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26 views19 pages

100

Nothing

Uploaded by

Naveen Naveen
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Cal ne | ak - 03 lorla3 Subject — Power systmt(2/0€E Uos c) PART =A map i= oe @@_As Sie Peatesin_lle tose ie cher ef _condiucky maternal i 2 ®©_ Decreases @ Goduchir used % 4 “iy "Gans itsetan fee ace @ Stonded ® SS a © Sepeasin_Sype_teake ome oe OTL. Ss ry series ui ll ar the ‘ati # ot —@D Coama blocs facreases with aan a ae” = Ot “the sag conduciny f TL. ts 2S when Ye @ GE ieee Spon 735 260m. the herglt g the towers , ; 3 al Ps Pnemreared by 2s-4 _ the Sog will be YS pies 2 @. Remains © same = Ss ees _ PS ee OI aus Lait ese | displaced b i DD. the capaci bance bedrean the $00 FS preportione)! —_— ek. be er eee fo = Pe i dost how ab. = sittin: os % fs At. , ee ae Be ee x = ee rT es —!J i wot th pecesony mbps prove “that “bt re, fi SA ft a oll pees Pe peat : pie NEY cog 3 e Frans m2 Bing conductor cohece 9 is resistivity ceo ductel area of Gross Secfion _ Nis bine voltage ae s ha or Bae qurente a % po ge EW crpereclp Ahh From eguadton” we con conclude thad te Volume conduchy maten’al fs tnversly Proper Hon: & Voltage because the valine Conducta decreases with fnorease fn trons missien vo Wag.» * Tn easing Mans messtog offyrc?ency we hoc that f= cull ove fa pe powrey oud pyd pose NBVZ cos” _Inpus fobor= NB VI cos d 4 Dice a bhi. > BVT cog + _p?€) if a — Heda, ine ie Jala él ee Subsite @ io @ . then i a L_ at - va ee Aiea ee ee et wee PE Pee ie re PATE See e2cin famebiion Dhecrem to above obtained Dp phying Lronomial h TAaeafe oO ——— D D&B we ome bh know that Mhe WV s because f saving conducts fries ¢ Reductag Sesser martuiads , Inweasiag Hea MME iota cli olathe t eG® Why an fnswlatorc veguival in oTh? Eso ond bogly op lao thefr properties | oy ___“ Incubations are used to ico late ground ond i : Sowa from elect cument on a OTL” Propertiess bes ° * High mehanical strength, ] % Should be sith diag hold the 7 bead of conducts (mechanical) eae + High electric resis Pe esis ait _abdt sleleass wa oll Tawetdows Deahage Cumrent High relative _permiabi li, Ea ‘ Di-ele fC Bron gth of tnsclofor st be high to ewortcle flow of charge Ty seater must tree from cracks, vorder, becca | | Ws Mie, Pepusrdes 2 We265 v ie (2-Stiy > Neng = lo 103-60 Sree eee ee Oe on |e eee’. Ves Cth) WM = Cito125) to 03.6 = 1366.57 Va= CH3k+KYMY > (14312594 ors? }row3.c = Mose. Mey > E 3 Noe Vy +VatU3 = 0103.64 11366. 5 + |Yoso. 214 and SS aS S VE i String Efticien oe ce BSS90. SF yom BU 267 meet a L io 3x Moses oh aaileeetheainesdlietiaaiteeentath le Peers ed is OTL. whot is critical disrup five. ee with —1efered. to cotona £ keduw the eee ame “the pleated of violet fos with ‘| hi 7 sound end. fibsatins oes gas fy on" 25 cabled. ee jm Coico dis nup tive ae ei r hih the corona torts gy occuns” Ee a mn tle, = rer tos, Ur | Sen normal conditiony Pediat 25h ale tohere b fs the meray Colum ge Qix BUR SRI E Pressuse as | capes is tis kemperatute fo degree cle? oxy gaat eZ a as 3% Seep in Jey, dh kul om — And also consider: ag the offect G the Surface © ack Sey ofthe _ conducts, anothey convertion factor is_intteducd tq mm, wohich is Keown as the trveg ity = pa | seis phon i. iwi é Cun de eee i y zie oliched _ condi Hoos) : Mo= 0.98 bo.9s fx dirty, conductor point eee ie hea yt oan = __ Sup pats at f= - bo Co eee ae a eh myal0.47 og Gr ol ctrandéd conduche ‘ by id en oan 7 we i See ‘ 8 = ade -2_tnegisal a a ee | fou ine a tse oles 4 L be he partes el Stag pot te —_____— 25 the tension actin: e_conductos be the 4° flere els of supports — ee m%, bethe Be fence from ot ee Aowest point 4 sag L. Ho be the sae “Ken eee ah i I i ; E ; ; 1 : ; i : Kinde Solving. ean @ L© , we gt Ses teen Rem abiacieas ea ic cat. fo 4 poles SIs0m pac Lina eee ee OM make» stronath = = 200 fig — ee. Oey Sectional oj0a = 2em™ peas. = ae és Specie guatly = 9. 9.9% ene Ws Spzedfie seatetly Value of fincas = 49 gra lem? Race” X100cm a SIRo) ay oo = 1-98 kg = Wn " s be ‘ Ss. Wor &T ” i eo E ea nd? ——— { ay ee ST : = Aas co) a hyp a 2 e ‘ ae = fae ; Oeenee! A BK2000 be SS 3.49 m : 3 are Wat ag a o Os elo eae ie ni ot el TiS seat ie Sea he. Oe ON Lhe b=, © © se =_ 2.04 (oS I4.| (os 3-928) ici eee th, we fo +fe 2 ZIT ER ne ag = Gies Faas fet a je a ee ae one = emma ee CaS, a 2T7E, | d a E | thee ST ‘by a Sk fig) = Bis Seca ie eae aa 8 lm ds a er 4. {a. Sy eras —_— Gey do | Sr es ee — 2S _ | _circatt , vectes diagano and | TOD atth_nectsony assum tent ons Ais curs he por formance medium 9TL toy Nom?na) ar oe ie te nh Same alee 4: -—" fT 5 = as CL I ————— fa] Consider, load ts inductive 2D fis laggiug oad |= _ Sakiog Vp oferunce - ae 0g Was 6 _— Vp = Recefying end voltage }——_1 Jsi= 2: Sending od cument a1 2, current so ee Xe - De, 2 Fen = Capact tm curr eyes tee AR oh Resa endKeschoe # fodusSs cme ll a Em Atk. T= Ree, es Saeed ea | EM Coco a [i Ea MASE A . Sm 2. ee — Fe re — bet visvs) +i Wothfin all T method means dividing “the foosmission Ine tot heo parte and Considasing a4 capacitrs en eer esc ——____*& And ale! constdor the Reststone ond of nd = Soon kk B= Np te cos fe 22 xX Tp KO.K Sooo to” mse Mo 22x18 Ko.8 Tp = 224.094 ai = Sey + Cey.oa x atic) = C2100t jo) +C1I34. ¢ + jttol- Sia eee Q 7 Regu) ation eC ton - ] Ve i fe ie T 7 = 13.8309 212900 foo —__— (2100 _ = 9.8936. ee ee a _Se_ 5 Ustog arigerous mebhed , dovive _expressfon by coing ‘i end volPage and current f a long Sle ae A a Gr ewer NAPs ee : ieee ree esa A. 5 Hol eaaemeios tt ibs be v1 #1 ___tonstdip 1G) Wea Sestalsl savte Th pedance sath — aden Hance of a Yne to be tani form dy dish aibukel aad os Ata x— oy = | 5 pe CSR aie sae aio “ [a de 1, pe siox We 4 ka Votes hx VV = KA NYS ston 1 the V2 cha IR i te [| aL | Ep Sabi ha osh x S93 = a ime oy Whin azech< Vay fa oe —_— well be Ve =k cosh olf thsi = KC} ka oe Vp=, i ati then substi ce —| a - EZ pst ere Ret tes | i Kae ser |> e a =! el : oie ! ‘ ye ce [eonenpene) Serie x O\br\ioe hecoson = VJ _ +f ota ak = a2 - —_—- a | yp OG will es. ee ee VO coh liye tm Ja cob iva] eee epee ae So aaa 2 a> JE Np sinh LYS) +R cosh CI ys) aE VA coh? eV Ya AE MAU e _| P= 30 mY a oe ___ Nip = 132 con —* 46 210. 23 ce Y= sisxis’ ¢ Sac a Cosda = 0.25 Bez 204jJs2 ee ae Find @PBCD constands ® Vs. @ ZL 1. Replay = 1 m Te= Pp el F350 x08 eS pac 4 Ve Cos da 132,13 X 0.8 J K Ng = Ve ap 3 2 ee ees ee nn = Narain seas (Cl Stas xaos) Hy a. = 162.32 + (1SU37 Hox Wwt5s2)_ = 9620-324 (154.370 x 51.71 64-26) | = 16200.32+ (7992.47 / 68-96) 6210.32 + jo+ 2866-26 - ) TY s0.29, $$} > 19816 18 <3) a4So. ee Se Bers WE = 79t26.39 [-s- Eee al 2 ee

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