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Tugas 2 Ekonomi Teknik Kimia

Estimating cost of equipment using scaling factors and cost index. The purchased cost of a 50 gal glass-lined, jacketed reactor (without drive) was $8350 in 1981. Estimate the purchased cost of a similar 300 gal glass-lined, jacketed reactor (without drive) in 1986. Use the annual average Marshall and Swift equipment-cost index (all industry) to update the purchase cost of the reactor.

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0% found this document useful (0 votes)
100 views6 pages

Tugas 2 Ekonomi Teknik Kimia

Estimating cost of equipment using scaling factors and cost index. The purchased cost of a 50 gal glass-lined, jacketed reactor (without drive) was $8350 in 1981. Estimate the purchased cost of a similar 300 gal glass-lined, jacketed reactor (without drive) in 1986. Use the annual average Marshall and Swift equipment-cost index (all industry) to update the purchase cost of the reactor.

Uploaded by

Fina Nahdiana
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© © All Rights Reserved
We take content rights seriously. If you suspect this is your content, claim it here.
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NAMA : Fina Nahdiana

NIM : 21103022026

KELAS : Tekkim B

TUGAS 2 EKONOMI TEKNIK KIMIA

1. Estimating cost of equipment using scaling factors and cost index. The purchased cost of
a 50 gal glass-lined, jacketed reactor (without drive) was $8350 in 1981. Estimate the
purchased cost of a similar 300 gal glass-lined, jacketed reactor (without drive) in 1986.
Use the annual average Marshall and Swift equipment-cost index (all industry) to update
the purchase cost of the reactor.
Penyelesaian :
2. The purchase price of a 500-gal reactor in 1950 was $6,000. What would be the
purchased cost of such a reactor in 1953? What would be the price of a 1,000-gal reactor
in 1953? (use Marshall and Stevens process-industry indices; 1950 index =167, 1953
index = 181).
3. It is desired to be able to pump 3,000 lb per hour of a liquid whose density is 50 lb per cu
ft through 100 ft of dur iron pipe of the most economic pipe diameter. The line will
contain 15 fittings and 3 valves
a. What pipe diameter should be employed?
b. What will be the installed cost of such a line?
c. If the line is insulated with 1 ½ in. 85 percent magnesia what will be the
insulation cost?

Penyelesaian :

a) Dari hasil pembacaan dari grafik, economic pipe diameter vs flow 1,000 pound/hr
diperoleh 1 inches pipe diameter.
b) Dari hasil pembacaan grafik pipe,
 dur iron pipe (30% of material cost equals installation) 1 inch $7.5*100 = $750
 fitting(125% of material cost equals installation) 1 inch $11*15 = $165
 valve(25% of material cost equals installation) 1 inch $60*3 = $180 ~ total $1,095
c) 1,5 in magnesia insulation cost didapat dari
(x-x1) / (x2-x1) = (y-y1) / (y2-y1)
(1.5-1) / (2-1) = (y-1.75) / (2.20-1.75)
( 0.5 * 0.45)+1.75 = y
y = $1.975

4. A one-story 20 ft high warehouse 100 ft by 60 ft in size is to be erected on 60 piles and


will be constructed of a reinforced-concrete floor, cinder-block walls, and a corrugated-
steel roof. What will be the cost of the building complete with sprinklers, heating and
lights?

Penyelesaian :

Diketahui :

 reinforced-conrete floor cost $1.40/sqft


 cinder-block walls cost $1.30/sqft
 corrugated steel roof cost $0.70/sqft
 springklers $0.50/sqft of floor area
 heating $1.00/sqft of floor area
 lighting electrical warehouse $0.50/sqft of floor area
 Floor area = 100ft * 60ft = 6000 sqft
 wall area = 2 * 20ft * 100ft + 2 * 20ft * 60ft = 6400 sqft
 roof area = floor area = 6000 sqft
Perhitungan total pembuatan warehouse

Total cost warehouse = floor + wall + roof + springklers + heating + lighting electrical +
pilling

= 6000 * $1.40 + 6400 * $1.30 + 6000 * $0.70 + 6000 * $0.50 + 6000


* $1.00 + 6000 * $0.50 + $100 * 60

= $38,920

5. It has been determined that a new process installation will require 10,000 lb per hr of
steam, 1,000 kva of electricity, and 30,000 gph of tower water. What will be the installed
cost of these utilities.

Penyelesaian :

Diketahui :

 Steam Cost $5/lb/hr


 Electricity Cost $200/kva
 well water $0.40 /gph
 Dibutuhkan 10,000 lb steam/hr ; 1,000kva of electricity ; 30,000 gph

Total cost to be installed these utilities is = steam cost + electricity cost + well water cost

= ($5/lb/hr * 10,000 lb) + ($200/kva * 1,000 kva) + ($0,40/gph * 30,000 gph)

= $50,000/hr + $200,000 +$12,000

= $262,000 /hr

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