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Y11 Mock Mark Scheme 2023

This document provides a mark scheme for a mock exam on programming. It lists several questions that could be asked and provides example answers for some questions. It also lists techniques and data structures that may be required to solve a scenario-based programming problem involving monsters with different attributes. An example 15-mark answer in Python is given that iterates through a list of monsters, calculates their attributes, and identifies the strongest monsters for attack, defense, and health.

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61 views8 pages

Y11 Mock Mark Scheme 2023

This document provides a mark scheme for a mock exam on programming. It lists several questions that could be asked and provides example answers for some questions. It also lists techniques and data structures that may be required to solve a scenario-based programming problem involving monsters with different attributes. An example 15-mark answer in Python is given that iterates through a list of monsters, calculates their attributes, and identifies the strongest monsters for attack, defense, and health.

Uploaded by

BigBoi
Copyright
© © All Rights Reserved
We take content rights seriously. If you suspect this is your content, claim it here.
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Download as DOCX, PDF, TXT or read online on Scribd
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Year 11 Mark Scheme Paper 2

for Mock Examinations 2023

1 Averaging numbers
Oct/Nov 2017 0478/22

2 Selection type
Oct/Nov 2017 0478/22

3 Inefficient code
0478/22/M/J/16
4 2d Arrays question

Max 7
9608/21/M/J/18

This question has been adapted from an AS level question, so there can be more flexibility in
terms of pseudocode. Marking notes: Use Next instead of ENDFOR & unlikely to be asked to
declare variables (So mark removed)
5
0478/22/O/N/20 [
6

9608/41 May/June 2018


8 Logic Gate Question
0478/12/F/M/20

9 Scenario based question.

Read the whole answer, award a mark from both of the following tables and add up the total.
Marks are available for:
• AO2 (maximum 9 marks) • AO3 (maximum 6 marks).

The techniques and the data structures required are listed below. The requirements may be
met using a suitable built-in function from the programming language used (e.g. Python,
VB.NET or Java).

Techniques required:

R1 Calculate health for each card (iteration and totalling)


R2 Outputs for each card (output with appropriate messages).
R3 Description (selection & iteration)
R4 Best attribute (selection)
R5 Calculate, store and output the cards with the  strongest attack, defence and health.
(iteration, counting and output with appropriate messages).
Data structures required:
The names underlined must be used as provided in the scenario.

Arrays or lists Monsters & Best_monster (Highest attack, defence & health
may be seen) 

Variables     Maxattack,maxdefence and maxhealth could be an array or list

Constants   Total_Value is 70 could be stored as a constant

Example 15 mark answer in Python

Monsters = [["Aatxe","Basque","Spirit that takes the form of a


bull.",36,17],
["Abaasy","Yakuts","Demons with teeth of iron.",24,21],
["Abada","African","Small type of unicorn reported to live in the lands of
the African Congo.",20,29]]

# To enable storage of maximum attack, defence & health


MaxAttack = ["","","",0,0,0]
MaxDefence = ["","","",0,0,0]
MaxHealth = ["","","",0,0,0]

# Calculates and then adds health to the list


for i in range (len(Monsters)):
   health = 70 - (Monsters[i][3] + Monsters[i][4])
   Monsters[i].append(health)

#Printing out monster cards


for i in range(len(Monsters)):
   print("Name:",Monsters[i][0])
   print("Origin:",Monsters[i][1])

   # Splits lines


   if len(Monsters[i][2])>30:
       print(Monsters[i][2][0:30])
       print(Monsters[i][2][30::])
   else: print(Monsters[i][2])

   print("Attack:",Monsters[i][3])
   print("Defence:",Monsters[i][4])
   print("Health:",Monsters[i][5])

   # Calculates best attribute and outputs it


   if Monsters[i][3] > Monsters[i][4] and Monsters[i][3] > Monsters[i][5]:
       print("Best Attribute is Attack")
   elif Monsters[i][4] > Monsters[i][3] and Monsters[i][4] > Monsters[i]
[5]:
       print("Best attribute is Defence")
   else: print("Best attribute is health")
   print("")

#Works out which is the strongest monster and adds to the relevant list
for current_monster in Monsters:
   if current_monster[3] > MaxAttack[3]:
       MaxAttack=current_monster
   if current_monster[4] > MaxDefence[4]:
       MaxDefence=current_monster
   if current_monster[5] > MaxHealth[5]:
       MaxHealth=current_monster

#Prints out strongest monster


print("Strongest Attack")
print(*MaxAttack,sep=',')
print("\nStrongest Defence")
print(*MaxDefence,sep=',')
print("\nBest Health")
print(*MaxHealth,sep=',')

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