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7
’CCl¡h ’ following cH)’2aCrad) given contact its O, and H,0
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of is
fromreduction Reduction of
tribromooctaoxide (d)to+4(b) 0oxidation Al,0, Choose (d) (b)found redox (dAg
) (b)Al
with in redox Redox
+ H,1
+2Cr + + +
30, 4NO, reactions Terms 0,
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3,1 8, reaction,
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(2020) carbon (2021) metal (2023) (1998) (1997) -

9. 8. 7. Reactions
Redox
10,
balanced correctThe (c+6 ) The
) (a-6 (d) (c) (b) (a)
Select (iv)disproportionation -Br-Br=0
(i) Which 0-Br(d)
O=Br-Br-Br--0(c) (b)
equationare TheMnO, +For (d) (c) (b) (a) order (ii) (ii) reactions?
(i), (i) 0=
correct the HNO,,HNO, HNO,,
of
oxidation (i), (i) 2KMn0,
2MnO0, + 3Mn0}2Cu’
NH,CI, (iü) and and the Br
redoX oxidation (ii)
C,0, correct of -
and and (ii) (iv) BrBr=0
NHC),
N, NO, NO, order
coefficientsreaction, state (iii) only only 3Mn²* +Cu'*
the
+ NO, NH,C, N, (iv) 4H’2MnO,
option
H*’ states of of +
HNO, NO, N-compounds
NH,CI Cr K,M+nO, following
from
2H,0’5MnO, Cu
Mn*
of N, N, ) +12(b)
is(Odisha (d+4 in
CrO,
the the +
+ NEET is following. MnO, +
reactants CO, MnO, reactions
in
+ its +
H,0 decreasing 2019, +
+ O,
2H,0
for (2019) 4H" (2019)
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the
21.(a) 11. 1.
17. 16. 15. 14. 13.
(d) (b) (a) bromineWhich moles0.(c6moles mole
Number
) 7.(a5) wilbe 12. HotI1.
(c) (a)Oxidationthat oxidation
(cCI
)number? which
(a) Ssulphuric A (C+H,sO,0,
Proton FeCl,,
SnCl,
(c ) SnCl,
FeCl(a,
) The (d ) (c) (b)
respetively ( a) Rol e () () (d) (b) reaions
(a) stong () (b)
22. 12. 2. H,0 of -3, +3, of mixture
is oxidizing
pair reducing oxidizing
reducing H,0,+
ot H.0, CaF, S+ ut
+ in ferrous of +6 +6 Cr element Mn),
c0,
(d) 13.(c) (b) acceptor Br, the the and and in of hydrogen 2H,sO,S0, oNizing
moles numbers +
’ best
reaction Cr,0;
acid ofcompounds
H,S0,CasO, + M,SO,CusO, does entrated
23. 3. oxalate +6 +5 potassium in in in Ag,0’2Ag
in 0,’H0+
HOBr of undergoes is
1) not
only description MnO, of
(1) (1) (1) (peroxide
and
(c) (c) (c) are heated. and and and showagent.
sulphui
given
+ moles.0.(dmoles4)
completely P
HBr (b)
0.2 respectively
(d) (b) 1) (11)reducing
24. 14,
in (d) C(b) H chlorate, FeCl(HgCi,
maximum dKI
),SnCl,(b) that (1oxidizing osidizing
+ Ibehaviour?
4 required +5, +5, PO,,
can in 20, 280, 21,0 + Whih
below? of During the + + +
(d) (c) (c) the in +6 +3 together existis 1,0 2HF S(), Acid
and and of oxalic in in above +
behaviour acidic to (II) (11) 211,0 thetollowing + of is
15. 5. oxidize inS change the 0,+ (NEET 21,0
+6 +6
medium SO, acid reactions oderately A
(2008) (2009) (2012) reaction
(d) ANSWER
(c) KEY in (2014) (2014)
of one and the and 2016) 1 (2018)
16. 6. is
24. 23. 22.
(d) (b) 21. 20. 19,
(c)Br
BrO;(a) Then corresponding theConsider 7.4 18. moG
(+7
c) (a) +The H,0(c) (aH* ) 14H"following
reaction?thWhich
e The (a)
NO,(c) CO,(a) sulphateio(cn) Reaction (a)
Oxidation () (b)
17. 7. the given Redox oxidation
() (c) (b) (a) S,0, lReduced he onlOxidised
(yd) onlyNEET-AIPMT
1 + oxide,
tetrathionate io n 4 5
BrO, S,0, S,0; S0; S,0 oxidation Both
(b) (b)8. species Br diagram the Cr,0, substance a nd
Reactions which of oxidised
1.0652 V L change sodium
18. to state +3Ni-’ (b) state<S,0; <s,0, <S,0, <S,0,
undergoing diferent 5 4 of
soS,0 states Chapterwine
: of is cannot
(a) (c) Bro;15V
-Bry in serVing thiosulphate Fe $,0, follow and
(d)BrO,(b) oxidation and (d) 5
+ (b ) 1
-
inI TH,0+2Cr*
(d)Ni
in soso; < of reduced
19. 9. emf HI0, Cr,(0b) act sulphide
SO,(d) ClO,(b) sulphite io(n.d) i(b)on (c) Fe,0, sulphur
the
HBrO
disproportionation 1.595 V Electrode Toplcwse
as as 2 3
(d) (a) values a a is order
state is reducing reducing with
HBrO thein
20. 10. + Solutions
as of
Processes 3N? iodine (d) anions
shown in
bromine
(a) (b (2018) agent agent 3 8
(1994) (1994) (1995) (1996) give (199, (2009, (2044%
is in is s
 numbers. 12. So,Here, 2MnO, 10. 9. +6
+Cuo
Cuz
LetPeroxobonds. simultaneously. oidation
the
(b) 6. 5(c): is
Sedes,
Oxidation evolved. isH,O, 11. CrO,:x+4(-1) 3MnO+4H* 2Cut-’ cCL known ired 4. 32Al ZnCl,whichaenZn lies(b) 2 AeacHons
Rodor
it oxidation samne
involvbote ahnd
(c): is the(d) (b): (a) (c) (b): oxidation (c):Cr,Oe) +
Both reducing
© actsas not oxygen then with ic) 3ZnCl wil
: number In as When :
H,0,+ H,O,+ OIncreaseoxidation : +The : +5
HNO, CrO,
element/compound
Disproportionation metadisplacement. more the
: Redox
redox
a CaF, 5C,0,
correct CHp Cr0,2AI + ionsofa displaconc.ce.
decrease Oxidation Only
FeCl,
SnCl,and Increase + state has number
Decrease in H,S0, +2 + has of active a 2AlCI, Al
'reactions
Decrease Ag,0 +1 oxidation + NO, 1(-2) of -1 carbonOXidation metal
agent in reaction. state > + when
in 16H*> balanced oxidation butterfly2MnO, metallower
oxidation in N, Cr +7 of metal
’
3SOso+ + fromaboveZn'
in oxidation of =0 be in
carbon from 3Zn keptZnCl,reduction are
oxidation ’ state everyCaS0, NH,CI -3 the number displaces
both equation is x structure + reactions ’ 'Al'in those
are state H,0 (reducing 2Mn²* ’ state. MnO, +4 gets given Hence, the
’ state -2 down 8H, solution.
reducing reactionsthe in 2Ag atom + is Al,0, electrochemical aq) in
chemical
state (reducing x= +4. container.
+ 2HF oxidised reaction of the simultaneously.
202 + +6 the in electrochemical
+ 0agent)
remains 10C0, having 2H,0 + are Thus,carbon + ’Therefore,
agents
H,0 agent) those
2Crcorrect less the 2Crta
Explanations
Hints & reactions
is electrochenmical
active
+O2 0 and from the is
+ two -4 reaction
with which the in change +
8H,0 reduced -4 while one, +4H,Ouseries3SOtag)
same peroxo which to series, which
low O, +4. in in this
is is
HBrO positive 24. (4get or or
Egl HBrOBr,;
2HBrO 23. to 22.agent. +4, 21. 19.
20. Oxidation On 16. oxidation
Let numberLet chlorine,
15.Maximum
E H=+land
x 2, S,0 S,0: 18. 17.(b) mole l moles2MnO,2(C,0’ 14.
cell therefore, addition,
>0 = = (d): 1) therefore
(c) (d) (a)
1.595- SRP
(a) (d): 2x 2x (a): Number (oxidation
d) 2z y+ x+(d) (c)
as +x
: - :2x -82x+ of of
+ +
> AG° For :
Let Since : Since : 12= oxalate : 4(-2) 4(-2) Let : i.e.,
(cathode)
AG BrO,; + 2Na,S,O, Fe,O,: states MnO, 16H* 2e(5e 7(-2) change KCIÓ, :
Br, (6xoxidation x=
+ -2= (- SO{
(- we fronm
1.5 = a it carbon -2 2)4
<0 + E= reaction acts the carbon 2)6= or
:x+(-2)3 =
of+5C,0 get + +number
2C0, = =oxidation =
= E -nFEO -Oxidation follow
3x required MnO, -2 -3
ontaneous) 0.095 BrO; 2) as or 2x= =-2 5
2/moles -2 +5 in +
- =
1.595 cell oxidation +1, (COOH),
H,SO, +
= state a dioxide + -2 = to
SRP -15 - reducing is 4(-2) the 2x -l.
0.4
...ii)] ’z=+ of ’ number oxidation
V to 1 +6
in ’ order = = 8H Cry= of x=
(anode) of
state tetrathionate)
(Sodium + ..
of to ’ S +5
V,SRP V, be
number (CO,) its =0’x=+ 10 -2 oxidise2Mn' x in
(anode) SOP spontaneous, O ’
5 +6 in +6SO,
N=+ 7 -2, = agent. maximum Na,S,O, : . x= or MnO, Mn* of
(cathode) of S, 0 Cr,O
I. cannot +3 x 5 + PnumberK,SO,
therefore Since X=+5 -6= in
of + bey.
Ni requiredmoles10CO, PO
oxidation
+ 3 sO; < -2 4H,0..(i)] be occurs +
oxidationincreases act 2 of z.
E Nal or + be KCI
for as < 8H,
oxalate. 0 x.
a x to
Should S,0; = inCO, +
H1O;, reducing state + x
state from case
4 oxidise 2
be
+H,0
weof 0 of ot 69