“Black body radiat
Peduction of Wiens ~ Planck’s then Geeee
Jeans’ Law from P| displacement law ene) e
and experimental a theory — Connie’ oe ie
waves ~ GP Thomann ect on ~ Properties of tice
equation - Time inde, ee - Schrédinger’s ae
i . pent ets
coatings = Phvtica sigutcutoebon srtacSeci
. Scanning Sie mona box - Meats nishoone
microscope. croscope - Transmission electron
Introduction
The classical mechanics is not adequate to explain the
motion of atomic particles like electrons protons etc. Many
examples for the failure of classical mechanics are (i) black body
radiation (ii) specific heat of solids at low. temperature
(iii) theory of atomic structure (iv) photo - electric effect and
(v) Compton effect. To explain the failures of classical mechanics,
the quantum theory was developed.
4a) BLACK BODY RADIATION
Black Body
In practice, a perfe
showing close approximation to a perfect black body c
ct black body is not available. The body
an be
constructed.
A hollow copper spherical shell is coated with lamp black
on its inner surface. In this, a fine hole is made and a pointed
projection is provided just in front of the hole. (Fig. 4.1(a)).
enter into this spherical shell
ffer multiple reflections
this body acts as an
When the heat radiations
through the hole, the heat radiations su
and they are completely absorbed. Now,
absorber.Engineering Physics - |
4.2
When this body is placed in a constant aan path
at high temperature, the heat radiations ee It is to
hole (Fig. 4.1(b)). Now, this hole acts as a of the body acts
be noted that only the hole and not the walls
as the radiator.
Pointed projection
7 Heat
Hole
(a) Absorber _ (b) Radiator
Fig. 4.1 Black body
Perfect black body
A perfect black body is one which absorbs all the
heat radiations (all the wavelengths) incident on it,
Further, when such a body is placed at constant high
temperature, it emits radiation of all the wavelengths.
Black body radiation
The heat radiation emitted from a black body is
known as black body radiation.
The wavelength at which the maximum energy of radiation
emitted depends only on temperature of the black body and it
does not depend on the nature of the material.
Any object coated with a dull black pigment is a good
approximation to a perfect black body.quantum Physics
f SS
Laws of black body rq diatio, ee cy
. ion
Wien’s displacement 1
law
This law State,
S th,
corresponding ty 44. “Mt the product of wavelength (4)
‘m
absolute temperature of energy of radiati d
the black lation an
. body (T) is @ constant.
je
mT = Constant
Ay = Sastant
It is found that the
: Wavelength corr i
_ esponding to the
maximum energy of black body Tadiation ig inversly proportional
to absolute temperature. ee
As the temperature
of black body ;
on corresponding to ody increases, the
maximum energy decreases,
Wien’s radiation law
Wien deduced the law for the energy emitted by a black
body at a given wavelength (A) and temperature (T) to explain
the blackbody spectrum. It is known as Wien’s radiation law.
The energy density in the wavelength range 4 and
i+d) is given by
8nhe 1 8nhe 1 [ : 5
= sh
E. “hvikT ~ 5 hele
- 5 hvikT 3 helMRF
we” Ne
-5 ~he/MkT
E, = 8nhch e
-5 -C,/aT
Le
\ 1
nts
where C, and C, are constaEngineerin| Physics - |
44
: body.
T is the temperature of the black
values,
The constants C, and Cp have the
he
C, = 8nhe and C,=
Limitation
length,
This law holds good only for short wavelengths
and not for longer wavelengths.
Rayleigh - Jean’s law
This law states that the energy distribution of a
black body is directly proportional to the absolute
temperature (T) and inversely proportional to the
fourth power of the wavelength (i).
ie., E,« T
i
uy 4
where k is Boltzmann’s constant.
Limitation
This law holds good only for longer wavelength
regions and not for shorter wavelengths.
It is found that both Wien’s and Rayleigh - Jeans laws do
not agree with the experimental results for entire wavelength
range. Therefore, it is concluded that classical theory failed to
explain the emission of black body radiation.quantum Physics
—_ ———— AS
Thus, Max - Planck fe oo
jaws of the black body radiation ‘d quantum theory to explain
TY of black body radiation
revoluti,
; tion was introd. ‘Planck hypothesis’ of black body
radia ned by Max Planck in the year 1900.
js theory successgf, :
es ey oplain ee laws of black body
yadiation.
(42) PLANCK’S THEORY
filled up with the radiations
a large number of tiny oscillators.
They are of atomic dimensions, Hence, they are known
as atomic Oscillators or Planck’s oscillators.
Each of these oscillators jis vibrating with a
characteristic frequency,
2. The frequency of radiation emitted by oscillator is same
as that of oscillator frequency.
3. The oscillator cannot absorb or emit energy in a
continuous manner. It can absorb or emit energy in
multiples of small units called quantum.
This quantum of radiation is called photon. The energy
of the photon (€) is directly proportional to the frequency of
radiation (V),
Le., Eocy
vhere h is a proportionality constant. It is known as
Planck’s constant.
4. The oscillator vibrating with frequency v ae only om
energy in quantum of values hv. It indicates : a
e
the oscillators vibrating with frequency v can only hav
discrete energy values £,,.En ineerin Physics - |
ing Pr =
It is given by
where n is a positive integer 1, 2, oo stems
It means that the energy of the a
quantized and integer n is known
number,
Planck’s law of Radiation
Statement
The energy density of heat radiation emitted from
a black body at temperature T in the wavelength range
from ). to A+dd is given by
Here,
h - Planck's constant
¢ — Speed of the light
V ~ Frequency of radiation
k — Boltzmann’s constant
T ~ Temperature of the blackbody
PLANCK’S LAW OF RADIATION (Derivation)
Consider a black body with a large number of atomic
oscillators,
Average energy E per oscillator ig given by
E- . (2)
2|byto all the oscillators
N-1
‘otal number of oscillators
Number of atom:
in ground ae °scillators
0
xwell’; Ae ji
of oscillators with a energy distribution law, the number
£, 18 given by
N= Nye c/kT oe
where T —
Absolute temperature of the black body
k- Boltzmann’s constant.
If N is total num]
ber of oscillators and No Nj, Ng, «+, are
the number of oscillators with energies ¢,,¢., ¢. then
0» Epp Ege
N=N, +N, + \
From the eqn. (2), we have
N=N, oN eT ay, et a)
From Planck’s quantum theory, ¢ can take only a quantum
of values Av. Therefore, the possible values of € are
0, lAv, 2hv, 3Av, ete., (Fig. 4.2)
ie., €,=nhv, n=0,1,2
E
p= 9, &=hv, &,=2hv
Substituting these values in eqn (3), we have
0 = hy/kT ~ Qhv/kT
N=Nye + Noe + Noe
_AVIAT ~ 2hv/kT w (4)
tae
N=N,+Noe + Noej=
lo
ENERGY
4
Fig. 4.2 Energy diagram for a Cee
N=
N=
N=
N=
Total energy
given by
E
Substituting
we have
Engineering Physies — |
ee = Number of
: oscillator
n=5 Ng
ne
s oscillator of
frequency V
~ hy/kT
put x=e N/K we get
3
= Ny + Nyx + Nox + No¥ +-- G)
2
Nj Wb+xtx ted
1 -» (6)
| a =|
1 =
ooo = (leap = Lex gets...
1%
by using binomial series.
No
(1-x)
of the black body due to all the oscillators is
= &)N, + €,N, + _ AT)
for €), &, &, and 7 -.)hUre ()),49
quantum Physics
E = 0xN, + hy Noe AVIA 2hv Noe Bhv/kT
E = AvNge. PUT So hy Nel BVT (8)
put =o ET. have
E = AvNox + 2hvNox' +... @)
E = AVNG Ix + 2x74...)
E = AVNgx [1+2x+...]
B= Ava] 1 | = (10)
(1 -x)
= (l-xy 2 = 14+2x+...
(1-x)?
by using binomial series.
Substituting eqns (6) and (10) in eqn (1), we get
hv Nox
—j x)
B= +7
No
(1 -x)
i- Av Nox x (1-x)
(1-2) No
ea hAvx
B a-®
= hv x
iD
ti |
x
z hyengineering Physics - |
4.10
wwikT ve have
On substituting x = @ ,
w. (12)
. h
Number of oscillators per unit volume in the wavelengt
range A and A+d)h is given by
8n dh -. (18)
3
The energy density of radiation between wavelengths
AandA+dd is given by
Number of oscillators
E ay =| Per unit volume Average energy
a” ~ | in wavelength range per oscillator
A and 2 + da
8ndd Ay (14)
E, dA = —— x —_— a
» if give
8n da Acld eye
a)
+» (15)
- (16)quantum Physics
This eqn (16) ,, eal
epres
of wavelength. Sents Planck's radiation law in terms
Note: Planck’s law is also @.
ae x i
gubstituting A = Pressed in terms of frequency by
C/V and d), = 2
ey in eqn (15) Then, we have
= region which is confirmed by deduction of
Wien’s law and Rayleigh’s Jean law from Planck's law.
4) DEDUCTION OF WIEN’S DISPLACEMENT
LAW FROM PLANCk’s LAW
We know that Wien’s law holds good only at shorter
wavelength.
Therefore, when 4 is very small, v is very large, hence
Ay AVIAT
i >> land e is large when compared to 1.
Thus, ‘1’ is neglected in the denominator of eqn (16)
Av/AT hv/RT
je., @ -1=e :
Hence, the eqn (16) reduces to
8 he . (18)
= 75 Aviat
e
This eqn (18) represents Wien’s displacement law.
Thus, Planck’s law reduces to Wien’s law at shorter
wavelengths.4.12 Engineering Physics ~ |
: "= LAW
45) DeDuction OF RAYLEIGH - JEAN'S |
FROM PLANCK'S LAW
d only at
We know that Rayleigh - Jean's law holds oy is very
longer Wavelength. Therefore, when ) is very large,
h
small, and on <<1
hv/kT ly
1+ op
(by using exponential series and neglecting higher orders)
Now, eqn (16) reduces to
&
"
oo
a
=
=
—i
<19°
"
~
ut
w (19)
This eqn (19) represents Rayleigh - Jeans law.
Hence, Planck’s law reduces to Rayleigh - Jean’s law at
longer wavelength.
Thus, Planck’s law reduces to Wien’s law of
radiation at smaller wavelengths and to Rayleigh - Jeans
law at longer wavelengths.MATTER WAVES
Wave Nature of Particle
The light radiation behaves like a wave in interference and
diffraction experiments. The same light radiation behaves like
a particle in photoelectric effect and Compton effect.
Thus, the light radiation has dual (two) nature ie., wave
nature and particle nature.
The idea of wave nature of the particle was put forward
from the observation of dual nature of light radiation.
de - Broglie’s Hypothesis
Louis de-Broglie proposed a very bold and novel
suggestion that like light radiation, matter or material
particle also posseses dual (two) characteristics i.e,
particle -like and wave - like since nature loves symmetry.
The moving particles of matter such as electrons, protons,
neutrons, atoms or molecules exhibit the wave nature in addition
to particle nature.
According to de - Broglie hypothesis, a moving particle is -
always associated with waves. (Fig. 4.7)
| a4
(a) Particle nature
Fig. 4.7 Particle and wave nature 0!
(b) Wave nature
f matter particlePROPERTIES OF MATTER WAVES
I
If the mass of the particle is smaller, then the
wavelength associated with that particle is longer.
. If the velocity of the particle is small, then the
wavelength associated with that particle is longer.
If v=0, then =~, ie, the wave becomes
indeterminate and if v=~, then 4=0. This indicates
that de - Broglie waves are generated by the motion of
particles.
These waves do not depend on the charge of the
particles. This shows that these waves are not
electromagnetic waves.
The velocity of de - Broglie’s waves is not constant since
it depends on the velocity of the material particle.Engineering Phy
(er
TION
4.11] SCHROEDINGER WAVE EQUA
describes the way,
. uation
Schroedinger wave ed 1 form. It is the basic
nature of a particle in mathematical
equation of motion for matter waves.
then there should be
has wave properties,
If the particle has 1 of that
some sort of wave equation to describe the behaviow:
particle.
Schroedinger connected the expression of de-Broglie's
wavelength with the classical wave equation for a moving
particle. He obtained a new wave equation. This wave equation
is known as Schroedinger wave equation.
Forms of Schroedinger wave equations
There are two forms of Schroedinger wave equations.
They are
(a) Time independent wave equation
(b) Time dependent wave equation
23 SCHROEDINGER TIME INDEPENDENT
WAVE EQUATION (Derivation)
Consider a wave associated with a moving particle.
Let x, y, 2 be the coordinates of the particle and y wave
function for de - Broglie’s waves at any given instant of time ¢,
(Fig 4.10)Quantum Physics 4.35
Fig 4.10
The classical differential equation for wave motion is given
by
dy , fy wy _ ay
52 +e t+ tao )
ax dy dz v ot
Here, v is wave velocity.
The eqn (1) is written as
2
2 ldy
Vv=s—a we (2)
vat
2 2 2
a Oc :
where V = i + — z + —z_ is a Laplacian’s operator.
Ix dy Iz
The solution of eqn (2) gives y as a periodic variations in
terms of time ¢,
iwt
WO, 2, 0) =W, (GY ze
yy ena . (8)
oO
Here, wy, (x,y,z) is a function of x,y,z only, which is the
amplitude at the point considered. w is angular velocity of the
Wave,Engineering Physicg i
ae
i to t, we get
Differentiating the eqn (3) with respect
oy _ : fied
2
=
"
T
&
ats
&
«
ca
Q
le
ul
“i
2
°
é
ay 2 w (4)
-iwt
[v@=-1 vewe |
Substituting eqn (4) in eqn (2), we have
2
vw+2 yo - (5)
Vv
We know that angular frequency « = 2ny = ats
Here, v is the frequency [= v= i]
@ Qn
re w (6)
Squaring the eqn (6) on both sides, we get
2 _ an wn (1)
2 2Quantum Physics 4.37
Substituting eqn (7) in eqn (5), we have
2
4n a (8)
oe h
on substituting, A = i in eqn (8), we get
an
Vy +—yv=0
22
mv
v anim" 9
wt a. a» (9)
If E is total energy of the particle, V is potential energy
and 5m is kinetic energy, then
Total energy = Potential energy + Kinetic energy
12
E = Vtgm
2(E - V) = mv
2
mv = 2(E-V)
Multiplying by m on both sides, we have
— ie
my? = 2m(E-V)
Substituting eqn (10) in eqn (9), we get
2
4
Wy + oy x amE-V)v = 0ineering Phys;
4.38 i Sig
The eqn (11) is known as Schroedinger tin,
independent wave equation.
h.
Let us now introduce # = 5, eqn (11),
P - an ee » (12)
“-73o° 42
20 4n
where i is a reduced Planck’s constant
The eqn (11) is modified by substituting 7,
vy +7; G-Yy=0
A
8n°
Vy + are =0
axon
2 2m
Vv t 77 GY 0 wa (13)
dn
On substituting eqn (12) in eqn (13), Schroedinger
time-independent wave equation is written as
w. (14)
In eqn (14), there is no term representing time. That
is why it is called as time independent equation.
Note:juantum Physics
Qi y' 4.39
Special case
If we consider one-dimens;
. ional motion ie., particle moving
along only X - direction, then Schroedinger time independent
equation (14) reduces to
+ (15)
(413) SCHROEDINGER TIME DEPENDENT
WAVE EQUATION
Schroedinger time dependent wave equation is derived from
Schroedinger time independent wave equation.
The solution of classical differential equation of wave
motion is given by
iwt
W195 2,8) = Woy, ze »
Differentiating eqn (1) with respect to time t, we get
oy . -iwt w» (2)
Fy = EWE
oy : -iot a
ay = EAM) Wye (2° @ = 2m)
a = -2nivy w (3)
ree)
® _ _oniBy oBa hove;
at h
h
ay EYE a-+]
ae REY 2n |1
Engineering Ph Sicg
4.40
(4
ov y
ot
‘ have
Multiplying i on both sides 10 eqn (4), we
(E __fl=lu
i% . ninil | ‘(a
jw _ zy te ixiel =~]
oO
» 6,
Meg )
hae iM
Schroedinger time independent wave equation is given by
.. (6)
Vy + 2m @E-v)y =0
h
2 2m =0
Vy t+ pew =
On substituting Ey from eqn (5) in eqn (6), we get
2 2m|.. oy
2m as =0
Vt ud at vy
«7
. (8)Quantum Physics
4.41
2
2m
he 2
where H -( 37 V+ v| is Hamiltonian operator
10
E-ih az 8 energy operator.
The eqn (8) is known as Schroedinger time dependent
Ff im
Note: In eqn (7), there is the term
fe
That is why it is called time dependent wave
equation.
representing time.
oy
ot
PHYSICAL SIGNIFICANCE OF WAVE FUNCTION wy
The variable quantity which describes de-Broglie wave
is called wave function w.
It connects the particle nature and its associated wave
nature statistically.
The wave function associated with a moving particle
at a particular instant of time and at a particular point
in space is related to the probability of finding the
particle at that instant and at that point.
. The probability 0 corresponds to the certainty of not
finding the particle and probability 1 corresponds to
certainty of finding the particle.
ie., Sif yv ydt=1, if particle is present.
= 0, if particle is not present.
where y — complex conjugate of w
rticle at a particular
ili f finding a pa :
. The probability of 1 ig eeeteare function
region must be real and positive,
y is in general a complex quantity.Engineering Physics |
4.42
) BOX
(4.15) PARTICLE IN A ONE-DIMENSIONAL
en two rigiq
ing betwet
Consider a particle of mass ™ moving :
walls of a box at x=0 and x=a along x-axis.
This particle is bouning back and forth inane
of the box. The potential energy (V) of the aa fa
box is constant. It is taken as zero for simplicity (fig. 4.4).
The walls are infinitely high. The potential energy _.
the particle is infinite outside the walls.
Thus, the potential function is given by
0 for 0O< x
x2a
This potential function is known as square well
potential. (fig. 4.11)
Fig.
4.11 Particle in a boxQuantum Physics eae
The particle can not come out of the box. Also, it can not
exist on the walls of the box. So, its wave function w is 0 for
x < 0 and x > a. Now, task is to find the value y within
the box i.e., between x=0 and x=a.
Schroedinger’s wave equation in one-dimension is given by
2
dw 2m
pao Pa OM =0
dx - (1)
Since V=0 between the walls, the eqn (1) reduces to
dy | ImE
mE
GW , ImE (2)
de oe
2mE
put z = KR in eqn (2), we get
2
d . w (3)
oY ey =0
dx
The general solution of eqn (3) is given by
w(x) = Asinkx + Beoskx ws (4)
Here, A and B are two unknown constants.
The values of the constants A and B are determined by
applying the boundary conditions.
Boundary condition (i) y = 0 atx =0
Applying this condition to eqn (4), we have
: “.' sind =
0 =Asin0+Bcos0 [ cos 0
nou
a
=
0 =0+Bxl
Hence, B= 0Engineering Physicg _
4.44
ii =a
Boundary condition (ii) y = 9 at *
Applying this condition to eqn (4), we have
0 = Asinka + 0 [. B=o)
Asin ka = 0
It is found that either A=0 or sinka = 0
A can not be ‘0’ since already one of the constants B is 0.
If A is also 0, then the wave function is zero even in between
walls of the box. Hence, A should not be zero.
sinka = 0
sin ka is ‘0’ when ka takes the value of nm
je., ka = nn
where n is positive integer 1, 2, 3...
p= tm = (5)
- a
On squaring eqn (5), we have
ae .. (6)
2 nu
k=
a
We know that 4° = 2% _ 2mE [8-8]
h h Qn
4n
2 (2mx4n )E
k= z
2
2 8nmE 1G)
k=
Ah
Equating eqn (6) and eqn (7), we haveQuantum Physics
4.45
2 2
nw 80 mE
. nw
(8)
+ (9)
Here n=1, 2,3...
For each value of n, there is an energy level.
The particle in a box cannot possess any arbitrary
amount of energy. It can only have discrete energy values
specified by eqn (8).
In otherwords, its energy is quantised.
Each value of E, is known as eigen value and the
corresponding y,, is called as eigen function.
Normalisation of wave function
The constant A is determined by normalisation of wave
function as follows.
Probability density is given by y yw
. Ax
We know that y, (x) = Asin —
nnux
* _ N1x .
Ww Wwe Asin—— x Asin——
Ps yv when the wave function is real (not complex)vs
NV
The second term of the integral becomes
2
ov"
Engineering Ph, Rigg
we
g{ 2% ..
+ _ gsi al Qy
jg some where inside
tig te particle inside the i
It is certain that the par”
box. Thus, the probability of findin8
of length a is given by
f vydee! Gy
0
. . we have
Substituting wy from eqn (10) in eqn a,
a
J A’ gin? 22 ay = 1
a
0
_ 2nnx
2 J _ 2 —]
dx =1|*.*sin'@ = SS
2
0
@ a g nan ~
ax / ad 1 cos 22 -1 oe
aad 3
0 \ 0
\
a 2ntec
alia 1{s—
A [3] 2) Onn ae
0 —_
e 0
zero at both limitsQuantum Physics 4.47
2
Thus, os 22
2 a
+» (12)
On substituting eqn (12) in eqn (9), we have
The eigen function (y,) belongs to eigen values E, and it
is expressed as
++ (18)
This expression (13) is known as normalised eigen
function. The energy E,, and normalised wave functions W,, are
shown in fig. 4.12.
Fig. 4.12 Energy levels and wave functions
Special cases
From eqns (8) and (13), the following cases can be taken
and they explain the motion of electron in one dimensional box.INeerin
ae Ph Sigg
Case (i) : For n=! 2
h
Ey=> 2
“l gma
c TH
sin =|
vy, = Va
H V, @) is maximum at exactly middle of the bo, a
lence, y, (x
shown in fig. 4,12.
Case (ii) : For n=2
2
h
g, =) =
8ma
Hence, y, (x) is maximum at quarter distance from either
sides of the box as shown in 4,12.
4/2. (3nx
Wo (x) = z sl .
Hence, Wy
() is maximum at exactly middle and one-sixth
distance from either sides of the box as shown in fig. 4.12.