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Kinematics (Motion in a Straight Line & Plane)

Exercise - I
DISTANCE & DISPLACEMENT 7. An ant is scramping on the stairs as shown in
1. If displacement of a particle is zero, the the figure. There are '4' stairs and each stair
distance covered : has width of 12 cm and height of 5 cm. The
(1) must be zero distance travelled by the ant to scramp the
(2) may or may not be zero stairs is :-
(3) cannot be zero
(4) depends upon the particle
2. If the distance covered is zero, the
displacement : 5 12

(1) must be zero

(1) 52 cm (2) 68 cm
(2) may or may not be zero
(3) 48 cm (4) 20 cm
(3) cannot be zero
8. An insect starts climbing a conical birthday
(4) depends upon the particle
hat of radius 5 cm at base. It starts from point
3. The location of a particle is changed. What
A and reaches point B, taking spiral path on
can we say about the displacement and
the hat. Find out its displacement if height is
distance covered by the particle :
12 cm:-
(1) Both cannot be zero
B
(2) One of the two may be zero
(3) Both must be zero
(4) If one is positive, the other is negative and 12cm
vice-versa
4. The numerical ratio of distance to the
displacement covered is always :– 5 cm
A
(1) less than one
(2) equal to one (1) 12 cm (2) 8 cm
(3) equal to or less than one (3) 13 cm (4) 25 cm
(4) equal to or greater than one
5. Milkha Singh can cover one round of a 9. Three particles P, Q and R are situated at
circular park in 40 second, After 1 minute and point A on the circular path of radius 10 m. All
40 second, he will cover a distance and three particles move along different paths
displacement respectively and reach point B as shown in figure. Then the
(R = Radius of circle):- ratio of distance traversed by particles P and
(1) Zero, Zero (2) 4R, R R is :
(3) 5R, 2R (4) 6R, 2R P
6. A hall has the dimensions 10 m × 10 m × 10 Q O
A
m. A fly starting at one corner ends up at a
diagonally opposite corner. The magnitude of R

its displacement is nearly B

(1) 5 3 m (2) 10 3 m
3 3 3 
(3) 20 3 m (4) 30 3 m (1) (2) (3) (4)
4 1 4 3

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10. A body moves along the curved path of a semi 17. Select the correct statements from the
circle. Calculate the ratio of distance to following.
displacement: S1 :Average velocity is path length divided by
(1) 11 : 7 (2) 7 : 11 time interval.
(3) 11 : 2  7 (4) 7 : 11 2
S2. In general, average speed  |average
11. Distance travelled by the tip of minute hand
velocity|
of length 10 cm in 100 sec is
S3. A particle moving in a given direction with
 
(1) m (2) m a non-zero velocity can have zero speed.
180 360
S4. The magnitude of average velocity is the
 3
(3) m (4) m average speed.
1200 2160
12. If a particle moves from point P(2, 3, 5) to (1) S1 (2) S2 (3) S3 (4) S4
point Q(3, 4, 5). Its displacement vector be :- 18. The magnitude of average velocity is equal to
(1) ˆi + ˆj + 10kˆ (2) ˆi + ˆj + 5kˆ the average speed when a particle moves :
ˆi + ˆj (1) on a curved path
(3) (4) ˆ
2iˆ + 4jˆ + 6k
(2) in the same direction
13. A man walks 30 m towards north, then 20 m (3) with constant acceleration
towards east and the last 30 2 m towards
(4) with constant retardation
south-east. The displacement from origin is :
19. A man walks for some time 't' with velocity
(1) 10 m towards west
(v) due east. Then he walks for same time 't'
(2) 50 m towards east
(3) 60 2 m towards north west with velocity (v) due north. The average
(4) 60 2 m towards east north speed of the man is :
14. A person walks 80 m east, then turns right (1) 2v (2) 2 v
through angle 143° walks further 50 m and v
(3) v (4)
stops. His position relative to the starting point is 2
(1) 50 m, 53° east of south 20. A car travels a distance d on a straight road in
(2) 50 m, 53° south of east two hours and then returns to the starting
(3) 30 m, 37° south of east point in next three hours. Its average speed
(4) 30 m, 53° south of east
and average velocity is :
15. A drunkard is walking along a straight road. He
d 2d
takes 5 steps forward and 3 steps backward, (1) , 0 (2) , 0
followed by 5 steps forward and 3 steps 5 5
backward and so on. Each step is one meter 5d d
(3) , (4) none of these
long and takes one second. There is a pit on the 6 5
road 13 meters away from the starting point. 21. A particle moves in the east direction with
The drunkard will fall into the pit after : 15 m/sec for 2 sec then northwards with
(1) 29 s (2) 21 s (3) 37s (4) 31 s 5 m/s for 8 sec. Average velocity of the
particle is :–
SPEED & VELOCITY, AVERAGE SPEED &
(1) 1 m/s (2) 5 m/s
AVERAGE VELOCITY
(3) 7 m/s (4) 10 m/s
16. A train covers the first half of the distance
between two stations with a speed of 30 22. A man walks on an equilateral triangle along
km/h and the other half with 70 km/h. Then path ABC with constant speed then the ratio
its average speed is : of average speed and magnitude of average
(1) 50 km/h (2) 48 km/h velocity for A to C :-
(3) 42 km/h (4) 100 km/h
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Kinematics (Motion in a Straight Line & Plane)
B 28. If a car cover 2/5th of total distance with v1
speed and 3/5th distance with v2 speed then
the average speed is :-
1 v + v2
(1) v1 v2 (2) 1
2 2

A C (3) 2v 1 + v 2 (4) 5v 1 v 2
v1 + v2 3v 1 + 2v 2
1 29. A particle moving in a straight line covers half
(1) 1 (2) 2 (3) (4) None
2 the distance with speed of 10 m/s. The other
23. A car runs at constant speed on a circular half of the distance is covered in two equal
track of radius 10 m taking 6.28s on each lap time intervals with speed of 4.5 m/s and 7.5
(i.e. round). The average speed and average m/s respectively. The average speed of the
velocity for half lap is : particle during this motion is :
(1) Velocity 20/ m/s, speed 10 m/s (1) 8.0 m/s (2) 12.0 m/s
(2) Velocity zero, speed 10 m/s (3) 10.0 m/s (4) 7.5 m/s
(3) Velocity zero, speed zero 30. A point object traverses half the distance with
(4) Velocity 10 m/s, speed zero velocity 0. The remaining part of the distance
24. A particle moves in straight line in same is covered with velocity 1 for the half time
direction for 20 sec. with velocity 3 m/s and and with velocity 2 for the rest half. The
then moves with velocity 4 m/s for another average velocity of the object for the whole
20 sec. and finally moves with velocity 5 m/s journey is
for next 20 sec. What is the average velocity (1) 21 (0 + 2) / (0 + 21 + 22)
of the particle? (2) 2 (0 + 1) / (0 + 1 + 2)
(1) 3 m/s (2) 4 m/s (3) 20 (1 + 2) / (1 + 2 + 20)
(3) 5 m/s (4) Zero (4) 22 (0 + 1) / (1 + 22 + 0)
25. An object travels 10 km at a speed of 100 m/s 31. A scooter going due east at 10 ms–1 turns in
and another 10 km at 50 m/s. The average right side through an angle of 90°. If the speed
speed over the whole distance is :- of the scooter remains unchanged in taking
(1) 75 m/s (2) 55 m/s this turn, the change in the velocity of the
(3) 66.7 m/s (4) 33.3 m/s scooter is :-
26. A body has speed V, 2V and 3V in first 1/3 (1) 20.0 ms–1 in south-west direction
part of total travelled distance S, second 1/3 (2) Zero
part of S and third 1/3 part of S respectively. (3) 10.0 ms–1 in south-east direction
Its average speed will be :- (4) 14.14 ms–1 in south-west direction
18 11 32. A person is moving in a circle of radius r with
(1) V (2) 2V (3) V (4) V
11 18 constant speed V. The change in velocity in
27. A body covers one-third of the time with a moving from A to B is
velocity v1 the second one-third of the time with
B
a velocity v , and the last one-third of the time
40°
with a velocity v3. The average velocity is : A
O
v + v2 + v3 3v 1 v 2 v 3
(1) 1 (2)
3 v1 v2 + v2v3 + v3v1
(1) 2V cos 40° (2) 2V sin 40°
v1 v 2 + v 2v3 + v3v1 v1v2v3
(3) (4) (3) 2V cos 20° (4) 2V sin 20°
3 3
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33. An insect crawls a distance of 4m along north 41. Equation of a particle moving along the x axis is
in 10 s and then a distance of 3m along east in x = u(t – 2) + a(t – 2)2
5 s. The average velocity of the insect is :- (1) the initial velocity of the particle is u
7 1 (2) the acceleration of the particle is a
(1) m/s (2) m / s
15 5 (3) the acceleration of the particle is 2a
1 4 (4) at t = 2 particle is not at origin
(3) m / s (4) m / s
3 5 42. If for a particle position x  t then :–
ACCELERATION, AVERAGE ACCELERATION (1) velocity is constant
& APPLICATION OF CALCULUS (2) acceleration is non zero
34. The position x of a particle varies with time (t) as (3) acceleration is variable
x = at2 – bt3. The velocity at time t of the particle (4) None of these
will be equal to zero, where t is equal to : 43. The velocity of a body depends on time
2a a a a according to the equation = 20 + 0.1t. The
(1) (2) (3) (4)
3b b 3b 2b body has :
35. If x denotes displacement in time t and x = a (1) uniform acceleration
sint, then acceleration is : (2) uniform retardation
(1) a cos t (2) – a cos t (3) non-uniform acceleration
(3) a sin t (4) –a sin t (4) zero acceleration
36. The motion of a particle is described by the 44. Which of the following relations representing
equation x = a + bt2 where a = 15 cm and velocity of a particle describes motion with
b = 3 cm/sec2. Its acceleration at time constant acceleration ?
3 sec will be :- (1) v = 6 – 7 t (2) v = 3t2 + 5t3 + 7
(1) 36 cm/sec2 (2) 18 cm/sec2 (3) v = 9t + 8
2 (4) v = 4t–2 + 3t–1
(3) 6 cm/sec2 (4) 32 cm/sec2 45. Which of the following equations represents
37. Equation of displacement for a particle is the motion of a body moving with constant
s = 3t3 + 7t2 + 14t + 8 m. Its acceleration at finite velocity? in these equations, y denotes
time t = 2 sec is :- the displacement in time t and p, q and r are
(1) 10 m/s2 (2) 16 m/s2 arbitary constants :
(3) 25 m/s2 (4) 50 m/s2 (1) y = (p + qt)2 (r + pt)
38. A body is moving according to the equation (2) y = p + tqr
x = at2 + bt – c. Then its instantaneous speed (3) y = (p + t) (q + t) (r + 1)
is given by :– (4) y = (p + qt)rt
(1) a + 2b + 3ct (2) a + 2bt – 3ct2 46. The displacement of a particle starting from
(3) 2b – 6ct (4) 2at + b rest (at t=0) is given by s = 6t2 – t3
39. The relation t = x + 3 describes the position The time when the particle will attain zero
of a particle where x is in meters and t is in acceleration is :
seconds. The acceleration of particle is :– (1) 2s (2) 8s (3) 12s (4) 16s
(1) 2 m/s2 (2) 4 m/s2 47. The displacement of a particle varies with
(3) 5 m/s2 (4) zero k
time according to the relation x = [1 − e− bt ] .
40. The displacement of a particle is given by b
y = a + bt + ct3. The initial velocity and Then the velocity of the particle is :
acceleration are respectively : k
(1) k(e–bt) (2) 2 − bt
(1) b, 0 (2) –b, 2c be
(3) b, 2c (4) 2c, – 4d (3) kbe –bt (4) None of these
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Kinematics (Motion in a Straight Line & Plane)
48. A particle moves along a straight line such 54. Starting from rest, the acceleration of a
that its displacement at any time t is given by particle is a = 2(t – 1)m/s2. The velocity of the
s = t3 – 6t2 + 3t + 4 metres. The displacement particle at t = 5 s is :-
when the acceleration is zero is : (1) 15 m/s (2) 25 m/s
(1) 3 m (2) –12 (3) 42 m (4) –6 m (3) 5 m/s (4) None of these
49. Displacement x of a particle is related to time 55. If the velocity of a particle is (10 + 2t2) m/s,
t as x = at + bt2 – ct3 where a, b and c are then the average acceleration of the particle
constants. The velocity of the particle when between 2s and 5s is :-
its acceleration is zero is given by :- (1) 2m/s2 (2) 4m/s2
b2 b2 (3) 12m/s2 (4) 14m/s2
(1) a + (2) a +
c 2c 56. If velocity of a particle is given by
b2 b2 v = (3t2+2)m/s, then average velocity in the
(3) a + (4) a +
3c 4c
interval 0  t  2sec:-
x2
50. A particle moves along the curve y = . Here (1) 6 m/s (2) 8 m/s
2
(3) 3 m/s (4) 4 m/s
t2
x varies with time as x = . Where x and y 57. A particle located at x = 0 at time t = 0, starts
2
moving along the positive x–direction with a
are measured in metre and t in second. At t =
velocity 'v' which varies as v =  x , then
2s, the velocity of the particle (in ms–1) is :
velocity of particle varies with time as : ( is
(1) 2iˆ − 4jˆ (2) 2iˆ + 4jˆ a constant)
(3) 4iˆ + 2jˆ (4) 4iˆ − 2jˆ (1) v  t (2) v  t2
51. The velocity-time relation of an electron (3) v  t (4) v = constant
starting from rest is given by u = kt, where 58. If the velocity of a particle is given by
k = 2 m/s2. The distance traversed in 4 sec is : v = (180 – 16x)1/2 m/s, then its acceleration
(1) 9m (2) 16 m (3) 27 m (4) 36 m will be:-
52. The initial velocity of a particle is u (at t = 0) (1) Zero (2) 8 m/s2
and the acceleration is given by f = at2. Which (3) –8 m/s2 (4) 4 m/s2
of the following relations is valid? 59. The acceleration of a particle moving in a
2
at straight line varies with its displacement as
(1) v = u + at2 (2) v = u +
2 a = 2S + 1. Velocity of the particle is zero at
at 3 zero displacement. The relation between
(3) v = u + (4) v = u + at
3 velocity and displacement is :-
53. A particle is moving with a velocity of 10m/s (1) v = S(S + 1) (2) v = 2S(S + 1)
towards east. After 20 s its velocity changes
(3) v= S(S + 1) (4) None of these
to 10m/s towards north. Its average
acceleration is:- 60. The position vector of a particle is given as
(1) zero ( ) ( )
r = t 2 − 4t + 6 ˆi + t 2 ˆj . The time after which
(2) 2 m/s2 towards N-W
the velocity vector and acceleration vector
1
(3) m/s2 towards N-E becomes perpendicular to each other is equal to:-
2
(1) 1 sec. (2) 2 sec.
1
(4) m/s2 towards N-W (3) 1.5 sec. (4) 5 sec.
2
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61. At any instant of time acceleration and 67. Initially a body is at rest. If its acceleration is
velocity of a particle are given by a = ˆi + ˆj & 5ms–2 then the distance travelled in the
5th second is :–
v = 6iˆ + 8jˆ , then rate of change of speed (1) 86.6 m (2) 87.5 m
(component of acceleration along velocity) at (3) 88 m (4) 22.5 m
the same instant will be:- 68. A car starts from rest travelling with constant
(3iˆ + 4j)
ˆ 6iˆ + 8jˆ acceleration. If distance covered by it in 10th
(1) (2)
25 25 second of its journey is 19m, what will be the
7 ˆ ˆ 7 ˆ ˆ acceleration of car?
(3) (3i + 8j) (4) (3i + 4j)
25 25 (1) 4 m/s2 (2) 3 m/s2
CONSTANT ACCELERATION MOTION, (3) 2 m/s2 (4) 1 m/s2
FREE FALL 69. A car starts from rest and moves with
62. If a body starts from rest, the time in which it constant acceleration. The ratio of the
covers a particular displacement with distance covered in the nth second to that
uniform acceleration is : covered in n seconds is :-
(1) inversely proportional to the square root of
2 1 2 1
the displacement (1) 2 − (2) 2 +
n n n n
(2) inversely proportional to the displacement
2 1 2 1
(3) directly proportional to the displacement (3) − 2 (4) + 2
n n n n
(4) directly proportional to the square root of
70. A body starts from rest. What is the ratio of
the displacement
the distance travelled by the body during the
63. A body at rest is imparted motion to move in
a straight line. It is then obstructed by an 4th and 5th second?
opposite force, then: 7 5 7 3
(1) (2) (3) (4)
(1) the body may necessarily change direction 5 7 9 7
(2) the body is sure to slow down 71. A car moving with a velocity of 10 m/s can be
(3) the body will necessarily continue to move stopped by the application of a constant force
in the same direction at the same speed F in a distance of 20m. If the velocity of the car
(4) none of the above. is 40 m/s. It can be stopped by this force in :
64. If a car at rest accelerates uniformly to a 20
(1) m (2) 320 m
speed of 144 km/h in 40 seconds, it covers a 3
distance of : (3) 60 m (4) 180 m
(1) 200 m (2) 800 m 72. A car moving with a speed of 40 km/h can be
(3) 1440 m (4) 2980 m stopped by applying brakes after at least 2m.
65. If a car at rest accelerates uniformly and If the same car is moving with a speed of
attains a speed of 54 km/h in 10s, then it 120 km/h., what is the minimum stopping
covers a distance of distance?
(1) 75 m (2) 100 m (1) 2 m (2) 4 m (3) 6 m (4) 18 m
(3) 200 m (4) 400 m
73. The velocity acquired by a body moving with
66. If a train travelling at 72 km/h is to be
uniform acceleration is 30 m/s in 2 seconds and
brought to rest in a distance of 100 m, then its
50 m/s in 4 seconds. The initial velocity is :
retardation should be :
(1) zero (2) 2 m/s
(1) 20 m/s2 (2) 2 m/s2
(3) 4 m/s (4) 10 m/s
(3)
TG: 10 m/s 2
@Chalnaayaaar (4) 1 m/s2
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Kinematics (Motion in a Straight Line & Plane)
74. A body starts from rest and with a uniform 80. A body dropped from a tower reaches the
acceleration of 5 ms– 2 for 5 seconds. During ground in 5s. The height of the tower is about :
the next 10 seconds it moves with uniform (1) 80 m (2) 125 m (3) 160 m (4) 40 m
velocity. The total distance travelled by the 81. A stone falls freely such that the distance
body is :– covered by it in the last second of its motion
(1) 100 m (2) 312.5 m is equal to the distance covered by it in the
(3) 500 m (4) 625 m
first 3 seconds. It remained in air for :–
75. The velocity of a particle moving with
(1) 2 s (2) 3 s (3) 5 s (4) 6 s
constant acceleration at an instant t0 is
82. A body dropped from the top of a tower
10 m/s. After 5 seconds of that instant the
velocity of the particle is 20m/s. The velocity covers 5x distance in the last second of its fall.
at 2 second before t0 is : The time of fall is if x is the distance covered
(1) 8 m/s (2) 4 m/s in first second of its fall-
(3) 6 m/s (4) 7 m/s (1) 2 sec (2) 4 sec.
76. A bullet moving with a velocity of 200 cm/s (3) 3 sec. (4)  50  sec
penetrates a wooden block and comes to rest  7 
after traversing 4 cm inside it. What velocity 83. An object is dropped vertically down on earth.
is needed for travelling distance of 9 cm in The change in its speed after falling through a
same block :- distance 2d from its highest point is
(1) 100 cm/s (2) 136.2 cm/s 2gd
(3) 300 cm/s (4) 250 cm/s (1) mgd (2)
77. Which of the following four statements is (3) 2 gd (4) 2 mg
true? d
(1) A body can have zero velocity and still be 84. A bullet enters in a thick wooden wall with
accelerated speed u. If the bullet penetrates a distance 's'
(2) A body can have a constant velocity and into the wood then retardation of the bullet is :
still have a varying speed u2 u2
(3) A body cannot have a constant speed if it (1) (2)
s 2s
has a varying velocity 2
u 2u2
(4) The direction of the velocity of a body (3) (4)
4s s
cannot change when its acceleration is
85. A body dropped from the top of a tower
constant.
78. If an iron ball and a wooden ball of same radii covers a distance 9x in the last second of its
are released from a height h in vacuum then journey, where x is the distance covered in
time taken by both of them to reach ground first second. How much time does it take to
will be : reach the ground?
(1) unequal (2) exactly equal (1) 3s (2) 4s (3) 5s (4) 6s
(3) roughly equal (4) zero 86. A stone is dropped into a well in which the
79. Three different objects of masses m1, m2 and level of water is h below the top of the well. If
m3 are allowed to fall from rest and from the v is velocity of sound, the time T after which
same point 'O' along three different the splash is heard is given by.
frictionless paths. The speeds of the three
2h 2h h
objects on reaching the ground, will be in the (1) T = (2) T = +
ratio of :– v g v
(1) m1 : m2 : m3 (2) m1 : 2m2 : 3m3 h 2h
(3) T = 2h + h (4) T = +
(3) 1 : 1 : 1 (4) 1 : 1 : 1 v g 2g v
m1 m 2 m3
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87. A body is released from the top of a tower of 92. A body is released from the top of a tower of
height H metres. It takes t time to reach the height H m. After 2sec it is stopped and then
t instantaneously released. What will be its
ground. Where is the body time after the
3 height from ground after next 2sec :-
release : (1) (H–5) m (2) (H–10) m
H (3) (H–20)m (4) (H-40) m
(1) At metres from ground
2 93. The ratio of the distances traversed, in
H successive intervals of time by a body falling
(2) At metres from ground
4 from rest, are
8H (1) 1 : 3 : 5 : 7 : 9 : ............
(3) At metres from the ground
9 (2) 2 : 4 : 6 : 8 : 10 : ............
H (3) 1 : 4 : 7 : 10 : 13 : ............
(4) At metres from the ground
9 (4) None of these
88. A body falling from height 'h' takes t1 time to 94. A particle is dropped from a certain height.
reach the ground. The time taken to cover the The time taken by it to fall through successive
1
th
distances of 1 km each will be :
first   of the height is :
4 2
(1) all equal, being equal to second.
t1 t2 g
(1) t2 = (2) t1 =
2 2 (2) in the ratio of the square roots of the
t1 integers 1: 2 : 3
(3) t2 = (4) None of these
2 (3) in the ratio of the difference in the square
89. A stone is dropped from a certain height roots of the integers, i.e.,
which can reach the ground in 5 seconds. It is
stopped after 3 seconds of its fall and is again
1,,( 2 − 1),( 3 − 2),( 4 − 3) .......
released. The total time taken by the stone to (4) in the ratio of the reciprocals of the square
reach the ground will be : 1 1 1
roots of the integers, ie., , , .....
(1) 6 s (2) 6.5 s (3) 7 s (4) 7.5 s 1 2 3
90. A body released from a height falls freely 95. Drops of water fall from the roof of a building
towards earth. Another body is released from 27m high at regular intervals of time. When
the same point exactly two second later. The the first drop reaches the ground, at the same
separation between them two seconds after instant fourth drop begins to fall. What are
the release of the second body is :– the distances of the second and third drops
(1) 9.8 m (2) 49 m from the roof?
(3) 58.8 m (4) 19.6 m (1) 6 m and 12 m (2) 6 m and 3 m
91. Two balls are dropped from different heights (3) 12 m and 3 m (4) 8 m and 2 m
at different instants. Second ball is dropped 96. Water drops fall at regular intervals from a
2 seconds after the first ball. If both balls tap 6 m above the ground. The third drop is
reach the ground simultaneously after 5 leaving the tap at the instant the first drop
seconds of dropping the first ball, then the touches the ground. How far above the
difference between the initial heights of the ground is the second drop at that instant?
two balls will be: (g=9.8m/s2) (1) 1.25 m (2) 2.50 m
(1) 58.8 m (2) 78.4 m (3) 98.0 m (4) 117.6 m (3) 3.75 m (4) 4.5 m
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Kinematics (Motion in a Straight Line & Plane)
97. Four marbles are dropped from the top of a 105. If a ball is thrown vertically upwards with
tower one after the other with an interval of speed u, the distance covered during the last
one second. The first one reaches the ground ‘t’ seconds of its ascent is :–
after 4 seconds. When the first one reaches 1
(1) ut (2) gt2
the ground the distances between the first 2
and second, the second and third and the 1 2
(3) ut – gt (4) (u + gt)t
third and forth will be respectively :- 2
(1) 35 m, 25 m and 15 m 106. A body thrown vertically upwards with an
(2) 30 m, 20 m and 10 m initial velocity u reaches maximum height in
(3) 20 m, 10 m and 5 m 6 seconds. The ratio of the distance travelled
(4) 40 m, 30 m and 20 m by the body in the first second and the
98. A particle is thrown vertically upward. Its seventh second is :-
velocity at half of the maximum height is (1) 1 : 1 (2) 11 : 1 (3) 1 : 2 (4) 5 : 3
10m/s. The maximum height attained by it is 107. A ball is thrown vertically upwards with
(g=10 ms–2) :– velocity 600 m/s. Calculate distance travelled
(1) 8m (2) 20m (3) 10m (4) 16m in last 2 sec of its upward motion :-
99. A ball is thrown upward with a velocity of (1) 20 m (2) 30 m (3) 10 m (4) 25 m
50 m/s. It will reach the ground after :– 108. A body is projected vertically up at t = 0 with
(1) 10 s (2) 20 s (3) 5 s (4) 40 s a velocity of 98 m/s. Another body is
100. Two bodies are thrown vertically upwards projected from the same point with same
with their initial speeds in the ratio 2 : 3. The velocity after 4 seconds. Both bodies will
ratio of the maximum heights reached by meet at t =
them and the ratio of time taken by them to (1) 6 s (2) 8 s (3) 10 s (4) 12 s
return back to the ground respectively are :- 109. A ball is thrown vertically upwards. The ball
(1) 4 : 9 and 2 : 3 (2) 2 : 3 and 2 : 3 was observed at a height h twice with a time
(3) 2 : 3 and 4 : 9 (4) 2 : 3 and 2 : 3 interval t. The initial velocity of the ball is
101. A particle is thrown from the ground upward 2
 g t 
(1) 8gh + (gt)2 (2) 2gh +  
with velocity 40 m/s. Calculate maximum  2 
height:-
(1) 40 m (2) 80 m (3) 160 m (4) 8 m (3) 8gh + (2gt)2 (4) 2gh
102. If a ball is thrown vertically upwards with 40 m/s. 110. A ball is thrown vertically upwards. Assuming
its velocity after three seconds will be : the air resistance to be constant and
(1) 10 m/s (2) 20 m/s considerable :–
(3) 30 m/s (4) 40 m/s (1) the time of ascent > the time of descent
103. When a ball is thrown vertically up with (2) the time of ascent < the time of descent
velocity v0, it reaches a maximum height 'h'. If (3) the time of ascent > the time of descent
one wishes to double the maximum height then (4) the time of ascent = the time of descent
the ball should be thrown with velocity – 111. A particle is thrown up vertically with a speed
(1) 2 v0 (2) 3v0 'v1', in air. It takes time t1 in upward journey
(3) 9v0 (4) 3/2v0 and t2 (> t1) in the downward journey and
104. With what speed should a body be thrown returns to the starting point with a speed
upwards so that the distances traversed in v2.Then:
7th second and 8th second are equal? (1) v1 = v2
(1) 58.4 m/s (2) 49 m/s (2) v1 < v2
(3) 98 m/s (4) 68.6 m/s (3) v1 > v2
(4) Data is insufficient
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NEET : Physics
112. A particle is thrown upwards from ground. It 119. A stone falls from a balloon that is descending
experiences a constant resistance force which at a uniform rate of 10 ms–1. The displacement
produces a retardation of 2 m/s2. The ratio of of the stone from the point of release after
time of ascent to the time of descent is 10 seconds is : (g = 10 m/s2)
(g = 10 m/s2):- (1) 490 m (2) 510 m
2 (3) 600 m (4) 725 m
(1) 1 (2) 2 (3) (4) 3
3 3 2 120. A parachutist after bailing out falls 50 m
113. A stone is thrown straight upward with a without friction. When parachute opens, it
speed of 20 m/sec from a tower 200 m high. decelerates at 2 m/s2. He reaches the ground
The speed with which it strikes the ground is with a speed of 3 m/s. At what approximate
approximately height, did he bail out?
(g = 9.8 m/s2) (1) 293 m (2) 111 m
(1) 60 m/sec (2) 65 m/sec (3) 91 m (4) 182 m
(3) 70 m/sec (4) 75 m/sec 121. A rocket is fired vertically from the ground. It
114. A balloon is at a height of 81 m and is ascending moves upwards with a constant acceleration
upwards with a velocity of 12 m/s. A body of 20 m/s2 for 30 sec after which the fuel is
2 kg weight is dropped from it. If g = 10 m/s2, finished. After what time from the instant of
the body will reach the surface of the earth in:- firing the rocket will attain the maximum
(1) 1.5 s (2) 4.025 s height? (Take g = 10 m/s2)
(3) 5.4 s (4) 6.75 s (1) 90 s (2) 45 s (3) 60 s (4) 75 s
115. A ball is thrown vertically upwards from the
top of a tower with velocity 4.9 ms–1. It strikes GRAPHICAL ANALYSIS
the pond near the base of the tower after 3 122. The velocity-time graph of an object is shown.
seconds. The height of the tower is :- The distance during the interval 0 to t4 is :-
(1) 73.5 m (2) 44.1 m 
(3) 29.4 m (4) None of these
116. A stone is thrown upwards with a speed 'u' C
A t3 E t5
0 t
from the top of the tower reaches the ground t1 t2 D t4
B
with a velocity '3u'. The height of the tower is:-
2 2 2 2
(1) 3u (2) 4u (3) 6u (4) 9u (1) Area A + Area B +Area C +Area D +Area E
g g g g
(2) Area A + Area C – Area B – Area D
117. A body dropped from a height h, strikes the (3) Area A + Area B + Area C + Area D
ground with velocity 3 m/s. Another body of (4) Area A + Area C + Area E –Area B +Area D
same mass is thrown downward from the 123. Figure below shows the acceleration-time
height h with an initial velocity of 4 m/s. Find graph of a one dimensional motion. Which of
the final velocity with which it strikes the
the following characteristics of the particle is
ground
represented by the shaded area?
(1) 3 m/s (2) 4 m/s a
(3) 5 m/s (4) 12 m/s
118. From a building two balls A and B are thrown
such that A is thrown upwards and B
downwards (both vertically) with same
O t
speed. If VA and VB are their respective
velocities on reaching the ground then :- (1) change in velocity
(2) change in position
(1) VB > VA (2) VA = VB
(3) change in momentum
(3) VA > VB (4) None of these
(4) velocity
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Kinematics (Motion in a Straight Line & Plane)
124. Fig. shows the displacement of a particle 128. The displacement–time graph for two
moving along x-axis as a function of time. The particles A and B are straight lines inclined at
velocity of the particle is zero at :-
Displacement angles of 30° and 60o with the time axis. The
ratio of velocity of particle A & B (VA : VB) is :-
A C B
s
B A
D
60°
time 30°
O t
(1) A (2) B (3) C (4) D
125. The displacement-time graph of a moving (1) 1 : 2 (2) 1 : 3
particle is shown. The instantaneous velocity (3) 3 : 1 (4) 1 : 3
of the particle is positive at the point : 129. Which one of the following curves do not
represent motion in one dimension :-
displacement

D v v
E
C
F t t
time (1) (2)
(1) D (2) F (3) C (4) E v v

126. A person walks along an east-west street and

a graph of his displacement from home is t t
shown in figure. His average speed for the (3) (4)
whole time interval is 130. Which of the following displacement–time
graphs shows a realistic situation for a body
40 in motion ?
x (meter)

20
15 18 20 21
0
3 6 9 12 t (sec)
–20 (1) s (2) s
–40 t
t

(1) 0 (2) 23 m/s

(3) 8 m/s (4) None of these (3) s (4) s
127. A particle is moving in a straight line y=3x. Its
t t
velocity time graph is shown in figure. Its
speed is minimum at t =............. 131. Which of the following velocity-time graphs
v(ms–1) represent uniformly accelerated motion ?
10 v v
(1) (2)
5 t(s)
0 2 4 6 8 t t

v v
–10
(3) (4)
(1) 2s (2) 4s (3) 6s (4) 8s
t t
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NEET : Physics
132. The fig. shows the position time graph of a 135. A particle moves according to given velocity–
particle moving on a straight line path. What time graph. Then the ratio of distance
is the magnitude of average speed of the travelled in last 4 seconds and 9 seconds is :-
particle over 10 seconds ? 10

V(m/sec)
60
40
30 1 3 5 9
Time (sec)
20
1 2 1 4
10 (1) (2) (3) (4)
4 5 8 11
0
2 4 6 8 10 t (s)
136. The velocity-time graph of a body moving in a
(1) 2 m/s (2) 4 m/s straight line is shown in the figure. The
(3) 6 m/s (4) 8 m/s displacement and distance travelled by the
133. From the following velocity time graph of a body in 6 s are, respectively :-
body the distance travelled by the body and 5–
4–
its displacement during 5 seconds in metres 3–
will be : 2–
1–
2 4 6
0–
40 –1 – 1 3 5 t(s)
–2–
30 – 3–
velocity (m/sec)

20
(1) 8 m, 16 m (2) 16 m, 8 m
10 (3) 16 m, 16 m (4) 8 m, 8m
0 137. The variation of velocity of a particle moving
1 2 3 4 5 t (in sec) along a straight line is illustrated in the figure.
–10
The distance transvered by the particle in
–20 3 seconds is
–30 v(m/s)
A B
–40 20
C D
(1) 75, 75 (2) 110, 70 10 C'

(3) 110, 110 (4) 110, 40 H G F E

t(s)
0 1 2 3 4
134. The v-t graph of linear motion of a particle
starts its motion from origin is shown in (1) 60 m (2) 45 m (3) 55 m (4) 30 m
138. Velocity-time (v-t) graph for a moving object
adjoining figure. The distance of particle from is shown in the figure. Total displacement of
origin after 8 sec. is :- the object during the time interval when
there is zero acceleration is:–
4 v(m/s)
velocity (m/s)

2 4
0 5 6 7 8
3
1 2 3 4 t (sec)
–2 2
–4 1

(1) 18 meters (2) 16 meters 0

10 20 30 40 50 60 t(sec)
(3) 8 meters (4) 6 meters (1) 60 m (2) 50 m (3) 30 m (4) 40 m

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Kinematics (Motion in a Straight Line & Plane)
139. The velocity versus time curve of a moving 143. Which of the following options is correct for
particle is as shown in the following figure. the object having a straight line motion
The maximum acceleration is represented by the following graph :-
C D
60 C

40 B
t
v(m/s)

A B
20 A
O s
D
0 10 20 30 40 50 60 70 (1) The object moves with constantly
t(sec.) increasing velocity from O to A and then it
(1) 1 m sec–2 (2) 2 m sec–2 moves with constant velocity.
(3) 3 m sec–2 (4) 4 m sec–2 (2) Velocity of the object increases uniformly
140. Find the average acceleration of the block (3) Average velocity is zero
from time t=2 sec to t=4 sec. (4) The graph shown is impossible
v(ms–1) 144. For the motion of a particle acceleration-time
graph is shown in figure. The velocity time
curve for the duration of 0 – 4 seconds is :
10
3
2

a(in m/s2)
t(sec.) 1
1 2 3 4
0
1 2 3 4 t(s)
(1) 5 m/s2 (2) 10 m/s2 –1
–2
(3) –5 m/s 2 (4) –10 m/s2 –3
141. A particle starts from rest. Its acceleration at
time t = 0 is 5 m/s2 which varies with time as 6
shown in the figure. The maximum speed of 5

velocity (in m/s)

4
the particle will be : 6 3
velocity (in m/s)

a 5 m/s2 5 2
4 1
(1) 3 (2) 0 t(s)
2 –1 1 2 3 4
1 –2
0 t(s) –3
0 t 1 2 3 4
8s
V V
(1) 7.5 m/s (2) 15 m/s 3 3
velocity (in m/s)

velocity (in m/s)

2 2
(3) 20 m/s (4) 37.5 m/s
1 1
142. A particle starts from rest, its acceleration- (3) 0 (4) 0
1 2 3 4 t(s) t(s)
time graph is shown in figure. –1 –1
–2 –2
(m/s2) –3 –3
a

145. Acceleration-time graph of a body initially at

10
rest is shown. The corresponding velocity-
time graph of the same body is :-

0 2 4 t (sec) a
5m/s2
Find out velocity at t = 4 sec 10s
6s
(1) 20 m/s (2) 30 m/s t
2s
(3) 40 m/s (4) None of these
–5m/s2
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NEET : Physics
v

distance

distance
10m/s
(1) t (1) (2)
2s 6s 10s
–10m/s t t
O T 2T O T 2T
v

distance
distance
(2) 10m/s (3) (4)
t t t
2s 6s 10s O T 2T O T 2T

v 148. A particle starts from rest and move with

20m/s constant acceleration. Its velocity-displacement
(3) 10m/s curve is :
t
2s 6s 10s v v
(1) (2)
v
s s
10m/s
(4) t v
2s 6s 10s (3) v (4)
–10m/s
s s
146. The given graph shows the variation of
velocity with displacement. Which one of the 149. The graph between the displacement x and
time t for a particle moving in a straight line
graph given below correctly represents the
is shown in figure. During the interval OA, AB,
variation of acceleration with displacement :- BC and CD, the acceleration of the particle is :
v x
30 D
A
B C
x O t
10 OA AB BC CD
a (1) + 0 + +
a (2) – 0 + 0
(1) (2) 90 (3) + 0 – 0
x x
(4) – 0 – 0
–90
150. Acceleration-time curve for a body projected
a a vertically upwards is a/an :–
(1) Parabola (2) Ellipse
(3) (4)
x –90 x (3) Hyperbola (4) Straight line
–90 151. A body is projected vertically upward from
147. The x – t graph of a particle moving along a the surface of the earth, its displacement-time
graph is :
straight line is shown in figure.
s
x s
(1) (2)
t t

O T 2T t s s
The distance-time graph of the particle is
(3) (4)
correctly shown by :
t t
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Kinematics (Motion in a Straight Line & Plane)
152. A rocket is launched upward from the earth's

velocity
surface whose velocity time graphs shown in T 2T
figure. Then maximum height attained by the (2) t
rocket is:
A
1000

velocity
T 2T
v(ms–1)

(3) t
B 140
0 t(s)
20 40 60 80 100 120
C
(1) 1 km (2) 10 km

velocity
2T
(3) 100 km (4) 60 km (4) T t
153. In above Q. no. 152, height covered by the
rocket before retardation is :
159. A ball is dropped vertically from a height d
(1) 1 km (2) 10 km
above the ground. It hits the ground and
(3) 20 km (4) 60 km
bounces up vertically to a height d/2.
154. In above Q. no. 152, mean velocity of rocket
Neglecting subsequent motion and air
during the time it took to attain the maximum resistance, The graph according to which its
height : velocity V varies with the height h above the
(1) 100 m/s (2) 50 m/s ground is :-
(3) 500 m/s (4) 25/3 m/s v v
155. In above Q. no. 152, the retardation of rocket
is: d
(1) h (2) d
h
(1) 50 m/s2 (2) 100 m/s2
(3) 500 m/s2 (4) 10 m/s2
v v
156. In above Q. no. 152, the acceleration of rocket
is :
d d
(1) 50 m/s2 (2) 100 m/s2 (3) h (4) h
(3) 10 m/s2 (4) 1000 m/s2
157. In above Q. no. 152, the rocket goes up and 160. A stone is thrown upwards from top of a
comes down on the following parts tower 60 m high at a speed of 20 m/s. The
respectively : correct position-time graph for the time
(1) OA and AB (2) AB and BC interval in which it reaches ground, is (g = 10
(3) OA and ABC (4) OAB and BC m/s2 & take origin at the base of the tower) :-
158. A ball is dropped from the certain height on x(m)
the surface of glass. It collides elastically and 60
comes back to its initial position. If this
(1)
process it repeated then the velocity time t(s)
graph is : 6

(Take downward direction as positive) x(m)

velocity

(1) T 2T t
20 6
(2) t(s)
2

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x(m) 164. A train takes 4 min. to go between stations
60
2.25 km apart starting and finishing at rest.
(3) The acceleration is uniform for the first 40 sec
6
t(s)
and the deceleration is uniform for the last 20
sec. Assuming the velocity to be constant for
x(m)
the remaining time, then maximum speed of
60
the train is :-
(4) (1) 75 m/sec (2) 18.75 m/sec
t(s) (3) 37.5 m/sec (4) 10.7 m/sec
6
165. A car accelerates from rest at a constant rate
161. A car starts from rest and accelerates
of 2 m/s2 for some time. Then, it retards at a
uniformly by for 4 seconds and then moves
constant rate of 4 m/s2 and comes to rest. If it
with uniform velocity which of the x-t graph
represent the motion of the car ? remains in motion for 3 seconds, then the
maximum speed attained by the car is :
x x (1) 2 m/s (2) 3 m/s
(1) (2) (3) 4 m/s (4) 6 m/s
t t
GROUND TO GROUND PROJECTION
x x 166. In the graph shown in fig. time is plotted along
(3) (4)
x-axis. Which quantity associated with a
t t projectile motion is plotted along the y - axis ?
162. Figure shows x-t graph of a particle. Find the
quantity

time t such that the average velocity of the

particle during the period 0 to t is zero
t
20
(1) kinetic energy (2) momentum
x(in m)

10
(3) horizontal velocity (4) none of the above
0 10 167. For ground to ground projection following
t(sec.)
(1) 6 sec. (2) 8 sec. curves are given :-
(3) 10 sec. (4) 12 sec. (a) (v)
vertical dir.

163. Graph between the square of the velocity (v)

acceleration

velocity in

of a particle and the distance (s) moved is

(a) (b)
shown in figure. The acceleration of the
t t
particle in kilometers per hour square is : O O
(x) (y)
4600
Horizontal

vertical
disp.

disp.

v2 (c) (d)
(km/hr2)
900 t t
O O
s(km) 0.6 Find incorrect one.
(1) a (2) b
(1) 2250 (2) 3084
(3) c (4) d
(3) – 2250 (4) – 3084

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Kinematics (Motion in a Straight Line & Plane)
168. If air resistance is not considered in projectile 174. A body is thrown with a velocity of 19.6 m/s
motion, the horizontal motion takes place making an angle of 300 with the horizontal. It
with will hit the ground after a time :–
(1) constant velocity (1) 3 s (2) 2 s (3) 1.5 s (4) 1 s
(2) constant acceleration 175. If a projectile is fired at an angle  to the
(3) constant retardation vertical with velocity u, then maximum height
attained is given by :
(4) variable velocity
(1) u cos  (2) u sin 
2 2 2
169. In a projectile motion, the velocity :-
2g 2g
(1) is always perpendicular to the acceleration
(3) u sin  (4) u cos 
2 2 2 2

(2) is never perpendicular to the acceleration

g 2g
(3) is perpendicular to the acceleration for
176. At the uppermost point of a projectile its
one instant only
velocity and acceleration are at an angle of :–
(4) is perpendicular to the acceleration for (1) 180° (2) 90° (3) 60° (4)45°
two instants 177. Two projectiles are projected with velocity
170. In projectile motion, the modulus of rate of vA, vB at angles A (from horizontal) and B
change of velocity– (from vertical) as shown in the figure below,
(1) is constant such that vA > vB but having same horizontal
(2) first increases then decreases component of velocity. Which of the following
(3) first decreases then increases can not be correct ?
(4) None of the above y
vA
171. Which of the following quantities remains
constant during projectile motion? B
vB
(A) Average velocity between two points.
A
(B) Average speed between two points x
dv (1) TA > TB (2) HA > HB
(C) (3) RA > RB (4) RB > RA
dt
178. A player throws a ball that reaches to the
d2
(D) (v) another player in 4s. If the height of each
dt 2
player is 1.5m, the maximum height attained
(1) only A (2) only C
by the ball from the ground level is :
(3) A and C (4) C and D
(1) 19.6 m (2) 21.1 m
172. A bomb is fired from a cannon with a velocity
(3) 23.6 m (4) 25.1 m
of 1000 m/s making an angle of 30° with the 179. A body of mass m is thrown upwards at an
horizontal. What is the time taken by the angle  with the horizontal with speed v.
bomb to reach at the highest point- While rising up the magnitude of the velocity
(1) 11 sec (2) 23 sec after t seconds will be:
(3) 38 sec (4) 50 sec
(1) (vcos )2 + (vsin )2
173. If time of flight of a projectile is 10 seconds.
Range is 500 meters. The maximum height (2) (vcos  − vsin )2 − gt
attained by it will be :-
(3) v2 + g2t 2 − (2vsin )gt
(1) 125 m (2) 50 m
(3) 100 m (4) 150 m (4) v2 + g2t 2 − (2vcos )gt

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180. A particle is fired with velocity u making 186. A projectile is thrown from a point in a
 angle with the horizontal. What is the horizontal plane such that its horizontal and
vertical velocity components are 9.8 m/s and
magnitude of change in velocity when it
4.9 m/s respectively. Its horizontal range is :
returns to the ground. (1) 4.9 m (2) 9.8 m
(1) u cos  (2) u (3) 19.6 m (4) 39.2 m
(3) 2u sin  (4) (u cos – u) 187. A projectile is projected with initial velocity
181. In the above, the change in speed is : (5i + 12j) m/s. If g = 10 ms–2, then horizontal

(1) u cos  (2) 0 range is :

(1) 4.8 metre (2) 9.6 metre
(3) u sin  (4) (u cos – u)
(3) 19.2 metre (4) 12 metre
182. The angle which the velocity vector of a 188. A shell is fired vertically upwards with a
projectile, will make with the vertical after velocity v1 from the deck of a ship moving
time t of its being thrown with a velocity v at with a speed v2. A person on the shore
an angle  to the horizontal, is : observes the motion of the shell as a parabola.
Its horizontal range is given by :

(1)  (2) tan −1   2 2

t (1) 2v1 v 2 (2) 2v1 v 2

g g
v sin  − gt 
(3) tan −1  v cos   (4) tan −1  2v 1 v 2 2 2
 (3) (4) 2v1 v 2
 v sin  − gt   v cos   g g
183. At a height 0.4 m from the ground, the 189. The range of a projectile when fired at 60° to the
velocity of a projectile in vector form is: horizontal is 0.5 km. What will be its range
v = (6iˆ + 2j)
ˆ m/s . The angle of projection when fired at 45° with the same speed ?
from horizontal is (g = 10 m/s2) :- 1.0
(1) 0.5 km (2) km
(1) 45° (2) 60° 3
(3) 30° (4) tan–1(3/4) (3) 1.5 km (4) 2.0 km
184. In case of a projectile fired at an angle 60° to 190. The speed of a projectile at its maximum
the horizontal with velocity u, the horizontal 1
range is: height is times of its inital speed 'u' of
2
2 2 2
(1) u (2) 3u2 (3) 2u (4) u2 projection. Its range on the horizontal plane
g 2g g g
is :
185. If the instantaneous velocity of a particle 2 2 2
projected as shown in figure is given by (1) 3u2 (2) u (3) 3u (4) 3u
2g 2g 2g g
ˆ ˆ where a, b and c are positive
191. A bullet is fired from a cannon with velocity
constants, the range on the horizontal plane
will be : 500 m/s. If the angle of projection is 15° and
y g = 10m/s2. Then the range is :-
(1) 25 × 103 m (2) 12.5 × 103 m
(3) 50 × 102 m (4) 25 × 102 m
v 192. For a given angle of projection if the initial
velocity is tripled the range of the projectile
becomes :-
x (1) 9 times (2) one-fourth
(1) 2ab/c (2) ab/c (3) two times (4) four times
(3) ac/b (4) a/2bc
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193. A ball is thrown at an angle  to the vertical and 199. Three particles A, B and C are projectied from
the range is maximum. The value of tan is : the same point with the same initial speeds
(1) 1 (2) 3 making angles 30°, 45° and 60° respectively
(3)
1
(4) 2 with the horizontal. Which of the following
3 statements are correct ?
194. The maximum horizontal range of a gun is (1) A, B and C have unequal ranges
25 km. If g = 10 m/s2, the muzzle velocity of
(2) Ranges of A and C are equal and less than
the shell must be :–
that of B
(1) 1600 m/s (2) 500 m/s
(3) 200 2 m/s (4) 160 10 m/s (3) Ranges of A and C are equal and greater
195. A grasshopper can jump maximum distance than that of B
1.6 m. It spends negligible time on the ground. (4) A, B and C have equal ranges
How far can it go in 10 seconds :- 200. A number of bullets are fired in all possible
(1) 5 2m (2) 10 2m directions with the same initial velocity u.
(3) 20 2m (4) 40 2m The maximum area of ground covered by
196. Three projectiles A, B and C are thrown from bullets is :–
the same point in the same plane. Their 2 2
 2
 u
trajectories are shown in the figure. Which of (1)   2u  (2) 3  
the following statement is incorrect?  g  g
2 2
 u   2
(3) 5   (4)   u 
 2g   g 
201. Four bodies P, Q, R and S are projected with
O AB C
equal speed having angles of projection 15°, 30°,
(1) The time of flight is the same for all the
45° and 60° with the horizontal respectively. The
three
(2) The launch speed is same for all the three body having shortest range is :-
(3) The horizontal velocity component is (1) P (2) Q (3) R (4) S
largest for particle C 202. A boy can throw a stone up to a maximum
(4) The maximum height is same for all the three height of 10 m. The maximum horizontal
197. A projectile is thrown with an initial distance up to which the boy can throw the
velocity of v = aiˆ + bjˆ . If range of the same stone will be :
projectile is four times the maximum height (1) 20 2m (2) 10 m (3) 10 2m (4) 20 m
attained by it then : 203. A cricketer can throw a ball to a maximum
(1) a = 2 b (2) b = a horizontal distance of 100m. How much high
(3) b = 2a (4) b = 4a
above the ground can the cricketer throw the
198. Two projectiles are fired from the same point
same ball :-
with the same speeds at angles of projection
(1) 200m (2) 400m (3) 100m (4) 50m
60° and 30° respectively. Which one of the
204. The maximum range of a projectile fired with
following is true ?
some initial velocity is found to be 2000 m.
(1) Their horizontal ranges will be the same
The maximum height (H) reached by this
(2) Their maximum heights will be the same
projectile is:
(3) Their landing velocities will be the same (1) 250 metre (2) 500 metre
(4) Their times of flight will be the same (3) 1000 metre (4) 2000 metre
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205. The cannon was set by mistake at 30° instead 210. Two stones are projected with the same
of 20° with the horizontal and was fired to hit speed but making different angles with the
the enemy target. The cannon-shell will now horizontal. Their ranges are equal. If the angle
fall at : 
of projection of one is and its maximum
(1) The enemy target 6
(2) Before the enemy target height is y1, then the maximum height of the
(3) Beyond the enemy target other will be :
(4) May fall at any place y y
(1) 3y1 (2) 2y1 (3) 1 (4) 1
206. Two similar cannon simultaneously fires two 2 3
identical cannon balls at target 1 and 2 as 211. A ball is thrown at different angles with the
shown in the figure. If the cannon balls have same speed u and from the same point; it has
identical initial speeds, which of the following the same range in both the cases. If y1 and y2
statements is true? be the heights attained in the two cases, then
y1 + y2 =... :
2 2 2 2
(1) u (2) 2u (3) u (4) u
g g 2g 4g
2 1
212. A body is projected at such an angle that the
(1) Target 2 is hit before target 1 horizontal range is four times the greatest
(2) Target 1 is hit before target 2 height. The angle of projection is :–
(3) Both are hit at the same time (1) 25° (2) 33° (3) 45° (4) 53°
(4) information is insufficient 213. The horizontal range of a projectile is 4 3
207. If R is the horizontal range of a particle times of its maximum height. Its angle of
projected at an angle 53° from horizontal, projection from horizontal will be:
then the greatest height attained by it is : (1) 45° (2) 60° (3) 90° (4) 30°
R 214. A projectile have range double as compare to
(1) (2) 2R its maximum height attained. The angle of
3
R R projection from horizontal is–
(3) (4) (1) tan–1 (2) (2) tan–1 (4)
2 4
(3) tan–1 (3) (4) tan–1 (5)
208. A projectile can have the same range R for
215. The speed of a projectile at its maximum
two angles of projection. If h1 and h2 be the
3
maximum height in the two cases, then :– height is times its initial speed. If the
2
(1) h1h2  R 2 (2) h1h2  R
range of the projectile is ‘P’ times the
1 1 maximum height attained by it, then P
(3) h1h2  (4) h1 h2  2
R R equals to -
209. A body is thrown with some velocity from the 4
ground. Maximum height attained when it is (1) (2) 2 3
3
thrown at 37° to the horizontal is 90 m. What 3
is the height attained when it is thrown at 53° (3) 4 3 (4)
4
to the horizontal? 216. A ball is projected to attain the maximum
(1) 90 m (2) 45 m range. If the height attained is H, the range is
(3) 120 m (4) 160 m (1) H (2) 2H (3) 4H (4) H/2

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Kinematics (Motion in a Straight Line & Plane)
gx 2 225. In the Q. 222, the angle of projection with the
217. The equation of a projectile is y = x – . The
2 horizontal is :
angle of projection is : (1) tan −1  4  (2) tan −1  5 
(1) 30° (2) 60° 5 4
(3) 45° (4) none (3) tan −1  5  (4) tan −1  8 
x 2 8 5
218. The equation of a projectile is y = 4x – . The
4 226. A projectile is thrown into space so as to have
horizontal range is : the maximum possible horizontal range equal
(1) 16 m (2) 8 m to 200m. Taking the point of projection as the
(3) 64 m (4) 12.8 m origin, the coordinates of the point where the
219. A particle is projected at an angle of 45° from velocity of the projectile is minimum are:
(1) (200, 100) m (2) (50, 200) m
horizontal, 6m away from the foot of a wall,
(3) (100, 50) m (4) (50, 100) m
just touches the top of the wall and falls on the
227. If the range of a gun which fires a shell with
ground on the opposite side at a distance 3m
muzzle speed v, is R, then the angle of
from it. The height of wall is :
elevation of the gun is :
4 8 3
−1  v 
(1) 2m (2) m (3) m (4) m 2
3 3 4 (1) cos   (2) cos −1  Rg2 
220. A stone is projected from the ground with  Rg  v 
velocity 50 m/s at an angle of 30° from 1 −1  v2 
(3) sin   (4) 1 sin −1  Rg2 
horizontal. It crosses a wall after 3 sec. How 2  Rg  2 v 
far beyond the wall the stone will strike the
228. Two balls A and B are thrown with speeds u
ground (g = 10m/sec2) and u/2 respectively. Both the balls cover the
(1) 90.2 m (2) 89.6 m same horizontal distance before returning to
(3) 86.6 m (4) 70.2 m the plane of projection. If the angle of
221. A shell fired from the ground is just able to cross projection of ball B is 30° with the horizontal,
the top of a wall 90m away and 45 m high then the angle of projection of A is :
moving horizontally. The direction of 1  3
(1) sin −1  1  (2) sin −1 
projection of the shell from horizontal will be :-
8 2  8 
(1) 25° (2) 30° (3) 60° (4) 45°  
222. An arrow is shot into the air. Its range is (3) 1 sin −1  1  (4) 1 sin −1  1 
3 8 4 8
100 metres and its time of flight is 5 s. If the
value of g is assumed to be 10 m/s2, then the 229. Two balls are projected from the same point
horizontal component of the velocity of arrow on the ground simultaneously. First ball is
is : projected vertically upwards and the second
ball at an angle of projection 60° from the
(1) 40 m/s (2) 20 m/s
horizontal. Both the balls reach the ground
(3) 31.25 m/s (4) 12.5 m/s
simultaneously. The ratio of their velocities of
223. In the Q. 222, the maximum height attained by
projection are :
the arrow is :
(1) 1 : 2 (2) 3 : 2 (3) 3 : 2 (4) 2 : 3
(1) 25 m (2) 20 m/s
230. A body is projected at an angle  with
(3) 31.25 m (4) 12.5 m
horizontal, another body is projected with the
224. In the Q. 222, the vertical component of the
same speed at an angle  with the vertical
projection velocity is :
then the ratio of the maximum height is :-
(1) 25 m/s (2) 40 m/s
(1) 1 : 1 (2) tan2 : 1
(3) 12.5 m/s (4) 31.25 m/s
(3) 1 : cot (4) none of these
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231. A ball is thrown from a point on earth surface PROJECTION FROM A HEIGHT
with a speed v at an angle of projection  from 239. A stone is projected horizontally with a speed
horizontal. From the same point and at the 10 m/s from a 80 m high building. The
same instant a person starts running with a distance of the target on the ground from the
v foot of the building is :- (g = 10 m/s2)
constant speed to catch the ball. The angle
2 (1) 80 m (2) 40 m (3) 20 m (4) 10 m
of projection of the ball from horizontal is :- 240. An aeroplane moving horizontally with a
(1) 60° (2) 30° (3) 90° (4) 45° speed of 90 km/h drops a food packet while
232. For a projectile the ratio of maximum height flying at a height of 490 m. The horizontal
reached to the square of flight time is range of the packet is :
(g=10 m/s2):- (1) 180 m (2) 250 m
(1) 5 : 4 (2) 5 : 2 (3) 5 : 1 (4) 10 : 1 (3) 500 m (4) 670 m
233. At what angle to the horizontal should a ball be 241. A stuntman plans to run along a roof top and
thrown so that its range R is related to the time then horizontally off it to land on the roof of
of flight T as R = 5 3T2 ? Take g = 10 ms–2 : next building. The roof of the next building is
(1) 30° (2) 45° (3) 60° (4) 90° 19.6 metres below the first one and 6.2
234. A ball whose kinetic energy is E, is thrown at an metres away from it. What should be his
angle of 60° to the horizontal. Its kinetic energy minimum roof top speed in m/s, so that he
at the highest point of its flight will be :– can successfully make the jump ?
E E E (1) 3.1 (2) 4.0 (3) 4.9 (4) 6.2
(1) (2) (3) (4) zero
4 2 2 242. Two stones are projected horizontally from
235. A cricket ball is hit at an angle of 30° with the the same height with speeds 100 m/s and 40
vertical with kinetic energy K . The kinetic m/s. The ratio of their horizontal range is :-
energy of the ball at the highest point of the (1) 1 : 1 (2) 5 : 2 (3) 2 : 5 (4) 3 : 4
path is :- 243. A body is thrown horizontally with a velocity
(1) Zero (2) K/4 (3) K/2 (4) 3K/4
20 m/s from the top of a tower of height 20
236. A ball is projected vertically upwards with a
m. It strikes the level ground through the foot
certain speed. Another ball of the same mass
of the tower at a distance x from the tower.
is projected at an angle 300 to the vertical
The value of x is :-
with the same initial speed. The ratio of their
potential energies at highest points of their (1) 20 m (2) 10 m (3) 40 m (4) 30 m
journey, will be 244. A bomber is flying horizontally with a
(1) 4 : 3 (2) 2 : 1 (3) 3 : 2 (4) 4 : 1 constant speed of 150 m/s at a height of 19.6
237. A particle is projected with a velocity u m. The pilot has to drop a bomb at the enemy
making an angle  with the horizontal. At any target. At what horizontal distance from the
instant, its velocity v is at right angle to its target should he release the bomb?
initial velocity u; then v is: (1) 0 m (2) 300 m
(1) u cos  (2) u tan  (3) 600 m (4) 1000 m
(3) u cot  (4) u sec  245. A boy wants to jump from building A to
238. A force F = (6t
2 ˆi + 4tj)N
ˆ acts on a particle of mass building B. Height of building A is 25 m and
that of building B is 5m. Distance between
1 kg. What will be velocity of the particle at
t = 3 second if at t = 0, the particle was at rest :- buildings is 8m. Assume that the boy jumps
horizontally, then calculate minimum
(1) (54iˆ + 12j)
ˆ m/s (2) (54iˆ + 18j)
ˆ m/s
velocity with which he has to jump to land
(3) (12iˆ + 6j)
ˆ m/s (4) none safely on building B.
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Kinematics (Motion in a Straight Line & Plane)
251. A plane is flying horizontally at 98 3 m/s
and releases an object which reaches the
25 m
ground in 10 s. The angle made by it with
A B 5m horizontal while hitting the ground is :
8m
(1) 55° (2) 45° (3) 60° (4) 30°
(1) 6 m/s (2) 8 m/s
252. From the top of a tower 78.4 m high, a ball is
(3) 4 m/s (4) 2 m/s
thrown horizontally. If the line joining the point
246. A boy wants to jump from building A to building
of projection to the point where it hits the
B. Height of building A is 39.2 m and building B
ground makes an angle of 45° with the
is 19.6m. Distance between buildings is 20 m.
horizontal, then the initial velocity of the ball is :
Assuming boy jumps horizontally, then
(1) 9.8 m/s (2) 4.9 m/s
calculate minimum velocity with which boy has
(3) 19.6 m/s (4) 2.8 m/s
to jump to land safely on building B :-
253. A particle is projected horizontally with a
20
39.2 m
speed of m/s, from some height at t = 0. At
3
A B 19.6 m
what time will its velocity make 30° angle
with the initial velocity
20m
20 m/s
(1) 10 m/s (2) 20 m/s 3
(3) 9.8 m/s (4) 19.6 m/s
247. Two buildings are separated by 30 m. By
what speed a ball is projected horizontally (1) 1 sec (2) 2 sec (3) 1.5 sec (4) 2/3 sec
from a window at height 150 m in one 254. In the above question what will be the
building so as to enter in the window at displacement of the particle in x-direction
height 27.5 m in the other building. when its velocity makes 30° angle with the
(1) 2 m/s (2) 6 m/s (3) 4 m/s (4) 8 m/s initial velocity
248. Two bodies of masses 100 kg and 50 kg are 20 40 50 10
(1) m (2) m (3) m (4) m
projected horizontally from same height with 3 3 3 3 3
speeds 40 m/s and 20 m/s, simultaneously. 255. A ball is projected upwards from the top of a
The ratio of time taken by both the bodies to tower with a velocity of 50 m/s making an
reach the ground is :- angle of 300 with the horizontal. The height of
(1) 1 : 1 (2) 1 : 2 (3) 2 : 1 (4) 1 : 4 the tower is 70m. After how much time from
249. A ball is thrown horizontally from a height of the instant of throwing, will the ball reach the
90 m with a speed of 4.5 m/s then find the ground?
time when it is at the height of 45 m from the (1) 2 s (2) 5 s (3) 7 s (4) 9 s
ground: RELATIVE MOTION IN ONE DIMENSION
(1) 3 2 sec (2) 10 sec (3) 9 sec (4) 3 sec 256. Which one of the following represents the
250. When a particle is thrown horizontally with displacement-time graph of two objects A and
speed u from top of tower, the displacement B moving with zero relative speed :-
of the projectile at any time t is given by :
Displacement

A
Displacement

1 2 4 B
(1) u2t 2 + g2t 2 (2) u2 t 2 + g t A
4 (1) B (2)
(3) u2 + g2t 2 (4) u2 − g2t 2 Time Time
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A 262. A train is moving towards East with a speed

Displacement

Displacement
A
B 20 m/s. A person is running on the roof of the
(3) (4) B train with a speed 3 m/s in the direction of
Time Time motion of train. Velocity of the person as seen
by an observer on ground will be :
257. A monkey is climbing up a tree at a speed of
3 m/s. A dog runs towards the tree with a (1) 23 m/s towards East
speed of 4 m/s. What is the relative speed of (2) 17 m/s towards East
the dog as seen by the monkey ? (3) 23 m/s towards West
(1) > 7 m/s (4) 17 m/s towards West
(2) Between 5 m/s and 7 m/s 263. A jet air plane travelling with a speed of 500
(3) 5 m/s km/h ejects its products of combustion with
(4) < 5 m/s a speed of 1600 km/h relative to the jet plane.
258. A train is moving towards east and a car is The speed of the latter with respect to an
along north, both with same speed. The observer on the ground is :–
observed direction of car to the passenger in (1) 1600 km/h (2) 2100 km/h
the train is:- (3) 1100 km/h (4) 500 km/h
(1) East-north direction 264. A train moves in north direction with a speed
(2) West-north direction of 54 km/h. A monkey is running on the roof
(3) South-east direction of the train, against its motion with a velocity
(4) None of these of 36 km/h. with respect to train. The velocity
259. Two car A & B start from rest (from the same of monkey as observed by a man standing on
point) in same direction with acceleration 8 the ground is:
m/s2 & 4 m/s2 respectively then acceleration (1) 5 m/s due north
of car B in frame of A(Take direction of
(2) 25 m/s due south
motion of car is positive) :-
(3) 10 m/s due south
(1) 4 m/s2 (2) –4 m/s2
(4) 10 m/s due north
(3) 12 m/s2 (4) None of these
265. A lift is moving upwards with acceleration a.
260. A motorcycle is moving with a velocity of
A man in the lift drops a ball within the lift.
80 km/h and a car is moving with a velocity
The acceleration of the ball as observed by
of 65 km/h in the opposite direction. What is
the man in the lift and a man standing
the relative velocity of the motorcycle with
stationary on the ground are respectively :
respect to the car ?
(1) g, g (2) g – a, g – a
(1) 15 km/h (2) 20 km/h
(3) g + a, g (4) a, g
(3) 25 km/h (4) 145 km/h
266. A stone is thrown upwards and it rises to a
261. Two cars A and B start moving from the same
height of 200 m. The relative velocity of the
point with same speed  = 5 km/minute. Car
stone with respect to the earth will be
A moves towards south and car B is moving
minimum at :–
towards west. What is the relative velocity of
(1) Height of 100 m (2) Height of 150 m
B with respect to A ?
(3) Highest point (4) The ground
(1) 5 2 km/min towards South-East
267. A 100 m long train crosses a man travelling at
(2) 5 2 km/min towards North-West
5 km/h, in opposite direction in 6 seconds,
(3) 5 2 km/min towards South-West
then the velocity of train is :–
(4) 5 2 km/min towards North-East
(1) 40 km/h (2) 55 km/h
(3) 20 km/h (4) 45 km/h
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Kinematics (Motion in a Straight Line & Plane)
268. A 300 metres long train is moving due north u
P Q
with a speed of 20 m/s. A small bird is flying u
due south a little above the train with 5 m/s d
speed The time taken by the bird to cross the u
train is :- S u R
(1) 6 s (2) 7 s (3) 9 s (4) 12 s d 2d 2d
(1) (2) (3) (4) d 3u
269. Two trains each 100 m long, are travelling in u 3u u
opposite directions with respective velocities 275. Six persons of same mass travel with same
35 m/s and 15 m/s. The time of crossing is :– speed u along a regular hexagon of side 'd' such
(1) 2 s (2) 4 s that each one always faces the other. After how
2 3s 4 3s much time will they meet each other ?
(3) (4)
u u
270. A train 200 m long crosses a bridge 300 m
long. It enters the bridge with a speed of 30 u u d
ms–1 and leaves it with a speed of 50 ms–1.
What is the time taken to cross the bridge ? u u
(1) 2.5s (2) 7.5s d 2d 2d
(1) (2) (3) (4) d 3u
(3) 12.5s (4) 15.0s u 3u u
271. Two cars get closer by 8 m in every second 276. A person walks up a stalled escalator in 45
while travelling in the opposite directions. sec. He is carried in 60s, when standing on the
They get closer by 0.8 m in every second same escalator which is now moving. The
while travelling in the same direction. What time he would take to walk up the moving
are the speeds of the two cars? escalator will be :–
(1) 4 ms–1 and 4.4 ms–1 (1) 27 s (2) 72 s
(2) 4.4 ms–1 and 3.6 ms–1 (3) 18 s (4) 25.71 s
(3) 4 ms–1 and 3.6 ms–1 277. A bus starts from rest moving with an
(4) 4 ms–1 and 3 ms–1 acceleration of 2m/s2. A cyclist, 96 m behind
272. Velocity of a swimmer in still water is 5 m/s. the bus starts simultaneously towards the
bus at 20 m/s. After what time will he be able
If he takes 10 sec to swim upstream a distance
to overtake the bus :–
of 30 m, then the speed of river is :-
(1) 8 s (2) 10 s (3) 12 s (4) 1 s
(1) 3 m/s (2) 5 m/s
278. A boat takes 2 hours to go 10 km and come
(3) 10 m/s (4) 2 m/s
back in still water lake. The time taken for
273. Two cars are moving in the same direction
going 10 km upstream and coming back with
with the same speed of 60 km/h. They are
water velocity of 5 km/h is :
separated by 10 km. What is the speed of a car (1) 140 min (2) 150 min
moving in the opposite direction if it meets (3) 160 min (4) 170 min
the two cars at an interval of 5 minute? 279. A river 2 km wide flows at the rate of 2km/h.
(1) 45 km/h (2) 60 km/h A boatman who can row a boat at a speed of
(3) 105 km/h (4) None 6 km/h in still water, goes a distance of 2 km
274. Four persons P, Q, R and S of same mass travel upstream and then comes back. The time
with same speed u along a square of side 'd' taken by him to complete his journey is
such that each one always faces the other. (1) 60 min (2) 45 min
After what time will they meet each other? (3) 80 min (4) 90 min

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NEET : Physics
280. Two bodies are held separated by 9.8 m RELATIVE MOTION IN TWO DIMENSION
vertically one above the other. They are 285. A boat is sent across a river with a velocity of
released simultaneously to fall freely under 8km/hr. If the resultant velocity of boat is
gravity. After 2 s the relative distance 10 km/hr, then velocity of the river is
between them is :- (1) 10 km/hr (2) 8 km/hr
(1) 4.9 m (2) 19.6 m (3) 6 km/hr (4) 4 km/hr
(3) 9.8 m (4) 39.2m 286. A bird is flying towards south with a velocity
281. Two balls are thrown simultaneously, (A) 40km/h and a train is moving with a velocity
vertically upwards with a speed of 20 m/s 40 km/h towards east. What is the velocity of
from the ground and (B) vertically the bird w.r.t. an observer in the train ?
downwards from a height of 80 m with the (1) 40 2 km/h. N-E (2) 40 2 km/h. S-E
same speed and along the same line of
(3) 40 2 km/h. S-W (4) 40 2 km/h. N-W
motion. At which point will the balls collide?
287. A bird is flying with a speed of 40 km/h in the
(take g = 10 m/s2)
(1) 15 m above from the ground north direction. A train is moving with a
(2) 15 m below from the top of the tower speed of 30 km/h in the west direction. A
(3) 20 m above from the ground passenger sitting in the train will see the bird
(4) 20 m below from the top of the tower moving with velocity :
282. While sitting on a tree branch 20m above the (1) 50 km/hr, 53° North of east
ground, you drop a walnut. When the walnut (2) 50 km/hr, 37° North of east
has fallen 5m, you throws a second walnut (3) 50 km/hr, 53° East of north
straight down. What initial speed must you (4) 50 km/hr in North East direction
give the second walnut if they are both to 288. A boat is sailing with a velocity (3iˆ + 4j)
ˆ with
reach the ground at the same time?
respect to ground and water in river is
(g=10ms–2)
flowing with a velocity (−6iˆ − 8j)
ˆ . Relative
(1) 5 ms–1 (2) 10 ms–1
(3) 15 ms –1 (4) None of these velocity of the boat with respect to water is :
283. A body A is thrown up vertically from the (1) 8jˆ (2) 9iˆ + 12jˆ
ground with velocity v0 and another body B is
(3) 6iˆ + 8jˆ (4) −6iˆ − 8jˆ
simultaneously dropped from a height H.
H 289. Let r1(t) = 3tiˆ + 4t 2ˆj and r2(t) = 4t 2ˆi + 3tjˆ
They meet at a height if v0 is equal to
2 represent the positions of particles 1 and 2,
(1) 2gH (2) gH respectively as functions of time t; r1(t) and
1 r2(t) are in metres and t is in seconds. The
(3) gH (4) 2g
2 H relative speed of the two particles at the
284. An elevator is accelerating upward at a rate of instant t = 2 sec, will be
6 ft/sec2 when a bolt from its ceiling falls to (1) 1 m/s (2) 13 2 m/s
the floor of the lift (Distance = 19 feet). The (3) 5 2 m/s (4) 7 2 m/s
time (in seconds) taken by the falling bolt to
290. Rain is falling vertically with a speed of 3 m/s.
hit the floor is (take g = 32 ft/ sec2)
If a man is running with the same speed then
(1) 2 (2) 1
the velocity of rain w.r.t. man is :-
1
(3) 2 2 (4) (1) 3 m/s (2) 6 m/s
2 2
(3) 4.2 m/s (4) 0 m/s
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Kinematics (Motion in a Straight Line & Plane)
291. A man is walking on a road with a velocity of
(1) tan −1  v 
5km/h. When suddenly it starts raining, u
velocity of rain is 10km/h in vertically (2) sin −1  v 
downward direction, relative velocity of the u
rain with respect to man is : (3) tan −1  u 
v
(1) 13 km/hr

(2) (4) cos −1  v 

7 km/hr u
(3) 109 km/hr 295. A river is flowing at the rate of 8 km/h. A
swimmer swims across the river with a
(4) 5 5 km/hr
velocity of 10 km/h w.r.t. water. The resultant
292. If the rain is falling vertically downwards velocity of the man will be in (km/h):-
with velocity 20 m/s and if a bike is going (1) 117 (2) 340
with velocity 30 m/s. Calculate at what angle (3) 164 (4) 3 40
from the vertical a man on the bike must
296. A river is flowing from W to E with a speed of
incline his umbrella so that he can save 5 m/min. A man can swim in still water with
himself from rain :- a velocity 10 m/min. In which direction
(1) tan −1  2  should the man swim so as to take the
3 shortest possible path to go to the north :-
(2) tan −1  3  (1) 30° with downstream
2 (2) 60° with downstream
(3) tan–1 (1) (3) 120° with downstream
(4) South
(4) tan −1  6 
5 297. A river 4.0 miles wide is flowing at the rate of
293. If rain is falling at some angle from vertical 2 miles/hr. The minimum time taken by a
and has horizontal velocity 2 m/s in east boat to cross the river with a speed  = 2
direction. With what velocity a man must miles/hr (in still water) is approximately
move on the horizontal surface so that rain (1) 1 hr and 0 minute
will appear vertical to him :- (2) 2 hr

(1) 4 m/s in east direction (3) 1 hr and 12 minutes

(4) 2 hr and 25 minutes
(2) 2 m/s in east direction
298. A river flows from east to west with a speed
(3) 2 m/s in west direction
of 5m/min. A man on south bank of river,
(4) 2 m/s in a circular path
capable of swimming at the rate of 10 m/min
294. A boy is running on a levelled road with in still water, wants to swim across the river
velocity (u) with a long hollow tube in his in shortest time; he should swim :
hand. Water is falling vertically downwards (1) due north
with velocity (v). At what angle to the vertical, (2) due north-east
should he incline the tube so that the water (3) due north-east with double the speed of river
drops enters without touching its side : (4) none of the above

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NEET : Physics
299. A boat-man can row a boat to make it move 301. Two particles are separated by a horizontal
with a speed of 10 km/h in still water. River distance x as shown in figure. They are projected
flows steadily at the rate of 6 km/h. and the as shown in figure with different initial speeds.
width of the river is 4 km. If the boat man The time after which the horizontal distance
cross the river along the minimum distance of between them becomes zero is :
approach then time elapsed in rowing the 3u
boat will be : u

2 3 2
(1) h (2) h 30° 60°
5 5 3 x
3 2 1
(3) h (4) h x
5 2 (1)
u
300. A man wishes to swim across a river 0.5 km
u
wide. If he can swim at the rate of 2 km/h in (2)
2x
still water and the river flows at the rate of
x
1 km/h. The angle made by the direction (3)
2u
(w.r.t. the flow of the river) along which he
(4) none of these
should swim so as to reach a point exactly
opposite his starting point, should be :
(1) 60° (2) 120°
(3) 135° (4) 90°

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Kinematics (Motion in a Straight Line & Plane)
EXERCISE-I (Conceptual Questions) ANSWER KEY
Question 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15
Answer 2 1 1 4 3 2 2 3 2 1 1 3 2 1 3
Question 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30
Answer 3 2 2 3 2 2 2 1 2 3 3 1 4 4 3
Question 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45
Answer 4 4 3 1 4 3 4 4 1 1 3 1 1 1 2
Question 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60
Answer 1 1 4 3 2 2 3 4 1 4 1 1 3 2 1
Question 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75
Answer 4 4 2 2 1 2 4 3 3 3 2 4 4 2 3
Question 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90
Answer 3 1 2 3 2 3 3 3 2 3 2 3 3 3 3
Question 91 92 93 94 95 96 97 98 99 100 101 102 103 104 105
Answer 2 4 1 3 3 4 1 3 1 1 2 1 1 4 2
Question 106 107 108 109 110 111 112 113 114 115 116 117 118 119 120
Answer 2 1 4 2 2 3 2 2 3 3 2 3 2 3 1
Question 121 122 123 124 125 126 127 128 129 130 131 132 133 134 135
Answer 1 3 1 2 3 3 2 4 2 2 4 4 2 4 2
Question 136 137 138 139 140 141 142 143 144 145 146 147 148 149 150
Answer 1 2 4 4 3 3 2 3 1 1 1 1 2 3 4
Question 151 152 153 154 155 156 157 158 159 160 161 162 163 164 165
Answer 4 4 2 3 4 1 4 3 1 3 4 4 4 4 3
Question 166 167 168 169 170 171 172 173 174 175 176 177 178 179 180
Answer 3 2 1 3 1 4 4 1 2 4 2 4 2 3 3
Question 181 182 183 184 185 186 187 188 189 190 191 192 193 194 195
Answer 2 3 3 2 1 2 4 3 2 1 2 1 1 2 3
Question 196 197 198 199 200 201 202 203 204 205 206 207 208 209 210
Answer 2 2 1 2 4 1 4 4 2 3 2 1 1 4 1
Question 211 212 213 214 215 216 217 218 219 220 221 222 223 224 225
Answer 3 3 4 1 3 3 3 1 1 3 4 2 3 1 2
Question 226 227 228 229 230 231 232 233 234 235 236 237 238 239 240
Answer 3 4 2 3 2 1 1 1 1 2 1 3 2 2 2
Question 241 242 243 244 245 246 247 248 249 250 251 252 253 254 255
Answer 1 2 3 2 3 1 2 1 4 2 4 3 4 2 3
Question 256 257 258 259 260 261 262 263 264 265 266 267 268 269 270
Answer 2 3 2 2 4 2 1 3 1 3 3 2 4 2 3
Question 271 272 273 274 275 276 277 278 279 280 281 282 283 284 285
Answer 2 4 2 1 3 4 1 3 2 3 3 3 2 2 3
Question 286 287 288 289 290 291 292 293 294 295 296 297 298 299 300
Answer 3 1 2 2 3 4 2 2 3 3 3 2 1 4 3
Question 301
Answer 3
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NEET : Physics

Exercise - II (Previous Year Questions) AIPMT/NEET

AIPMT 2006 7. The position x of a particle with respect to
1. A car runs at a constant speed on a circular time t along x-axis is given by x= 9t2–t3 where
track of radius 100 m, taking 62.8 seconds for x is in metres and t in seconds. What will be
the position of this particle when it achieves
every circular lap. The average velocity and
maximum speed along the + x direction ?
average speed for each circular lap
(1) 24 m (2) 32 m (3) 54 m (4) 81 m
respectively is :- 8. The distance travelled by a particle starting
(1) 0,0 (2) 0, 10 m/s from rest and moving with an acceleration
(3) 10 m/s, 10 m/s (4) 10 m/s, 0 4
m / s2 , in the third second is :-
2. A particle moves along a straight line OX. At a 3
time t (in seconds) the distance x (in metres) of 10 19
(1) m (2) m (3) 6m (4) 4m
the particle from O is given by x = 40 + 12t – t3. 3 3
How long would the particle travel before AIPMT 2008
coming to rest ? 9. A particle moves in a straight line with a constant
acceleration. It changes its velocity from 10 m/s
(1) 24 m (2) 40 m (3) 56 m (4) 16 m
to 20 m/s while passing through a distance of
3. Two bodies, A (of mass 1 kg) and B (of mass 3 135 m in t seconds. The value of t is :-
kg), are dropped from heights of 16 m and 25 (1) 12 (2) 9 (3) 10 (4) 1.8
m respectively. The ratio of the time taken by 10. A particle shows distance-time curve as given
them to reach the ground is :- in this figure. The maximum instantaneous
5 12 5 4 velocity of the particle is around the point :-
(1) (2) (3) (4)
4 5 12 5
Distance

D
4. For angles of projection of a projectile S
C
(45° – ) and (45° + ), the horizontal
ranges described by the projectile are in the A B
ratio of :- t Time
(1) 1 : 1 (2) 2 : 3 (3) 1 : 2 (4) 2 : 1 (1) D (2) A (3) B (4) C
AIPMT 2007 11. A particle of mass m is projected with velocity
v making an angle of 45° with the horizontal.
5. A car moves from X to Y with a uniform speed
When the particle lands on the ground level,
vu and returns to X with a uniform speed vd.
the magnitude of the change in its momentum
The average speed for this round trip is :- will be:-
v + vd (1) mv 2 (2) zero (3) 2 mv (4) mv/ 2
(1) u (2) 2v d v u
2 vd + vu AIPMT 2009
12. A body starting from rest is moving under a
vu vd
(3) (4) v d v u constant acceleration up to 20 sec. If it moves
vd + vu S1 distance in first 10 sec., and S2 distance in
6. A particle moving along x-axis has acceleration next 10 sec. then S2 will be equal to :
(1) S1 (2) 2S1 (3) 3S1 (4) 4S1
f, at time t, given by f = fo  1 − t  , where fo and 13. A bus is moving with a speed of 10 m/s on a
 T
straight road. A scooterist wishes to overtake
T are constants. The particle at t = 0 has zero the bus in 100 s. If the bus is at a distance of 1
velocity. At the instant when f = 0, the particle's km from the scooterist, with what speed
velocity is :- should the scooterist chase the bus ?
1 1 (1) 10 m/s (2) 20 m/s
(1) fo T (2) foT (3) fo T2 (4) foT2 (3) 40 m/s (4) 25 m/s
2
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Kinematics (Motion in a Straight Line & Plane)
AIPMT (Pre) 2010 AIPMT (Mains) 2011
14. A particle moves a distance x in time t 21. A particle covers half of its total distance with
according to equation x = (t + 5)–1. The speed v1 and the rest half distance with speed
acceleration of particle is proportional to :- v2. Its average speed during the complete
(1) (velocity)2/3 (2) (velocity)3/2 journey is:-
v + v2
(3) (distance)2 (4) (distance)–2 (1) 1 (2) v 1 v 2
15. A ball is dropped from a high rise platform at 2 v1 + v2

t = 0 starting from rest. After 6 seconds v 12 v 22

(3) 2v 1 v 2 (4) 2
another ball is thrown downwards from the v1 + v2 v 1 + v 22
same platform with a speed v. The two balls 22. A projectile is fired at an angle of 45° with the
meet at t = 18s.What is the value of v ? horizontal. Elevation angle of the projectile at
(take g = 10 m/s2) its highest point as seen from the point of
(1) 60 m/s (2) 75 m/s projection, is :
(3) 55 m/s (4) 40m/s (1) 45° (2) 60°
16. ( )
A particle has initial velocity 3iˆ + 4jˆ and
(3) tan–1
1  3
(4) tan–1 
2  2 
( )
has acceleration 0.4iˆ + 0.3jˆ . Its speed after
AIPMT (Pre) 2012
 

10s is :- 23. The motion of a particle along a straight line

(1) 10 units (2) 7 units is described by equation x = 8 + 12t – t3 where
(3) 7 2 units (4) 8.5 units x is in metres and t in seconds. The
AIPMT (Mains) 2010 retardation of the particle when its velocity
17. The speed of a projectile at its maximum becomes zero is :-
height is half of its initial speed. The angle of (1) 6 m/s2 (2) 12 m/s2
projection is :- (3) 24 m/s2 (4) zero
(1) 15° (2) 30° (3) 45° (4) 60° 24. The horizontal range and the maximum
height of a projectile are equal. The angle of
AIPMT (Pre) 2011
projection of the projectile is :-
18. A boy standing at the top of a tower of 20 m
(1)  = tan–1(2) (2)  = 45°
height drops a stone. Assuming g = 10 m/s2,
1
the velocity with which it hits the ground is :- (3)  = tan–1   (4)  = tan–1(4)
4
(1) 10.0 m/s (2) 20.0 m/s
(3) 40.0 m/s (4) 5.0 m/s 25. A particle has initial velocity ( 2iˆ + 3jˆ ) and
19. A body is moving with velocity 30 m/s acceleration ( 0.3iˆ + 0.2jˆ ) . The magnitude of
towards east. After 10 seconds its velocity
velocity after 10 seconds will be :
becomes 40 m/s towards north. The average (1) 5 units (2) 9 units
acceleration of the body is :- (3) 9 2 units (4) 5 2 units
(1) 1 m/s2 (2) 7 m/s2 AIPMT (Mains) 2012
(3) 7 m / s2 (4) 5 m/s2 26. A stone is dropped from a height h. It hits the
20. A missile is fired for maximum range with an ground with a certain momentum P. If the
initial velocity of 20 m/s. If g = 10 m/s2, the same stone is dropped from a height 100%
range of the missile is :- more than the previous height, the
(1) 40 m (2) 50 m momentum when it hits the ground will
(3) 60 m (4) 20 m change by :-
(1) 200 % (2) 100 % (3) 68% (4) 41%
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NEET : Physics
NEET-UG 2013 AIPMT 2015
27. A stone falls freely under gravity. It covers 31. A particle of unit mass undergoes one-
distances h1, h2 and h3 in the first 5 seconds, dimensional motion such that its velocity
the next 5 seconds and the next 5 seconds varies according to
respectively. The relation between h1, h2 and v(x) = x–2n
h3 is :- where  and n are constants and x is the
(1) h1 = h2 = h3 position of the particle. The acceleration of
(2) h1 = 2h2 = 3h3 the particle as a function of x, is given by :
h h (1) –2n2x–4n–1 (2) –22x–2n+1
(3) h1 = 2 = 3
3 5 (3) –2n2e–4n+1 (4) –2n2x–2n–1
(4) h2 = 3h1 and h3 = 3h2 32. A ship A is moving Westwards with a speed of
28. The velocity of a projectile at the initial point 10 km/h and a ship B 100 km South of A, is

A is
( 2iˆ + 3jˆ ) m/s. Its velocity (in m/s) at
moving Northwards with a speed of 10 km/h.
The time after which the distance between
point B is :- them becomes shortest, is :-
Y
(1) 5 h (2) 5 2 h
(3) 10 2 h (4) 0 h
Re-AIPMT 2015
B
A X 33. Two particles A and B, move with constant
velocities v1 and v2 . At the initial moment
(1) 2iˆ + 3jˆ (2) −2iˆ − 3jˆ
(3) (4) their position vectors are r1 and r2
−2iˆ + 3jˆ 2iˆ − 3jˆ
AIPMT 2014 respectively. The condition for particle A and
B for their collision is:-
29. A projectile is fired from the surface of the
earth with a velocity of 5 m/s and angle  with (1) r1 − r2 = v1 − v2 (2) r1 − r2 = v 2 − v 1
r1 − r2 v2 − v1
the horizontal. Another projectile fired from
another planet with a velocity of 3 m/s at the (3) r1  v1 = r2  v2 (4) r1  v1 = r2  v2
same angle follows a trajectory which is NEET-I 2016
identical with the trajectory of the projectile 34. If the velocity of a particle is v = At + Bt2, where
fired from the earth. The value of the A and B are constants, then the distance
acceleration due to gravity on the planet is (in travelled by it between 1s and 2s is :-
m/s2) is: (given g = 9.8 m/s2) 3
(1) A + 4B (2) 3A+7B
(1) 3.5 (2) 5.9 2
(3) 16.3 (4) 110.8 3 7 A B
(3) A + B (4) +
30. A particle is moving such that its position 2 3 2 3
coordinates (x, y) are NEET-II 2016
(2m, 3m) at time t = 0 35. Two cars P and Q start from a point at the
(6m, 7m) at time t = 2 s and same time in a straight line and their
(13m, 14m) at time t = 5s. positions are represented by xp(t) = at + bt2
Average velocity vector ( Vav ) from t = 0 to t = 5 and xQ (t) = ft – t2. At what time do the cars
have the same velocity?
s is
a+f f −a
(1) (2)
1
(
(1) 13iˆ + 14jˆ
5
) 7
( )
(2) ˆi + ˆj
3
2(1 + b) 2(1 + b)
a−f a+f
(3) (4)
(
(3) 2 ˆi + ˆj ) (4)
11 ˆ ˆ
5
i+j ( ) 1+b 2(b − 1)
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Kinematics (Motion in a Straight Line & Plane)
NEET(UG) 2017 41. Two bullets are fired horizontally and
36. Preeti reached the metro station and found simultaneously towards each other from roof
that the escalator was not working. She tops of two buildings 100 m apart and of same
walked up the stationary escalator in time t1. height of 200m with the same velocity of
On other days, if she remains stationary on 25 m/s. When and where will the two bullets
the moving escalator, then the escalator takes collide. (g =10 m/s2)
her up in time t2. The time taken by her to (1) after 2s at a height 180 m
walk up on the moving escalator will be (2) after 2s at a height of 20 m
(1) t 1 t 2 (2) t 1 t 2 (3) after 4s at a height of 120 m
t2 − t1 t2 + t1 (4) they will not collide
t1 + t2 42. A person travelling in a straight line moves
(3) t1 – t2 (4) with a constant velocity v1 for certain
2
37. The x and y coordinates of the particle at any distance 'x' and with a constant velocity v2 for
time are x = 5t – 2t2 and y = 10t respectively, next equal distance. The average velocity v is
where x and y are in meters and t in seconds. given by the relation
The acceleration of the particle at t = 2s is :- (1) 1 = 1 + 1 (2) 2 = 1 + 1
(1) 5 m/s2 (2) – 4 m/s2 v v1 v2 v v1 v2
(3) – 8 m/s2 (4) 0 v v1 + v2 v = v1 v 2
NEET(UG) 2019 (3) = (4)
2 2
38. The speed of a swimmer in still water is 20 m/s. NEET(UG) 2020
The speed of river water is 10 m/s and is 43. A ball is thrown vertically downward with a
flowing due east. If he is standing on the south velocity of 20 m/s from the top of a tower. It hits
bank and wishes to cross the river along the the ground after some time with a velocity of
shortest path, the angle at which he should 80 m/s. The height of the tower is :
make his strokes w.r.t. north is given by : (g = 10 m/s2)
(1) 30° west (2) 0° (1) 300 m (2) 360 m
(3) 60° west (4) 45° west (3) 340 m (4) 320 m
39. When an object is shot from the bottom of a NEET(UG) 2020 (Covid-19)
long smooth inclined plane kept at an angle 44. A person sitting in the ground floor of a
60° with horizontal, it can travel a distance x1 building notices through the window, of
along the plane. But when the inclination is height 1.5 m, a ball dropped from the roof of
decreased to 30° and the same object the shot the building crosses the window in 0.1 s.
with the same velocity, it can travel x2 What is the velocity of the ball when it is at
distance. Then x1 : x2 will be the topmost point of the window ?
(1) 1: 2 (2) 2 :1 (g = 10 m/s2)
(3) 1 : 3 (4) 1:2 3 (1) 15.5 m/s (2) 14.5 m/s
NEET(UG) 2019 (Odisha) (3) 4.5 m/s (4) 20 m/s
40. A person standing on the floor of an elevator NEET(UG) 2021
drops a coin. The coin reaches the floor in 45. A small block slides down on a smooth
time t1 if the elevator is at rest and in time t2 inclined plane, starting from rest at time t = 0.
if the elevator is moving uniformly. Then :- Let Sn be the distance travelled by the block in
(1) t1 < t2 or t1 > t2 depending upon whether the interval t = n – 1 to t = n. Then, the ratio
the lift is going up or down Sn
is :
(2) t1 < t2 S n +1
(3) t1 > t2 2n − 1 2n − 1 2n + 1 2n
(4) t1 = t2 (1) (2) (3) (4)
2n 2n + 1 2n − 1 2n − 1
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NEET : Physics
46. A car starts from rest and accelerates at 49. The ratio of the distances travelled by a freely
5 m/s2. At t = 4 s, a ball is dropped out of a falling body in the 1st, 2nd, 3rd and 4th second :
window by a person sitting in the car. What is (1) 1 : 4 : 9 : 16 (2) 1 : 3 : 5 : 7
the velocity and acceleration of the ball at (3) 1 : 1 : 1 : 1 (4) 1 : 2 : 3 : 4
t = 6 s ? (Take g = 10 m/s2) 50. A ball is projected with a velocity, 10 ms–1, at an
(1) 20 m/s, 5 m/s2 (2) 20 m/s, 0 angle of 60° with the vertical direction. Its speed
(3) 20 2 m/s,0 (4) 20 2 m/s,10m/s2 at the highest point of its trajectory will be:
47. A particle moving in a circle of radius R with (1) 5 3ms−1 (2) 5 ms–1
a uniform speed takes a time T to complete (3) 10 ms–1 (4) Zero
one revolution. RE-NEET(UG) 2022
If this particle were projected with the same
51. A cricket ball is thrown by a player at a speed
speed at an angle '' to the horizontal, the
of 20 m/s in a direction 30° above the
maximum height attained by it equals 4R. The
horizontal. The maximum height attained by
angle of projection, , is then given by :
1 1 the ball during its motion is : (g = 10 m/s2)
   2 
(2)  = cos −1   R2 
2 2 2
(1)  = cos −1  gT 
(1) 5 m (2) 10 m (3) 20 m (4) 25 m
 R
2
 gT  52. he position-time (x – t) graph for positive
1 1 acceleration is :
 2   
(3)  = sin −1   R2 
2 2 2
(4)  = sin −1  2gT  x
 R 
2
 gT 
NEET(UG) 2022 (1)
48. The displacement-time graphs of two moving t
particles make angles of 30° and 45° with the x
x-axis as shown in the figure. The ratio of
their respective velocity is : (2)
t
x
displacement

(3)
t

30°
45° x
0 time
(1) 1 : 1 (2) 1 : 2 (3) 1 : 3 (4) 3 : 1 (4)
t

EXERCISE-II (Previous Year Questions) ANSWER KEY

Question 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15
Answer 2 4 4 1 2 1 3 1 2 4 1 3 2 2 2
Question 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30
Answer 3 4 2 4 1 3 3 2 4 4 4 3 4 1 4
Question 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45
Answer 1 1 2 3 2 2 2 1 3 4 1 2 1 2 2
Question 46 47 48 49 50 51 52
Answer 4 4 3 2 1 1 1
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Kinematics (Motion in a Straight Line & Plane)

Exercise – III (Analytical Questions) Master Your Understanding

1. For ground to ground projectile motion with (t 1 + t 2 )2
(A) u (i) g
initial velocity u at angle  from horizontal. 8
y (B) h (ii) (t1 + t2)
1
u (C) Time of flight (iii) g(t1 + t2)
2
1
(D) Maximum height (iv) gt1t2
2
 (1) (A)–(ii), (B)–(i), (C)–(iii), (D)–(iv)
x (2) (A)–(i), (B)–(ii), (C)–(iii), (D)–(iv)
(A) Change in speed (i) u – (3) (A)–(iii), (B)–(iv), (C)–(ii), (D)–(i)
from initial to final ucos (4) (A)–(iv), (B)–(iii), (C)–(ii), (D)–(i)
point 4. Given below are two statements: one is
labelled as Assertion (A) and the other is
(B) Magnitude of (ii) usin
labelled as Reason (R).
change in velocity
Assertion (A) : The distance between two
from initial to final
floating objects on a river flowing uniformly
point does not change with time.
(C) Change in speed (iii) 2usin Reason (R) : The floating object has the same
from initial to top velocity as that of the river.
(D) Magnitude of (iv) zero In the light of the above statements, choose
change in velocity the most appropriate answer from the
from initial to top options given below:
Options :- (1) Both (A) and (R) are true and (R) is the
(1) (A)–(i), (B)–(ii), (C)–(iii), (D)–(iv) correct explanation of (A).
(2) (A)–(iv), (B)–(ii), (C)–(i), (D)–(iii) (2) Both (A) and (R) are true and (R) is NOT
the correct explanation of (A).
(3) (A)–(iv), (B)–(iii), (C)–(i), (D)–(ii)
(3) (A) is true but (R) is false.
(4) (A)–(iv), (B)–(iii), (C)–(ii), (D)–(i)
(4) (A) is false but (R) is true.
2. For initial velocity ( v i ) = 3iˆ − 4jˆ and final 5. Given below are two statements: one is
labelled as Assertion (A) and the other is
velocity ( v f ) = 3iˆ + 4jˆ :- labelled as Reason (R).
(A) | v | (i) 8jˆ Assertion (A) : Horizontal component of
(B)  | v | (ii) 6iˆ velocity is constant in projectile motion
under gravity.
(C) v f − v i (iii) 0
Reason (R) : Two projectiles having same
(D) vf + vi (iv) 8 horizontal range must have the same time of
(1) (A)–(iii), (B)–(iv), (C)–(ii), (D)–(i) flight.
(2) (A)–(iii), (B)–(iv), (C)–(i), (D)–(ii) In the light of the above statements, choose
(3) (A)–(iv), (B)–(iii), (C)–(ii), (D)–(i) the most appropriate answer from the
(4) (A)–(iv), (B)–(iii), (C)–(i), (D)–(ii) options given below:
(1) Both (A) and (R) are true and (R) is the
3. A particle is projected vertically upward from
correct explanation of (A).
ground with initial velocity u such that it
(2) Both (A) and (R) are true and (R) is NOT
clears the top of a pole of height h after time
the correct explanation of (A).
t1 in its path. It takes further time t2 to reach (3) (A) is true but (R) is false.
the ground. (4) (A) is false but (R) is true.
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NEET : Physics
6. Given below are two statements: one is (C) the average speed is zero
labelled as Assertion (A) and the other is (D) the average velocity is zero
labelled as Reason (R). Option
Assertion (A) : A particle with constant (1) (A) & (D) (2) (B) & (C)
acceleration always moves along a straight (3) (A) & (C) (4) (B) & (D)
line. 10. Instantaneous velocity of a particle -
Reason (R) : A particle with constant (A) depends on instantaneous position
acceleration will not change direction of (B) depends on instantaneous speed
motion. (C) independent of instantaneous position
In the light of the above statements, choose (D) independent of instantaneous speed
the most appropriate answer from the (1) Btoth (A) & (B) are correct
options given below: (2) Both (C) & (D) are correct
(1) Both (A) and (R) are true and (R) is the (3) Both (A) & (D) are correct
correct explanation of (A). (4) Both (B) & (C) are correct
(2) Both (A) and (R) are true and (R) is NOT 11. For a body moving on a straight line if x is
the correct explanation of (A). position coordínate and t is time then
(3) (A) is true but (R) is false. acceleration of body is constant when -
(4) Both (A) and (R) are false. (A) x and velocity is linear
7. An object may have- (B) x and square of velocity is linear
(A) varying speed without having varying (C) t and velocity is linear
velocity (D) t and square of velocity is linear.
(B) varying velocity without having varying (1) Both (A) & (B) are correct
speed (2) Both (C) & (D) are correct
(C) non-zero acceleration without having (3) Both (A) & (D) are correct
varying velocity (4) Both (B) & (C) are correct
(D) non-zero acceleration without having 12. If the velocity of a body is constant -
varying speed (A) |Velocity| = speed
(1) Only B is correct (B) |Average velocity| = speed
(2) Only D is correct (C) Velocity = average velocity
(3) Both B and D are correct (D) Speed = average speed
(4) All are correct (1) Only (A) is correct
8. The velocity of a particle is zero at t = 0, then - (2) (A) and (B) are correct
(A) the acceleration at t = 0 must be zero (3) (C) and (D) are correct
(B) the acceleration at t = 0 may be zero (4) All are correct
(C) if the acceleration is zero from t = 0 to 13. A particle can move only along x-axis. Three
t = 10 s, speed is also zero in this interval pairs of initial and final positions of particle at
(D) if the speed is zero from t = 0 to t = 10 sec, two successive times are given
the acceleration is also zero in the interval Pair Initial position Final position
(1) (A), (C) and (D) are correct 1 – 3m + 5m
(2) (B), (C) and (D) are correct 2 – 3m – 7m
(3) (A) and (D) are correct 3 + 7m – 3m
(4) (B) and (C) are correct Find the sum of magnitudes of displacement
9. Consider the motion of the tip of the minute in the pairs which give negative displacement
hand of a clock for one hour motion which of in m.
the following is/are correct. (1) 14 (2) 12
(A) the displacement is zero (3) 20 (4) 22
(B)
TG: the distance covered is zero
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Kinematics (Motion in a Straight Line & Plane)
14. In first and second columns of the following 15. The average speed for the first 6 s is
table, unit vectors â and b̂ of some geographical 5
(1) zero (2) ms–1
directions are mentioned. Complete the third 3
column. 10 20 −1
(3) ms–1 (4) ms
Unit vector â Unit Scalar 3 3
Vector b̂ Product 16. The average velocity for the first 12s is
ˆ (1) zero (2) 5 m/s
â  b
10
A West Up .......... (3) m/s (4) 10 m/s
3
B South East .......... 17. The average acceleration from t=5s to t=15s is
C 30° North of Down .......... (1) zero (2) –0.5 m/s2
west (3) +0.5 m/s2 (4) 1 m/s2
D 30° Down of Up .......... 18. A car is moving along a straight line. It’s
south displacement (x) - time(t) graph is shown in
Options :- column II. Match the entries in column I with
points on graph.
1
(1) A → 0, B → 0, C → 0, D → − x
2
1 1
(2) A → 0, B → 0, C → , D → −
2 2 P Q
1 1 t
(3) A → 1, B → 1, C → , D → R
2 2 S
1 1 Column I Column II
(4) A → 1, B → 1, C → − , D →
2 2 (A) x → negative, v → positive, (P) P
Paragraph for Question Nos. 15 to 17 a → positive
A moving particle is acted upon by three (B) x → positive, v → negative, (Q) Q
forces at different times to bring it to rest. Its a→ negative
velocity versus time graph is given below (C) x → negative, v → negative, (R) R
v a→ positive
20m/s (D) x → positive, v → positive, (S) S
a → negative
Options :-
10m/s
(1) A → S, B → Q, C → R, D → P
t (2) A → P, B → R, C → Q, D → S
4s 6s 8s 12s 15s
–15m/s (3) A → S, B → R, C → Q, D → P
(4) A → S, B → Q, C → R, D → S

EXERCISE-III (Analytical Questions) ANSWER KEY

Question 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15
Answer 3 4 3 1 3 4 3 2 1 4 4 4 1 1 4
Question 16 17 18
Answer 2 2 1
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NEET : Physics

Important Notes

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