Count Calculations
1.   Direct Count System:
The count of yarn expresses the number of weight units in one length unit.
If higher the count then coarser the yarn.
                           W×l
Direct yarn count, N = ………..............
                           w×L
Where,
N denotes the yarn number or count,
W denotes the weight of the sample,
L denotes the length of the sample,
l denotes the unit length of the system,
w denotes the unit weight of the system.
2. Indirect Count System:
The count of yarn expresses the number of length units in one weight unit.
If higher the count then finer the yarn.
                          L×w
Indirect system, N = …………....….
                          l×W
Where,
L indicates the length of the sample,
l indicates the unit length of the system,
w indicates the unit weight of the system,
W indicates the weight of the sample.
                   Count in Different System:
1.   English cotton count System:
It is defined as the number of hanks of 840 yds per pound.
                           Length (yds) × 1 pound
English cotton count, N = …………………........…………....
                           840yds × weight (pound)
2. Worsted System:
It is defined as the number of hanks of 560 yds per pound.
                Length (yds) × 1 pound
Worsted count = …………………………….....
                560yds × weight (pound)
3. Metric System:
It is defined as the number of hanks (1000m) per kg.
               Length (m) × 1kg
Metric count = ………………………..........
              1000m × weight (kg)
4. Tex System :
The weight in grams of 1000 mt..
             Weight (gm) × 1000m
Tex count = …………………….....…….....
              1gm × length (m)
5. Denier System:
The weight in grams of 9000 mt.
                Weight (gm) × 9000m
Denier count = …………………....……….
                1gm × length (m)
6. Pounds per spyndle (Jute System):
The weight in pounds of 14400 yards.
                    Weight (pound) × 14400 yds
Pounds per spindle = …………….....……………………
                      1pound × length (yds)
Q-1: Find out the English cotton count if weight of 800 yds yarn is 10 gram.
Q-2: Find out the Worsted count if weight of 700 yds yarn is 8 gram.
Q-3: Find out English cotton count if the weight of 150 m yarn is 0.2 ounce.
Q-4: If the length of yarn is 140 yds and weight 70 grain then find out the cotton
   count.
Q-5: If the length of lap is 40 m and weight 15 kg then find out the hank of lap.
Q-6: If Length of lap is 40 m and Hank is 0.0015 then find the weight of lap in kg.
Q-7: If the weight of 960 m yarn is 20 gm. Find out the Tex count.
Q-8: If the weight of 1100 yds yarn is 22 gm. Find out the Denier count.
Problem-01:
Find out the cotton yarn count if weight of 800 yds yarn is 10 gram.
Solution:
Here,
Length of yarn (yds) =800,
Weight of yarn (pound) = 10/ 453.6 = 0.022,
Unit length (yds) =840,
Unit weight (pound) = 1,
So,
Cotton count (Ne)
  Length of yarn (yds) × Unit weight (pound)
= ………………………………………………………
  Unit length (yds) × Weight of yarn (pound)
   800×1
= ……………               = 43.29
  840× 0.022
Problem-02:
Find out the Worsted count if weight of 700 mt yarn is 8 gram.
Solution:
Here,
Length of yarn (yds) =700 x 1.09 = 763 yds,
Weight of yarn (pound) = 8/ 453.6 = 0.017,
Unit length (yds) =840,
Unit weight (pound) = 1,
So,
Cotton count (Ne)
  Length of yarn (yds) × Unit weight (pound)
= ………………………………………………………
  Unit length (yds) × Weight of yarn (pound)
    763×1
=    ……………        = 80.14
    560× 0.017
Problem-03:
Find out English cotton count if the weight of 150 m yarn is 0.2 ounce.
Solution:
Here,
Yarn length (yds) =150 X 1.09 = 163.5,
Yarn weight = 0.2 ounce=0.2/16=0.0125pound,
Unit length (yds) =840,
Unit weight= 1 pound,
So,
English cotton count (Ne)
  Yarn length (yds) × Unit weight (pound)
= …………………………………………………
  Unit length (yds) × yarn weight (pound)
  163.5 ×1
=…………………            = 15.57
  840×0.0125
Problem-04:
If the length of yarn is 140 yds and weight 70 grain then find out the cotton count.
Solution:
Here,
Length of yarn (yds) = 140,
Weight of yarn= 70 grain= (70/7000) pound=0.01 pound,
Unit length (yds) = 840,
Unit weight (pound) = 1,
Now,
Cotton count (Ne)
    Yarn length (yds) × Unit weight (pound)
= ……………………………………………………
   Unit length (yds) × Weight of yarn (pound)
   140×1
=………………          = 16.66
  840×0.01
Problem-05:
If the length of lap is 40 m and weight 15 kg then find out the hank of lap.
Solution:
Here,
Length of lap (yds) = 40 × 1.09 = 43.6
Weight of lap= 15 kg= (15 × 2.2) pound= 33 pound,
Unit length (yds) = 840,
Unit weight (pound) = 1,
Now,
Hank = 0.001572
Problem-06:
If Length of lap is 40 m and Hank is 0.0015 then find the weight of lap in kg.
Solution:
Here,
Length of lap (yds) = 40 × 1.09 = 43.6
Hank of lap = 0.0015
Unit length (yds) = 840
Unit weight (pound) = 1,
Weight of lap = 15.72 kg
Problem-07:
If the weight of 960m yarn is 20gm. Find out the Tex count.
 Solution:
Here,
Weight of yarn= 20gm,
Length of yarn=960m,
Unit length of yarn=1000m,
Unit of weight of yarn=1gm,
So,
Tex count
       Weight of yarn (gm) × unit length (m)
=     …………………………………………………………
      Unit weight of yarn (gm) × length of yarn (m)
     20×1000
=    ……………            = 21 tex
      1×960
Problem-08:
If the weight of 1100 yds yarn is 22 gm. Find out the Denier count.
 Solution:
Here,
Weight of yarn= 22gm,
Length of yarn=1100 yds = 1100 / 1.09 = 1009 ,
Unit length of yarn=1000m,
Unit of weight of yarn=1gm,
So,
Tex count
       Weight of yarn (gm) × unit length (m)
=     …………………………………………………………
      Unit weight of yarn (gm) × length of yarn (m)
     22×9000
=    ……………          = 196.23 Denier
      1×1009
• Lap : 0.001 - 0.002 Hank (Ne), 590.5 KTex - 295.25 KTex
• Sliver : 0.1 - 0.2 Hank (Ne),    5.9 KTex - 2.95 KTex
• Roving : 1 - 2 Hank (Ne),       590.5 Tex - 295 Tex
• Yarn :   10 - 100 Ne,           59 Tex - 5.9 Tex