Mathematics and Ancient Mesopotamia
Deepak kumar
              April 18, 2023
          Deepak kumar   Mathematics and Ancient Mesopotamia
Method of Computation
  Base-60 place value system
  Babylonians used various system of numbers in different period of
  times but in the ”Old Babylonian” period base-60 place value
  system together with a grouping system based on 10 to represent
  numbers up to 59 was used. In their system a vertical stoke of
  stylus (as given below) would represent 1.
  A horizontal stroke of stylus would represent 10.
                         Deepak kumar   Mathematics and Ancient Mesopotamia
How Babylonians used to write numbers
  Number less than 59
  Suppose they have to write the number 37 then would simply draw
                               Figure: 37
                       Deepak kumar   Mathematics and Ancient Mesopotamia
Number Greater than 59
Now if they have to write numbers greater than 59 like
                 3 × 602 + 42 × 60 + 9 = 13329
They would write it as
                              Figure: 13329
From now we would write 3 × 602 + 42 × 60 + 9 to be 3,42,09.
                         Deepak kumar   Mathematics and Ancient Mesopotamia
Zero
  The Old Babylonians did not use a symbol for 0, but often left an
  internal space if a given number was missing a particular power.
  There would not be a space at the end of a number, making it
  difficult to distinguish 3 × 60 + 42(3, 42) from
  3 × 602 + 42 × 60(3, 42, 00). Sometimes, however, they would give
  an indication of the absolute size of a number by writing an
  appropriate word, typically a metrological one, after the numeral.
  Thus, “3 42 sixty” would represent 3,42, while “3 42 thirty-six
  hundred” would mean 3,42,00.
                        Deepak kumar   Mathematics and Ancient Mesopotamia
Addition
  Addition
  Extensive tables for multiplication and reciprocals have been found
  so far but no tablet involving addition has yet been
  discovered.Perhaps the scribes knew their addition procedure so
  well that they didn’t find it worthy to explictly write down tables
  for addition. Suppose one has to add 23,37 (= 1417) to 41,32 (=
  2492).
    1   First add 37 and 32 to get 1,09(=69)
    2   Next add 23 + 41 + 1 = 1, 05(65)
    3   Result is 1,05,09.
                             Deepak kumar   Mathematics and Ancient Mesopotamia
Sexagecimal System
  Babylonian treated all fractions as Sexagcimal fraction analogus to
  our decimal fractions.First place after ”sexagecimal point”(which
  we’ll denote by ;) represents 60th place,second place represents
  3600ths and so on.
  Fractions
    1 Reciprocal of 48 is 0; 1, 15 and
                                             1  15
                              0; 1, 15 =       + 2
                                            60 60
    2   Reciprocal of 1,21 (= 81) is 0;0,44,26,40 and
                                            44   26 40
                     0 : 0, 44, 26, 40 =      2
                                                + 3+ 4
                                            60   60 60
                          Deepak kumar     Mathematics and Ancient Mesopotamia
Geometry
  Scribe did not have any symbolism for ”operations” and
  ”unknowns”.Therefore the solution of the problems are presented
  with only verbal techniques.
  The number 0; 52, 30(= 7/8) as the coefficient for the height of a
  triangle means that the altitude of an equilateral triangle is 7/8 of
  the base, while the number 0; 26, 15(= 7/16) as the coefficient for
  area means that the area of an equilateral triangle is 7/16 times
  the square of a side.
  Therefore their approximation for
                                 √         7
                                     3≡
                                           4
                         Deepak kumar     Mathematics and Ancient Mesopotamia
Circle
  Tablet YBC 7302
  Instead of radius r of the circle Babylonians used circumfence as
  the defining component of a circle. The diameter and area of cicle
  are as follows:- Diameter is 0; 20( 13 ) of cicumfrence and
  area is 0; 05 of the square of the circumfrence.Therefore they used
  3 as an approximation of pi
                        Figure: Tablet YBC 7302
                         Deepak kumar   Mathematics and Ancient Mesopotamia
Barge and Bull’s Eye
  In analogy with the circle, the defining component of these figures
  was the arc making up one side. The coefficient of the area of the
  barge is 0; 13, 20 ( 29 ), while that of the bull’s eye is
                   9
  0; 16, 52, 30 ( 32 ).
  Thus, the areas of these two figures are calculated as 92 a2 and
   9 2
  32 a , respectively, where in each case a is the length of that arc.
                       Figure: Barge and bull’s eye
                         Deepak kumar   Mathematics and Ancient Mesopotamia
Volume of Solids
  Prism and Pyramidal structures
  Babylonian’s knew how to calculate the volume of rectangular
  block and how to calculate the volume of prisms with given base
  area.In tablet BM 96954, there are several problems involving a
  grain pile in the shape of a rectangular pyramid with an elongated
  apex, like a pitched roof. The method of solution corresponds to
  the modern formula
                                 hw
                            V =      (l + t/2)
                                  3
                        Deepak kumar   Mathematics and Ancient Mesopotamia
Square Roots and The Pythagoras Theorem
  √
    2
  In the tablet YBC 7289 a square is drawn with side indicated as
  30 and two numbers, 1 : 24, 51, 10 and 42; 25, 35,written on the
  diagonal.The product of 30 and 1 : 24, 51, 10 is precisely
  42; 25, 35.It is then a reasonable assumption that the last number
  represents √the length of the diagonal and that the other number
  represents 2.
                        Figure:  SquareMathematics
                        Deepak kumar    root of 2and Ancient Mesopotamia
Speculation
  Now the question arises that how scribes calculated the square
  roots of positive integers.One possible method is based on the
  identity
                        (x + y )2 = x 2 + 2xy + y 2
  Suppose we have to find square root of the integer N(or side of the
  square whose area is N).
    1   b = N − a2
    2   Now we have to choose a value of c such that b = 2ac + c 2
    3   If a2 is close enough to N then we can approximate c by
        c = 21 1a b
               √       √
    4   Then N = a2 + b ≈ a + 12 1a b
                         Deepak kumar   Mathematics and Ancient Mesopotamia
Pythagoras Theorem and Pythagorean Triplets
  Pythagoras Theorem
  In any right triangle the sum of area of squares on the legs is equal
  to the area of the square on the diagonal.
  Tablet Plimpton 322
  This tablet give an insight to the fact that scribes knew how to
  compute Pythagorean triples. The extant piece of the tablet
  consists of four columns of numbers. Other columns were probably
  broken off on the left.
                         Deepak kumar   Mathematics and Ancient Mesopotamia
Puzzle
  Tablet Plimpton 322
                        Deepak kumar   Mathematics and Ancient Mesopotamia
Figure: Completing the Puzzle
   Deepak kumar   Mathematics and Ancient Mesopotamia
Speculative Answer
            x2 + y2 = d2
                  x2       d2
             =⇒      + 1 =
                  y2       y2
                                                 d      x
             =⇒ v 2 − u 2 = 1 and v =              ,u =
                                                 y      y
             =⇒ (v − u)(v + u) = 1
                    1
             =⇒ u = [(u + v ) − (u − v )]
                    2
                    p
             =⇒ v = 1 + u 2
                     Deepak kumar   Mathematics and Ancient Mesopotamia
Gnomon
         Deepak kumar   Mathematics and Ancient Mesopotamia