AS Level Core Pure Math Exam
AS Level Core Pure Math Exam
com
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Level 3 GCE
Further Mathematics
Advanced Subsidiary
Paper 1: Core Pure Mathematics
P58302A
©2018 Pearson Education Ltd.
1/1/1/
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Muhammed Ali Mehmood
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E s
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L's s fast
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wt2q
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w3 9w2tl9wt29
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IZ I i 1 E3 is circle with
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a
Centre Ci 1 radius 3
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F
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2
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y X
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Z
i
y
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Question 3 continued
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x 2 into circle
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subbing y
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x l t 3 9
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x
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x 2 11 tx 6 9 9
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2 8 1 0
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value
we want
bigger so
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the
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4114
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Question 3 continued
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*P58302A01036*
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4. Part of the mains water system for a housing estate consists of water pipes buried beneath the
ground surface. The water pipes are modelled as straight line segments. One water pipe, W, is
buried beneath a particular road. With respect to a fixed origin O, the road surface is modelled
a road r 7
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g
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normal
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ABT di of W
Ig Ig
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eanotw
f Hf
i r
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sino Ess
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fingybejameg
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tf
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Question 4 continued
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i D arcsin 7 58
g
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7 580
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or
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b let X closestpoint
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C then CX
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to W
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w c
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filth
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r
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FEED fi
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at
Question 4 continued
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f H T
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5.
⎛ 1 3⎞
⎜− 2 −
2 ⎟
(a) Describe fully the single geometrical transformation U represented by the matrix A.
(3)
The transformation V, represented by the 2 × 2 matrix B, is a reflection in the line y = –x
(b) Write down the matrix B.
i
(1)
Given that U followed by V is the transformation T, which is represented by the matrix C,
(c) find the matrix C.
(2)
(d) Show that there is a real number k for which the point (1, k) is invariant under T.
(4)
fail
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w
f.io
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Question 5 continued
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II L L
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d Gus invariant
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s
Ht's 1
YI
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I i 53 tu 2
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k2 53
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IZ
i l t 53 U ZU
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is 2 53 1
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Is
u
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n n
6. (a) Use the standard results for ∑r
r =1
2
and ∑ r to show that
r =1
II Gr 25 L9rH2rt4
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9 Incntill2ati 12
IHH t4n
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Question 6 continued
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b Gr t 103 roos 3
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Gr 25
II Gr 25 712 ref y
r
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6h73m 645314 D
I i
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3h3 3 166
Iz
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looking at
rt
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now roos
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ri l r L r 3 r 4 r S r 6 r 28
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adding up all
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such terms manually
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roost
14g
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Question 6 continued
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the
25
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Gr t 103 roos 3 n
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t 1276 0
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3zn2 I n
Quadratic formula n 29
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reject
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*P58302A02236*
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7.
f (z) = z3 + z2 + pz + q
f 33 5 3 O
Oi
ptq
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3ptq 36
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let Zz Zz at bi
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2 a 4
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c a Z
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Zz n Tem
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y
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2b_ ly
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t 3k
4
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x
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23 s
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Area
tbh L 35
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i b 353
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Question 7 continued
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told
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dpy ad
3 f2t7i fZ7i JE
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i
from 3ptq 36
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36 C 159
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Question 7 continued
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+
8. (i) Prove by induction that for n
n
⎛ 5 −8⎞ ⎛ 4n + 1 −8n ⎞
f (n) = 4n + 1 + 52n – 1
is divisible by 21
(6)
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Ig
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II I KID
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i n true for
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is D
E
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Consider h UH i
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k p
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Question 8 continued
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is X
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164 8144117 244
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µ4UtD
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10kt 2 8k 164
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31 124
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tl Uti
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44Mt
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Uti
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i true for nzuti
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we have proved the statement true
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for I
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it to be true for
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when assumed the torn ak
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By Mathematical Inductiont it is
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t
Question 8 continued
f n 4M 52N dirt
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true for me 1
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fafothtuffzscyutit.su J 4h
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25 f Cle 21 44
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Div
T 21
n
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by D by 21
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feet't divisible 21
is
by
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Question 8 continued
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for
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n I
it to be true for
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we have shown
n UH assumed the torn
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By Mathematical Induction it is
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for all n E
Rft
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9.
2 cm
14 cm
E
D E
O 1 4 x
8 cm
Figure 1 Figure 2
y = ax2 + b 1 x 4
where a and b are constants and O is the fixed origin, as shown in Figure 2.
(a) Find the value of a and the value of b according to the model.
(2)
(b) Use the model to find the volume of water that the bottle can contain.
(7)
(c) State a limitation of the model.
(1)
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The label on the bottle states that the bottle holds approximately 750 cm3 of water.
(d) Use this information and your answer to part (b) to evaluate the model, explaining your
reasoning.
(1)
l
y _18 72 14
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Question 9 continued
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4 Isa i a
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2 l
So b 18 f
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Off
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D E
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i V Tith LOT
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it lo
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i trth 4 14 2241T
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IT
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TJ x'dy
i
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y x't
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Question 9 continued 18
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141274 Isy dy
Ie 2749 1512
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Volume total
268T 842cm
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the simplified
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d
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8427750.1
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842 751
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error 100 12 3 1
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