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Text 11

The document presents two partial differential equations describing the relationships between u1, u2, x, and t. The equations are solved over the intervals of 0 to 1 for x and 0 to 20 for t, with initial conditions of u1=0 and u2=0 and specified boundary conditions. Constants in the equations are set to pec=pet=7, y=10, c=2.5, da=0.1, and r=0.5.

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gverma9461
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0% found this document useful (0 votes)
54 views4 pages

Text 11

The document presents two partial differential equations describing the relationships between u1, u2, x, and t. The equations are solved over the intervals of 0 to 1 for x and 0 to 20 for t, with initial conditions of u1=0 and u2=0 and specified boundary conditions. Constants in the equations are set to pec=pet=7, y=10, c=2.5, da=0.1, and r=0.5.

Uploaded by

gverma9461
Copyright
© © All Rights Reserved
We take content rights seriously. If you suspect this is your content, claim it here.
Available Formats
Download as TXT, PDF, TXT or read online on Scribd
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du1/dt=(1/pec)*d2u1/dx2-du1/dx-da*(1+u1)*exp(y*u2/(1+u2))

du2/dt=(1/pet)*d2u2/dx2-du2/dx+c*da*(1+u1)*exp(y*u2/(1+u2))

pec=pet=7, y=10, c=2.5 da=0.1 r=0.5


initial condition: u1=0, u2=0
boundary conditions at x=0, du1/dx=-pec*(r*ur(1)-r*ul(1)) and du2/dx=-pet*(r*ur(1)-
r*ul(1))
BC at x=1, du2/dx=0 and du2/dx=0
K 'WS 'ILJ [87 [09 I[8 U- 8 U- 8U -98 U - 98 [8 U -98 U [98 P

solve in the interval of 0 to 1 for x and 0 to 20 for tdu1/dt=(1/pec)*d2u1/dx2-


du1/dx-da*(1+u1)*exp(y*u2/(1+u2))
du2/dt=(1/pet)*d2u2/dx2-du2/dx+c*da*(1+u1)*exp(y*u2/(1+u2))

pec=pet=7, y=10, c=2.5 da=0.1 r=0.5


initial condition: u1=0, u2=0
boundary conditions at x=0, du1/dx=-pec*(r*ur(1)-r*ul(1)) and du2/dx=-pet*(r*ur(1)-
r*ul(1))
BC at x=1, du2/dx=0 and du2/dx=0

solve in the interval of 0 to 1 for x and 0 to 20 for tdu1/dt=(1/pec)*d2u1/dx2-


du1/dx-da*(1+u1)*exp(y*u2/(1+u2))
du2/dt=(1/pet)*d2uWQKJH QLKJQNKL LKJ LKJ LK JL KJ
LKJK LJ LK J LKJ L 2/dx2-du2/dx+c*da*(1+u1)*exp(y*u2/(1+u2))

pec=pet=7, y=10, c=2.5 da=0.1 r=0.5


initial condition: u1=0, u2=0
boundary conditions at x=0, du1/dx=-pec*(r*ur(1)-r*ul(1)) and du2/dx=-pet*(r*ur(1)-
r*ul(1))
BC at x=1, du2/dx=0 and du2/dx=0

solve in the interval of 0 to 1 for x and 0 to 20 for tdu1/dt=(1/pec)*d2u1/dx2-


du1/dx-da*(1+u1)*exp(y*u2/(1+u2))
du2/dt=(1/pet)*d2u2/dx2-du2/dx+c*da*(1+u1)*exp(y*u2/(1+u2))

pec=pet=7, y=10, c=2.5 da=0.1 r=0.5


initial condition: u1=0, u2=0
boundary conditions at x=0, du1/dx=-pec*(r*ur(1)-r*ul(1)) and du2/dx=-pet*(r*ur(1)-
r*ul(1))
BC at x=1, du2/dx=0 and du2/dx=0

solve in the interval of 0 to 1 for x and 0 to 20 for tdu1/dt=(1/pec)*d2u1/dx2-


du1/dx-da*(1+u1)*exp(y*u2/(1+u2))
du2/dt=(1/pet)*d2u2/dx2-du2/dx+c*da*(1+u1)*exp(y*u2/(1+u2))

pec=pet=7, y=10, c=2.5 da=0.1 r=0.5


initial condition: u1=0, u2=0
boundary conditions at x=0, du1/dx=-pec*(r*ur(1)-r*ul(1)) and du2/dx=-pet*(r*ur(1)-
r*ul(1))
BC at x=1, du2/dx=0 and du2/dx=0

solve in the interval of 0 to 1 for x and 0 to 20 for tdu1/dt=(1/pec)*d2u1/dx2-


du1/dx-da*(1+u1)*exp(y*u2/(1+u2))
du2/dt=(1/pet)*d2u2/dx2-du2/dx+c*da*(1+u1)*exp(y*u2/(1+u2))

pec=pet=7, y=10, c=2.5 da=0.1 r=0.5


initial condition: u1=0, u2=0
boundary conditions at x=0, du1/dx=-pec*(r*ur(1)-r*ul(1)) and du2/dx=-pet*(r*ur(1)-
r*ul(1))
BC at x=1, du2/dx=0 and du2/dx=0
K 'WS 'ILJ [87 [09 I[8 U- 8 U- 8U -98 U - 98 [8 U -98 U [98 P

solve in the interval of 0 to 1 for x and 0 to 20 for tdu1/dt=(1/pec)*d2u1/dx2-


du1/dx-da*(1+u1)*exp(y*u2/(1+u2))
du2/dt=(1/pet)*d2u2/dx2-du2/dx+c*da*(1+u1)*exp(y*u2/(1+u2))

pec=pet=7, y=10, c=2.5 da=0.1 r=0.5


initial condition: u1=0, u2=0
boundary conditions at x=0, du1/dx=-pec*(r*ur(1)-r*ul(1)) and du2/dx=-pet*(r*ur(1)-
r*ul(1))
BC at x=1, du2/dx=0 and du2/dx=0

solve in the interval of 0 to 1 for x and 0 to 20 for tdu1/dt=(1/pec)*d2u1/dx2-


du1/dx-da*(1+u1)*exp(y*u2/(1+u2))
du2/dt=(1/pet)*d2uWQKJH QLKJQNKL LKJ LKJ LK JL KJ
LKJK LJ LK J LKJ L 2/dx2-du2/dx+c*da*(1+u1)*exp(y*u2/(1+u2))

pec=pet=7, y=10, c=2.5 da=0.1 r=0.5


initial condition: u1=0, u2=0
boundary conditions at x=0, du1/dx=-pec*(r*ur(1)-r*ul(1)) and du2/dx=-pet*(r*ur(1)-
r*ul(1))
BC at x=1, du2/dx=0 and du2/dx=0

solve in the interval of 0 to 1 for x and 0 to 20 for tdu1/dt=(1/pec)*d2u1/dx2-


du1/dx-da*(1+u1)*exp(y*u2/(1+u2))
du2/dt=(1/pet)*d2u2/dx2-du2/dx+c*da*(1+u1)*exp(y*u2/(1+u2))

pec=pet=7, y=10, c=2.5 da=0.1 r=0.5


initial condition: u1=0, u2=0
boundary conditions at x=0, du1/dx=-pec*(r*ur(1)-r*ul(1)) and du2/dx=-pet*(r*ur(1)-
r*ul(1))
BC at x=1, du2/dx=0 and du2/dx=0

solve in the interval of 0 to 1 for x and 0 to 20 for tdu1/dt=(1/pec)*d2u1/dx2-


du1/dx-da*(1+u1)*exp(y*u2/(1+u2))
du2/dt=(1/pet)*d2u2/dx2-du2/dx+c*da*(1+u1)*exp(y*u2/(1+u2))

pec=pet=7, y=10, c=2.5 da=0.1 r=0.5


initial condition: u1=0, u2=0
boundary conditions at x=0, du1/dx=-pec*(r*ur(1)-r*ul(1)) and du2/dx=-pet*(r*ur(1)-
r*ul(1))
BC at x=1, du2/dx=0 and du2/dx=0

solve in the interval of 0 to 1 for x and 0 to 20 for tdu1/dt=(1/pec)*d2u1/dx2-


du1/dx-da*(1+u1)*exp(y*u2/(1+u2))
du2/dt=(1/pet)*d2u2/dx2-du2/dx+c*da*(1+u1)*exp(y*u2/(1+u2))

pec=pet=7, y=10, c=2.5 da=0.1 r=0.5


initial condition: u1=0, u2=0
boundary conditions at x=0, du1/dx=-pec*(r*ur(1)-r*ul(1)) and du2/dx=-pet*(r*ur(1)-
r*ul(1))
BC at x=1, du2/dx=0 and du2/dx=0
K 'WS 'ILJ [87 [09 I[8 U- 8 U- 8U -98 U - 98 [8 U -98 U [98 P

solve in the interval of 0 to 1 for x and 0 to 20 for tdu1/dt=(1/pec)*d2u1/dx2-


du1/dx-da*(1+u1)*exp(y*u2/(1+u2))
du2/dt=(1/pet)*d2u2/dx2-du2/dx+c*da*(1+u1)*exp(y*u2/(1+u2))
pec=pet=7, y=10, c=2.5 da=0.1 r=0.5
initial condition: u1=0, u2=0
boundary conditions at x=0, du1/dx=-pec*(r*ur(1)-r*ul(1)) and du2/dx=-pet*(r*ur(1)-
r*ul(1))
BC at x=1, du2/dx=0 and du2/dx=0

solve in the interval of 0 to 1 for x and 0 to 20 for tdu1/dt=(1/pec)*d2u1/dx2-


du1/dx-da*(1+u1)*exp(y*u2/(1+u2))
du2/dt=(1/pet)*d2uWQKJH QLKJQNKL LKJ LKJ LK JL KJ
LKJK LJ LK J LKJ L 2/dx2-du2/dx+c*da*(1+u1)*exp(y*u2/(1+u2))

pec=pet=7, y=10, c=2.5 da=0.1 r=0.5


initial condition: u1=0, u2=0
boundary conditions at x=0, du1/dx=-pec*(r*ur(1)-r*ul(1)) and du2/dx=-pet*(r*ur(1)-
r*ul(1))
BC at x=1, du2/dx=0 and du2/dx=0

solve in the interval of 0 to 1 for x and 0 to 20 for tdu1/dt=(1/pec)*d2u1/dx2-


du1/dx-da*(1+u1)*exp(y*u2/(1+u2))
du2/dt=(1/pet)*d2u2/dx2-du2/dx+c*da*(1+u1)*exp(y*u2/(1+u2))

pec=pet=7, y=10, c=2.5 da=0.1 r=0.5


initial condition: u1=0, u2=0
boundary conditions at x=0, du1/dx=-pec*(r*ur(1)-r*ul(1)) and du2/dx=-pet*(r*ur(1)-
r*ul(1))
BC at x=1, du2/dx=0 and du2/dx=0

solve in the interval of 0 to 1 for x and 0 to 20 for tdu1/dt=(1/pec)*d2u1/dx2-


du1/dx-da*(1+u1)*exp(y*u2/(1+u2))
du2/dt=(1/pet)*d2u2/dx2-du2/dx+c*da*(1+u1)*exp(y*u2/(1+u2))

pec=pet=7, y=10, c=2.5 da=0.1 r=0.5


initial condition: u1=0, u2=0
boundary conditions at x=0, du1/dx=-pec*(r*ur(1)-r*ul(1)) and du2/dx=-pet*(r*ur(1)-
r*ul(1))
BC at x=1, du2/dx=0 and du2/dx=0

solve in the interval of 0 to 1 for x and 0 to 20 for tdu1/dt=(1/pec)*d2u1/dx2-


du1/dx-da*(1+u1)*exp(y*u2/(1+u2))
du2/dt=(1/pet)*d2u2/dx2-du2/dx+c*da*(1+u1)*exp(y*u2/(1+u2))

pec=pet=7, y=10, c=2.5 da=0.1 r=0.5


initial condition: u1=0, u2=0
boundary conditions at x=0, du1/dx=-pec*(r*ur(1)-r*ul(1)) and du2/dx=-pet*(r*ur(1)-
r*ul(1))
BC at x=1, du2/dx=0 and du2/dx=0
K 'WS 'ILJ [87 [09 I[8 U- 8 U- 8U -98 U - 98 [8 U -98 U [98 P

solve in the interval of 0 to 1 for x and 0 to 20 for tdu1/dt=(1/pec)*d2u1/dx2-


du1/dx-da*(1+u1)*exp(y*u2/(1+u2))
du2/dt=(1/pet)*d2u2/dx2-du2/dx+c*da*(1+u1)*exp(y*u2/(1+u2))

pec=pet=7, y=10, c=2.5 da=0.1 r=0.5


initial condition: u1=0, u2=0
boundary conditions at x=0, du1/dx=-pec*(r*ur(1)-r*ul(1)) and du2/dx=-pet*(r*ur(1)-
r*ul(1))
BC at x=1, du2/dx=0 and du2/dx=0

solve in the interval of 0 to 1 for x and 0 to 20 for tdu1/dt=(1/pec)*d2u1/dx2-


du1/dx-da*(1+u1)*exp(y*u2/(1+u2))
du2/dt=(1/pet)*d2uWQKJH QLKJQNKL LKJ LKJ LK JL KJ
LKJK LJ LK J LKJ L 2/dx2-du2/dx+c*da*(1+u1)*exp(y*u2/(1+u2))

pec=pet=7, y=10, c=2.5 da=0.1 r=0.5


initial condition: u1=0, u2=0
boundary conditions at x=0, du1/dx=-pec*(r*ur(1)-r*ul(1)) and du2/dx=-pet*(r*ur(1)-
r*ul(1))
BC at x=1, du2/dx=0 and du2/dx=0

solve in the interval of 0 to 1 for x and 0 to 20 for tdu1/dt=(1/pec)*d2u1/dx2-


du1/dx-da*(1+u1)*exp(y*u2/(1+u2))
du2/dt=(1/pet)*d2u2/dx2-du2/dx+c*da*(1+u1)*exp(y*u2/(1+u2))

pec=pet=7, y=10, c=2.5 da=0.1 r=0.5


initial condition: u1=0, u2=0
boundary conditions at x=0, du1/dx=-pec*(r*ur(1)-r*ul(1)) and du2/dx=-pet*(r*ur(1)-
r*ul(1))
BC at x=1, du2/dx=0 and du2/dx=0

solve in the interval of 0 to 1 for x and 0 to 20 for tdu1/dt=(1/pec)*d2u1/dx2-


du1/dx-da*(1+u1)*exp(y*u2/(1+u2))
du2/dt=(1/pet)*d2u2/dx2-du2/dx+c*da*(1+u1)*exp(y*u2/(1+u2))

pec=pet=7, y=10, c=2.5 da=0.1 r=0.5


initial condition: u1=0, u2=0
boundary conditions at x=0, du1/dx=-pec*(r*ur(1)-r*ul(1)) and du2/dx=-pet*(r*ur(1)-
r*ul(1))
BC at x=1, du2/dx=0 and du2/dx=0

solve in the interval of 0 to 1 for x and 0 to 20 for t

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