ELECTRICAL ENGINEERING
LECTURE NOTES
                         CIRCUIT THEORY
                         Mr Ted Spooner &
                            Dr B. Farah
                THE UNIVERSITY OF NEW SOUTH WALES,
                SCHOOL OF ELECTRICAL ENGINEERING
                               2002
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1.       INTRODUCTION:
Reasons for studying the “Circuit Theory”:
  To be able to understand the principles, specifications and performance of
  electrical and electronic devices (eg. filters, amplifiers), transformers, power
  supplies and machines (eg. DC and AC motors).
  To be able to communicate effectively with electrical engineers.
  Electrical systems are an integral part of many mechanical & mining systems.
  Mechanical Engineers need to have a broad understanding of important electrical
  issues.
  Need to know of electrical options for measurement and control of mechanical
  systems.
2.       The International System of Units “SI”
     2.1.       Basic Units
Quantity                  Symbol               Unit                Unit Symbol
Length                    l                    Metre               m
Mass                      m                    Kilogram            kg
Time                      t                    Second              s
Electric Current          I or i               Ampere              A
Temperature               T                    Kelvin              K(=273 + deg.C)
     2.2.       Mechanical Units Based on SI
Quantity                Qty. Symb.               Unit               Unit Symb.
Velocity                u                        metre/second       m/s
Acceleration            a                        metre/(second)2    m/s 2
Force                   F (= ma)                 newton             N
Weight                  W (= mg = 9.81m)         newton.            N
Turning Moment or Torque T (=F.r)                newton.metre       N.m
Work or Energy          W.D. or E                joule              J (= 1 N.m)
                                                 Megajoule          MJ(= 106 J)
                                                 watt second        W.s(=1J)
                                                 watt hour          W.h(=3600J)
                                                 kilowatt hour      kW.h(=3.6MJ)
Angular Velocity              ω                  radian/second      rad/s
Frequency                     f                  hertz              Hz
                                                 kilohertz          kHz(=103 Hz)
                                                 Megahertz          MHz(= 106Hz)
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     2.3.   Electrical Units Based on SI
Quantity                            QtY.Symb.          Unit             Symb.
Charge (or Qty. of Electricity)     Q, q               coulomb            C
Current                             I, i               ampere             A
                                                       milliampere        mA
                                                       micro-ampere       µA
Potential Difference or Voltage     V. v               volt               V
or Electromotive Force              E                  millivolt          mV
                                                       kilovolt           kV
Resistance                          R                  ohm                Ω
                                                       Micro-ohm          µΩ
                                                       Mega-ohm           MΩ
Conductance                         G(= 1/R)           siemens            S
                                                       or mhos            Ω -1
Capacitance                         C                  farad              F
                                                       microfarad         µ F(=10-6F)
                                                       nanofarad          nF(=10-9 F)
                                                       picofarad          pF(=10-12 F)
Inductance                          L                  henry              H
Power                               P                  watt               W
                                                       kilowatt           kW
3.      FUNDAMENTAL CONCEPTS:
     3.1.   Classification of Electrical Components:
        All electrical components can be placed in one of two groups:
                                  Electrical Components
             Active elements:                     Passive elements:
             voltage source, current source,      resistor, inductor, capacitor, diode, etc.
             (which do supply energy to a         (which do not supply energy to a
             circuit).                            circuit; rather they dissipate or store
                                                  energy).
   3.2.     Basic Components
          The three main passive components are:
       3.2.1.       Resistor:
       The current through a resistor is directly proportional to the voltage across it.
        OHM’s LAW:                        V       =    IR
V-I relationship for a resistor
                                  Volts
                                              Amps          Ohms
                                   (V)
                                               (A)           (Ω)
       3.2.2.       Inductor
           Wire wound coil. The magnitude of the induced voltage is proportional to
           the rate of change of the current flowing through the coil.
V vs I relationship for an inductor
                                              L:     inductance (henrys) usually      µH
                                              (microhenrys) or mH (millihenrys)
                                  di
                v    =    L
                                  dt
   3.2.3.         Capacitor
       Two parallel plates. The charge on the plates is proportional to the voltage
       between the plates:
                    q = Cv
                    However, as the current is defined as the rate of flow of charge,
            ie:
                          dq        dv
                     i=        =C         C: Capacitance (farads)
                          dt        dt
                    Or
                                         1
                               dv    =     idt
                                         C
   V vs I relationship for a capacitor
                             1               The farad is rather large, hence the
                     v=        idt           units to be used practically are:
                             C
                                             Microfarad     = 10-6 farads = µF
                                             Nanofarad      = 10-9 farads = nF
                                             Picofarad      = 10-12 farads = pF
3.3.   Fundamental Terminology:
   3.3.1.         Symbols:
            The symbol convention used in this course is:
            Capital letters for the time independent quantities eg. R, C
            Small letters for the time-varying quantities eg. v. i.
3.3.2.      Nodes:
         A node in an electrical circuit is any point where 2 or more components
         have a common connection viz.
                             NODE
3.3.3.      Branches:
         A branch is the part of a circuit which exists between 2 nodes, viz.
                     BRANCH
3.3.4.      Loops:
         A loop is any physical loop, open or closed which can be described in a
         circuit:
                                                            Closed
     Open                                                   Loop
     Loop
3.3.5.   Current & Voltage Sign Conventions
    For the voltage sign convention (active or passive element) the terminal
    with algebraically highest potential is denoted by ' + ' and that with the
    algebraically lowest potential by ' - '. Thus the symbol representing a
    voltage generator is:
                              +    More general as it can be
                +
                                   used for both AC and DC
                                   sources.
    When a DC voltage generator (or a DC voltage source) is connected to a
    circuit, it drives current out of its positive terminal (and consequently into
    its negative terminal).
    If an external circuit of a resistor is connected to the voltage source, then
    the current flows into the resistor’s positive terminal. Note that the
    polarity of its terminals is established by the voltage source. Thus:
          For all passive elements, current flows in at the
                            positive terminal.
                                           +
                          +
         Voltage                               Voltage
         Rise                                  Drop
                                           -
3.3.6.      Open circuit Voltage & Short-Circuit Current
     a) Consider any circuit with two free terminals A and B. The open-circuit
        voltage at terminals A and B is the voltage which appears at the
        terminals with nothing connected between them, ie. infinite resistance
        between them.
                                   A
                       Circuit
                                     Vo/c
                                   B
                 Open Circuit Voltage Vo/c = voltage across 2 terminals
                                             which are not connected in
                                             any way.
                                             (i.e. RAB=∞)
         b) if terminals A and B are connected together with a piece of wire i.e.
            zero resistance, then the short-circuit current is the current that
            flows along the wire.
                        CIRCUIT                          ISC
                Short Circuit Is/c = current which flows between 2 terminals
                                  when connected directly together.
                                  (i.e. RAB = 0)
3.3.7.      Electric Power
A considerable part of electrical technology is concerned with the transmission
of power, so it is appropriate to take a quick look at the basic relations here. In
an electric circuit:
                           Power, P = v.i. watts
     Power is the rate of doing work, or the rate of change of energy in a system,
     i.e.
                                              dW
                                         P=
                                               dt
                    Where:
                         W:        energy or work for an electrical system in joules:
                    W = Pdt = vidt
              As an example, consider the dissipation of power in a resistor in
            watts:
            PR      =     vi       =      i2R       =       v2/R
             which gives the power dissipated in a resistor (due to a current flowing
            through the resistor) and lost as heat.
4. KIRCHHOFF'S LAWS
  4.1.   KIRCHHOFF'S VOLTAGE LAW
  It states that the algebraic sum of the voltage drops around any loop, open or
  closed, is zero.
                                   V =0
  Mathematically:
                        AroundLoop
  Example
                                          2Ω
                                     +                  -
                                                                 +
                               +
                    10V
                                              I                    3Ω
                                                             -
     Going round the loop in the direction of the current, I, Kirchhoff's Voltage Law
     gives:
                                   10- 2I - 3I = 0
    - 2I and - 3I are negative, since they are voltage drops
   i.e. represent a decrease in potential on proceeding round the loop in the
   direction of I. For the same reason + 10V is positive as it is a voltage rise or
   increase in potential.
   Concluding:
                 5 I = 10            Therefore, I = 2A
4.2.   KIRCHOFF'S CURRENT LAW
   It states that the algebraic sum of all currents entering a node is zero.
   Mathematically:
                     I =0
              Into a node
           Currents are positive if entering a node
           Currents are negative if leaving a node.
         Example:
                                I2 = -3A
                   I1= 5A
                                                      I3
              I4 = 2A
         Applying Kirchhoff's current law:
                                   I1 + I2 + I3 + I4 = 0
         (the negative sign in I2 indicates that I2 has a magnitude of 3A and is
         flowing in the direction opposite to that indicated by the arrow)
         Substituting:
                5 - 3 + I3 + 2 = 0       Therefore, I3 = - 4A (ie 4A leaving node)
5. CIRCUITS
A circuit is an interconnection of components, and as most electrical components are
2-terminal devices, such as a resistor, many of their interconnections can be resolved
into series and parallel branches.
   5.1.   SERIES CONNECTION OF RESISTORS:
   Common Current = I = V1 / R1 = V2 / R2 = V3 / R3
                     = ( V1 + V2 + V3 )/ ( R1 + R2 + R3 ) = VT / RS
                    As VT = V1 + V2 + V3       Therefore, RS = R1 + R2 + R3
             RS is an equivalent resistor that has the same voltage across it, and the
             current through it as that through the 3 resistors in series.
      Example
      Total Resistance = 6 + 8 = 14Ω
      5.2. PARALLEL CONNECTION OF RESISTORS
      Common Voltage: V = I1 R1 = I2 R2 = I3 R3 = IT RP
      As IT = I1 + I2 + I3    Then, V/RP = V/R1 + V/R2 + V/R3
      Therefore, 1/RP = 1/R1 + 1/R2 + 1/R3 , or, GP = G1 + G2 + G3
      Where, RP is the equivalent resistor, and GP the equivalent conductance (often
      useful in parallel circuits).
       For 2 resistors, 1/RP = 1/R1 + 1/R2 = (R2 + R1 )/R1R2 ie. RP = (R1R2)/(R1 + R2)
       Example:
  Equivalent resistance, RP = (6 x 8 )/(6 + 8) = 48 / 14 = 3.43Ω
6. CHARACTERISTICS
The characteristic of a device, circuit, or system is a functional relationship between a
dependent variable of interest and an independent variable. The description of a
circuit, etc. by means of its characteristic allows the prediction of its operational
conditions without the digression into perhaps unwanted detail as in the loop current
method of analysis which produces every current and voltage in the circuit.
   6.1.   RESISTOR
The V-I relationship for a simple resistor (load line) is given by Ohm's Law which may
be plotted thus:
The resistor can only have values of voltage across it, and current flowing though it,
which are consistent with its characteristic. This is true for any device or system.
   6.2.   IDEAL VOLTAGE SOURCES
An ideal voltage source is represented in the diagram. For this ideal source V is
constant for all I, and its open circuit voltage: Vo/c = E.
We could also make I the dependent variable and plot the characteristic as:
   6.3.    NON-IDEAL VOLTAGE SOURCE
   Non-ideal voltage source, for example a torch battery, can be modelled or
   represented by an ideal voltage source in series with a resistor.
                                                               V
                           Internal                                         Slope = dV/dI
                                                           VOC = E
                           Resistance                                         =d(E-IRi)/dI
                                                 +                            = -Ri
            E                           I
                   +                              V
      Ideal                                                                      V = E-IRi
      Voltage
      Source                                     -
                                                Non-Ideal
                                                                                       ISC   I
                                                Voltage
                                                Source
Here, taking KVL around the loop :
   - IRi - V + E = 0                  Therefore, V = E - IRi
The V-I relationship for the non-ideal source shows that as the current drawn from
the source, I, increases, the voltage drop across the internal resistance, IRi ,
increases. Since E remains constant this reduces the voltage V, available at the
output terminals,
Therefore, V is not constant for all I
The V-I characteristic can be plotted from the equation, V = E – IRi , as shown in the
above figure. From this equation:
If I = 0 (open circuit), then Vo/c = E, and if V = 0 (short circuit), then Is/c = E / Ri
Comparing the characteristics for the two types of voltage sources we can comment
on the internal resistance of both:
The internal resistance of ideal V-source = 0Ω , and of non-ideal V-source = Ri Ω.
                                                         I
                      Internal                                      Slope = dI/dV
                      Resistance                      ISC = E/RiI
                                                                          = -1/Ri
                                          +
                                                                          = -G
        E                         I
              +                            V
  Ideal
  Voltage
  Source                                  -
                                         Non-Ideal
                                                                       VOC = E      V
                                         Voltage
                                         Source
We could of course rearrange our equation to make I the dependent variable and V
the independent variable as shown below:
As, V = E - I Ri , then, I = ( E/Ri ) - ( V / Ri ).    Slope, dI/dV = - 1 / Ri
Example
Kirchhoff’s Voltage Law (KVL) around the loop:
- 2 I - V + 10 = 0         Therefore, V = 10 - 2 I.
7.      VOLTAGE REGULATION:
By comparing the V-I characteristics for the ideal and the non-ideal cases, we can
see how good a representation of constant voltage source is the non-ideal source.
We would prefer to have a voltage source whose terminal voltage remained constant
over a wide range of currents. However, in real life we are usually dealing with non-
ideal sources where, as a result of the internal resistance of the source, the terminal
voltage decreases as the current increases.
The usual method of characterising the change in the terminal voltage V. with change
in current drawn from the voltage generator is to specify the regulation of the
generator. This is a measure of how constant V remains as the source goes from the
'no load' condition to the 'full load' condition as explained below. It is particularly
important when considering transformers and electrical machinery.
                                                                 V
                        Ri                                 VOC = E           V = E-IRi
                                            B
                                                +
            E                       I
                 +                              V
                                                -
                                            A
                                                                                             I
No-load condition means that no load resistor is connected between A and B
i.e. , I = 0 ,   .'. Vno load = Vo/c = E (for this circuit).
Connecting a load resistor:
                                                             V                   Operating
                                                                                 Point
                 Ri                                  Vno load
                                   B
                                       +            VFull Load
 E                           I
        +                               V
                                            RL
                                                                     Load Line
                                       -
                                   A                                             IMax    I
Full load condition: The load resistor is connected between A and B such that I has
its maximum possible value. (This means that if I were to exceed Imax the generator
would burn out.)
Therefore, I = E / ( Ri + RL ) , and Vfull load = I RL = E RL / ( Ri + RL ) < Vno load .
The 'regulation' of a voltage source is a measure of how constant the terminal
voltage remains as the circuit goes from the 'no load' to the 'full load' condition.
                                    V no − load − V full −load
Voltage Regulation =                                             ×100%
                                           V full − load
Example:
With the load resistor (4Ω ) disconnected, RAB = ∞ ,       ∴   I = 0,   hence
V = Vno-load = 10V.
With the load resistor now connected,    I = 10 / ( 1 + 4) = 2A.
∴ V = Vfull-load = 2A x 4Ω = 8V
(Alternatively, V = 10 - 2A x 1Ω = 10 - 2 = 8V)
∴ Voltage Regulation = 10 - 8 x 100 % = 25 %
                              8
8. THEVENIN'S THEOREM
Quite often, particularly in a complex circuit we need more information than just the operating
conditions which we could obtain from the characteristics, but at the same time we are not
interested in every voltage and current in the circuit as would result from a loop current
analysis. For example, consider the circuit of a DC transmission system such as that found in a
car, we may be confronted by this multi-loop circuit.
                                                                         Appliance of
                                                                         interest say
                                 Lead Resistance
                                                                         radio
                                                                            I       A
V
      +
                                                                            V
                                                                                B
                Appliances, Lights, Motors etc
If we are interested only in what current is drawn by the load (radio), clearly we have quite a
task ahead of us, if we set up, say 4 loop equations, and find every loop current. It would be a
decided advantage if we could replace everything to the left of line AB by a much simpler, yet
EQUIVALENT CIRCUIT. By equivalent we mean having the same V-I characteristics at the
terminals A and B.
Thevenin's Theorem gives us just such an equivalent circuit. In fact it is a method of modelling
or simulating the behaviour of a complex circuit whose actual configuration may be unknown,
but whose characteristics at its output terminals are well known.
8.1. DEFINITION OF THEVENIN'S THEOREM
It states that any complex, linear, active or passive 2 terminal network may be
modelled by an ideal voltage source in series with a resistor.
                                                                RT
     Linear                I                                                I
                                                 ET
                                    V                  +                                V
     Network
                                                           V
V-I Relationship: V = ET - I RT                        VOC = ET
ET :  Vo/c at terminals (A and B) of                                   Slope = dV/dI = -RT
       the linear network
RT : Resistance of the Linear network at
terminals (A and B) with all energy sources
replaced by their internal resistances.
                                                                                         I
                                                                          ISC =ET/RT
Example:
Consider the following linear network, determine the V- I characteristic at its output
terminals, then calculate the Thevenin's equivalent of the circuit, plot its V-I
characteristic and see if there is any connection:
            I1        2Ω             I         4Ω        A
                                                          +
50V
                           I2                                    V
                                  2Ω
                                                             -
                                                         B
Derivation of the V- I characteristic at terminals A and B using Kirchoff's laws:
Using Kirchoff's current law.
I1 − I 2 − I = 0
Using Kirchoff's voltage law around first loop:
50 - 2I1 - 2I2 =0
Using Kirchoff's voltage law around second loop:
2I2 - 4I - V = 0
Substituting current equn in first loop eqn:
50 - 2(I2+I) - 2I2 =0
50 - 4I2 - 2I =0
From 2 nd loop eqn
2I2 = 4I + V
Substituting in above
50 - 2(4I + V) - 2I =0
50 - 10I - 2V = 0
V = 25 -5I
    V
V OC = 2 5V
                    S lo p e = d V /d I = -5 Ω
                                                 I
                               IS C = 5 A
Plotting the V-I relationship:
if A - B short-circuited V = 0 and I = 5A
If A - B open circuited then I = 0 and V = 25V
Superposition
    Y1
       Y1
                 x1              x2 (x1+x2)                        X
If an output is a linear function of an input parameter y = f(x) and y=0 when x=0.
then f(x1+x2) = f(x1) + f(x2) = y1 + y2
Consider a linear deflecting beam:
                                          F1
                                                 D1
                                          F2
                                                 D2
                                      F1+F2
                                                 D1+D2
If the deflection of the beam is completely linear or that the only region we are studying is the
linear region then if:
     we apply a force of F1 and get a deflection D1
     we apply a force of F2 and get a deflection D2
Then if we apply a force of F1+F2 we will get a deflection D1+D2.
     Another similar example using the same beam is shown below only now the forces are
     applied at different positions.
                                                         F1
                                                              D1
                                                F2
                                                              D2
                                                F2      F1
                                                              D1+D2
     The same superposition applies....
     If:
         we apply a force of F1 and get a deflection D1
         we apply a force of F2 and get a deflection D2
     Then if we apply a force of F1 and F2 we will get a deflection D1+D2
     So we can for such a system do tests or analysis of the system and apply forces separately and
     look at the systems reaction. The result of applying both forces simultaneously is the sum of
     the individual reactions.
                                        Superposition in circuits
     The same principle may be used in analysing circuits.
     ie if cause and effect are linearly related then the total effect of several causes is the sum of
     the effects of the individual causes .
     Consider the circuit below.
                                                R1            V2
                                                           +
                                    +
                                                                         I3
                          V1
                                                             R2           R3
     We could analyse this circuit by doing loop analysis or writing down all the node equations
     but it can be simpler to solve two separate simpler circuits and find the currents due to each
     voltage source individually and then to sum the results.
     I3 =    sum of effects of each voltage source taken individually.
                    R1                                                 R1            V2
                                                                                  +
       +                                      I31                                               I32
V1
                                R2             R3                                 R2             R3
I3 = I31 + I32
Note: When a source is removed it is replaced by its internal resistance...
   for an ideal voltage source this is 0Ω or a short circuit.
   for an ideal current source this is ∞Ω or an open circuit.
Example of circuit with Current Source
               R1
      +
                                      I3
V1
                       R2      I2     R3
This is analysed in two parts as before
1)      by open circuiting the current source I2 as shown below and calculate I31.
              R1
      +
                                      I31
V1
                       R2              R3
2)    put current source back and replace the voltage source V1 by a short circuit and
calculate I32.
               R1
                                      I32
                       R2      I2     R3
Again
I3 = sum of effects of each source taken individually.
I3 = I31 + I32