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Count Calculations

The document discusses different count calculation systems for yarn including direct count, indirect count, and various specific systems like English cotton count, worsted count, metric count, tex count, and denier count. It provides formulas to calculate count based on the weight and length of a yarn sample for each system. Several example problems are also included and solved to find the count under different systems given yarn weight and length.

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Sagar Shri
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0% found this document useful (0 votes)
366 views15 pages

Count Calculations

The document discusses different count calculation systems for yarn including direct count, indirect count, and various specific systems like English cotton count, worsted count, metric count, tex count, and denier count. It provides formulas to calculate count based on the weight and length of a yarn sample for each system. Several example problems are also included and solved to find the count under different systems given yarn weight and length.

Uploaded by

Sagar Shri
Copyright
© © All Rights Reserved
We take content rights seriously. If you suspect this is your content, claim it here.
Available Formats
Download as PDF, TXT or read online on Scribd
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Count Calculations

1. Direct Count System:

The count of yarn expresses the number of weight units in one length unit.
If higher the count then coarser the yarn.

W×l
Direct yarn count, N = ………..............
w×L
Where,
N denotes the yarn number or count,
W denotes the weight of the sample,
L denotes the length of the sample,
l denotes the unit length of the system,
w denotes the unit weight of the system.
2. Indirect Count System:

The count of yarn expresses the number of length units in one weight unit.
If higher the count then finer the yarn.

L×w
Indirect system, N = …………....….
l×W
Where,
L indicates the length of the sample,
l indicates the unit length of the system,
w indicates the unit weight of the system,
W indicates the weight of the sample.
Count in Different System:

1. English cotton count System:

It is defined as the number of hanks of 840 yds per pound.

Length (yds) × 1 pound


English cotton count, N = …………………........…………....
840yds × weight (pound)

2. Worsted System:

It is defined as the number of hanks of 560 yds per pound.

Length (yds) × 1 pound


Worsted count = …………………………….....
560yds × weight (pound)
3. Metric System:

It is defined as the number of hanks (1000m) per kg.

Length (m) × 1kg


Metric count = ………………………..........
1000m × weight (kg)

4. Tex System :

The weight in grams of 1000 mt..

Weight (gm) × 1000m


Tex count = …………………….....…….....
1gm × length (m)
5. Denier System:

The weight in grams of 9000 mt.

Weight (gm) × 9000m


Denier count = …………………....……….
1gm × length (m)

6. Pounds per spyndle (Jute System):

The weight in pounds of 14400 yards.

Weight (pound) × 14400 yds


Pounds per spindle = …………….....……………………
1pound × length (yds)
Q-1: Find out the English cotton count if weight of 800 yds yarn is 10 gram.

Q-2: Find out the Worsted count if weight of 700 yds yarn is 8 gram.

Q-3: Find out English cotton count if the weight of 150 m yarn is 0.2 ounce.

Q-4: If the length of yarn is 140 yds and weight 70 grain then find out the cotton
count.

Q-5: If the length of lap is 40 m and weight 15 kg then find out the hank of lap.

Q-6: If Length of lap is 40 m and Hank is 0.0015 then find the weight of lap in kg.

Q-7: If the weight of 960 m yarn is 20 gm. Find out the Tex count.

Q-8: If the weight of 1100 yds yarn is 22 gm. Find out the Denier count.
Problem-01:
Find out the cotton yarn count if weight of 800 yds yarn is 10 gram.

Solution:
Here,
Length of yarn (yds) =800,
Weight of yarn (pound) = 10/ 453.6 = 0.022,
Unit length (yds) =840,
Unit weight (pound) = 1,

So,
Cotton count (Ne)
Length of yarn (yds) × Unit weight (pound)
= ………………………………………………………
Unit length (yds) × Weight of yarn (pound)

800×1
= …………… = 43.29
840× 0.022
Problem-02:
Find out the Worsted count if weight of 700 mt yarn is 8 gram.

Solution:
Here,
Length of yarn (yds) =700 x 1.09 = 763 yds,
Weight of yarn (pound) = 8/ 453.6 = 0.017,
Unit length (yds) =840,
Unit weight (pound) = 1,

So,
Cotton count (Ne)
Length of yarn (yds) × Unit weight (pound)
= ………………………………………………………
Unit length (yds) × Weight of yarn (pound)

763×1
= …………… = 80.14
560× 0.017
Problem-03:
Find out English cotton count if the weight of 150 m yarn is 0.2 ounce.

Solution:
Here,
Yarn length (yds) =150 X 1.09 = 163.5,
Yarn weight = 0.2 ounce=0.2/16=0.0125pound,
Unit length (yds) =840,
Unit weight= 1 pound,

So,
English cotton count (Ne)
Yarn length (yds) × Unit weight (pound)
= …………………………………………………
Unit length (yds) × yarn weight (pound)

163.5 ×1
=………………… = 15.57
840×0.0125
Problem-04:
If the length of yarn is 140 yds and weight 70 grain then find out the cotton count.

Solution:
Here,
Length of yarn (yds) = 140,
Weight of yarn= 70 grain= (70/7000) pound=0.01 pound,
Unit length (yds) = 840,
Unit weight (pound) = 1,

Now,
Cotton count (Ne)

Yarn length (yds) × Unit weight (pound)


= ……………………………………………………
Unit length (yds) × Weight of yarn (pound)

140×1
=……………… = 16.66
840×0.01
Problem-05:
If the length of lap is 40 m and weight 15 kg then find out the hank of lap.

Solution:
Here,
Length of lap (yds) = 40 × 1.09 = 43.6
Weight of lap= 15 kg= (15 × 2.2) pound= 33 pound,
Unit length (yds) = 840,
Unit weight (pound) = 1,

Now,

Hank = 0.001572
Problem-06:
If Length of lap is 40 m and Hank is 0.0015 then find the weight of lap in kg.

Solution:
Here,
Length of lap (yds) = 40 × 1.09 = 43.6
Hank of lap = 0.0015
Unit length (yds) = 840
Unit weight (pound) = 1,

Weight of lap = 15.72 kg


Problem-07:
If the weight of 960m yarn is 20gm. Find out the Tex count.
Solution:
Here,
Weight of yarn= 20gm,
Length of yarn=960m,
Unit length of yarn=1000m,
Unit of weight of yarn=1gm,

So,
Tex count
Weight of yarn (gm) × unit length (m)
= …………………………………………………………
Unit weight of yarn (gm) × length of yarn (m)

20×1000
= …………… = 21 tex
1×960
Problem-08:
If the weight of 1100 yds yarn is 22 gm. Find out the Denier count.

Solution:
Here,
Weight of yarn= 22gm,
Length of yarn=1100 yds = 1100 / 1.09 = 1009 ,
Unit length of yarn=1000m,
Unit of weight of yarn=1gm,

So,
Tex count
Weight of yarn (gm) × unit length (m)
= …………………………………………………………
Unit weight of yarn (gm) × length of yarn (m)

22×9000
= …………… = 196.23 Denier
1×1009
• Lap : 0.001 - 0.002 Hank (Ne), 590.5 KTex - 295.25 KTex

• Sliver : 0.1 - 0.2 Hank (Ne), 5.9 KTex - 2.95 KTex

• Roving : 1 - 2 Hank (Ne), 590.5 Tex - 295 Tex

• Yarn : 10 - 100 Ne, 59 Tex - 5.9 Tex

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