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Heat Conduction Analysis Guide

This document discusses methodology for one-dimensional, steady-state conduction analysis without thermal energy generation. Specifically, it examines conduction through plane walls, tube walls, and spherical shells. For each geometry, the document derives the heat equation, temperature distribution, heat flux, heat rate, and thermal resistance expressions. It also discusses applying thermal circuit models and determining overall heat transfer coefficients for composite walls.
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0% found this document useful (0 votes)
62 views12 pages

Heat Conduction Analysis Guide

This document discusses methodology for one-dimensional, steady-state conduction analysis without thermal energy generation. Specifically, it examines conduction through plane walls, tube walls, and spherical shells. For each geometry, the document derives the heat equation, temperature distribution, heat flux, heat rate, and thermal resistance expressions. It also discusses applying thermal circuit models and determining overall heat transfer coefficients for composite walls.
Copyright
© © All Rights Reserved
We take content rights seriously. If you suspect this is your content, claim it here.
Available Formats
Download as PDF, TXT or read online on Scribd
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CHAPTER 3_Part 1

One-Dimensional, Steady-State
Conduction without
Thermal Energy Generation
Instructor
Dr. Salman Abbasi
Methodology

Methodology of a Conduction Analysis


• Specify appropriate form of the heat equation.
• Solve for the temperature distribution.
• Apply Fourier’s law to determine the heat flux.

Simplest Case: One-Dimensional, Steady-State Conduction with No Thermal Energy


Generation.

• Common Geometries:
– The Plane Wall: Described in rectangular (x) coordinate. Area
perpendicular to direction of heat transfer is constant (independent of x).
– The Tube Wall: Radial conduction through tube wall.
– The Spherical Shell: Radial conduction through shell wall.
Plane Wall
The Plane Wall
• Consider a plane wall between two fluids of different temperature:

• Heat Equation:
d  dT 
k =0 (3.1)
dx  dx 

• Implications:
Heat flux ( qx ) is independent of x.
Heat rate ( qx ) is independent of x.
• Boundary Conditions: T ( 0 ) = Ts ,1, T ( L ) = Ts,2

• Temperature Distribution for Constant k :


T ( x ) = Ts ,1 + (Ts ,2 − Ts ,1 )
x
(3.3)
L
Plane Wall (cont.)

• Heat Flux and Heat Rate:


= (Ts ,1 − Ts ,2 )
dT k
qx = − k (3.5)
dx L
= (Ts ,1 − Ts ,2 )
dT kA
q x = − kA (3.4)
dx L
 T 
• Thermal Resistances  Rt =  and Thermal Circuits:
 q 
L
Conduction in a plane wall: Rt ,cond = (3.6)
kA
1
Convection: Rt ,conv = (3.9)
hA
Thermal circuit for plane wall with adjoining fluids:

1 L 1
Rtot = + + (3.12)
h1 A kA h 2 A
T,1 − T,2
qx = (3.11)
Rtot
Plane Wall (cont.)

• Thermal Resistance for Unit Surface Area:


L 1
Rt,cond = Rt,conv =
k h
Units: Rt  K/W Rt  m2  K/W
• Radiation Resistance:
1 1
Rt ,rad = Rt,rad =
hr A hr
(
hr =  (Ts + Tsur ) Ts2 + Tsur
2
) (1.9)

• Contact Resistance:

TA − TB Rt,c
, =
Rtc Rt ,c =
qx Ac

Values depend on: Materials A and B, surface finishes, interstitial conditions, and
contact pressure (Tables 3.1 and 3.2)
Plane Wall (cont.) • Composite Wall with Negligible
Contact Resistance:

T,1 − T,4
qx = (3.14)
 Rt

For the temperature distribution


shown, kA > kB < kC.

1  1 LA LB LC 1  Rtot
 Rt = Rtot =  + + + + =
A  h1 k A k B kC h4  A
• Overall Heat Transfer Coefficient (U) :
A modified form of Newton’s law of cooling to encompass multiple resistances
to heat transfer.
qx = UAToverall (3.17)

1
Rtot = (3.19)
UA
Plane Wall (cont.)

• Series – Parallel Composite Wall:

Assuming isothermal
surfaces perpendicular
to x-direction.

Assuming adiabatic
surfaces parallel
to x-direction.

• Note departure from one-dimensional conditions for k F  kG .

• Circuits based on assumption of isothermal surfaces normal to x direction or


adiabatic surfaces parallel to x direction provide approximations for qx .
Tube Wall (cont.)

• Heat Flux and Heat Rate:

qr = − k
dT
=
k
dr r ln ( r2 / r1 )
(Ts,1 − Ts,2 ) [W/m2]

2 k
qr = 2 rqr =
ln ( r2 / r1 )
( Ts ,1 − Ts ,2 ) [W/m]

2 Lk
qr = 2 rLqr =
ln ( r2 / r1 )
(Ts,1 − Ts,2 ) [W] (3.32)

• Conduction Resistance:
ln ( r2 / r1 )
Rt ,cond = [K/W] (3.33)
2 Lk
ln ( r2 / r1 )
Rt,cond = [m  K/W]
2 k
Tube Wall (cont.)

• Composite Wall with


Negligible Contact
Resistance

T,1 − T,4
qr =
Rtot
(
= UA T,1 − T,4 ) (3.35)

Note that
For the temperature distribution
−1
UA = Rtot shown, kA > kB > kC.

is a constant independent of radius,


but U itself is tied to specification of an interface.
−1
U i = ( Ai Rtot ) (3.37)
Spherical Shell
Spherical Shell

• Heat Equation for Constant k:


1 d  2 dT 
2 dr 
r =0
r  dr 

What does the form of the heat equation tell us about the variation of
qr with r ? Is this result consistent with conservation of energy?

• Temperature Distribution:

T ( r ) = Ts ,1 − (Ts ,1 − Ts ,2 )
( )
1 − r1/ r
(
1 − r1 / r 2 )
Spherical Shell (cont.)

• Heat Flux, Heat Rate and Thermal Resistance:

dT
qr = −k = 2
k
dr r (1 / r1 ) − (1 / r2 ) 
( Ts ,1 − Ts ,2 )

4 k
qr = 4 r 2qr =
(1 / r1 ) − (1 / r2 )
( Ts ,1 − Ts ,2 ) (3.40)

Rt ,cond =
(1 / r1 ) − (1 / r2 ) (3.41)
4 k

• Composite Shell:
Toverall
qr = = UAToverall
Rtot

UA = Rtot −1  Constant

−1
U i = ( Ai Rtot )  Depends on Ai

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