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Lecture WEEK 14

1) The document describes the design of an air conditioning system for a classroom measuring 10m x 14m containing 40 people. 2) Five air conditioning trunks (TR) are used, each with a flow rate of 550 cubic meters per hour, for a total of 2750 cmh. 3) Detailed calculations are shown to determine the sizes of the main branch and five sub-branches based on maintaining proper air flow ratios throughout the system.

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Ebrahem saeed
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14 views16 pages

Lecture WEEK 14

1) The document describes the design of an air conditioning system for a classroom measuring 10m x 14m containing 40 people. 2) Five air conditioning trunks (TR) are used, each with a flow rate of 550 cubic meters per hour, for a total of 2750 cmh. 3) Detailed calculations are shown to determine the sizes of the main branch and five sub-branches based on maintaining proper air flow ratios throughout the system.

Uploaded by

Ebrahem saeed
Copyright
© © All Rights Reserved
We take content rights seriously. If you suspect this is your content, claim it here.
Available Formats
Download as PDF, TXT or read online on Scribd
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Air Conditioning Systems

Dr. Mohamed Elhelw


Faculty of Engineering – Alexandria University
Dr. Mohamed Elhelw Faculty of Engineering – Alexandria University
10 m

Class Room

40 Persons 14 m

5 TR

5 x 550
2750 cmh

Dr. Mohamed Elhelw Faculty of Engineering – Alexandria University


B

L
A

𝟐𝟕𝟓𝟎
𝐀𝐱𝐁=
𝟏. 𝟏𝟖 ∗ 𝟑𝟔𝟎𝟎
𝟏. 𝟏𝟖

= 0.65
𝟐. 𝟕𝟓

Dr. Mohamed Elhelw Faculty of Engineering – Alexandria University


𝐀 𝐱 𝐁 =0.65
𝐀 𝐱 𝟎. 𝟖 𝐀 =0.65

𝐀 = 90 cm
B= 72 cm
𝟐𝟔𝟎
𝐋 = 260 cm

𝟐. 𝟕𝟓
Dr. Mohamed Elhelw Faculty of Engineering – Alexandria University
1.5 m 1.5 m 𝐀 = 0.9 m
𝐋 = 2.6 m

1m 1m 1m 1m 1m

1.5 m 1.5 m

Dr. Mohamed Elhelw Faculty of Engineering – Alexandria University


Y
Z

Dr. Mohamed Elhelw Faculty of Engineering – Alexandria University


10 m
Class Room

Class Area = 10 x 14 = 140 m

Air Outlet Covered Area = 10- 16 m2


14 m
Air Outlet Number = 140/ 14 = 10

Dr. Mohamed Elhelw Faculty of Engineering – Alexandria University


Class Room
Main Branch
Main Branch
𝟐𝟕𝟓𝟎
𝐗 ∗𝐘=
𝟔 ∗ 𝟑𝟔𝟎𝟎

= 0.127
𝐅𝐚𝐥𝐬𝐞 𝐜𝐞𝐢𝐥𝐢𝐧𝐠 =45 cm
14 m
𝐘 =45-15 = 30 cm
𝟎. 𝟏𝟐𝟕
𝐗 =
𝟎. 𝟑
𝐗 = 42 cm

𝐗 =45 cm 𝐘 =30 cm
10 m
Dr. Mohamed Elhelw Faculty of Engineering – Alexandria University
Class Room
Branch 1
𝐕𝐨𝐥𝐮𝐦𝐞 𝐟𝐥𝐨𝐰 𝐫𝐚𝐭𝐞 =2750-2*275
= 2200 cmh Branch 1

𝐀𝐫𝐞𝐚_𝟏 𝐕_𝟏 0.75


= ( )
𝐀𝐫𝐞𝐚_𝐌𝐚𝐢𝐧 𝐕_𝐌𝐚𝐢𝐧
𝐀𝐫𝐞𝐚_𝟏 𝟐𝟐𝟎𝟎 0.75 14 m
= ( )
𝟎.𝟏𝟐𝟕 𝟐𝟕𝟓𝟎
𝐀𝐫𝐞𝐚_𝟏 = 0.107 m2
𝐘 =30 cm
𝐗 = 42 cm

𝐗 =35 cm 𝐘 =30 cm
10 m
Dr. Mohamed Elhelw Faculty of Engineering – Alexandria University
Class Room
Branch 2
𝐕𝐨𝐥𝐮𝐦𝐞 𝐟𝐥𝐨𝐰 𝐫𝐚𝐭𝐞 =2750-4*275
= 1650 cmh

𝐀𝐫𝐞𝐚_𝟐 𝐕_𝟐 0.75


= ( ) Branch 2
𝐀𝐫𝐞𝐚_𝐌𝐚𝐢𝐧 𝐕_𝐌𝐚𝐢𝐧
𝐀𝐫𝐞𝐚_𝟐 𝟏𝟔𝟓𝟎 0.75 14 m
=( )
𝟎.𝟏𝟐𝟕 𝟐𝟕𝟓𝟎
𝐀𝐫𝐞𝐚_𝟐 = 0.086 m2
𝐘 =30 cm
𝐗 = 28 cm

𝐗 =30 cm 𝐘 =30 cm
10 m
Dr. Mohamed Elhelw Faculty of Engineering – Alexandria University
Class Room
Branch 3
𝐕𝐨𝐥𝐮𝐦𝐞 𝐟𝐥𝐨𝐰 𝐫𝐚𝐭𝐞 =2750-6*275
= 1100 cmh

𝐀𝐫𝐞𝐚_𝟑 𝐕_𝟑 0.75


= ( )
𝐀𝐫𝐞𝐚_𝐌𝐚𝐢𝐧 𝐕_𝐌𝐚𝐢𝐧
𝐀𝐫𝐞𝐚_𝟑 𝟏𝟏𝟎𝟎 0.75 14 m
= ( ) Branch 3
𝟎.𝟏𝟐𝟕 𝟐𝟕𝟓𝟎
𝐀𝐫𝐞𝐚_𝟑 = 0.064 m2
𝐘 =30 cm
𝐗 = 21 cm

𝐗 =30 cm 𝐘 =20 cm
10 m
Dr. Mohamed Elhelw Faculty of Engineering – Alexandria University
Class Room
Branch 4
𝐕𝐨𝐥𝐮𝐦𝐞 𝐟𝐥𝐨𝐰 𝐫𝐚𝐭𝐞 =2750-8*275
= 550 cmh

𝐀𝐫𝐞𝐚_𝟒 𝐕_𝟒 0.75


= ( )
𝐀𝐫𝐞𝐚_𝐌𝐚𝐢𝐧 𝐕_𝐌𝐚𝐢𝐧
𝐀𝐫𝐞𝐚_𝟒 𝟓𝟓𝟎 0.75 14 m
=( )
𝟎.𝟏𝟐𝟕 𝟐𝟕𝟓𝟎
𝐀𝐫𝐞𝐚_𝟒 = 0.038 m2
𝐘 =20 cm Branch 4
𝐗 = 19 cm

𝐗 =20 cm 𝐘 =20 cm
10 m
Dr. Mohamed Elhelw Faculty of Engineering – Alexandria University
Class Room
Branch 5
𝐕𝐨𝐥𝐮𝐦𝐞 𝐟𝐥𝐨𝐰 𝐫𝐚𝐭𝐞 =275 cmh

𝐀𝐫𝐞𝐚_𝟓 𝐕_𝟓 0.75


= ( )
𝐀𝐫𝐞𝐚_𝐌𝐚𝐢𝐧 𝐕_𝐌𝐚𝐢𝐧
𝐀𝐫𝐞𝐚_𝟓 𝟐𝟕𝟓 0.75 14 m
=( )
𝟎.𝟏𝟐𝟕 𝟐𝟕𝟓𝟎
𝐀𝐫𝐞𝐚_𝟓 = 0.022 m2
𝐘 =20 cm
𝐗 = 11 cm
Branch 5
𝐗 =20 cm 𝐘 =15 cm
10 m
Dr. Mohamed Elhelw Faculty of Engineering – Alexandria University
Dr. Mohamed Elhelw Faculty of Engineering – Alexandria University
Dr. Mohamed Elhelw Faculty of Engineering – Alexandria University

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