Remember, when it comes to electrical equipment, it's better to be cautious
and take your time to familiarize yourself with the equipment properly,
rather than rushing in and risking injury or damage.
Discussion:
1)
The trainer board
and the multi-
meter were
checked before the
start of the
experiment.2)
The resistor was
placed properly
according to the
figure.3)
The value of the
voltage was
increased
gradually as
applying a large
voltage can
damage
theresistors.4)
Because of the
potentiometer,
converted values
of resistance were
not so perfect. So
theconverted
values of voltages
and currents were
not so much
perfect.5)
Finally all the data
was placed in the
data table. For the
given equation, a
result was
obtained
.
Result and Discussion:
1) Wheatstone bridge establishes a reference voltage or maintains a constant
electric potential ratio within linear operational amplifier circuits.2) This
experiment teaches the how to use a potentiometer in order to understand the
basic.3) This lab shows the basic concept of how a Wheatstone bridge operates to
allow the calculation of an unknown resistance using a standard resistance with the
relationships between the resistances of a specified material.4)
There may be some systematic errors in the voltmeter or ammeter, so the actual determination
of the resistance may not be as good as is implied by the uncertainty.
Result and Discussion:
1) Same terminals of wye and delta circuits have identical values.2) Although the
DELTA and WYE have the same total resistance they still have different
individualresistance.3) A bridge circuit can be simplified to a series/parallel circuit
by converting half of it from a Delta to Wye network.
Discussions
1. We observed that when voltage V = 0, the reading of the
ammeter is zero. That means the current through the wire is
zero. Now, one cannot calculate the resistance for this data
because one cannot measure the opposition faced by the
current until the current flows.
2. While taking data we can see that for the last two data current
has not increased as much as first three observations. This is
because of the increase in resistance of the wire due to
heating. Here current flow through the wire causes joule’s
heating.
3. The calculated value of resistance almost matches the
resistance calculated from the graph.
4. If the radius (r) and length (L) of the wire are not supplied, then
we have to determine those parameters by screw gauge and
the meter scale respectively.
5. In this experiment 1) verification of ohm’s law is done 2)
Unknown resistance of the wire and 3) Resistivity of the
material of the wire is determined.
6. DISCUSSION
7. As displayed in the graph voltage increases as current increases. This
implies similarly as current
8. is directly proportional to voltage between two points in a conductor, the
inverse is likewise
9. evident. . The applied voltage was periodically increased from 5V to 30V
and as the voltage
10.increased so did the current and resistance. The diagram showed this by
having a positive slope.
11.The values of resistance gained from the graph calculations is 4.6 KΩ and
the equivalent
12.resistance is 4.6kΩ. hence the measured resistance and equivalent resistance
are equal.
13.CONCLUSION
14.The experimental data gathered shows the experiment obeys ohms law. The
chart of voltage
15.against current is direct and has a positive slope, as such it upholds ohm's
law.
16.The measured resistance is 4.6 kΩ
17.The equivalent resistance is 4.6 kΩ
Procedure
1. Now we set up the circuit on our breadboard.
2. We connect the DC power supply’s red probe to one end of the resistor,
and the resistor’s other end to the red probe of the multimeter.
3. To make sure the multimeter shows the value of current, we insert the
black probe in the COM section of the multimeter and the red probe in
the µA/mA section. Then we rotate the dial of the multimeter so that it
points to the mA.
4. Make sure to click the FUNC button to put the multimeter in the DC
current mode as we are using a DC power supply.
5. Now the multimeter is working as an Ammeter.
6. Attach the black probe of the multimeter to the second resistor.
7. Now connect the black probe of the DC power supply to the other end of
the resistor, and attach the voltmeter in parallel to the one of resistors.
8. The circuit arrangement is shown below:
9. Now keep increasing the voltage of the DC power supply and note down
the readings of voltage and current from the ammeter and the voltmeter.
Procedure
1. Now we set up the circuit on our breadboard.
2. We connect the DC power supply’s red probe to one end of the resistor,
and the resistor’s other end to the red probe of the multimeter.
3. To make sure the multimeter shows the value of current, we insert the
black probe in the COM section of the multimeter and the red probe in
the µA/mA section. Then we rotate the dial of the multimeter so that it
points to the mA.
4. Make sure to click the FUNC button to put the multimeter in the DC
current mode as we are using a DC power supply.
5. Now the multimeter is working as an Ammeter.
6. Attach the black probe of the multimeter to the second resistor.
7. Now connect the black probe of the DC power supply to the other end of
the resistor, and attach the voltmeter in parallel to the one of resistors.
8. The circuit arrangement is shown below:
9. Now keep increasing the voltage of the DC power supply and note down
the readings of voltage and current from the ammeter and the voltmeter.
DISCUSSION
As displayed in the graph voltage increases as current increases. This implies
similarly as current
is directly proportional to voltage between two points in a conductor, the inverse is
likewise
evident. . The applied voltage was periodically increased from 5V to 30V and as
the voltage
increased so did the current and resistance. The diagram showed this by having a
positive slope.
The values of resistance gained from the graph calculations is 4.6 KΩ and the
equivalent
resistance is 4.6kΩ. hence the measured resistance and equivalent resistance are
equal.
CONCLUSION
The experimental data gathered shows the experiment obeys ohms law. The chart
of voltage
against current is direct and has a positive slope, as such it upholds ohm's law.
The measured resistance is 4.6 kΩ
The equivalent resistance is 4.6 kΩ
