KWAME NKRUMAH UNIVERSITY OF SCIENCE AND TECHNOLOGY.
COLLEGE OF ENGINEERING.
            DEPARTMENT OF CHEMICAL ENGINEERING.
           PCE 353 - PETROCHEMICAL ENGINEERING LAB 2
              PERMEABILITY/FLUIDIZATION STUDIES.
GROUP 5A
NAMES                      INDEX NUMBER      SIGNATURE
MACCARTHY COMFORT SIKA     8369119           ….…………
AMOANYI JOYCELIN AKUWA      8365619          …………….
AZU AZARIAH JONATHAN        8367319          ……............
MENSAH COLLINS             8369519           ……………..
KPAKPO JOCHEBED NAA A.     8368619         ………..........
                               1
                                      Contents
AIMS AND OBJECTIVES .............................................................................................. 3
INTRODUCTION ............................................................................................................ 4
APPARATUS/CHEMICALS ........................................................................................... 8
PROCEDURE ................................................................................................................... 9
TABLE OF RESULTS ................................................................................................... 10
PRECAUTIONS ............................................................................................................. 13
ERROR ANALYSIS ....................................................................................................... 14
DISCUSSIONS ............................................................................................................... 15
REFERENCES................................................................................................................ 17
POST LAB ...................................................................................................................... 18
                                                                2
                            AIMS AND OBJECTIVES
   To determine the permeability coefficient of a given sample
   To determine the void ratio of a given sample
                                          3
                                    INTRODUCTION
The permeability of soil describes how fluids (water, air or other liquid) are able to
move through the soil. It describes the property of the soil to transmit water and air. It
depends on the physical and chemical properties of the soil, notably grain size
distribution (the range of particle sizes present), pore space, pore size, solid type, soil
history and the continuity of the spaces. The degree of permeability is characterized by
the coefficient of permeability and often referred to as hydraulic conductivity by
hydrologists and environmental scientists. They define it as the ability of a soil to
conduct water. Hydraulic conductivity, or K, is measured in cm/hour – that is, how far
water will move through soil in a given time.
Hydraulic conductivity is a complex feature of soils, varying with location, soil type,
depth, soil moisture content and direction of flow; for example, horizontal conductivity
is often greater than vertical on account of soil horizons. There are two main types of
hydraulic conductivity namely;
1.Surface infiltration rate. This is the rate at which a soil surface will take in irrigation
or rainfall. It is influenced by plant cover, the initial moisture content, and the texture
and structure of the soil. Surface compaction, slaking, dispersion and crusting impede
surface infiltration.
2. Saturated hydraulic conductivity (Ksat). This is the rate at which a soil that is
already saturated with water will conduct water away from the source. It is necessary
for predicting such things as whether a purchased soil will have good drainage, whether
a dam will hold water, how quickly a subsoil will allow ponded or perched water to
drain away, and whether a landfill liner will leak contaminants into the surrounding
ground water.’
                                             4
The coefficient of permeability, k is a product of Darcy’s law. When the soils are
saturated (soils that contain only water in their pore spaces) and homogenous or when
they are unsaturated (soils that contain only water and air in their pore spaces), the
Darcy or Buckingham-Darcy equations can be solved to determine the rate of water
flow and the distribution of water potentials in a one-dimensional soil column under
steady state conditions.
The Darcy’s equation is often used to describe water movement in saturated soils. For
one- dimensional water flow, it can be written as:
                                                  ∆𝑃
                                       𝑞 = −𝐾
                                                  ∆𝐻
Where q is the flux density of water passing through the soil, K is the saturated
hydraulic conductivity, P is the total energy and H is the height.
For unsaturated soils, this equation takes the modified form developed by Buckingham
for this one:
                                                    ∆𝑃
                                     𝑞 = −𝐾(𝜗)
                                                    ∆𝐻
                                                    ∆𝑃
                                     𝑞 = −𝐾(ℎ)
                                                    ∆𝐻
Where K (𝜗) or K(h) is the unsaturated hydraulic conductivity function, (𝜗) is the
volumetric water content and h is a matric potential. The total potential is the sum of the
matric potential and the gravitational potential. For uniform saturated soils, we can
write this equation as
                                                 𝑃2 − 𝑃1
                                     𝑞 = −𝐾
                                                    𝐿
Where q can also be expressed in terms of volumetric flow and cross-sectional area as ;
                                         𝑄
                                    𝑞 = 𝐴, cm/s
                                             5
Where P1 and P2 are the total potentials at the inlet and outlet of the soil system
respectively. The difference in total potential divided by the length of the system is the
driving force causing water to flow. This equation is applicable to layered or
unsaturated soils if the hydraulic conductivity, K, in the equation is regarded as the
equivalent conductivity of the entire soil system.
When the soils are saturated and homogenous, the flux density can be easily obtained if
the conductivity of the soil is known because it is more difficult when the soil is not
homogenous or when it’s unsaturated. The soil is assumed to be either homogenous or
composed of two layers. The table below shows the various soil types, their degree of
permeability and their coefficient of permeability.
 Soil                           Coeff. Of Perm.,           k, Degree of Permeability
                                cm/sec
 Gravel                         > 0.1                          Very high
 Sandy Gravel, clean sand, fine 0.1> k > 10 -3                 High to medium
 sand
 Sand, dirty sand, muddy sand   10 -3 >k>10-5                  Low
 Silt, muddy clay               10-5 >k>10-7                   Very low
 Clay                           <10-7                          Virtually impermeable
The coefficient for soil escape can be calculated in a variety of ways, including in-situ
(field) approaches and laboratory procedures. This soil attribute is often assessed in the
lab using two common methods. Falling head and continuous head permeability are
these two tests. The soil being analyzed will determine this. Constant head is employed
for soils with high permeability.
The instrument used for this experiment is the EDIBON Permeability/Fluidization
Studies Unit, "PEFP. This unit allows to observe the behavior of liquid fluidization in a
granular bed.
                                            6
The main element is a permeability meter. It is a transparent cylinder that supports the
soil sample to be studied. Water will flow downward to study permeability or upward to
study fluidization. The cylinder has four pressure taps: one at the top and one at the
bottom to measure the pressure drop through the bed and two along the cylinder to
measure the total pressure at those specific points of the sample. Water is supplied to
the permeability meter by a constant pressure supply device. It is a transparent tank with
an overflow located above the permeability meter. The height of this tank can be
changed, thus modifying the pressure. Two metal filtering discs are placed between the
floor and the porous element at the top and bottom of the cylinder. These discs act as
filters and distribute the flow over the cross-sectional area of the sample. The unit has
two manometers: a tube manometer used to measure low pressures and a Bourdon
manometer used to measure high pressures.
EDIBON Permeability/Fluidization Studies Unit, "PEFP.
                                            7
                            APPARATUS/CHEMICALS
1.   PEFP unit
2.   Mass Balance
3.   Source of water(tap)
4.   Soil sample
                                     8
                                    PROCEDURE
The mass of sand required for the experiment was measured. Dry sand was Placed in the
permeameter up to the desired height in a loose way. the apparatus was not jarred or
bumped. Course grained soils are densified rather easily with vibrations. The height of
sand in the cylinder and cross-sectional area of the cylinder were noted. The
permeameter was covered, screwed down tightly and placed in the clamps. The upper
tank was filled up to the overflow. V2 was Opened slowly until water was seen at the
bottom inlet. V2 Valve was closed. The level of water level L1 was recorded. The purge
valve located at the top of the cylinder was opened. V2 valve was Opened until water
came out of the purge valve. The new level of water L2 was recorded. The difference of
height was Measured by selecting the water manometer with the corresponding valves.
The valves were opened and closed to configure the unit as described in the table below:
                     Valve         Bottom inlet
                     V1            Closed
                     V2            Open
                     V3            Open
                     V4            Closed
                                           9
                                                      TABLE OF RESULTS
Q(L/min)                                    H1(cm)                 H2(cm)                    ∆𝐻 =H1-H2(cm)
0.25                                        28.0                   20.8                      7.2
0.50                                        29.2                   20.8                      8.4
0.75                                        29.2                   20.8                      8.4
1.00                                        28.6                   21.0                      7.6
1.25                                        28.2                   21.0                      7.2
1.50                                        27.4                   20.8                      6.6
1.75                                        27.2                   20.6                      6.6
2.00                                        27.0                   20.6                      6.4
                                          A GRAPH OF PRESSURE AGANIST FLOWRATE
                     9                      8.4      8.4
                                                            7.6
                     8              7.2                                7.2
                                                                              6.6      6.6   6.4
                     7
  Pressure Head/mm
                     0
                         0                  0.5             1                 1.5             2         2.5
                                                           Flowrate/ L per min
Determining The Mass Of Saturated Sand
𝑀𝑎𝑠𝑠 𝑜𝑓 𝑠𝑎𝑡𝑢𝑟𝑎𝑡𝑒𝑑 𝑠𝑎𝑛𝑑 = 𝑚𝑎𝑠𝑠 𝑜𝑓 𝑑𝑟𝑦 𝑠𝑎𝑛𝑑 + 𝑚𝑎𝑠𝑠 𝑜𝑓 𝑤𝑎𝑡𝑒𝑟 𝑓𝑜𝑟 𝑠𝑎𝑡𝑢𝑟𝑎𝑡𝑖𝑜𝑛
𝑀𝑎𝑠𝑠 𝑜𝑓 𝑤𝑎𝑡𝑒𝑟 = 𝐷𝑒𝑛𝑠𝑖𝑡𝑦 × 𝑣𝑜𝑢𝑚𝑒 (𝜌𝑉)
                                                                             𝑑2
𝐼𝑛𝑖𝑡𝑖𝑎𝑙 𝑉𝑜𝑙𝑢𝑚𝑒 𝑜𝑓 𝑤𝑎𝑡𝑒𝑟 𝑖𝑛 𝑐𝑦𝑙𝑖𝑛𝑑𝑒𝑟 (𝑉) = 𝜋 ×                                4
                                                                                  ×ℎ
                             1442
𝑉 = 𝜋×(                             ) × 150𝑚𝑚 = 2442902.447𝑚𝑚3
                              4
                                                                  10
                                            𝑑2
𝐹𝑖𝑛𝑎𝑙 𝑉𝑜𝑙𝑢𝑚𝑒 𝑜𝑓 𝑤𝑎𝑡𝑒𝑟 𝑖𝑛 𝑐𝑦𝑙𝑖𝑛𝑑𝑒𝑟 (𝑉) = 𝜋 ×    ×ℎ
                                            4
          1442
𝑉 = 𝜋×(        ) × 125𝑚𝑚 = 2035752.04𝑚𝑚3
           4
Volume of water for saturation, Vs = (Initial – Final )volume of water
Vs =2442902.45mm3 - 2035752.04mm3
Density of water = 0.001 g/mm
Mass of water for saturation = Density of dry sand × Volume of water
                                 = 0.001g/mm3 × 407150.4mm3
                                 = 407.15g
𝑀𝑎𝑠𝑠 𝑜𝑓 𝑠𝑎𝑡𝑢𝑟𝑎𝑡𝑒𝑑 𝑠𝑎𝑛𝑑 = (1147.66 + 407.15)𝑔 = 1554.81𝑔
Determining the densities of dry and saturated sand.
𝜌             𝑚𝑎𝑠𝑠𝑑𝑟𝑦 𝑠𝑎𝑛𝑑    1147.66𝑔
 𝑑𝑟𝑦 𝑠𝑎𝑛𝑑 =                =            = 0.0004698𝑔.𝑚𝑚−3
                𝑣𝑜𝑙𝑢𝑚𝑒       2442902.45
𝜌                   𝑚𝑎𝑠𝑠𝑠𝑎𝑡𝑢𝑟𝑎𝑡𝑒𝑑 𝑠𝑎𝑛𝑑    1554.81𝑔
 𝑠𝑎𝑡𝑢𝑟𝑎𝑡𝑒𝑑 𝑠𝑎𝑛𝑑 =                      =           = 0.00076375𝑔𝑚𝑚−3
                         𝑉𝑜𝑙𝑢𝑚𝑒          2035752.04
Void Ratio Determination.
        = 𝜌𝑠𝑎𝑛𝑑 − 𝜌𝑑𝑟𝑦 𝑠𝑎𝑛𝑑
       = (0.00076375– 0.0004698)𝑔𝑚𝑚−3
       = 0.00029395𝑔𝑚𝑚−3
Dividing by the density of the dry sand we have,
                   0.00029395𝑔𝑚𝑚−3
𝑉𝑜𝑖𝑑 𝑅𝑎𝑡𝑖𝑜 =                        = 0.626
                    0.0004698𝑔𝑚𝑚 −3
Determination of k (permeability coefficient of the sample)
According to Darcy’s equation,
                                               11
              ∆ℎ
𝑄 = 𝑘𝐴 (         )
               𝑙
Where k = permeability coefficient of the sample
L = height of cylinder filled with sand = 480.0mm
                                 𝑑2
Volume of cylinder = 𝜋 ×                ×ℎ
                                 4
                                 462
                          =𝜋 ×           × 480𝑚𝑚
                                    4
                          =797713.2066 mm3
A = cross-sectional area of the cylinder filled with sand
     𝑣𝑜𝑙𝑢𝑚𝑒 𝑜𝑓 𝑐𝑦𝑙𝑖𝑛𝑑𝑒𝑟 𝑓𝑖𝑙𝑙𝑒𝑑 𝑤𝑖𝑡ℎ 𝑠𝑎𝑛𝑑         797713.2066𝑚𝑚3
𝐴=                                           =
     ℎ𝑒𝑖𝑔ℎ𝑡 𝑜𝑓 𝑐𝑦𝑙𝑖𝑛𝑑𝑒𝑟 𝑓𝑖𝑙𝑙𝑒𝑑 𝑤𝑖𝑡ℎ 𝑠𝑎𝑛𝑑               480𝑚𝑚
                                         𝐴 = 1661.9025𝑚𝑚2
From the graph (the line of best fit equation), the slope is 4.8
          𝐾𝐴
Slope =   𝐿
Making k the subject,
     𝐿×𝑆𝑙𝑜𝑝𝑒         480𝑚𝑚×4.9048                  𝑚𝑚
𝑘=              =                       = 1.3863        = 0.01386𝑐𝑚/𝑠
          𝐴          1661.9025𝑚𝑚2                  𝑠
From the standard Table the calculated K value lies between 1x10-1 and 1x10-3
Therefore, the sample has a high to medium degree of permeability.
                                                   12
                                   PRECAUTIONS
   There should be no volume change in the soil sample used during the test.
   There should be no compressible air present in the voids of soil i.e. soil should be
    completely saturated.
   The flow should be laminar and in a steady state condition.
                                           13
                                 ERROR ANALYSIS
   The mass of the dry sand was not accurately measured and this could affect the
    result.
   The presence of air in the permeameter affected the permeability of the dry sand.
                                           14
                                    DISCUSSIONS
In this experiment, the Edibon permeability unit was used to observe the behavior of
liquid fluidization in a granular bed and to determine the permeability of some soil
materials. Here, sand was used in the experimentation and water used as the fluid for
fluidization. The permeability of the sample was determined using Darcy’s formula:
Q=kA(∆h/L)
Rearranging the equation above gave;
k=(QL/∆hA)
                                                                        𝐾𝐴
by plotting the change in pressure head against flow rate. The slope,        was used to
                                                                         𝐿
identify the permeability coefficient, k, which gave a value of 0.01386cm/s from the
graph. This shows that the sample has a high to medium degree of permeability and
could be sandy gravel, clean sand or fine sand. The volume of water saturation was
found by subtracting the final volume of water from the initial. This was found to be
407150mm3. The density of water is known to be 0.001g/mm3. Hence, the mass of
water for saturation was found to be 407.15g. this gave the mass of saturated sand (that
is, the mass of dry sand + mass of water for saturation) to be 1554.81g. the densities of
dry sand and saturated sand were found to be 0.0004698 gmm-3 and 0.00076375 gmm-3
respectively. Void ratio can be defined as the ratio of the volume of voids to the volume
of the soil. The volume of voids was 0.00029395 gmm-3. Dividing by the density of the
sand, the void ratio was 0.626. Generally, the higher the void ratio, the higher the
coefficient of permeability. Thus, the higher the permeability.
Generally, four laboratory techniques can be employed in determining the permeability
coefficient. These are:
a.   Constant-head test.
b.   Falling-head test.
c.   Indirect determination form consolidation test.
                                           15
d.   Indirect determination by horizontal capillary test.
Of these, the Constant-head test and the falling-head test are widely used to determine
the permeability coefficient of the soil sample and is briefly described as follows;
Constant-head test: For granular materials that are more permeable, the constant head
test is used. The test sample of soil is placed inside a cylindrical mold and by regulating
the supply, the head loss, h, of water passing through the soil is measured and recorded.
The bottom in flow water observed in the cylinder containing the soil sample is
measured and recorded as R1. The experiment is carried out up to the point where the
purge valve releases water, then the new water level in the cylinder is measured as R2.
From Darcy’s law, the total amount of flow can be calculated as;
Q=kA(∆h/L) ……. A,
Where Q= flux density of water passing through the soil,
         k= the saturated hydraulic conductivity
         A= cross sectional area
         ∆h= head loss
         L= length of the system
Rearranging the equation above gives;
k=(QL/∆hA) ………. B
Once all the quantities on the right-hand side of equation have been determined, the
coefficient of permeability of the soil can be calculated.
Falling-head test: This test is performed in a manner similar to that of the constant-head
test. The major difference is that the falling-head test is more suitable for fine-grained
soils.
                                            16
                                     REFERENCES
A.Ivan Johnson, David S. M (2014) Permeability and capillarity of soils- 6th edition,
Published by Wiley publications, USA,page 507-582.
ASTM D6391, Standard Test Method for Field Measurement of Hydraulic Conductivity
Using Borehole Infiltration, 2011.
BS 5930 Code of Practice for Site Investigations British Standards Institution (1999)
191 pages
Hart, J. Roger, Furia T( 1964) Manual of soil laboratory testing- 3rd edition, Published
by Dr. Henry and sons, page 333-335.
Lakshmi R, Havard L., Holler F(2009) Laboratory Measurement of soil permeability-
2nd edition, page 378-386.
                                          17
                                       POST LAB
1.   Permeability coefficient allows us to estimate the type of soil sample we are
     working with.
2.   The permeability of a soil is a measure indicating the capacity of the soil to allow
     fluids to pass through it. It is often represented by the permeability coefficient (k)
     through the Darcy’s equation
        Knowledge in permeability is applicable in the following areas:
        Estimation of quantity of underground seepage water under various hydraulic
         conditions.
        Quantification of water during pumping for underground construction
        Stability analysis of slopes, earth dams, and earth retaining structures
        Design of landfill liner
        Permeability helps in the purification of water.
        Permeability helps determine the flow characteristics of hydrocarbons in oil
         and gas reservoirs.
3.   Porosity is taken to be the ratio of the volume of empty space (or pores) in a rock to
     its total volume, and it is often expressed in terms of a fraction or a percentage and
     as such has no unit whereas permeability is a measure of the ability of a porous
     media to transmit fluids and has unit of area (m2 in the SI system).
4.   a. Particle size
     b. Void ratio
     c. Mass of soil sample.
                                            18
d. Structural arrangement of soil particles.
e. Properties of pore fluid
f. Degree of saturation
g. Stratification of soil
   Particle size: The coefficient of permeability of a soil is directly proportional to
    the square of the particle size. If the soil is coarse grained, permeability is more
    and if it is fine grained, permeability is low. Particle size can be gauged
    by performing sieve analysis.
                                                                                𝑒3
   Void ratio: The coefficient of permeability varies with the void ratio as 1+𝑒. for
    a given soil, the greater the void ratio the higher the value of the coefficient of
    permeability. Here, e is the void ratio. But it is not applicable to all types of
    soils. For example, clay has a higher void ratio than any other types of soil but
    permeability of clays is very low. This is due to the flow path through voids, in
    case of clays, it is extremely small such that water cannot permit through this
    path easily.
   Structural arrangement of soil particles: permeability is inversely proportional
    to specific surface. As angular soil has more specific surface area compared to
    round soil therefore, the soil with angular particles is less permeable than soil
    of rounded particles. For fine grained soils if the soil particles are arranged in
    flocculated structure, then its permeability will be more when compared to that
    if the particles are arranged in the dispersed structure as we know flocculated
    structure has more voids than in the dispersed structure. e.g.
   Properties of pore fluid: Pore fluids are fluids that occupy pore spaces in a soil
    or rock. Permeability is directly proportional to the unit weight of pore fluid
    and inversely proportional to viscosity of pore fluid
                                        19
          Degree of saturation: If the soil is not fully saturated, it contains air pockets.
           The permeability is reduced due to the presence of air which causes a blockage
           to the passage of water. Consequently, the permeability of a partially saturated
           soil is considerably smaller than that of fully saturated soil. In fact, Darcy's
           Law is not strictly applicable to such soils.
          Stratification of soil: Stratified soils are those soils which are formed by layer
           upon layer of the earth or dust deposited on each other. If the flow is parallel to
           the layers of the stratification, the permeability is max. while the flow in
           perpendicular direction occurs with min. permeability.
5.    Packer Method:
A packer is an expandable cylindrical rubber sleeve. Packers are used as a means of
sealing of a section borehole. Two types of packer methods are used.
They are:
     i.      Single Packer Method :
In single packer method the hole is drilled to the required depth. The packer is fixed at a
desired level above the bottom of hole and the water pumped into the section below the
packer. The constant rate of flow, q that is attained under an applied head, H is found.
     ii.     Double Packer Method:
In the double packer method, the hole is drilled to the final depth and cleaned. Two
packers are fixed at a distance apart equal to 5 times the diameter of borehole. Both
packers are then expanded and water pumped into the section between the two packers,
the constant rate of flow, q that is attained under an applied head, H is found. The
coefficient of permeability, k is computed using the following equations –
                                               20
                                       𝑞       𝐿
                                𝑘=        𝑠𝑖𝑛−1 𝑓𝑜𝑟 𝐿 < 10𝑟
                                     2𝜋𝐿𝐻      2𝑟
                                       𝑞      𝐿
                                𝑘=        𝑙𝑜𝑔𝑒 𝑓𝑜𝑟 𝐿 ≥ 10𝑟
                                     2𝜋𝐿𝐻     𝑟
Where, r = radius of borehole
H = differential head for maintaining a constant rate of flow in test section
q = constant rate of flow into the test section
L = length of the test section the unit
6.   3.6 × 10−3 = 0.2 𝑡ℎ𝑒𝑛 0.5 = 𝑥
     𝑥 = 9 × 10−3 𝑐𝑚/𝑠.
     The soil sample is likely to be sandy gravel, clean sand or fine sand.
                                             21