 + 3 x 6,30 = 40.10 m Fig. 2-9 represents the foundation trench plan. Fig. 2-9 If the total centre length is multiplied by the breadth and depth, at the junction the portions A and B shown by hatch lines in Fig. 2-9 come twice, and we get the quantity in excess by these portions, and these excesses shall have to be deducted. The'deduction may be effected reducing the centre length by half breadth for each junction. Thus the quantity of earthwork in excavation — = [Total centre length —(2 4 breadth)] x breadh x depth. = (40.10 - 2x % x 1.10) x 1.10 x 1.00 = 39.00 x 1.10 x 1.00 = 42.90 cu m. The same principle applies to foundation concrete, to footings, plinth wall and superstructure wall. At every stage deduction of half breadth of the main wall at that particular level shall have to be made per junction (i.e. one breadth for two junctions) from the total centre length, and this net centre length after deduction shall be multiplied by the respective breadth and the height or depth to get quantities. : The estimate of the quantities of this Example 4(b) is as follows: — asMETHOD OF BUILDING ESTIMATE 4“ ETAILS OF MEASUREMENT AND CALCULATION OF QUANTITIES (Ex. 4b) Particulars of Height Items No. |Length|Breadth| or /Quantity| Explanatory notes _ Depth Total centre length = 40.10 Earthwork in excavation in foun- 1 — cee} 1 [39.00 m} 1.10 m] 1.00 m} 42.99 | L= 40.10 -2* —— Lime conerete in = 39.00 m foundation... | 1 39.00 m|1.10m| .30m] 12.87 | L same as above. cum Ist class brick-work in 1:6 cement mortar in foundation and plinth— Istfooting | 4 39.30m] .80m| 20m| 6.29 | L=40.10-2* 89 = 39.30m dnd footing | 1 |39.40m) 70m| 10m] 2.76 | L=40.10- 2% 2 = 39.40m 3rd footing | 1 {39.50 m| 60m| .10m| 237 | L=40.10-2* -=39.50m th footing | 1. {39,60 m) .50m| 10m| 1.98 | L=40.10-2* 53-= 39.60m Plinth wall above footing ..| 1 [39.70 m| .40m| .80m| 12.70 | L=40.10 - 2 AC =39.70m Total | 26.10 cum Damp proof course eC 1 [39.70 m| 40m] — | 15.88 Deduct door sill ..| 2 | 120m] 40m] — | 096 Net | 1492 cum Ist class brick-work in lime mortar in superstructure... | 1 (39.80 m| .30m/4.20m| 50.15 | L= Deduct door, window, shelve openings and lintels | 1 | Same | as per [etait in page 37| 4.40 | Deduction to be made as neces as 79| ota cum Note. — The length of 2nd footing can be obtained simply by adding 10cm (i.e. 2x 5cm) to the hof the Ist footing, the length of 3rd footing by adding 10cm to the length of the 2nd footing 50 on. This may be compared with the solution by method I worked out in pages 36-37.50 ESTIMATING AND COSTING Example 5(b).—Estimate by centre line method the quantities of the following items of a residential building, Fig. 247 of Example Sa (page 38). (1) Earthwork in excayation in foundation, (2) Lime concrete in foundation, (3) First class brickwork in 1:6 cement sand mortar in foundation and plinth, (4) Damp proof course and (5) First class brickwork in lime mortar in superstructure. Total centre length of all 30 cm walls (same type) of main rooms =Total centre length of walls of drawing and left side bed room + Total centre length of walls of bed rooms right side = (2X, toc. length of long wall + 3 xc. to c. length of short walt) + (2c. toc. length of long wall + 2 xc. toc. Jength of short wall) (2 x 10.60 + 3 x 5.30) + (2 x 9.60 + 2 x 4.80) 7.10 + 28.80 = 65.90 m. Number of junctions for these walls is 6 marked ‘x’ in the plan Fig. 2-7, page 38 and all these junctions are with main walls of 30 cm. Total centre length of all 20 cm walls (same type) of front verandah, back verandah and bath room =(c. toc. length of front wall + c, to c, length of side wall) + (c. to c. length of back verandah Tong wall including bath + 2 c. to c. length of cross walls of bath room) = (9.65 + 2.25) + (9.65 + 2X 2.75) = 11.90 + 15.15 = 27.05 m. Number of junctions of these wall is 5 is marked ‘+" and one is,marked ‘-"in the plan Fig. 2-7, page 38. Five junctions are with main walls of 30 cm and one junction with similar wall of 20 cm. ‘See page 39 for centre length of different walls. The estimate of the different items by cenive line method is as follows —METHOD OF BUILDING ESTIMATE SI tem] Particulars of Height No. | Items No. |Length Breadth] or |Quantity| Explanatory notes ee Depth 1. | Earthwork in exca~ T : = vation in foundation — Wall of main room (Gixjunetions) || 1 63.20m) .90 m| 1.00 m| 56:88 | L=65.90- 6%-0-= 63.20m including bath (five | - and onejunctions)...| 1 124.50 m| 60 m| s0m| 7.35 |L=27.05-5x-92- 1 x-$0 4.50 mi a) Total | 64.23 . oum 2. | Lime conerete in foundation — Walls of main rooms + | 1 {63.20 m} 90m} 30m] 17.06 | L same as above. Walls of verandah ee =| 1 25.50.m| .60m| 20m] 3.06 |i =27.05 5x52 1x60 = 25,50 m (Minus half breadth per Total | 20.12 | junction at the same level cum 3. | Ist class brick-work in foundation and plinth in |: 6 cement mortar — Walls of main rooms — , Ist footing 1 l64.10 m) .60 m| .20m| 7.69 | L=65.90 - 6 x-$2-= 64.10m 2nd footing 1 [6440] 50m] 20m| 6.44 | L= 65.90 ~6 x32 =64.40m Plinth wall above footing 1 [64.70 m| .40m| 90 m| 23.29 | L=65.90 - 6 x3 = 64.70m (Length of subsequent footing after first can be obtained by adding 6 * 5 = Walls of verandah ie cm to the previous and bath — footing). moe Footing 1 [25.85m} 40m) .20m| 2.07 |L=27.05-5x=>- 13> = 25.85 m Plinth wall above maf footing 1 [25.90 m} 30m] 70m] 5.44 | L=27.05-5x-37- 19> | —__] = 25.90. m Total | “44.93 cumESTIMATING AND COSTING Item| Particulars of L same as for plinth wall, L=(2.20+2x.15)+2x 4030) (295-8) = 130m Details of deduction as usual L=27.05 - 5 x"- 1 x= = 26.20 m 7 : Details of deduction as Height No. | Items No. |Length Breadth} or —|Quantity’ ao Depth 4. | 2.5m Damp proof a 7 course Walls of main rooms w | 1 64.70m} 40m}.— | 25.88 Verandah pillars ...| 4 | 0.50m| .30m| — | 0.60 Bath room (total o 3 walls) | 1 {730m} 30m] — | 249 Total | 28.67 | Deduct door sills Same | as per |detail in| page | 43 391 Net | Total | 24.76 sqm 5. | Ist class brick-work in superstructure in lime mortar— . Walls of main a 1 65.00 m) .30 m}4.00 m| 78.00 Walls of verandah and bath (as solid)| 1 |26.20m} .20m|3.05 m| 15.98 Total | 93.98 Deduct openings ian and lintels Same | as per {detail in| pages | 44-45 27.40_| usual. Net | Total | 66.58 cum i 5. ‘Note. —This solution may be compared with that of by method I worked out in pages 40-45 Method I, ‘Long wall and Short wall” method as explained in followed in the Engineering Department. The measurement of the wor foreach wall for preparing bill for payment and the quantity foreach wall as per: be compared with the estimated quantity. ly sages 2910 45 is general! Fi done, is taken separate measurement mayESTIMATING OF R.C.C. FRAMED BUILDING 215 ‘om the given Example 1. — Prepare a detailed estimate of a small R.C.C. framed building fr te of plan, elevation and sectional elevation (Figs. 5~ -3). Fi i Building. The General Specifications wre asollowss ee eH — All 20 cm panel walls shall be of Ist class brickwork in | : 6 cement sand mortar. Half brick wall shall be of Ist class in | : 3 cement sand mortar with hoop iron 25 mm * 1.5 mm or equivalent reinforcement at every fourth layer. Reinforced work. — Exposed surfaces ofall R.C.C. work shal be fair finished with plastering or floating with | : 3 cement sand mortar of sufficient thickness just to give a smooth and even surface without any extra payment, Mild steel reinforcement shall be estimated separately. The percentage reinforcement for different reinforced works are as follows :— @ R.C.C. footing of columns — 0.5% (iv) R.C.C. chujja and sunshade — 0.5% (ii) R.C.C. beams — 1.0% (v) R.C.C. roof slab — 0.8% (iii) R.C.C. columns — 1.5% Doors and Windows. — Doors and windows shall be of Ist class teak wood and finished with 2 coats of painting over one priming coat. All chaukhats shall be 12 x 8 cm. Door shutters shall be 4 cmthick panelled and Window and fan light shutters shall be 4 cm thick glazed. Rates of shutters shall be excluding fittings. Windows shall be provided with 16 mm dia. bars. Finishing. — Exposed surface of brickwork and half brickwork shall be plastered 12mm thick I : 6 cement sand mortar. Inside shall be finished with 3 coats of white washing, and outside shall be finished with 2 coats of colour washing over one coat of white washing. (ID) Calculate also the P.A. Rate. 20cm 60cm 10cm L.C. Terrace aE semdiaC-LPi HRP eg =a rary SEE era R.C.C, Som, Thick AV w= R.C.C. Footing For Col. SECTION ON. ABC Fig. 5-2 4 Elevation see next page Fig. 5-3 Note.-- For Plan anR.C.C. FRAMED BUILDING LI ( : PL Kitchen 2.10m-x 3.70m 2.10m goon Livi 10cm x-210em Panelled ing Room 3.70cm x 5.50cm 370m 106m Brick Wall Above Plinth 20cm Brick Wall upto Plinth above R.C.C. Beam Door 120cm x 210m PD with 500m High Fanlight —s 140 omx 180cm:R.C.C. FRAMED BUILDING a Detai pose tails of Measurement and Calculation of Quantities (Ex. 1) Item] Particulars of ee ___— No. | items and detail | ig) ares Is | No. | Length |Breadth! aoe Quantity] Explanatory notes m m m 1. | Earthwork in excavation in foundation— Columns an 90 Cee 90 | 1.30 | 9.48 columns — Front and back walls wef 2 | 430} 20 | 1S Side and inter walls we Walls in between kitchen and verandah afd 3 3.90 20 AS 1.30 20 AS 21.60 [x .20%] IS | = Steps and side walls including 6” projections— Step including side walls @ {a | 180} 70} .i7 | 021 { Sp ienten. 7) fa | tao] to |_17_| 0.02 _| step extended portion. L Total | 10.36 Deduct for column ; Portion doubly taken. right side of gate | 1 | 075 0.35 | 17 | 0.05 Net. | Total | 10.31 |cum 2, | Earthwork in filling in plinth— Living room 1 | 3.70} 5.50 Kitchen s] yp | 200 | 3.70 1 | 2.00 | 1.70 Verandah 3. | Sand filling in plinth— Livingroom | | | 370 5.50 | 1S | 3.05 Kitchen 1 | 200] 370] 15 | LU Verandah 1 | 200] 1.70 | 15 | 05!218. ESTIMATING AND COSTING a Particulars of aa: = jo. | items and details No. | Length |Bread: leight ; — of works readth| Da Quantity| Explanatory notes a m m 4. | Cement concrete i ef ff _ 1:3:6 in ee foundation— Column base 9 l- Steps and side 90 | 90 | 10 | 0.729 walls — @ w.{ 1 | 180] 70 | 07 i) ~ | : ; 0.088 (ii) | 1 | 110} 10 | 07 | 0.008 5 Total | 0.825 |cum beams, slabs and chujjas fair finished excluding steel reinforcement and its bending but including centering and shuttering and binding steel- Footing of cols— Total of footing Sq. bottom 9 | 90} 90 | 1S | 1.094 }f2.147 cum ‘Trapezoidal portion = h/6 (Ar + Az + 4An) ce] 9 [3092] + 32 fa 6} 1.053 Columns | 9 | 20] .20 | 4.35 | 1.566 Plinth beams — “ ; Front and back ...| 2 5.70 20 30. Total length excluding col. Sides and inter ...| 3 | 530] .20 | .30 soem” In between kitchen . and verandah i} a | 200] .20 | 30 joe ons 79,30 | 0.20 x} 0.30= | 1.758 Roof beams — Front and back 2! 5.20}| 20] 40 Sides and inter 3 | 5.30] .20 | .40 In between kitchen and verandah 1 | 200] .20 | .40 ree 39.30 [x20] 0.40 =| 2.344 | Total of beams . pat R.CC. work in columns, beams. ‘slabs and chujjas each one may be a oan : : oat for item as the rates differ. But in this estimate all \ypes weR.C.C. work are take ‘simplicity.R.C.C. FRAMED BUILDING a (Ex. 1 Contd.) Ttem| Particulars of —| Height No. | items and details . ii (orl No. | Length |Breadth| con Quantity Explanatory notes | m | mj am Roof slab | 1 | 630] 5.90 7 a 7 ee . 12 | 4.460 sunshades—Chuijja / front w| 1 | 5.76] 60 | 06 Chujjaleft side ...] 1 | 356] .60-| .06 9.32 |x0.60x| 0.06=| 0.336 Sun-breakers vertical 12 | 0 | .06 | 1.80 | 0.151 | 10 em inside wall Sunshade over right side windows ---| 2 | 150] .45 | .05 Total of chujja and Sunshade over back windows wef i 2.10 AS 05 sunshades =0.633 cum 1 1.40 45 05 6.50 |*0.45x| 0.05=| 0.146 Total | 12.908 | cum 6 | Mild steel including bending in reinforcement in R.C.C, works— R.C.C. footing 9.147 x| 5.x | 78.54 | 0.843 4 | Density of steel @ 05% cum | 100 78.5 q/cum R.C.C. column 1,566 x{_L2 x) 78.54 18444 @15% ' Sam | 100 R.C.C. beams 4.138 x|_L2 x) 78.54 | 3.248 4 @ 1.0% ~ cum | 100 R.C.C. roof slab 4.460 x|_2_*] 78:54 | 2804 @ 0.8% ae Py | R.C.C. chujjas and sunshades @ 0.5%Item) Particulars of | items and details No. ESTIMATING AND COSTING of works Ist class brickwork in 1 : 6 cement mortar — Living room — Front and back walls 2 Right side wall excluding column | 1 Kitchen— Front and back | walls 2 Left side walls 1 ‘Wall in between ver. and living room Height Length Breadth] or |Quantity Depth m m m 3.70 20 3.05 5.30 .20 | 3.05 2.00 .20 | 3.05 3.70 .20 3.05 1.60 .20 | 3.05 22.00 | x0.20x| 3.05=| 13.420 3.70 20 AS 2.00 20 45 1.60 |" .20 45 Plinth wall— Under 10 cm partition wall 1 Under verandah front parapet 1 Under verandah side parapet - 1 Steps (i) f (iii) 1 Walls by the side of steps 2 Parapet wall over roof slab— Front and back 2 | Sides 2 Deduct openings— Door Windows Rene 730 | *0.20x| 0.45=| 0.657 Loo | 75 | 25 | 0.188 100 | 25 | 15 | 0.038 60 30 70° | 0.252 Explanatory notes Full height in between plinth and roof beams. 20 cm wall up to floor.eS BSULLDING —Ppantculars of —-— | particulars of - a na items and details No. |Lengsa [Breadth Height of works or |Quantity’ Depth — | m m g | Half brick masonry caalaaen 4 Ist class in 1: 3 cement mortar with hoop iron 25 mm x | 1.5mm or equivalent reinforcement at every fourth course Wall in between kitchen and living room a 705) 121) 2.00) | 9.62) Ver. parapet wall front eels 2.00 80 1.60 | Ver. parapet wall side . 1 1.60 oa 80 1.28 Total | 12.50 Deduct opening— Door oe (i k 1.00 = 2.10 2.10 Gate 1 1008 sce 80 0.80 9. |10 cm Lime Total | of ded juction 2.90 concrete in roof Net | Total | 9.60 terracing finished with gur | and belsiri : 2 es treatment 1 | 5.90 | £50 ° 10 | Teak wood wrought, frazaed and fixed in door and windowchaukhat 1 5.28 2 08 | (framed) —Doot | 200m a Boor with fan light |) | 7,68 2 | 08 120%260 cm - \ 12.30 | -12 | 08 Window 170%1806m can 690 | 12 | 08 Window 110*180e™ 2) % : , 6.60 | 12 | 08 Window 100*1800m an nee ee { 64.56 |x0.12x| 0.08=| 0.620 - *4cm insertion # 221 (Ex. | Contd.) Explanatory notes sqm «floor for verticals of door chaukhat. 2 verts. — 2.14 m* Uhors. — 1.00 m 2 verts. — 2.64 m 2 hors, — 1.20 m 4 verts. — 1.80 m { { { 3 hors. — 1.70 m G verts. — 1.80 m 3 hors. — 1.10m 2 verts. — 1.80 m 3 hors. —1.00 m cum ——— &222 ESTIMATING AND COSTING Item No. Particulars of items and details of works No. Length m /Breadth| Height or Depth m m Quantity Explanatory notes Door shutters 4 cm thick panelled of teak wood excluding fittings— Door 100210 cm Door 120x210 cm Window shutters 4 em thick glazed of teak wood excluding fittings— Window 170x180cm including fan-light Window 110x180cm including fan-light including fan-light Fan-light over Door 120«50cm Brass fittings in doors and windows, supplying and fixing Iron work in hold fasts and. window bars— Hold fasts— Door 120x260cm Door 100x210cm Window 6 nos. Window bars 16 mm dia. (10 cm c/c approx.) Window 110x180cm excluding fan-Light Fan-light of above Window 100x180cm excluding fan-light Window 100x180cm |. 1x8 1x6 6x6 50 87 1.07 97 87 1.07 Same nos.@ 1.30 1.10 2.03 2.03 1,766 2.172 Total 1.62 1.62 1.62 45 Total items +11.207| as for =3.938 23.40 4.40 20.80 3.938 =15.145 50 kg Ht = 210-8 + 1.5 - 5 = 203 cm sqm L=170 - (4x8) + (6*1.5)=147 cm Ht.=180 - (38) +(4x1.5)=162 em sqm ll and 12) sqm 4 on each side. 3 on each side. 3 on each side. 2 nos. horizontals. 1.30 Note— Rebate of door and window shutters 1.5 cm, clearance at the bottom of door shutters SemR.C.C. FRAMED BUILDING 223 ere >——— Particulars of a B tem ems and details | No. |Length [Breadth] cs” © 1 Conia) of works Depth (Quantity! Explanatory notes _|—— cs m m Fan‘light of above .|2x2| 1.00] = : 4.00 m| 2.nos. horizontals. Windows 170%180 cm excluding fan-light 2x15} 1.30 Fanlight of above |2x2| 1.70| = ice oe 80 m| 2 nos. horizontals ee 155.47 ke Flat bars 25x6 mm | horizontal at the | middle of window— Windows foxig0cm «sf 2X1] LO | = ]220m Windows 100x180cm | 2x1] 1.00) = |2.00m Windows Iox180cm [2X1 | 1-70 | = [340m 7.60 rm| @ 1.2 | kg= | 9-12 ke Total |214.59| ke= | 2.1464 Iron gate (grill) framed, fixed ..-| 1 | 1.00) — 80 | 80 sqm 12 mm plaster in | : 6 cement mortar— INSIDE— Living room walls | 2 | 550 | — o 3.70 | — | 2 : Kitchen walls 2 3.70 | — 260 Bactoding R.C-C- Peas 2 | 210) — oa Vv wf dl = \5 erandah walls = | 260 133.0 | x |260=| 87.36 Verandah parapet— 80 1.28 : Inner face side 1 | 160) ~ | ‘go | 0.80 | Excluding gate Inner face front 1 | 100) ~ au ; Vertical'jamb of ‘io | 80 | 0.08 | One side pate wf dl == ||224 ESTIMATING AND COSTING Item| Particulars of Height | ] No. | items and details | No. |Length|Breadth| or {Quantity Explanatory notes of works Depth | | m)om | m Upper surface of Pparapet— Front ve) 1} 100] 10 O10 | | Side «| Lf] eo) co | 0.16 | | Jambs of door | and fan-light | 120*260 cm | 2 08 | 260 | 0.42 | Jambs and sills of ; large window L=180+180 170%180cm, s+} 2] 530} 08 | — +170=530 cm | Total Deduct openings— Door 100120em ..,) 2 | 1.00 — | 1:20 | 240 | Both faces, jambs being | small and no sills and Door 120260 2 | 120! — | 260 | 6.24 | soffits. Total | of ded | uction| 8.64 OUTSIDE— Total | inside | 82.41 | sqm Back wall (whole length) cl! 1 | 630 3.05 Right outer side -..) 1 | §.90| — | 3005 Excluding beams, Front livingroom | 1 | 410| — | 3.05 including plinth. Left outer side | of kitchen v-} L | 440} — | 305 20.40 |] 3.05=| 62.22 | Verandah parapet front vf 1 | 120] — | was | 13g Verandah parapet Excluding band. side Brat et ey) | tl! oy) Side wall steps— Outer sides 2/ 6} — | 6 | o7 Inner sides 2! 60 30 | 0.36 | Average height Top “| 2 | 60| — | 30 | 036 Parapet above roof am— Inner faces front and back Seas 0} ee 60 | 7.08 Inner facessides ... | 2 | 5159 | _ 60 | 6.60 Top front and back 2 \ 630) 20) — | 259 Top sides --1 2 | 5.50] 20 | — | 239 Outer faces of front and back including grooveSx Sem... | 2) 630) — 85 | 10.71 —Do— sides 5.90 85 | 10.03 Sus. =60+ 10+ (3x5)=85 om pees tL toRoo CC. FRAMED BUILDING 225 vem) Particulars of : 5 (Ex. 1 Contd.) No. | items and details No. Length Breadth ight ‘of works | Dea ‘ Quantity) Explanatory notes ee ee | Deduct openings— Windows TOxI80em | xt 396 Windows : oox180em | 2x1 Jone face. te oe line bs and sills faces, jambs Ve ] 12.24 | taken separately led 19.80 | | Total |outside| 86.45 | sqm Total | of nsi | de Pirates si | de and | outside | 168.86 sq m steps in 1 : 3 cement | mortar finished neat ement floated— Tread and rise 1 | 1.00 | 1.35 135 Ends of step 42 - 15 0.05 | Beyond side walls. 1.40 | sqm 18 | Brick band 10x10 cm in 1:4 cement mortar complete with plastering— Front (Horizontal) | 1 | 4.10| — | — | 4.10 Side 1] 350] — | — |. 350 front vertical 2| 70) — | — | 140 | Total | 9.00 |rm 19 25emC.C.1:2:4 over and including 7.5 cm L.C. floor finished with neat cement floating— Living room 1 | 3.70} $50 | — a Kitchen 1} 240) 370) — | 27 Verandah 1 | 210} 1.70 | - ci ' i Door sill 1] 100] 10) — | oq "yo. 1c. in sil Door sill 1 | 220 |e Total | 32.03 |sqm 0] White washing , coats inside— side | plaster Wa inside | laste Ceiling living room = Ceiling kitchen . _ —_|Ceiting verandah =226 TIMATING AND COSTING Htem| Particulars of Height No. | items and details Breadth) or | Quantity Explanatory notes Sf works | Depth | om m m Inner face of root | cams Living room 2 | 3.70 Living room 2 | 550 | Kitchen 2 | 200) = | Kitchen 12 | 370] — j 29.80 Kitchen—soffit of beam 1] 370) a0 | 0.37 | Over partition wall, Verandah 2 | 200) — 40 | 1.60 | Verandah 2 | 160) — 40 | 1.28 Verandah soffit of beam s+| 1 | 200] 20 | — | 040 Verandah soffit of beam s+ 1] 160} 20} — | 032 Lower faces of chujjas and sunshades— Chujja front 1 | 5.70] 60 | — 3.42 | Lower face white washed. Chujja side 1 | 350] 60 | — | 210 Sun-breaker 2 60; — | 180) 2 Sunshades over windows 2} 450 | 45 |y— Sun shades over windows...) 1 | 210 | 45 | \— Sun shades overwindows ...| 1 | 1.40 | 45 |) — | 6.50x] 0.45 | = 2.93 Total | 139.86 | sqm 21 | Colour washing 2 coats over one coat white washing— Outside walls oe Same | as for |outside| plaster initem| (16) 86.45 Outer faces of roof slab, roof beams and plinth beam above G.L.— ‘ Front and back 2} 630) — 60 | 7.56 | Ht.=40 + 12 + 15 - 7=60em Sides 2 | 590 | — 60 | 7.08 Upper faces of chujjas and Sun-shades— Chuja front 1) 5.76] .66 | — | 3.80 | Upper faces and edges Chujja side se[ 1 | 3.56 | 66 | — ) 235 | colour washed Sun-breaker =. .| 2 | 66 | 1.80 | 238 | L7 oa Lee —FRAMED. BUILDING 227 < rticulars of > (Ex, I Contd.) lem | ems and details | No |Length|Breaath| "8" 1 - ontd.) Now of works Depth Quantity| Explanatory notes $$ — m m inshade over > ~ —y — _ indows | 2 | 150 Sunshade over 7 153, | windows =| 1} 20} si} — | | Sunshade over i 1.07 | inane |) to) st | — | on | | Total Deduct step ef | 60 | — | *5' | "33 Net | Total 2 | Painting doors and otal | 112.69 | sqm windows two coats over one priming coat— Panelled door... 1x24) 1.00 | — | 210 | 4.73 : |Panelled door... 1x24) 1.20 | — | 210 | S67 }} 2% time one surface. | Glazed fan-light over door -.| Pt] 1.20 | — | 50 | 0.60 | One surface for both sides | Glazed window ax1| 170 | — | 180 | 612 | Glazed window 2x1 1.10 _- 1.80 3.96 ne surface for both sides. Glazed window ...|2x1| 1.00 | — | 1.80 | 3.60 Iron gate (grill) ...|1x1| 1.00 | — | 80 | 0.80 Window bars (excluding chowkhat) w.[>a| 154) — | 164 | 5.05 | ax1| 94) — | 1.64 3.08 ‘One surface for over all. | ax1| 84 oa | 2.7 Bars of fan-light over door | ba] 104) — 42 \_ 0.44 | Total | 36.81 \sq.m. 23 | Solignum paint two coats in back of | chaukhat — oor | 100x120 cm ww) 1 | 5.28) 12] — | 063 Door with fan-light 1202260. me ea) ae lS oe Window 170180cm | 2 | 12.30) 12 | — fee Window 110x180em | 2 | 6.90) -12 | — ee Window 100x180cm | 2 | 6.60 | — | Total | 7.74 |sqm ne mm Dia. C.1. tain water pipe 21m - _|fitted and painted | 2 | 100) — | oo)228 ESTIMATING AND COSTING ABSTRACT OF ESTIMATED COST (Ex. 1) Hem | No. | Particulars of items 1 | Farthwork in excavation in founda 2) Farthwork in filling in plinth 3 | Sand filling in plinth (Local sand) 4 Cement cones with brick balls 1.3:6 in toundation RCC. work 1 2:4 fair finished | excluding steel reinforcement and but including centering shuttering and binding steel © | Mild steel reinforcement in R.C.C. work 7 | Lelass brickwork in 1: 6 cement | mortar (one brick. 20 em thick) i 8 | Halt brick masonry [-class in I : 3 cement | mortar including hoop iron reinforcement 9 | 10cm lime concrete in roof terracing | finished with gur and belgiri-treatment 10 | Teak wood wrought, framed and fixed in chowkhat LL | Door shutters 4em thick panelled of teak wood excluding fittings 12 | Window shutters 4 em thick glazed of teak | wood excluding fittings 13. | Brass fittings in doors and windows. supplying and fixing 14 | Iron work in hold fasts and window bars ] Rate | ‘Amount Quantity] Unit _| Per | [Rs Rs. P. 10.31 cum) 350.00 /% cum) 36.08. 10.90 cum) 275.00 |% cu m) 29.97 4.67 cum) 30.00) cum 140.10 0,825 cum) 300.00 cum| 247.50 | | i | | | | | 12.944 |cu m| 675.00 | cum) 8737.20 8.985 | q |515.00/ q | 4627.28 14.694 cu m] 340.00] cum! 4995.95 9.60 'sqm! 50.00! sqm! 480.¢9 32.45 bq m| 35.00/ sqm| 1135.75 0.620 cu m}9200.00| cum | $704.00 | 3.938 |sq m| 200.00! sqm! 787.60 | 11.207 [sq m| 150.00| sqm | 1681.05 15.145 |sqm! 40.00| sqm! 605.80 2.146 | q | 700.00) q 1502.20 C.0. | 3071049 _