Block 3
Block 3
ANALYTICAL METHODS IN
Indira Gandhi National
Open University                     CHEMISTRY
School of Sciences
Block
3
THERMAL AND ELECTROANALYTICAL METHODS
UNIT 8
Thermal Methods of Analysis                  7
UNIT 9
Potentiometry                               30
UNIT 10
Conductometry                               64
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    BLOCK 3: THERMAL AND ELECTROANALYTICAL METHODS
In the preceding blocks of this course, you studied about the various chromatographic
techniques. In this block our focus will be on thermal and electroanalytical methods. This
block consists of three units. Unit 8: Thermal Methods of Analysis, deals with the methods
which are based on the determination of changes in chemical or physical properties of
material on heating. These analytical methods are known as thermal methods. These have
been developed based on the scientific study of changes in the properties of a sample which
occur on heating. In this unit our focus will be on therogravimetric methods of analysis. Unit 9
and Unit 10 deal with three important electroanalytical methods i.e. potentiometry, pH metry
and conductometry. In Unit 9, we are going to cover classification of electroanalytical
method, principle of potentiometry and pH metry, and different types of reference and
indicator electrodes. Procedural details of measurement of potential and pH along with
potentiomertic titation and pH metric titration have also been discussed in detail.
 Unit 10, deals mainly with Conductometry is one of the oldest and in many ways simplest
among the other electroanalytical techniques. This technique is based on the measurement
of electrolytic conductance. In this unit we have covered principle and application of
conductometry in acid base titrations.
Both thermal methods and electroanalytical could be employed for the determination of
elemental concentration or compound in varying sample size of complex matrices of
geological, biological, environmental, forensic, pharmaceuticals and other industrial products.
UNIT 8
                   THERMAL METHODS OF
                                                       ANALYSIS
Structure
8.1      Introduction                     8.6     Factors Affecting TG Curve
8.1 INTRODUCTION
In the preceding blocks you have studied various chromatographic methods.
These methods are commonly used to separate mixtures. We now turn our
attention to other analytical methods which are based on the determination of
changes in chemical or physical properties of material on heating. These
analytical methods are known as thermal methods. These have been
developed based on the scientific study of changes in the properties of a
sample which occur on heating. You may be familiar will the facts like, when
ice is heated, it melts at 0 oC and then boils at 100 oC, when sugar is heated; it
first melts, and then forms brown Caramel. In your undergraduate Organic
Chemistry lab you may have used melting points of organic solids in assessing
the purity and characterization of organic compounds. Melting points are
independent of experimental conditions whether we were using an oil bath or a
heating block. Basically in this process we are subjecting the organic sample
to a heating procedure and measuring a physical property (melting point) by
observing the physical change of the material, as it is heated. In fact, every
material behaves in a characteristic way when heated. The thermal methods
of analysis are based on the determination of change in chemical or physical
                                                                                                       7
Block 3                                              Thermal and Electroanalytical Methods
 phase transitions.
2. Pharmaceuticals
8. Catalysts
10. Explosives
          The more frequently used thermal methods of analysis are shown in Table1,
          with the brief names commonly used for them.
8
Unit 8                                                                         Thermal Methods of Analysis
Though in this unit our focus will be on thermogravimetric analysis, but a brief
description these techniques is given below.
TGA: This is a technique in which weight of a material is measured as a
function of temperature in controlled conditions. This technique provides
information regarding weight change of a material on heating and enables the
stoichiometry of the reaction involved during process. When we heat a
sample there may be two situations, sample either loses weight or gain weight,
which are shown below:
         Sample (Solid)                  Product (Solid) + Gas (Loss of weight)
         Gas + Sample (Solid)             Product (Solid)   (Gain of weight)
                 Recorder to collect the data from the sensors and to process the data to
                  produce meaningful results
8.3 INSTRUMENTATION
The instrument used in thermogravimetry (TG) is called a thermobalance. It
consists of several basic components in order to provide the flexibility
necessary for the production of useful analytical data in the form of TGA
curve as shown in Fig. 8.4.
i) Balance
iv)    Recorder: automatic recording unit for the mass and temperature
       changes
Balance
Furnace
          The furnace and control system must be designed to produce linear heating
          rate over the whole working temperature range of the furnace and provision
          must be made to maintain any fixed temperature. A wide temperature range
          generally from ambient temperature to 2000 °C of furnaces is used in
          different instruments manufacturers depending on the models. The range of
          furnace basically depends on the types of heating elements are used.
Recorder
          Graphic recorders are preferred to meter type recorders. X-Y recorders are
          commonly used as they plot weight directly against temperature. The present
          instrument facilitate microprocessor controlled operation and digital data
          acquisition and processing using personal computer with different types of
          recorder and plotter for better presentation of data.
          In Fig. 8.3, we have shown a schematic diagram of the specific balance and
          furnace assembly as a whole to better understand the working of a
          thermobalance. In this diagram you can clearly see that the whole of the
          balance system is housed in a glass to protect it from dust and provide inert
          atmosphere. There is a control mechanism to regulate the flow of inert gas to
          provide inert atmosphere and water to cool the furnace. The temperature
          sensor of furnace is linked to the programme to control heating rates, etc. The
12
Unit 8                                                                              Thermal Methods of Analysis
balance output and thermocouple signal may be fed to recorder to record the
TG Curve.
Thermogravimatic Curves
Fig. 8.4: TG Curve. Note the plateau of constant weight (region A), the mass loss
         portion (region B), and another plateau of constant mass (region C)
                                                                                                            13
Block 3                                             Thermal and Electroanalytical Methods
          SAQ 1
          List the different components of a thermobalance.
SAQ 2
What are common source of errors in thermogravimetric analysis?
Where Mr is relative mass. Now again consider the Fig. 8.5 (c), it indicates the
% mass lost by the sample is 44 (100.1–56.1) between 600 and 900° C. This
exactly corresponds to the mass changes calculations based on stoichiometry
of the decomposition of CaCO3 expressed by the chemical Eq. (8.1). As in this
case, percentage weight loss of CaCO3 will be
                            M
                 m
                            r (CO 2 )
                           M
                  %                    100                           … (8.2)
                           r (CaCO3 )
                           44×100
                       =                =   44
                            100.1
                                                                   o        o
Fig. 8.5: TG and DTG Curve of CaCO3 at various heating rates (b =8 C, c = 3 C)
         (DTG = Rate of Change of mass, dm/dt) curve.                                                   15
Block 3                                            Thermal and Electroanalytical Methods
          SAQ 3
          Calculate the percentage mass change (m %) for the following reactions.
                                   Δ
          i)     Ca(OH)2 (s) 
                              Heat
                                    CaO(s)+H2O(g)
                                       Δ
          ii)    6PbO (s) + O2 (g)  2Pb3O4 (s)
                               Δ
          iii)   NH4NO3 (s)  N2O(g) + 2H2O(g)
                                   Δ
          iv)    CuSO 4 .5H2O  CuSO4 .4H2O +H2O
                           Δ
          v)     CuSO 4  CuO + SO3
          SAQ 4
          A thermogram of a magnesium compound shows a loss of 91.0 mg from a
          total of 175.0 mg used for analyte. Identify the compound either as MgO,
          MgCO3, or MgC2O4.
16
Unit 8                                                                       Thermal Methods of Analysis
1. Instrumental factors:
2. Sample Characteristics:
a) Amount of sample
c) Particle size
d) Heat of reaction
e) Sample packing
f) Nature of sample
g) Thermal conductivity.
iii) ( Tf – Ti ) F > ( Tf – Ti ) S
c) Furnace Atmosphere
               The effect of atmosphere on the TG curve depends on (i) the types of the
               reaction (ii) the nature of the decomposition products and (iii) type of the
               atmosphere employed. The effect of the atmosphere on TG curve may
               be illustrated by taking the example of thermodecomposition of a sample
               of monohydrates of calcium oxalate in dry O2 and dry N2 as shown in
               Fig. 8.7.
18
               The first step, which is dehydration is reversible reaction.
Unit 8                                                                          Thermal Methods of Analysis
d) Sample Holder
     The sample holders range from flat plates to deep crucible of various
     capacities. The shape of the TG curve will vary as the sample will not be
     heated in identical condition. Generally, it is preconditioning that the
     thermocouple is placed on near the sample as possible and is not dipped
     into the sample because it might be spoiled due to sticking of the sample
     to the thermocouple on heating. So actual sample temperature is not
     recorded, it is the temperature at some point in the furnace near the
     sample. Thus it leads to source of error due to the thermal lag and partly
     due to the finite time taken to cause detectable mass change. If the
     sensitivity of recording mechanism is not enough to record the mass
     change of the sample then this will also cause error in recording the
     weight change of the sample. If the composition of the sample contains
     is such that it reacts either with the sample, or product formed or the
     evolved gases then this will cause error in recording the mass change of
     the sample.
e)   Effect of Sample Mass
     ii)    The degree of diffusion of evolved gases through the void space
            around the solid particles.
                 The heat of reaction will affect the extent to which sample temperature
                 proceeds or succeeds the furnace temperature. This depends on
                 whether the reaction is exothermic or endothermic and consequently the
                 extent of decomposition will also be affected.
                 If the sample reacts with the sample container on heating then it will not
                 give the mass of the product formed so the sample will change. We can
                 avoid this effect by a sensible choice of sample container.
          SAQ 5
          What are the common instrumental factors affecting TG curves.
We have already seen that single and pure compound gives characteristic TG
curves. Now, we will see how TG Curves can be used in predicting relative
quantities of the components of a mixture.
Binary mixtures
Fig. 8.8: (a) Thermogravimetric curves of two compounds AB and CD and (b)
           their Mixture.
          do in the TG Curves for the pure compounds AB and CD. You can also notice
          that the mass loss overall up to T1 is x mg and from T1 to T2 it is an additional y
          mg. By measuring these two quantities x and y from the TG curves of Fig. 8.8
          (b), we can determine the relative quantities of AB and CD in the original
          binary mixture. To understand further consider the mixtures of calcium and
          magnesium carbonates.
22
Unit 8                                                                      Thermal Methods of Analysis
     Thus, m1 – m2 is the loss of CO2 between 600° C and 900° C due to the
     decomposition of CaCO3. Using TGA curve we can relate the mass of
     different components formed during TGA experiment.
The mass of CaO (m3) formed can be calculated using following Eq. (8.8)
Mr 100.1 56.1 44
     From the above equation 1mole of CaCO3 gives 1 mole of CO2 and
                                                             (m - m2 )
     1mole of CaO. Thus, moles of CO2 in the given examples = 1
                                                              Mr (CO2 )
     and this is equal to moles of CaO formed
                                             (m1 - m2 )
     Thus the amount of CaO must be, m3 =               × Mr (CaO)
                                                44
                     (m1 - m2 )
              m3 =              ×56.1 g
                        44
m3 = 1.27(m1 – m2) g
     We know the mass of residue left, i.e., m2, the mass of MgO (m4) can be
     calculated.
m4 = m2 – m3
     Here m3 is the mass of CaO formed, which is equal to 1.27 (m1 – m2).
     Thus
     Mass of the Ca (mca) in the original sample can also be related to m1 and
     m2 by the following formula
                            Ar(Ca)                     Ar(Ca)
              mCa = m3 ×           = 1.27 (m1 - m2 )×
                           Mr(CaO)                    Mr(CaO)
     where, Ar(Ca) and Mr (CaO) are the relative atomic mass and relative
     molar mass of Ca and CaO, respectively. Thus,
                                                                                                    23
Block 3                                            Thermal and Electroanalytical Methods
                                                                     Ar (Mg)
                             = (mass of residue – mass of CaO)×
                                                                    Mr (MgO)
                                              Ar (Mg)                   24.3
                         mMg = (m2 - m3 )×              = (m2 - m3 )×
                                             Mr (MgO)                   40.3
Organic Mixtures
TGA also provides quantitative information on organic compound
decompositions and is particularly useful for studying polymers. For example
TGA can be used in the determination of the amount of vinyl acetate in
copolymers of vinyl acetate and polyethylene. When vinyl acetate is heated it
looses acetic acid at about 340 °C. TG curves shown in Fig. 10.11 for several
vinyl acetate polyethylene copolymers are clearly indicating the loss of acetic
acid at about 340 °C due to the decomposition of vinyl acetate. Each mole of
vinyl acetate losses one mole of acetic acid. The amount of vinyl acetate in the
polymers can be calculated.
SAQ 6
A mixture of CaO and CaCO3 is analysed by TGA. The result indicates that
mass of the sample decreases from 250.6 mg to 190.8 mg only between
600°C and 900°C. Calculate the percentage of calcium carbonate in the
mixture.
                                                                                                     25
Block 3                                                Thermal and Electroanalytical Methods
          8.8 SUMMARY
          Thermogravimetric Analysis (TGA) technique has been described for its basic
          principle, instrumentation and applications. The interpretation of results and
          applications are discussed by taking different examples. The elementary
          calculation are included to elaborate the topics. The probable cause of errors,
          their remedies, interpretation of result are also discussed.
          8.10 ANSWERS
          Self Assessment Question
          1.   Balance; furnace; unit for temperature measurements and control; and
               recorder.
                     Percentage loss =
                                              74.1- 56.1 = 24.3%
                                                74.1
Mr 223.2 × 6 685.6 × 2
1339.2 1371.2
                                     1371.2  1339.2 
                                                          100
            So, percent gain                1339.2
                                  2. 4 %
                             Δ
     iii)   NH 4 NO 3 (s)  N 2 O (g)  2H 2 O (g)
            In this case, both the products are volatile when NH4NO3 is heated
            at 300°C no solid residue is left. The percentage loss in this case is
            80%.
                                 Δ
     iv)    CuSO 4 .5H 2 O  CuSO 4 .4H 2 O  H 2 O
Mr 249.7 231.7 18
                             249.7  231.7                  18
            percen loss                            100           100
                                  249.7                      249.7
                             7. 2 %
                       Δ
     v)     CuSO 4  CuO  SO 3
Mr 231.7 151.7 80
                    231.7 - 151.7
            %m                   × 100
                       231.7
                     80
            %m            100  34.5%
                    231.7
MgO → No reactive
                                        44
     % mass loss for MgCO3 =                100  52.2%
                                       84.3
                                      44  28 
     % mass loss for MgC2O4 =                      100  64.3%
                                        112.3
                                         91.0
     % mass loss of the sample =              100  52%
                                         175
               Mass loss in the mixture is due to the formation of CO2 (g). We can
               calculate the m moles of CO2, i.e. (250.6 – 190.8) mg/44 =1.359 mmol.
               From the above chemical equation, 1 mole of CaCO3 give 1 mole of CO2.
               Therefore the amount of CaCO3 in the mixture must be 1.359 mmol. This
               will equal to = 1.359 × 100.1 mg = 135.9 mg.
                                                              135.9
               So percentage of CaCO3 in the sample will be         100  54.2% by
                                                              250.6
               mass.
          Terminal Questions
          1.   Reaction proceed in following steps
               This equation indicates that one mole of CaCO3 produces one mole of
               CaO and one mole of CO2. Therefore,
                                  = 29.9/44.0
28
Unit 8                                                                      Thermal Methods of Analysis
= 0.682 m moles
= 0.682 × 100.1 mg
= 68.2 mg
                     68.2
     % of CaCO3 =         100.  46.9 %
                    145.3
n 1 2 3 4 5
                                      250  145.7 
     In this problem % mass loss =                      100
                                          250
= 41.7%
6.   Table the help of Fig.8.12 to draw a labeled diagram of the TG curve for
     mixture of CaC2O4.H2O and BaC2O4.H2O.
= 78.9 mg.
                                                                                                    29
Block 3                                             Thermal and Electroanalytical Methods
UNIT 9
POTENTIOMETRY
          Structure
          9.1   Introduction                              Measurement of Potential
                Expected Learning Outcomes                Direct Potential
          9.2   Classification of                         Electrodes
                Electroanalytical Methods
                                                    9.4   Potentiometric Titrations
                Potentiometry
                                                          Types of Potentiometric
                Voltammetry                               Titrations
                Polarography                        9.5   pH Metric Titration
                Amperometry                         9.6   Summary
                Coulometry                          9.7   Terminal Questions
                Conductometry                       9.8   Answers
          9.3   Basic Principle of Potentiometry
          9.1 INTRODUCTION
          Electroanalytical methods find applications in all branches of Chemistry,
          industries, engineering and a number of other technologies. The possibility of
          the determination of low level of pollutants has prompted the use of these
          methods in environmental studies.
We hope you are already aware of the electrode potentials and how it can be
calculated using Nernst equation from your earlier studies. In this unit, we are
going further to discuss how the electromotive force developed in a cell can be
measured using a potentiometer. This method consists of measuring the
potential between any two electrodes immersed in the solution to be analysed.
For measuring the potential, we require two electrodes, an indicator electrode
and a reference electrode along with a device called potentiometer.
In this unit, first we study the classification of electro analytical methods. After
that you will describe different types of reference and indicator electrodes.
There will be a brief description about instrumentation and potentiometric
titrations and pH titrations too.
ii) the mode of mass transport as: diffusion, convection and migration.
Further many of these techniques may be divided into two types on the basis
of the procedures adopted for the analytical determination:
          9.2.1 Potentiometry
          This technique involves the measurement of potential at zero current flow.
          Analytical use of this technique is made in two ways. In one, known as direct
          potentiometry, in this technique, we utilize the single measurement of potential
          and the Nernst Equation is used to relate cell potential to the concentration of
          analyte. The liquid-junction potentials and activity coefficients influence the
          value of cell potential. In the other technique, known as potentiometric titration,
          a set of measured potential is used to detect the changes in concentration that
          occur at the equivalence point of a titration. In these titrations the change in
          the potential is of importance and thus the influence of junction potentials and
          activity coefficients may be ignored. Let us discuss more about these
          techniques.
a) Direct Potentiometry
          Usually, one of the electrodes (half-cell) is chosen such that its potential is
          invariant and is termed as reference electrode. The potential of the other
          electrode is then a function of the concentration (more correctly activity) of the
          species involved in the electron transfer process (a redox reaction), through
          the Nernst Equation. This electrode is termed the indicator electrode. Under
          these conditions the cell emf is given by
Potentiometric Titrations
Further details of these methods will be discussed in Section 9.3, 9.4 and 9.5.
9.2.2 Voltammetry
In voltammetry an electroactive species is consumed (oxidized or reduced
only at the surface layer of the indicator electrode in an electrolytic cell. The
resulting current, due to the electron transfer process is measured as a
function of applied potential. Such electrolysis is carried out under controlled
conditions of diffusion (or/and convection). In diffusion layer electrolysis
methods only a thin layer of solution immediately adjacent to the electrode
undergoes electrolysis. In these methods, the electrical variable is related to
the concentration of the bulk, and usually, the time of electrolysis is short that
only a negligible fraction of the reactant is electrolysed and the reactant
concentration in the bulk solution is not altered (theoretically).
9.2.3 Polarography
Various types of electrodes can be used in voltammetry, but one of them, the
dropping mercury electrode (dme), is particularly useful and the corresponding
voltammetric method is referred to as polarography.
The use of dme in chemical analysis was originated at the Charles University
in Prague, Czechoslovakia in the early 1920s by Heyrovsky who coined the
name polarography to designate this technique. The dropping mercury
                                                                                                33
Block 3                                             Thermal and Electroanalytical Methods
          On applying the potential between two electrodes and increasing its value in a
          stepwise manner the following processes take place. At first only a small
          current flow-the so called residual current. This continues until the
          decomposition potential of the reducible
                                          reducible ionic species is reached. At this point
          the following reaction takes place,
          Afterward a steep rise in current is observed and will continue to rise with
          increasing potential till the current reaches a limiting value (Fig. 9.2).
34
Unit 9                                                                                   Potentiometry
The conditions are set such that the diffusion is the main process of mass
transfer. This can be done by minimising convection and migration. The
limiting current under these conditions is known as the diffusion current (Id ).
The factors affecting the diffusion current were examined by D. Ilkovic and he
gave the following equation which is known as the Ilkovic equation.
Equation 9.2 gives a direct relation between Id and concentration, hence can
be applied for quantitative measurements, we can write from equation 9.4,
Id  c or Id = Kc … (9.3)
where K can be evaluated by noting the current with a standard solution of the
substance of interest.
SAQ 1
Distinguish between voltammetry and polarography.
9.2.4 Amperometry
In Polarography, we have seen that in a particular polarogram, the limiting
current of an electroactive substance, at a suitable (fixed) potential depends
on the substance concentration only. If we reduce the concentration of the
electroactive substance by its interaction with another substance, the current
will be reduced. This principle is made to get the equivalence point by
measuring the current flowing at an indicator electrode. This technique is
                                                                                                    35
Block 3                                             Thermal and Electroanalytical Methods
Electrogravimetry
          The method is very simple to apply in the analysis of a single element in the
          absence of any other substance which might be deposited. For this analytical
          method the appropriate electrode potential is essential. The potential for the
          selective deposition of a metal can be calculated from the Nernst equation or it
          can be determined from data obtained by voltammetry.
Coulometry
O + ne R
                Q
         nA =                                                 … (9.4)
                nF
a) Potentiostatic Coulometry
          SAQ 2
          Differentiate between potentiostatic coulometry and amperostatic coulometry.
          SAQ 3
          A 9.65 ampere current is passed through a solution of AgNO3 for 50 minutes.
          Calculate the amount of Ag deposited at the cathode.
          9.2.6 Conductometry
          In conductometry we examine the transport of electricity in solution and
          application of this phenomenon to chemical analysis. The principle advantage
          of this technique is its simplicity and relatively good sensitivity. It is, one of the
          earliest techniques to study the behaviour of electrolytic solutions. Since the
          conductance (which is reciprocal of resistance) of an electrolytic solution
          depends on the number of ions present, their charge, their mobility, and
                                    applications of conductometry are thus possible. More
          temperature; analytical applications
          detail discussion on the methods is given in Unit 10.
          In order to understand the above concept, we shall study the galvanic cell in
          some detail. For example, consider the simple galvanic cell illustrated in
          Fig.9.5. In this cell there are two half cells. Where a half cell is the
          combination of an electrode and the solution with which it is in contact. In one
          half cell zinc gets oxidized to Zn2+ ions.
Fig. 9.5: Simple galvanic cell having Cu2+/Cu and Zn2+/Zn half cells.
          This electrode is, therefore positively charged relative to the solution and, this
          is referred to as cathode. Note that reduction always occur at the cathode.
          As shown in the Fig.9.6 both electrodes of half cells are connected externally
          via an electric circuit and the circuit is completed by ionic conduction through
          the solution and KCl salt bridge. The voltmeter will then measure the
          difference in potential between the two electrodes.
          Note that the one half cell involves an oxidation process and the other half cell
          a reduction process. These are then combined in the cell to give a redox
          reaction represented below by Equation,
          This notation starts with the left hand electrode and move to the right through
40        the solution to the right hand electrode. The simple vertical bars signify phase
Unit 9                                                                                Potentiometry
boundary, whilst the double vertical bar the salt bridge. a1 & a2 are the
activities of two ions.
The potential difference between the electrode and solution in a half cell is
referred to as the electrode potential. It is impossible to determine the potential
of a single electrode and rather it is the potential difference that is measured.
A number of conventions have been established in order to compare the
potential of different half reactions. The half-reaction is written as a reduction
process i.e. for the metal, M and its own ion Mn+, it is written as
Mn+ + ne ⇌ M(s)
If the constituents in the half-cell are present at unit activity, the potential
difference is measured at 25ºC with respect to a standard hydrogen electrode
(SHE), which has been arbitrarily assigned the zero potential. Under these
conditions the potential difference or electrode potential is known as the
standard electrode potential, Eº. We will take up standard hydrogen electrode
in detail in the next section.
Ecell = E1  E2
The junction potential developed at the junction between the two half cells are
also contributing to the cell potential, the Ecell calculation can be rewritten as:
Using Nernst equation, the relationship between cell potential and activity of
species involved can be developed.
                         RT a(reduced)
         E = Eº           ln                                   ..… (9.6)
                         nF a(oxidised)
For the Copper half cell of the galvanic cell mentioned earlier it is written as
                                           RT         a(Cu)
         E   2+        = E0           -        ln
          
             Cu    
                Cu 
                            2+ 
                            Cu Cu 
                                  
                                           2F        a(Cu2+ )
                  
                                                                                    RT                    1
                    E Cu                           = E0                         -                 ln
                               2+
                                     Cu                      Cu2+
                                                             
                                                             
                                                                       
                                                                    Cu             2F                    2+
                                                                                                       a(Cu )
                                                                                    0.
                                                                                     0591       1
                    E Cu                          = E0                         +         log
                               2+
                                     Cu                      Cu2+
                                                             
                                                             
                                                                       
                                                                    Cu              n      a(Cu2+ )
                                                                                    0.
                                                                                     0591      1
                    E Cu                          = E0                                  log
                               2+
                                     Cu                      Cu2+
                                                             
                                                             
                                                                       
                                                                    Cu              n      [Cu2+ ]
                                                                                    0.
                                                                                     0591
          Or        E Cu                          = E0                                  log [Cu2+ ]
                               2+
                                     Cu                      Cu2+
                                                             
                                                             
                                                                       
                                                                    Cu              n
                                                                                0.0591      1
                    E Zn                          = E0                                log 2+
                           2+
                                     Zn                    2+ 
                                                            Zn Zn 
                                                                  
                                                                                   n      [Zn ]
                                                                                0.0591
          Or        E Zn                          = E0                                log [Zn2+ ]
                               2+
                                     Zn                    2+ 
                                                            Zn Zn 
                                                                  
                                                                                   n
          If the liquid junction potential is negligible, the potential of the cell is then given
          by:
                    Ecell = E                                      - E Zn
                                                   Cu2+
                                                  
                                                  
                                                            
                                                         Cu                      2+
                                                                                         Zn   
          Clearly the potential of the cell will depend upon the concentration of both the
          copper(II) and zinc(II) ions. In such situation it is not possible to determine the
          activity or concentration of the two ions from the cell potential. In practice, we
          determine the activity or concentration of a single substance, rather than a
          combined value for two or more substances. For this reason if we keep the
          concentration of zinc(II) ions at a fixed value so that its potential also remain
          constant. Then,
                                                                           0.0591
                    Ecell = E0                                    +               lna(Cu2+ ) - E Zn
                                                   Cu2+
                                                  
                                                  
                                                            
                                                         Cu                 2                                     2+
                                                                                                                          Zn   
          As E0                 and E Zn                                   are both constant, they can be combined into one
                  Cu2+
                 
                 
                           
                        Cu                                2+
                                                                  Zn   
          value K. Then,
                                                             0.0591
                    Ecell = K +                                     log [Cu2+ ]
                                                                2
                       0.0591
         Ecell = K ±          log [I]n 
                          n
                       0.0591
Or       Ecell = K ±          log aM       I+                    ..… (9.7)
                          n
SAQ 4
Calculate the potential of a copper electrode immersed in 0.044 M CuSO4
                                                                                                    43
Block 3                                                                 Thermal and Electroanalytical Methods
                  SAQ 5
                  Calculate the potential of a zinc electrode immersed in 0.060 M ZnSO4.
                  SAQ 6
                  Calculate the cell potential for the cell made by combining the half-cell in
                  SAQs 4 and 5 in the following way:
                  Consider the indicator electrode whose potential vary with cation activities or
                  concentrations, we can write Nernst Equation similar to Eq. 9.7.
                                   o       0.0591
          (a)             Eind = Eind +           log a n+                                       … (9.9)
                                              n        M
                                     o           0.0591
                         Ecell = ( Eind +               log a n+ ) – Eref + Ej
                                                    n        M
                  On rearrangement
                                          n(Ecell - K )
                         log a        =                                                          … (9.10)
                               Mn +         0.0591
                                                        n(Ecell - K )
                  or     pM = – log a             = –                                            … (9.11)
                                          Mn +            0.0591
            (b)
                  For anion An- Eq. 9.11 will have reversed sign
                                                     n(Ecell - K )
                         pA = – log a            =                                               … (9.12)
                                          An-          0.0591
                  where pM and pA are the negative logarithm of the metal ion activity a                   and
                                                                                                    Mn +
                  an anion a       , respectively. These terms are more general forms of the
                             An-
                  familiar term pH. K is summation of several constants, including standard
                  electrode potential of metal ion or anion, potential of reference electrode,
                  junction potential, asymmetrical potential if membrane electrode is involved.
                  All direct potentiometric methods are based on Eqs 9.11 and 9.12. Both these
                  equations in terms of Ecell may be written as
44
Unit 9                                                                                     Potentiometry
                       0.0591
         Ecell = K –          pM                            … (9.13)
                          n
                       0.0591
         Ecell = K +          pA                            … (9.14)
                          n
Using Eqs. 9.11 and 9.12,we can determine concentration of metal ions or
cations and anions in terms of pM and pA, respectively. Further, Eq. 9.13 also
indicates that for a metal ion-selective electrode, an increase in pM results in
decrease in Ecell as shown in Fig. 9.7. But before that constant K should be
known to us. As you know K is made up of several constants, including the                  (a)
junction potential, which cannot be measured directly or calculated from theory
without assumptions. This problem can be overcome by electrode calibration
method using standard solution of the analyte. Though calibration methods are
simple, take less time and convenient to the continuous monitoring of pM or
pA, but suffer somewhat limited accuracy because of uncertainty in junction
potential.
SAQ 7
Following emf readings are obtained for the standard solutions of Ca2+ ions in
a potentiometry experiment. What is the concentration of a sample if its emf 33
mV?
Concentration of Ca2+/mol dm-3 (M)           emf/mV
         1.00 × 10-4                         –2
         5.00 × 10-4                         +16
         1.00 × 10-3                         +25
         5.00 × 10-3                         +43
9.3.2 Electrodes
In previous part we saw that a electrochemical cell were composed of two
electrodes: indicator and reference electrodes. A reference electrode must be
easy to construct, and must maintain a constant, reproducible potential even if
small currents are passed. An indicator electrode responds to change in                                   45
Block 3                                              Thermal and Electroanalytical Methods
Reference Electrode
 Calomel Electrode
          The standard hydrogen electrode (Fig. 9.8) is constructed from a platinum foil
          plate, which has been platinized, that is coated with platinum black (finely
          divided platinum) by chemical or electrochemical reduction of chloroplatinic
          acid. The finely divided layer of platinum black helps in achieving the largest
          possible surface area. Its composition can be formulated as
          Pt, H2 (1 atm) 1 H+ (a =1)
          The half cell reaction, may occur in either direction depending upon the type of
          electrode which is coupled with it.
                 2H+ + 2e    ⇌ H (g)
                                2
                 E=E +02.303 RT     a+
                                log H
                                                                          ..… (9.15)
                          2F        p       H2
           where E0, the standard electrode potential for hydrogen electrode is zero. For
          the standard hydrogen electrode, having H+ activity, aH+ equal to one and
          pressure exerted by hydrogen gas PH2 also equal to one atmosphere, the
                                               (9.15) becomes equal to zero and E = E0 =
          logarithmic term on the right of Eq. (9.15)
46
Unit 9                                                                              Potentiometry
The SHE was selected as a primary reference electrode for several reasons
as given below:
Besides these advantages, the use of SHE has certain limitations as:
(i)      It can not be used in solutions containing strong oxidizing and reducing
         substances.
(ii)     It is not handy and hence transfer from one place to another is not
         easy.
(iii)    The platinum surface is poisoned in presence of species like H2S, CN
         and Hg.
          It consists of an outer glass tube with a crack in the end of the tube. A crack is
          made by an asbestos filament or fitted porcelain plug or quartz fiber. A
          mercury and mercurous chloride paste is filled in the inner tube, which is
          connected to the saturated potassium chloride solution in the outer tube
          through a small opening. The saturated potassium chloride solution in the
          outer tube can be easily renewed through a lateral hole. Calomel, i.e.,
          mercurous chloride is a sparingly soluble salt. Its solubility product (Ksp) is
          given as:
                          0        0.0591 K sp
                  or E = EHg +           log                                     ..… (9.17)
                                      2      a Cl-
          The activity of chloride ions (by excess of chloride ions obtained from
          potassium chloride) remains constant for a particular electrode. The
          experimental value of the potential of the saturated calomel electrode is 0.244
          V at 250 C.
Silver chloride is a sparingly soluble salt. Its, solubility product, Ksp, is:
E = E 0 A g + 0 .0 5 9 1 lo g a A g +
                                     K sp
         E = E 0 Ag + 0.0591 log                             ...(9.19)
                                    a Cl -
Indicator Electrodes
          Metal indicator electrodes are not selective as these electrodes can respond to
          its own ions and can also respond to a number of other metal ions. There are
          several other indicator electrodes which are selective to particular ions. Many
          of them are very valuable in potentiometric analysis and are collectively
          referred to as ion selective electrodes (ICE). The most common of these is the
          glass electrode, which is selective to H+ ions and, consequently, pH.
Glass Electrode
          The most convenient way for determining pH has been by the use of the glass
          electrode. It is an ion-selective electrode. Glass electrode is a membrane type
          electrode whose membrane is made by a special type of glass. A potential
          develops across a thin glass membrane separating two solutions of different
          acidities. The measurement of potential difference can thus be related to
          hydrogen ion concentration. This phenomenon was first recognized by
          Cremer in 1906 and systematically explored by Haber in 1909 with the
          construction of a glass bulb electrodes. After the work of Sorenson (1909) to
          determine hydrogen ion concentration in terms of pH and the use of vacuum
          tube voltmeter by A. Beckmann (1930) made the use of glass pH electrodes
          more practical. Development of transistor based pH meters and the special
          purpose glass for the measurement of high pH values has further improved
          the technology.
          The glass electrodes of various sizes, shapes and for different pH ranges are
          commercially available. Fig. 9.12 illustrates the construction of a common type
          of glass electrode. It consists of a thin, H+ sensitive glass membrane bulb at
          the end of a heavy-walled glass tubing. A buffer solution (or 0.1M HCl) is filled
          in the glass membrane bulb. A reference electrode (usually silver-silver
          chloride electrode) is placed in contact with the inner solution. It is connected
          to one terminal of the pH meter. The bottom portion (bulb) of the glass
          electrode is immersed in the external solution whose pH is to be measured.
          An external reference electrode (usually an SCE) is immersed in the external
          solution and is connected to the other terminal of the pH meter.
50
Unit 9                                                                             Potentiometry
Ecell = E1 - E2 + Emembrane + Ej
The potential for this cell response is related to the logarithm of hydrogen ion
activities on the two sides of the glass membrane and is given by Nernst
equation:
                                             (aH )1
                                                 +
           Ecell = Easym - 0.0591 log
                                             (aH )2
                                                 +
                                    (aH )1
                                         +
           Ecell = k - 0.0591 log                                     ...(9.20)
                                    (aH )2
                                         +
Since the pH on the internal side of the glass membrane is held constant using
a buffer, the potential of the glass membrane electrode will depend upon the
pH of the external solution (aH )2 . Now Eq. 9.20 can be written as:
                                     +
          Where k1 now includes the constant factor related to aH+. Thus, the emf
          produced in the glass electrode system varies linearly with pH. From the
          Eq.18.18 the constant k1 can be eliminated by measuring potential, first with
          standard buffer solution whose pH is precisely known and then with known
          solution. Thus for the standard buffer
or
          As said above, the constant k1 includes the asymmetry potential which exists
          across the glass membrane even if the two sides of the cell are of identical
          composition. For this reason, a pH meter is to be calibrated from time to time
          (preferably every time when pH measurements are done) with standard
          buffers.
          In pH meter voltmeter is used to measure the potential of the cell. The voltage
          scale is calibrated in pH units so that 0.0591V correspond to 1pH Unit at 25C.
          This value will change with temperature and modern pH meters have a
          temperature compensation device. This may be set before taking pH readings.
Combination Electrodes
52
Unit 9                                                                                  Potentiometry
While measuring pH you should be little care full as there are few factors
which limit the accuracy of pH measurements. We are listing few of them
below:
2.       The acid error: At low pH range – less than 0.5, the values determined
         by the glass electrode tend to be somewhat higher. This error is due to
         the activity of water which we have ignored while writing Nernst equation
         for the indicator electrode. We have assumed that activity of water may
         be taken to be unity as it is in large excess in the solution and it behaves
         as a pure substance. However, in highly acidic solution, the activity of
         the water becomes less than unity because a good amount is used in
         hydrating the protons.
                                                                                                   53
Block 3                                                             Thermal and Electroanalytical Methods
                           With this theoretical background now we will see how the pH is measured
                           using pH meter, but before that try following SAQs.
                           SAQ 8
                           Why is it necessary to calibrate the glass electrode before use?
                           SAQ 9
                           List some factors which may cause errors in pH measurements.
The potential between the reference electrode half cell (whose potential is
known) and the indicator electrode half cell (whose potential varies with
concentration of the solution) is measured at the start and after the addition of
small amounts of titrant, say each 1 cm3, and more closely near the
equivalence point, when &dings start to change by larger values. After each
addition the solution is stirred well and the reading is allowed to become
steady.
Fig. 9.15 : Methods of equivalence point determination (a) normal plot (b)
first derivative (c) second derivative
Once the titration curve is at hand, we must determine where the curve is
steepest, normally by some sort of inspection. We may draw a vertical line
through the steep portion of the curve and find the intersection of this line with
the volume axis. To overcome the uncertainty in this procedure, we plot
another graph as shown in Fig. 9.15(b). This is a plot of the slope of a titration
curve, that is, the change in potential with change in volume (∆E/∆V) against
volume of the titrant. The resulting curve rises to a maximum height at the
equivalence point. The volume at the equivalence point (V) is determined by
drawing a vertical line from the peak to the volume axis. Fig. 9.15(c) shows a
plot of the change in the slope of a titration curve (  E/  V2) against the
                                                        2
          particularly useful for titration of coloured or opaque solutions and for detecting
          the presence of unsuspected species in a solution. Titrations of more dilute
          solutions are possible using potentiometry. Unfortunately, it is more time
          consuming than a titration performed with an indicator.
                         [H+ ] [A - ]
                  Ka =                                                            … (9.23)
                           [HA]
                                                   [A - ]
                  log Ka = log H+ + log
                                                  [HA]
                                                       [A - ]
                  – log Ka = – log H+ – log
                                                      [HA]
                                         [A - ]
                  pKa = pH – log
                                        [HA]
or pKa = pH … (9.24)
          This is the midway point to the equivalence pint. Therefore, pKa values can
          also be directly read from the titration curves.
         The determining factor in the values of potential is the ratio of the activity
         or concentration of the oxidised and reduced forms of certain ion
         species.
Automatic Titrations
9.5 pH TITRATION
Similar to potentiometric titrations, in contrast to direct pH measurements, pH
titrations generally offer increased accuracy and precision. Accuracy is
increased because, measured pH are used to detect rapid changes in activity
that occur at equivalence point of the titration. Furthermore, it is the change in
pH versus titre volume rather than absolute value of pH that is of interest.
Thus, the errors due to liquid-junction potentials and activity coefficients are
minimized. pH titrations may be applied to a variety of systems including those                      57
Block 3                                              Thermal and Electroanalytical Methods
          involving weak acids and weak bases. In such titration, it is difficult to get end
          point using indicator method. A typical acid-base titration using pH metry is
          briefed as follows.
             Over most of the titration range the pH varies gradually, but near the end
              point the pH changes very abruptly. The resulting titration curve
              resembles Fig. 9.17(a).
              Fig. 9.16:
                   9.16: Typical Instrumental set up for pH titration
             By inspection, the end point can be located from the inflection point of the
              titration curve.
             Once the pH has been established for a given titration, it can be used to
              indicate subsequent end points for the same chemical reaction.
58
Unit 9                                                                                Potentiometry
    The equivalence point can be more precisely located from the 1st and 2nd
     derivative curves as illustrated in Fig. 9.17(b) and 9.17(c). Solutions more
     dilute than 10-3 M generally do not give satisfactory end points. This is
     limitation of pH metry and potentiometric titrations.
Fig. 9.17: pH titration curves; (a) Normal curve; (b) First derivative curve; and
(c) second derivative curve     `
9.6 SUMMARY
In this unit, you have learnt that about electrode potentials, principles of
potentiometer and measurement of potential, different types of reference
electrodes : such as Hydrogen Electrode, Calomel Electrode, Silver-Silver
Chloride Electrode and different types of indicator electrodes. You have also
learnt about the measurement of potential and location of end points from the
graphs obtained from the experimental values of emf and volume of titrant.
Different types of titration such as acid-base titrations and redox titrations were
also explained in detail. You have also learnt that pH tells the acidic or basic
nature of an aqueous solution and is defined as negative logarithm of
hydrogen ion concentration. pH can be readily measured in an accurate
manner with the help of a pH meter. There is also detail discussion on pH
titration.
          9.8 ANSWERS
          Self Assessment Questions
nA=Q/nF where Q = It
Ag+ + e Ag (s)
                                 28950 C
               nAg =                                 =0.300 mol Ag
                       1 e / molAg× 96485 C / mole e
                                             0.0591        1
               Nernst equation : E = E o -          log
                                                2       [Cu2+ ]
                                     0.0591
               or         E = Eo +          log Cu2+ 
                                        2            
                               0.0591
                E = 0.337 +           log0.044
                                  2
               E = 0.297 V
60
Unit 9                                                                               Potentiometry
E = – 0.799 V
Zn + Cu2+ ⇌ Zn2+ + Cu
         Ecell = E          -E
                 Cu2+ /Cu        Zn2+ /Zn
7.       Draw a calibration graph using the data given in SAQ 7 on special type
         of graph paper called semi-log (or log/mm) paper. The calibration graph
         is shown in Fig. 9.18. You can find the concentration of sample from this
         graph is 2.1 × 10-3 M.
9. i) Alkaline error
v) Temperature
vi Calibration procedures
Terminal Questions
1.   This is the tendency of an electrode to get oxidised or reduced. But as
     per the IUPAC conventions, it is the reduction potential of the electrode.
                            0.0591    a 2+ × aH2
               E = Eo -            log cu              at 25o C
                               2         (a + )2
                                            H
                                       (Ecell )u - (Ecell )s
                (pH)u = (pH)s –                              … (iii)
                                             0.0591
                                                   Appendix I
         Standard Electrode Potentials*
                                                                   0
         Reaction                                                 E at 25° C,V
         MnO 4 + 8 H + 2e ⇌ Mn + 4H2O                            + 1.51
                     +         2+
                                                                  + 1.359
         Cl2(g)+ 2e⇌ 2Cl 
         Cr2O
                   2–              +
                        + 14 H + 6e ⇌ 2Cr
                                                   3+
                                                        + 7 H2O   + 1.33
                         +
         O2(g)+4H + 4e ⇌ 2H2O                                     + 1.229
                                                                  + 1.087
         Br2(aq) + 2e ⇌ 2Br 
                                                                  + 1.065
         Br2(l) +2e ⇌ 2Br 
              +
         Ag + e ⇌ Ag (s)                                          + 0.799
         Fe
             3+
                   + e ⇌ Fe
                                    2+                            + 0.771
                                                                  + 0.536
         I 3 + 2e ⇌ 3I 
         -
         Cu
              2+
                   + 2e ⇌ Cu (s)                                  + 0.337
         UO
              2 +             +
                    + 4H +2e⇌ U
                                          4+
                                               + 2H2O             + 0.334
               2
                                                                  + 0.268
         Hg2Cl2 (s) + 2e ⇌ 2Hg (l) + 2Cl 
                                                                  + 0.222
         AgCl(s) + e ⇌ Ag(s) + Cl 
                                  + e ⇌ Ag (s) + 2S2O 32         + 0.017
                         3-
         Ag(S2O3)             2
              +
         2H + 2e ⇌ H2(g)                                          0.000
                                                                  – 0.151
         AgI(s) + e ⇌ Ag(s) + I 
         PbSO4 + 2e ⇌ Pb(s) + SO 24                              – 0.350
         Cd
              2+
                   + 2e ⇌ Cd (s)                                  – 0.403
         Zn
              2+
                   + 2e ⇌ Zn(s)                                   – 0.763
         Ce
              4+
                   + e ⇌ Ce
                                    3+                            – 1.70 V
                                                                  – 2.363
         Mg 2  + 2e ⇌ Mg (s)
                                                                                            63
Block 3                                             Thermal and Electroanalytical Methods
UNIT 10
CONDUCTOMETRY
          Structure
          10.1   Introduction                                The Wheatstone Bridge Principle
                 Expected Learning Outcomes                  Measurement of Conductance of
                                                             a Solution
          10.2   Electrolytic Conductance
                                                     10.4    Application of Conductometry
                 Molar Conductivity
                                                     10.5    Summary
                 Variation of Conductance with
                 Concentration                       10.6    Terminal Questions
                 Limiting Molar Conductivity         10.7    Answers
                 Effect of other Factors on          10.8    Further Reading
                 Conductance
          10.3   Measurement of Electrolytic
                 Conductance
          10.1 INTRODUCTION
          So far we have discussed potentiometric methods. In these methods we
          measure the emf of a galvanic cell which is operating near zero current.
          Because this emf is a function of the ionic activities within the cell, it can be
          used to measure ionic concentrations in titration, water samples, biological
          samples and other industrial and environmental samples. We have also seen
          that both potentiometry and pH metry are most widely used electroanalytical
          technique. In this unit you will study another electroanalytical technique called
          the conductometry, which is one of the oldest and in many ways simplest
          among the other electroanalytical techniques. This technique is based on the
          measurement of electrolytic conductance.
Electrolytic conduction, in which charges carried by ions, will not occur unless
the ions of the electrolyte are free to move. Hence, electrolytic conduction is
exhibited principally by molten salts and by aqueous solutions of electrolytes.
The principle of electrolytic conduction is best illustrated by reference to an
electrolytic cell such as that shown in Fig. 10.1 for the electrolysis of molten
NaCl between inert electrodes. The entire assembly except that of the external
battery of Fig. 10.1 is known as the cell.
          The electrons are received from the negative end of the external battery by the
          negative electrode of the cell. These are used up in the reduction reaction at
          this electrode. The numbers of electrons received at the negative electrode
          are given back to the positive end of the external battery from the positive
          electrode of the cell where electrons are released as the result of oxidation
          reaction. Within the cell, current is carried by the movement of ions; cations
          moves towards negative electrode called the cathode and anions towards the
          positive electrode called anode. This movement of ions give rise to what is
          known as the electrolytic conduction. The latter, thus, depends on the mobility
          of ions and anything that inhibits the motion of ions causes resistance to
          current flow. Factors that influence the electrical conductivity of solutions of
          electrolytes include interionic attraction, solvation of ions, and viscosity of
          solvents. These factors depend on the attraction i.e. solute-solute, solute-
          solvent and solvent-solvent respectively. The average kinetic energy of the
          solute ions increases as the temperature is raised and, therefore, the
          resistance of electrolytic conductors generally decreases, that is, conduction
          increases as the temperature is raised.
          The ionic compounds, which furnish ions in solution and conduct electric
          current, are electrolytes e.g. NaCl, KCl etc. There are covalent compounds,
          which also conduct electric current in solutions. These include HCl, CH3COOH
          etc. All other substances which do not produce ions in solutions are called
          non-electrolytes, e.g. cane sugar, benzene, carbon tetrachloride etc.
          The potential electrolytes do not conduct electricity in the pure normal state
          rather they conduct electricity when dissolved in water, e.g. HCl, CH3COOH
          and NH3.
          Weak electrolytes: The substances which ionize only to a certain extent are
          called weak electrolytes, e.g. CH3COOH, HCN etc.
          The terms strong and weak are relative. The behaviour of electrolytes also
          depend on the nature of solvents, e.g. NaCl behaves as strong electrolyte
          where as acetic acid as a weak electrolyte in water. On the other hand, when
          dissolved in ammonia both NaCl and acetic acid show comparable behaviour
          towards electricity.
  66
Unit 10                                                                               Conductometry
Conductance of solutions
The ease of flow of electric current through a body is called its conductance.
In metallic conductors it is caused by the movement of electrons, while in
electrolytic solutions it is caused by applied electrical field. The electrolytic
conductance, G, of a medium is equal to the reciprocal of its electrical
resistance R in ohms:
                1
          G                                                              … (10.1)
                R
Ohm’s Law states that the current I (amperes) flowing in a conductor is directly
proportional to the applied electromotive force E (volts) and inversely
proportional to the resistance, R (ohms) of the conductor:
               E
          I            or    I  EG                                      … (10.2)
               R
                                       2        2
                                  Am           Am
Consider the electrolytic cell shown above, its two electrodes are having a
cross-sectional area of A m2 and separated by l m. The resistance (R) of the
electrolyte solution present between the two electrodes is:
R l
                   1
          R 
                   A
                    l
          R 
                    A
                    l
          R= ρ                                                            … (10.3)
                    A
                             A
                   = R                                                           … (10.4)
                             l
Substitute the value R in Eq. 10.1 The expression for the conductance, G is
                         1       1        A
                   G=                 κ                                         … (10.5)
                         R   ρ ( A/l )    l
          Cell constant: For a given cell, l and A are constant, and the quantity (l/A) is
          called the cell constant (Kcell).
                             l
                   Kcell =
                             A
 = G Kcell … (10.6)
          To obtain the value of the cell constant, it is not necessary to determine l and
          A directly. Instead, it is measured by a solution of known conductivity.
          Potassium chloride solutions are invariably used for this purpose, since their
          conductances have been measured with sufficient accuracy in cells of known
          dimensions. A given solution of potassium chloride of conductivity K' is placed
          in the cell and its resistance R' is measured. The cell constant is then equal to
          K'R'. Therefore,
          Where the summation is to be carried over all the electrolytes present in the
          solution and G (water) is the conductance of water, which is utilized for making
          the solution. G (water) is often negligible in comparison to Gi as repeatedly
          distilled water (known as conductivity water) of very low conductance is
  68      employed for making the solutions.
Unit 10                                                                              Conductometry
SAQ 1
The resistance of a conductivity cell containing 0.01 mol dm 3 KCl is 150 Ω.
The same conductivity cell gives the resistance of 0.01 mol dm 3 HCl 51.4 Ω.
The conductivity of the KCl solution is 1.41 × 10–3 -1 cm-1 Calculate the
following values:
                  
          m =                                                            … (10.8)
                  c
                  1000  
          eq =                                                          … (10.10)
                     c
SAQ 2
Write the units of the following:
          SAQ 3
          From the following data, calculate the molar conductivity of KCl in aqueous
          solution:
                     –3
          c/mol dm         KCl       NaCl      HCl         AgNO3     CH3COOH       CH3COONa
minor changes observed are due to interionic interactions. In the case of weak
electrolytes (for example CH3COOH, ammonia, organic fatty acids etc), the
ionization will increase with dilution, and hence, the molar conductivity
increases with dilution. Thus the conductivity is directly proportional to the
degree of dissociation of a weak electrolyte.These above results are depicted
in Fig. 10.2 in which the molar conductivity, m, of two electrolytes (KCl and
acetic acid) at a constant temperature is plotted against c. It may be seen
from the figure that two different types of behaviours are exhibited by these
electrolytes. The strong electrolyte, KCl shows a linear plot (almost straight
lines). On the other hand, the weak electrolyte, CH3COOH seems to approach
the dilute solution limit almost tangentially. It is, however, impossible to draw a
sharp line of demarcation between the two categories as many substances are
known to exhibit intermediate behaviour, e.g., nickel sulphate. Such
electrolytes are sometimes called moderately strong electrolytes.
                             0
                                             (a)
                                                   KCl
                           
                                             (b)
                                                    CH3COOH
                               0
                                         c
Fig. 10.2: Variation of molar conductivity on dilution (a) for aqueous solution of
          potassium chloride (strong electrolyte) (b) acetic acid (weak
          electrolyte).
The conductance of a solution depends on the number of ions and the speed
with which the ions move in solution. In case of strong electrolytes, the number
of ions is the same at all dilutions (since strong electrolytes are completely
ionized) and the variation of equivalent conductance with dilution is therefore
due to the change in the speed of the ions with dilution. In a concentrated
solution of such electrolytes, the interionic attractions among the oppositely
charged ions would be quite appreciable. The ions may also form some ion-
pairs of the type A+B  that would not contribute to the conductance. These
interionic forces considerably lower the speed of the ions and hence the
conductivity of the solution. As the dilution is increased the interionic
attractions decrease with the result that the ions will move more freely and
independently of their co-ions and thus increasing the molar conductivity with
dilution. At infinite dilution, the ions are quite far apart, the interionic attractions
are almost absent and each ion moves completely independent of its co-ions.
The molar conductivity then approaches a limiting value at infinite dilution and
represents the conducting power of 1 mole of the electrolyte when it is
completely split up into ions. It is denoted by .
m =   – bc … (10.11)
  =   +   … (10.12)
          where         
                   and   are the ionic conductivities at infinite dilution of the cation
          and anion, respectively.
                                                         OH 
              +
          H            349.8          349.8                             198.3         198.3
                                                         F
              +
          Li           38.7           38.7                              55.4          55.4
                                                         Cl 
                  +
          Na           50.1           50.1                              76.3          76.3
                                                         Br 
              +
          K            73.5           73.5                              78.1          78.1
                                                         I
                  +2
          Be           90.0           45.0                              76.8          76.8
                                                         NO3 
                  2+
          Mg           106.2          53.1                              71.5          71.5
  72
Unit 10                                                                                 Conductometry
                                        SO4 
     2+                                    2
Ca        119.0           59.5                      160.0         80.0
                                        CH3COO 
     2+
Ba        127.2           63.6                      40.9          40.9
                                        C6H5CO 
 3+
Al        183.0           61.0                      32.4          32.4
                                        HCO3 
     2+
Cu        107.2           53.6                      44.5          44.5
                                        CO3 
     +                                     2
Ag        61.9            61.9                      138.6         69.3
                                        Fe(CN)6 
     2+                                        3
Zn        105.6           52.8                      302.7         100.9
                                        Fe(CN)6 
     3+                                        4
Ce        209.4           69.8                      442.0         110.5
The answer lies in the fact that different ions have different mobilities in
solution. The mobility of an ion in solution is mainly dependent upon the size of
the hydrated ion. The ionic mobility is defined as the velocity with which an ion
would move under a potential gradient of 1 V m–1 in a solution. It provides a
link between theoretical and measurable quantities. For instance, ionic
mobility, (u) is related to limiting molar ionic conductivity (  ) by the following
equations:
where z+ and z– are the valency of the ions, u+ and u– represent the ionic
mobilities and F is the Faraday constant. In the above equation, if one of the
two quantities,   or u, is known, the other can be calculated.
           t+ =  
                   /m    and t– =  
                                       / m                              … (10.14)
The transport number and the limiting molar conductivity are measurable
quantities. Hence, the molar ionic conductivity value can be calculated from
Eq. 10.14. The limiting molar conductivities of some common ions are given in
Table 10.2. These values are important in predicting the molar conductivity of
electrolytes and course of conductomatric titrations. Finally, once the molar
ionic conductivity value is obtained, we can then make use of Eq. 10.13 to
calculate the ionic mobility. Some typical values of ionic mobility (in infinite
dilute solutions) are listed in Table 10.3.                                                       73
Block 3                                                         Thermal and Electroanalytical Methods
H+ 36.24
Li+ 4.01
Na+ 5.19
K+ 7.62
Ag+ 6.42
OH– 20.58
Cl– 5.74
Br– 7.92
I– 8.09
NO3– 7.41
          It is interesting to look at Table 10.3 in more detail. You will see the Li+ ion,
          because of its larger hydration shell, has a lower mobility than the potassium
          ion. Similar argument can be applied to the F– & Br– ions. Exceptional
          mobilities are observed for the H+ and OH– ions. This is because, in these
          case charge is transported through proton jump mechanism along with general
          migrations mechanism, consider he case of H+ ion.
                                               H            H         H        H
                                                  |1        |            |3    |4
                                                               2
                            H   H  O  H - - - O  H- - - O  H - - - O  H
                                               
                                    H                  H             H         H
                                        |1             |2             |3        |4
                           - - - H  O- - - H – O  H - - - O  H - - - O  H
                                                       
                                  H                    H             H         H
                                   |1                  |2            |3         |4
                           – H  O – - - -H – O- - - H – O  H - - - O  H
                                                                     
          You can see how hydrogen ion jumps from O1 to O2, O2 to O3, ......., this
          result is equivalent to as the migration of charge from left to right. This
          conduction mechanism is more like a charge than ion movement. Such
          conduction is possible because of the peculiar structure of water and therefore
          only found in hydrogen-bonded solvents.
      where   (t) and   (25) are the value of molar conductivities at t and
      25oC respectively, and x is a constant for each electrolyte. For salts x is
      about 0.022 to 0.025 and for acids and bases it is usually 0.016 to 0.019.
      It means that molar conductivity increases approximately by 2% for
      every one degree rise in temperature. For strong electrolytes, even at
      appreciable concentration,
      Eq. (10.15) holds well, whereas in case of weak electrolytes, the
      variation of  with temperature is not so regular. The rise in conductance
      with temperature is due to the decrease in the viscosity of the solution,
      increase in the speed of the ions and an increase in the degree of
      ionization in cases of weak electrolytes.
  0 = constant … (10.16)
SAQ 4
List the factors which are affecting the conductivity of the solution.
                                                             i1       i2
                                                    R1                              R2
                           S
                                             B                                           D
                                                         G                      K
                               _
                                                    i1
R3 i2 RX
          To measure the resistance Rx, the tapping key K is held down momentarily
          and the bridge is balanced by adjusting R3 to get no deflection in galvanometer
          under these conditions.
          In the bridge the total current is divided into two paths: i1 through R1 and R3,
          and i2 through R2 and Rx. Under the balancing conditions, the potential at
          points B and D must be the same, i.e. the ohmic voltage drop through the
          resistors R1 and R2 must be the same. Hence, the potential at B (EB) must be
          equal to potential at D (ED).
EB = ED … (10.17)
Or i1 R1 = i2R2 … (10.18)
Similarly, i1 R3 = i2 Rx … (10.19)
                           R2R3
          and       Rx                                                                      … (10.20)
                            R1
  76
Unit 10                                                                             Conductometry
E0 = Ei (Rf/Rx + 1)
E0 = Ei(RfG + 1)
Rf
                                            _
                                                            D
                                                       E0
                                            +
                          Rx
                                     Ei
(i)     Since a direct current would polarize the electrodes in the conductivity
        cell by electrolyzing the solution; to avoid polarization an alternating
        current (ac) source of power must be used in place of a dc source
        (battery) usually ac voltages of 3-6 volts with frequency of 50 Hz or
        1000 Hz used across points A and C of Fig. 10.5.
(iii)   Since, the cell also acts like a small capacitor (Cx), and to balance its
        capacitive resistance a variable capacitor, CB, must be inserted into the
        bridge.
(iv)    The balance indictor (BI) may be an ac galvanometer, but some other
        devices may also be used:
R1 R2
                               ac
                                         B                            BI                      D
                                                                                                  Conductivity cell
                                                        R3
                                                                                RX
                                              CB
                                                                                             CX
                                                                      C
Conductometer
                                                               Read
                                         .4 .8 1.2             Cal.
                                     0               1.6
                                                         2.0                  Sensitiv ity
                                                                  mS range
                                                                  selector
Conductometer
Cells
Various types of cells have been designed and are in use for the
measurement of conductance of a solution. These are made of Pyrex glass
fitted with electrodes of platinum or gold. To overcome the imperfections in the
current and the other effects at the electrodes, these are coated with a layer of
finely divided platinum black. This is achieved by electrolyzing a 3% solution of
chloroplatinic acid containing a little of lead acetate. The distance between the
electrodes is determined by the conductance of the solution to be measured.
For highly conducting solution, the electrodes are widely spaced whereas for
low conducting solutions the electrodes are mounted near each other. A cell
suitable for conductometric titration is depicted in Fig. 10.7 (a, b and c); the
electrodes are firmly fixed in the Perspex lid which is provided with opening for
the stirrer and the jet of the burette. A magnetic stirrer can be used in place of
mechanical stirrer.
For most purposes a special cell is not required and good results are obtained
by clamping a commercially available dip cell [shown diagramatically in
Fig. 10.7 (b)] inside a beaker which is placed on a magnetic stirrer. With this
arrangement, the dipping cell should be lifted clear of the solution after each
addition from the burette to ensure that the liquid between the electrodes
becomes thoroughly mixed. Since absolute conductivity values are not
required it is not necessary to know the cell constant.
2. Put the frequency selector switch to required frequency (say 1000 Hz).
3.      Set the mode selector on CAL and set the range selector on the desired
        setting e.g., 2, 20 or 200. These figures refer to the full scale meter value             79
Block 3                                                Thermal and Electroanalytical Methods
                  in milli Siemens (mS). With the help of sensitivity knob keep the pointer
                  roughly midway between the lowest and highest sensitivity say at 1
                  position.
          5.      Take the standard KCl solution (say 0.1M) in a clean beaker. Introduce
                  a stirring rod (to be used for magnetic stirring) in the solution and put the
                  solution beaker on a magnetic stirrer plate.
          6.      Insert the conductivity cell in the solution. Ensure that the platinum plate
                  electrodes are completely immersed in the solution and they do not
                  touch the stirring rod or the sides or the bottom of the beaker.
          9.      Remove the KCl solution from the beaker, wash the conductivity cell
                  properly with distilled water. Take the unknown solution in the beaker
                  and measure its conductance, Gu, in the manner as for standard KCl
                  solution.
          10.     Calculate the cell constant, from the conductance and conductivity
                  values of the standard,
                              Conductivi ty (specific conductanc e)
                  K cell 
                             Observed conductanc e of the standard
                                   S
                  K cell cm 1         cm 1
                                   GS
          12.     For titration work, the value of cell constant, Kcell is not required to be
                  calculated, since the cell constant will remain unchanged during the
                  course of any given titration.
Notes:
          (ii)    The conductivity cell, when not in use, should be kept in distilled water to
                  prevent drying the platinum electrodes.
          (iii)   In case of fouling the conductivity cell electrode plates, clean them by
                  keeping in dilute K2Cr2O7 containing H2SO4 solution (i.e. dilute chromic
                  acid) for 24 hours and then washing with running water followed by
                  rinsing with distilled water.
  80
Unit 10                                                                                Conductometry
SAQ 5
At 298 K, the resistance of 2.00  102 M KCl is 195.96  and that of 2.50  10-
3
  M K2SO4 is 775.19 . The conductivity () of 2.00  102 M KCl at 298 K is
0.2768 S m1. Calculate molar conductivity of K2SO4 solution.
Perhaps the most common application of direct condutometry has been for
estimating the purity of distilled water. Kohlrausch with a painstaking work
after 42 successive distillations of water in vacuo obtained a conductivity water
with specific conductance,  = 4.3 × 10‾8 S cm‾1 at 180C. Traces of an ionic
impurity will increase the conductance appreciably. Ordinary distilled water in
equilibrium with the carbon dioxide of the air has a conductivity of about
7.0 ×10–7 S cm–1. The sea water has much higher value of conductivity and
the conductometric measurements are widely used to check the salinity of
water in oceanography.
Conductometric Titrations
          The principle of conductometric titration is based on the fact that during the
          titration, one of the ions is replaced by the other and invariably these two ions
          differ in the ionic conductivity with the result that conductivity of the solution
          varies during the course of titration. The equivalence point may be located
          graphically by plotting the change in conductance as a function of the volume
          of titrant added.
          The main advantages to the conductometric titration are its applicability to very
          dilute, and coloured solutions and to system that involve relative incomplete
          reactions. For example, which neither a potentiometric, nor indicator method
          can be used for the neutralization titration of phenol (Ka = 10–10) a
          conductometric endpoint can be successfully applied.
          1. Strong Acid with a Strong Base, e.g. HCl with NaOH: Before NaOH is
             added, the conductance is high due to the presence of highly mobile
             hydrogen ions. When the base is added, the conductance falls due to the
             replacement of hydrogen ions by the added cation as H+ ions react with
                
             OH ions to form undissociated water. This decrease in the conductance
             continues till the equivalence point. At the equivalence point, the solution
             contains only NaCl. After the equivalence point, the conductance increases
             due to the large conductivity of OH- ions (Fig. 10.8).
          Fig. 10.8: Conductometric titration of a strong acid (HCl) vs. a strong base
  82      (NaOH)
Unit 10                                                                          Conductometry
2. Weak Acid with a Strong Base, e.g. acetic acid with NaOH: Initially the
   conductance is low due to the feeble ionization of acetic acid. On the
   addition of base, there is decrease in conductance not only due to the
   replacement of H+ by Na+ but also suppresses the dissociation of acetic
   acid due to common ion acetate. But very soon, the conductance increases
   on adding NaOH as NaOH neutralizes the un-dissociated CH3COOH to
   CH3COONa which is the strong electrolyte. This increase in conductance
   continues raise up to the equivalence point. The graph near the
   equivalence point is curved due the hydrolysis of salt CH3COONa. Beyond
   the equivalence point, conductance increases more rapidly with the addition
                                            
  of NaOH due to the highly conducting OH       ions (Fig. 10.9).
3. Strong Acid with a Weak Base, e.g. sulphuric acid with dilute
   ammonia: Initially the conductance is high and then it decreases due to the
   replacement of H+. But after the endpoint has been reached the graph
   becomes almost horizontal, since the excess aqueous ammonia is not
   appreciably ionised in the presence of ammonium sulphate (Fig. 10.10).
4. Weak Acid with a Weak Base: The nature of curve before the
   equivalence point is similar to the curve obtained by titrating weak acid
   against strong base. After the equivalence point, conductance virtually
   remains same as the weak base which is being added is feebly ionized
   and, therefore, is not much conducting (Fig. 10.11).
                                                                                           83
Block 3                                            Thermal and Electroanalytical Methods
  84
Unit 10                                                                               Conductometry
10.5 SUMMARY
In this unit, various parameters like resistance (R), conductance (G), resistivity
(), conductivity(K), equivalent conductivity(eq), molar conductivity(m), molar
conductivity at infinite solution(o) and cell constant have been defined in
detail along with their units for measurements. The relationships among these
parameters have also been worked out.Various factors affecting the
conductance of solution are also given. At the end detail procedure for the
measurement of conductance is given.
6.    The conductivity of 0.1 M HCl is 0.0394 -1 cm-1. What is the molar
      conductivity of the solution?
8.    A certain conductance cell was filled with 0.0100 M solution of KCl, whose
      conductivity is 0.001409 -1 cm-1 (S cm-1) at 25oC, it had a resistance of
      161.8 , and when filled with 0.0050 M NaOH, it had a resistance of
      190 . Calculate the cell constant, conductivity and molar conductivity of
      NaOH solution.
10.   The resistance of a conductivity cell was 702 ohms when filled with 0.1 M
      KCl when filled with 0.1 M KCl solution (K = 0.14807 ohm-1 m-1) and 6920
      ohm when filled with 0.01M acetic acid solution. Calculate the cell constant
      and molar conductance for the acid solution.
                                                                                                85
Block 3                                                 Thermal and Electroanalytical Methods
          10.7 ANSWERS
          Self-Assessment Questions
                                  7.38×10-3 S m-1
               m = K/c =              -4   3     -1
                                                     = 1.476  10–2 S m2 mol−1
                               5.0 × 10 ×10 molm
Kcell =   R
= 54.24 m1.
                     K cell            54.24 m 1
               =                                  =    0.06997 S m1.
                      R                775.19 
                              0.06997
               Λm                    Sm 2mol 1
                       c         2.50
                           = 0.028 S m2 mol1
  86
Unit 10                                                                             Conductometry
Terminal Questions
1.   The ionic compounds which forming ions in solution and conduct electric
     current are called electrolyte e.g. MaCl, KCl etc. They can be classified
     strong and weak electrolyte on the basis of their degree of ionisation.
                                              1000 
      Λm                     S m 2 mol 1           S cm 2 mol 1 κ
              c       M1000                      M
Λeq  V
Relationship
4.   To overcame the imperfection in the current and the other effects at the
     electrode.
7. m = K/c, therefore,
m = 0.0394 ( -1 cm-1)/ 0.1 M =0.0394 (-1 cm-1)/0.1  103 mol cm3
          =1/96 (-1 cm-1)  1/0.1  103 (mole cm-3) =104.16 -1 cm2 mol-1
                                                                                              87
Block 3                                              Thermal and Electroanalytical Methods
                m = K/c = 1.2  10-3 -1 cm-1/ 0.0050  103 mol cm-3 = 240 -1 cm2
                mol–1
          11.   Cell constant = KR = (0.14807 702) (ohm-1 m-1) (ohm) =103.94 m-1
                = 1.039 cm-1
88