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Unit 6 RK Jain

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184 views19 pages

Unit 6 RK Jain

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Basanti Das
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Chapter 9 fourier Series, Fourier Integrals and Fourier Transforms al Introduction sachapter7 (section 7.2.4), we have defined the orthogonal and orthonormal functions. For example, te tancions cos mx and sin mx are orthogonal over the interval [-1, zt]. The orthonormal set of jomtions corresponding t0 cos mx are given by (Example 7.7) _1_ cosx cos pn" ve ‘Animportant application discussed in section 7.2.4 was the series expansion of (suitable) functions intems of a complete set of orthogonal or orthonormal functions. The expansion of a continuous fission f(x), having continuous derivatives over the interval [-1, 1] in terms of Legendre poly- nomials was discussed in section 7.2.6. This series was called Fourier-Legendre series. The Fourier- Bessel series was discussed in section 7.4.2. A series expansion in terms of the trigonometric functions cosmeand sin mx is called a Fourier series. Many functions including some discontinuous periodic functions can be expanded in a Fourier series. Therefore, Fourier series solution method is a powerful tol in solving some ordinary and partial differential equations. cos mx 92 Fourier Series Let (490), 6) (2), (a). - .} be an orthogonal set of functions, orthogonal with respect 10 a weight nection W(x), on an interval a, b}. Let f (x) be a continuous function defined on the same interval (0.5, Then, f(x) can be expanded in an infinite series of the form (sce section 7.2.4) F(X) = codo(x) + erPils) + 2G20) #--- 9.1) The coefficients cj, i= 0, 1, 2, «are given by = (f Fo) WO8: cons| / oe(a)) IPs F= 0,1, 20--- a 2 Engineering Mathe * ; f wong? Cds where He corr of orthogonal finetions Bray ) Consider now, the set ie {i o(4¢) sn (2) | (2) + weight f . hich thogonat on the interval [= fF] wills respect 0 the weight Funetion WO) 1 yy Which are orthogonal on the interval [= functions have the following propertics : . q i vos (Fas =f sin( 4) Jai 1 " dx = 0, men, [fom (282) oo (SF) ) 0 at ees ams) dy = 0, for all mand 1 (96) Er t v mtx J, cos? (2) a= f, me aa = 2) where m and n are integers. Now, let f(x) be a periodie function of period 2/ defined on [= 1, 1], that is ((x + 21) = f(x) and assume that it can be expanded in an orthogonal series in terms of the trigonometric functions. We shall discuss later in this section, the conditions under which such an expansion is possible. Let the series be written as FI 7 [a os (4) +a, cvs (24) te | + [* sin (#) + by sin (4) + | +E [+ cos (4) +b, sin (*)} (08) ie coefficients ay, ay, a3, .. «bi, by... can be determined by using the orthogonal properties of the trigonometric functions gi i interval (=, ], we obtain EA O-4) t0 (9.7). Integrating Eq, (9.8) term by term on te t te if fordr=2 [deg Sq [' (nm. y Ei pe n+ Z| ay [, cos (Blars by j sin (SE) = Ido ot since cos (nzx/) and sin (axl) are orthogonal with Fespect to W(x) = 1, on [= 1, {J Therefor" 7 a i f S(x)dx, Now, multiply both si . i Len TW ett iS OF Ea, (08) by cog (mmx/I) and int tei" rn legrate term by term on the rourter Series, Fourier Imegrals and Fourier Transforms 9.3 ay f! max . : =a | cs| —Jdx+ Dla, cos ( M7 wee i 7 wat [Gn J S08 | TJ cos = y mmx by [cos an ( 22E f, (= ) sin (2 ax). je ontogonal properties given in Eqs. (9.4) to (9.7), we get g the wi ; f Feoyeos (Jax ata EF 7 an =4 j F(x) cos (M2) 4 set TJ dx. iging bot sides of Eq, (.8) by sin (mi) and integrating term by term on the interval ; 1) we obtain y = 1 {nom (™E)e= $f 130 SFE) te [om fan SFE) oo (SE) ex bp [sin 222) sin( ax 1 t T r tng he othogonal properties given in Eqs. (9.4) to (9.7), we get 1 j f(x) sin (AE ax = [Bp -1 1 Terefore, bn = + j f(x) sin (7 as. a1 ltcan be observed that the expressions for ay and aq, can be combined as a single expression. It is to obtin this simplicity of notation that ao/2 is used in Eq. (9.8). This does not mean that the value of can be obtained after evaluating a, and setting n = 0 in this expression. The orthogonal series for f (x) given in Eq. (9.8) is called the Fourcer series. The coefficients ao, 4g, are called the Fourier coefficients on (~ 1, 1]. The expressions for the coefficients 1 f fix)dx, (9.9) 1 a,=4 f F(x) 0s (=) dx, (9.10) ot 1 Da f fo sin( "ax (9.1) x “Called the Buler formulas. pli cod of the function is 27, that is f (x) is defined on (-7, 7]. then the Euler formulas are led as net "pads ©.) wa), ; 1" f(a) cos nx de. ny oneal, elf" poo sinardx. ny bn = i is continuous or piecewise ¢ tegrals, we have that iff (2) is ONtinuoy, finitic efinite integrals, From the definition of definit 4 on the integrals given in Eqs. (9.9), vara finite number of finite jumps) ten the integ 1015.14 (continuous except fo e ea exist and f (x) can bé expanded as a Fourier Serie sie tuncon i - i eriodic ful Example 9.1 Find the Fourier series expansion of the ee , cos (nil) are even functions on (~ I, 1], since FOR = 0" = (xP = = f(y), F(X) = 008 (~ natxIN) = cos (nztx/l) = f (2). -f£@), -Isxs xsl 9.16) equ v yy. sin (nat/l) are odd functions on (— 1), since FRE CaP = CAP! eet oP epee) fx) = sin (— naxil) = = sin (neil) =~ F(x). gapis of even functions | x |, x? and a typical cosine like function are given in Figs. 9.3. 2, b.c. Ll x 4018) 0 x oO} (@) (b) © Fig, 9.3, Graphs of even functions. Guaphs of odd functions x, x° and a typical sine like function are given in Figs. 9.4. a, b, ¢ |. - iO * / 0 x a f@) @ ) = Fig. 9.4. Graphs of odd functions. tra "/0) isan even function on [- I, I], then we have f J jonas=2 | finds. on 1 0 9.8 Engineering Mathematics Le} then we have IE F(x) is an ok function on [- v= 0. / fod on om the definition 7 x results can be easily proved from U a: function) (even function) = even function (even functio' 5 cen function) (odd function) = odd function (even fune (odd funetion) (odd function) = even function od finition, we have that Therefore, from the definition, we have t si II) is odd, if f(x) is even then f (x) cos (nzx/l) is even and f (x) sin (aztx/l) is 0 it 1) is even, if f (x) is odd then f(x) cos (nz-x/l) is odd and f (x) sin (n7tx 2 ’ Hence, if f(x) is an even function on [- J, J. then we have the following Fourier series ey (2 O05) aHeos (oa F(a) = B+ F ay 08 | oy nx where 23f f(x)dx and a, = 2f Fea) eos (7 Jax. oxo The Fourier series of an odd function on the interval (- /, 1] is given by F(x) = & by sin way where Ff F(x) sin (a ax. 02) The series given in Eq. (9.19) is called the Fourier cosine series and the series given in Eq, (9.21)is called the Fourier sine series. Consider Example 9.1. The function f (x) series. The function f (x) = x, -1<$x <1 is an even function and we obtain a cosine series. 2+x, -2 +26 1)" ay at both the end points, x = / and ~ /. Remark 2 Let the sum upto j terms of the Fourier series be denoted by ME) +0, sin") 212300. that is, the approximations Tepresent Then, partial sums S; give successive approximations to f (x), F (2) closer and closer as j increases. Example 9.5 Using the results of Examples 9.2, 9.3 and 9.4 prove the following i) eed 7 O rtatat reget Ptyts Gi) Seat 10s 2263 2h ii) (ee, 1 (iii) 1 zo Solution In Example 9.2, the Fourier series expansion of fa)= {a “M (1-x), OKIS% 16. fayelebo bers i 18. f(x) = sinh (x), — 1 <8 <1. 17. fw =l+lah =x, -2 i) cos nn. the complex form of the Fourier series ig clots her . y= Sinha 1) ns PO IEE Be (Lott), ssyto convert the complex exponental form of the Fourier series to a real trigonometric form, ise Wehave 0 20) ty = oy + Cm bn =i (eye), ana ateas of engineering, the complex form of Fourier series is used. Since f (x) is defined eb Nand fx+ 20) =f (3), the Sundamental period Tot J (2) is T= 21. We define @ = 2n/T = vias the Jundamental angular frequency, In erms of «, we can write the ‘ourier series as L)= Bs Fla, cos (nx) + by sin (nox) (9.31) 2" ast I} y F(x) = Z cyeinor, (9.32) Tepotof the points (1, | cy |) where «ois the fund: lamer ceffcients defined in Eq. ( 9-30), is called the frequenc Sumple99 Find the frequency spectrum of the pet ntal angular frequency and cy are the Fourier -Y'spectrum of f (x). odie pulse defined by vl, -lsx

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