PROBLEM #1:
A tank can be filled by three pipes separately in    PROBLEM #8:
20, 30 and 40 minutes respectively. In how many      One crew can do a job in 10 days. After this crew
minutes can it be filled by the three pipes acting   had worked for 4 days, another crew joins him
together?                                            and together they complete the job in 4 more
       a. 10.69 mins.         b. 1.23 mins           days. How long could the second group have
       c. 9.23 mins           d. 8.19 mins           done the job alone?
                                                            a. 15 days           b. 18 days
PROBLEM #2:                                                 c. 18 days           d. 20 days
In problem #1, if only the first two pipes will be
opened, how long will it take to fill up the tank?   PROBLEM #9:
       a. 20 mins              b. 115 mins           Two pipes can fill up a tank alone separately in 3
       c. 12 mins              d. 31mins             and 2 hours respectively. When a third pipe is
                                                     used to help with the first two pipes, the tank can
PROBLEM #3:                                          be filled in 1hr. How long can the third pipe fill the
A and B working together can complete a job in       tank alone?
30 hrs. A works twice as fast as B. How many                  a. 8 hrs.             b. 2 hrs.
days! would it take A working alone to complete               c. 5 hrs.             d. 6 hrs.
the job?
       a. 45 hrs.            b. 20 hrs.              PROBLEM #10:
       c. 15 hrs.            d. 8 hrs.               Two pipes running simultaneously can fill a tank
                                                     in 8 hrs. If both pipes run for 4 hrs. and the first is
PROBLEM #4:                                          then closed, it requires 12 hrs. more for the
Workman A's rate of doing work is twice that of      second to fill the pool. How long does it take the
workman B's. One day, A and B work together for      first pipe to fill the pool?
8 hrs; then B due to injury stops and A finishes              a. 11 hrs.              b. 22 hrs
the rest of the job in 2 hours. How long would it             c. 10 hrs               d. 12 hrs
take B to complete the job alone?
        a. 28 hrs.            b. 124 hrs.            PROBLEM #11:
        c. 32 hrs.            d. 6 hrs.              Two pipes running simultaneously can fill a tank
                                                     in 8 hrs. If both pipes run for 4 hrs. and the first is
PROBLEM #5:                                          then closed, it requires 12 hrs more for the
A contractor divided the total length of a road he   second to fill the pool.
had contracted to construct into 3 equal spans       When a third pipe is used simultaneously with
and assigned to each span a group of workers.        the first two pipes the tank can be filled in 4 hrs.
Each group has equal number of workers. The          How long would it take the third pipe alone to fill
first group finished the assigned span in 25 days,   the tank?
the second group                                              a. 8 hrs                b. 17hrs
in 20 days, and the third group in 18 days. How               c. 10 hrs               d. 12 hrs.
many days would be needed to finish one span if
the three groups were to work together?              PROBLEM #12:
         a. 10.57 days         b. 11 days            A pipe can fill a tank in 4 hrs if the drain is open.
         c. 6.87 days          d. 7.59 days          If the pipe runs with the drain open for 1 hour
                                                     and the pipe is then closed, the tank will be
PROBLEM #6:                                          emptied in 40 minutes more. How long does it
A farmer can plow a certain field twice as fast as   take the pipe to fill the tank if the drain is closed
his son. Working together, it would take them 4      right at the start of filling?
days to plow the field. How long would it take the            a. 1.6 hrs.             b. 15 hrs.
son to do it alone?                                           c. 12.4 hrs.            d. 24 hrs.
       a. 5 days              b. 11 days
       c. 12 days             d. 15 days             PROBLEM #13:
                                                     A, B and C can do a piece of work in 8 days. A
PROBLEM #7:                                          and B can do it in 10 days, A and C in 15 days.
A Mason can do a given job in 4 hrs. His helper      How many days I would it take for A to do the
can do the same job in 9 hrs. The mason begins       work alone?
working and after 1hr. Is joined by his helper. In          a. 24 days            b. 21 days
how many hrs. will they complete the job?                   c. 48 days            d. 32 days
       a. 2.08 hours          b. 4.87 hours
       c. 2.65 hours          d. 1.986 hours
Name: Vela, Niña P.      Year, and Section: 4B       PROBLEM #9:
ER1 │ ME Review 1       Age Problem                  Ten years ago, John was four times as old as
                                                     Bill. Now he is only twice as old as Bill. Find their
PROBLEM #1:                                          present ages.
Mary is 36 years old. Mary was twice as old as               a. 15 & 30             b. 10 & 20
Ann was when Mary was as old as Ann is now.                  c. 20 & 40             d. none of these
How old is Ann?
       a. 24                b. 25                    PROBLEM #10:
       c. 26                d. 27                    Ten years ago, I was three times as old as you
                                                     are. In six more years, I will be twice as old as
PROBLEM #2:                                          you are. How old are you?
A man is 25 years old and his son is 5. In how               a. 26                 b. 32
many years will the father be three times as old             c..33                 d. 30
as the son?
        a. 25                b. 3                    PROBLEM #11:
        c. 5                 d. 9                    The sum of the ages of the father and his son is
                                                     99. If the age of the son is added to the inverted
PROBLEM #3:                                          age of the father, the sum is 72. If the inverted
Ten years ago, Boyet was three times as old as       age of the son is subtracted from the age of the
Joy. Now he is 10 more than twice as old as Joy.     father; the difference is 22. What are their ages?
Find their present ages.                                      a. Son= 20 years old,
       a. 40 and 20         b. 30 and 70                         father= 74 years old
       c. 20 and 40         d. 20 and 60                      b. Son = 22 years old,
                                                                 father= 70 years old
PROBLEM #4:                                                   c. Son= 25 years old,
A man is 25 years older than his son. In 10                      father 70 years old
years, he will be 10 more than twice as old as his            d. Son= 25 years old,
son. How old is the son?                                         father= 74 years old
       a. 10                 b. 5
       c. 8                  d. 9                    PROBLEM #12:
                                                     The sum of the ages of a married couple and
PROBLEM #5:                                          their four children are 40 years over the century
Mara is 5 years older than her sister Clara. 10      mark. Ten years ago, the sum of the ages of the
years ago, Mara was twice as old as Clara. How       couple, the eldest child and the second child is 5
old is Mara?                                         decades and five less than the sum of all (the six
        a. 10              b. 20                     of them) their ages now. The father's age is 10
        c. 30              d. 40                     times the age of the youngest while the mother's
                                                     age is 8 times that of the youngest. The
PROBLEM #6:                                          difference between the ages of the second child
Kaye is now thrice as old as Koy. Five               and the sum of the age of the third and the last is
years ago, Kaye was 5 times as old as                zero, while
Koy. How old is Kaye.                                the difference between the ages of the first child
       a. 10.         b. 20                          and the sum of the ages of the second and the
       c. 30          d. none in the choices         last child is zero. Find their ages now.
                                                          a. F = 40, M = 50 1st = 20
PROBLEM #7:                                                   2nd = 15, 3rd = 8, 4th = 6
Olie is three times as old as Bong. Four years            b. F = 40, M = 50 1st = 20
ago, he was four times as old as Bong was at                  2nd = 15, 3rd = 10, 4th = 5
that time. How old is Bong?                               c. F = 45 M = 45 1st = 15
        a. 12                c. 13                            2nd = 10, 3rd = 8, 4th = 6
        b. 14                d. 16                        d. F = 55 M = 45 1st = 25
                                                              2nd = 15, 3rd = 10, .4th = 5
PROBLEM #8:
A man is 41 years old and his son is 9. In how       PROBLEM #13:
many years will the father be three times as old     Two years ago, a boy was 5/4 as old as his
as the son?                                          sister.
        a. 5                 b. 6                    In 13 years, he will be 10/9 as old as his sister.
        c. 7                 d. 8                    How old is the boy?
                                                             a. 6                 b. 17
                                                             c. 12                d. 21
PROBLEM #14: EE Board April 1997
The sum of Kim's and Kevin's ages is 18. In 3
years, Kim will be twice as old as Kevin. What
are their ages now?
        a. 4, 14            b. 5, 13
        c. 7, 11            d. 6, 12
PROBLEM #15: ECE Board April 2004
Hary is 1/3 as old as Ron and eight years
younger than Hermoine. Find the sum of their
ages if Hary is 8 years old.
        a. 8                 b. 24
        c. 48                d. 16
PROBLEM #16:
A man is three times as old as his son. Five
years ago, he was five times as old as his son
was at that time. How old is the son?
       a. 8                    b. 10
       c. 12                   d. 14
PROBLEM #17:
Two years ago, a boy is 2/3 as old as his sister.
In two years, the boy will be % as old as she.
How old is the boy?
       a. 8                  b. 10
       c. 12                 d. 14
PROBLEM #18:
Mary is 24 years old. Mary is twice as old as Ana
was when Mary was as old as Ana is now. How
old is Ana?
        a. 20                 b. 16
        c. 19                 d. 18