Module №1 «Organization, characterization and provision of
areas of transport modes' interaction»
PRACTICAL 1.8
“INTERACTION OF TRANSPORT MODES”
Problem 1.
Determine the number of wagons in the reserve fleet Nw, if the net carrying capacity
of the vessel is 9000 tons, the carrying capacity of the wagon is 40 tons, the
correction factor that takes into account the multiplicity of the net carrying capacity
of the vessel to the net train weight - 0.1.
Cmax∗D
Nw= , where
Qw
D – net carrying capacity of the vessel;
Qw - carrying capacity of the wagon;
Cmax - correction factor.
0.1∗9000
The number of wagons in the reserve fleet: Nw = 40 = 22,5 ≈ 23 wag.
Problem 2.
Determine the average extension of storage of one ton of cargo in the port on wheels
ts when creating a reserve fleet of wagons, if the net carrying capacity of the vessel -
5000 tons, the average hourly load on the line - 30 t / h , the correction factor that
takes into account the multiplicity of net carrying capacity of the vessel to the net
train weight is 0.09.
Cmax∗D
t s= , where
q
D – net carrying capacity of the vessel;
q - average hourly load on the line;
Cmax - correction factor.
The average extension of storage of one ton of cargo in the port on wheels:
0.09∗5000
t s= = 15
30
Problem 3.
Determine the reduced cost of a vessel-hour in the berth, if the construction cost of
the vessel is $ 800,000, the standard payback period is 5 years, the current costs of
maintaining the vessel in the berth is $ 19 per hour.
800,000 $
The reduced cost of a vessel-hour in the berth: Kc = 5 years + 19$ = 160,090$.
Problem 4.
Determine the interval of the technological break It.b. at the accumulated supply of
wagons, if the net train weight is 1300 tons, the total productivity of cranes at the
direct option of cargo transshipment is 200 t / h.
Qn
I t .b .= , where
Pd
Qn - net train weight;
Pb - total productivity of cranes at the direct option of cargo transshipment;
The interval of the technological break: It.b.¿ 1300 / 200 = 6.5 hours.
Problem 5.
Determine the average hourly flow of cargo on the line, if the monthly volume of
cargo flow is 14.4 thousand tons.
Q
q= , where
Nh
Q - volume of cargo flow;
Nh- number of hours per month. (average working hours = 173.3)
The average hourly flow of cargo on the line: q = 14.4 / 173,3 = 83.
Problem 6.
Determine the average hourly flow of cargo on board of the vessel at the accumulated
supply without a reserve fleet of wagons, if the total capacity of cranes at the
warehouse option of cargo transshipment is 300 t / h, total capacity of cranes at the
direct option of cargo transshipment is 360 t / h, correction factor is 0.8.
Pw.- total capacity of cranes at the warehouse option of cargo transshipment;
Cmax- correction factor.
Pw
γ= , where
Pd
Pd .- total capacity of cranes at the direct option of cargo
transshipment;
γ =¿ 300 / 360 = 0.833
q = 300 / ( 0.833 + ( 1/0.8 -1)) = 277.008
Problem 7.
The station receives 32 transit trains and 36 processing trains every day; their
average composition is 60 wagons. Also the station receives 150 wagons for
unloading and 50 wagons for loading per day. The average idle time of a transit
wagon is 0.6 hours, a transit wagon with processing is 6 hours, a local wagon with
one freight operation is 10 hours, and a local wagon with two freight operations is 16
hours. Determine the availability of wagons of each category at the station and the
total number of wagons (work fleet).
1. Availability of transit wagons without processing:
nttr - number of transit trains;
twtr - average idle time of a transit wagon, hours;
nw- number of wagons in the train.
ntr = (32* 0.6 * 60)/ 24 = 48
2. Availability of transit wagons with processing:
ntpr- number of processing trains;
twpr- average idle time of a transit wagon with processing hours.
npr = (36* 6* 60)/ 24 = 540
3. Availability of local wagons:
nw1- number of local wagons with one freight operation;
t1- average idle local wagon with one freight operation;
t2 - average idle local wagon with two freight operations;
nw2- number of local wagons with two freight operations.
nl = (32*10 +26*16) / 24 = 31
Since the loading is 150 and the unloading is 50 wagons, 100 wagons are empty.
Availability of wagon’s fleet at the station:
nt = 48 + 540 + 31 = 619
Problem 8.
Determine the macroeconomic indicator of the level of transport service to the
population, if the reduced freight turnover of the country is 300 million tkm, gross
national profits is UAH 40 million:
1. Macroeconomic indicator of the level of transport service:
dm = 300 million tkm / 40 UAH million = 7,5
Problem 9.
Determine the deadline for providing clarified information in case of accumulated
supply of wagons, if the net carrying capacity of the vessel - 7000 tons, the total
productivity of cranes at a direct option of transshipment - 300 t / h, the average
hourly arrival of empty
wagons at the port station - 200 t / h (by carrying capacity), train travel time from the
port station to the port - 0.5 h, average hourly cargo arrival at the port - 100 t / h.
tin = 7000/200 * (1-100/300) + 0.5 = 24
Problem 10.
The total cargo turnover of the port is 15 million tons, including 5 million tons of
transit cargo turnover. The amount of port maintenance costs related to transportation
is UAH 210 million. Calculate the amount of costs related to the transit cargo
turnover and the computed rate for the maintenance of 1 ton of transit cargo
turnover.
1. The amount of costs related to the transit cargo turnover:
Cp- amount of port maintenance costs related to transportation;
Qt- total cargo turnover of the port;
Qt.c.- transit cargo turnover.
Ct.c. =( 210 / 15) * 5 = 70
2.The computed rate for the maintenance of 1 ton of transit cargo turnover:
at.c. = 70 * 5 = 350
Problem 11.
Calculate the commercial speed and delivery time of coal from port A to port B. The
distance between these ports is 467 nautical miles. Vessels with a speed of 348 miles
per hour and a carrying capacity of 6,000 tons operate at this line with a utilization
factor of 0.9; rate of cargo operations in the port of cargo loading is 12000 t/day, in
the port of cargo unloading is 7440 t/day and additional time 1.35 days (waiting for
loading - 1 day, processing documents and checking in the port of loading - 0.15
days, in the port of unloading – 0.2 days).
1. Commercial speed:
L - distance between ports, miles;
Vday - speed of vessels operating on this line, miles / day;
a - capacity utilization factor of the vessel;
D - load capacity of the vessel, t;
М - weighted average daily rate of cargo operations in the port of departure and in
the port of destination, t / day;
tadd - time for additional operations in the port.
Vcom = 467 / (467/348 + 2*0.9*6.000/7440 + 1.35) = 173,4 miles per hour
2. Delivery time:
L
T=
Vcom
T =¿ 467 / 173,4 = 2,7
Problem 12.
The port's cargo turnover is 10 million tons, the monthly irregularity of the cargo
flow is 0.8, the port's navigation period is 5 months, the wagon loading rate is 60
tons, the number of wagons in the supply is 16 wagons. Calculate the number of
required wagons and the number of supplies of wagons per day required to service
the port's freight traffic, as well as the interval between the supply of wagons.
1. Number of wagons per day:
Qn- cargo turnover during the navigation period;
Im - monthly irregularity of the cargo flow;
G - accepted wagon loading rate;
Тn- navigation period.
nw = 10 *0.8 / 60*5 = 26
2. Number of supplies of wagons per day:
пw.s- number of wagons in supply.
ms = 26 / 16 = 2
3.Interval between the supply of wagons:
Ts = 24 / 2 = 12
The daily truck turnover and the interval of truck’s arrival for processing are similarly
determined.
Problem 13.
Determine the average total productivity of cranes when processing a vessel with
accumulated supply of wagons without a reserve fleet of wagons, if the average
hourly load of cargo on board the vessel at accumulated supply of wagons is 60 t / h;
correction factor is 0.79:
M = 60 / 0.79 = 75.949
Problem 14.
Determine the productivity, ie the amount of cargo that can be transported by a truck
or road train serving the river port, if the weight of cargo loaded on the train is 5 tons,
mileage with and without cargo is 130 km, the average technical speed is 50 km / h,
the time for loading and unloading the train is 0.5 hours, the time for technological
breaks is 0.4 hours, the waiting time is 1 hour.
1. Productivity:
P = 5 / 4.5 = 1.111
2. Turnaround time of a truck or a road train:
Tt = 130/ 50 + 0.5 + 0.4 + 1 = 4.5 hour
Problem 15.
Calculate the capacity of the road, i.e. the number of cars passing per hour, if the
number of streams moving in parallel is 4, interval between cars at one-way flow is 5
m, the average speed is 70 km / h.
Road capacity (highway):
C = 4 * 70 / 5 = 56 cars per hour
Problem 16.
The condition for the uninterrupted operation of rolling stock engaged in the
transportation of containers is the equality of the rhythm of supply of containers and
the interval of movement of vehicles. Calculate the interval of movement of trucks, if
the circulation time of the container is 10 days, the flow of cargoes in one direction is
5 thousand tons per day, the load capacity of the container is 25 tons, the capacity
utilization factor of the container 0.9, the number of containers set on the truck is 2.
1. The interval of movement of trucks:
It = 10 / 3600 = 0.003
2.Number of trucks on the route:
Nr = 10* 5000 / 25* 0.9* 2 = 3600
Problem 17.
Determine the required number of pallets for processing of cargo flow, if the
circulation time of one pallet is 20 days, cargo flow per day in one direction is 3
thousand tons, load capacity of pallet is 3 tons, pallet stock ratio, taking into account
possible supply disruptions, equals 1.3.
Xp = (3000 t/day * 20 days * 1.3) / 3 tons = 26 000
Conclusion : In this work we got acquainted with the interaction of modes of
transport.
