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Problem Set 1

Problem set 1 in machine design

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Jerome Azañes
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0% found this document useful (0 votes)
42 views6 pages

Problem Set 1

Problem set 1 in machine design

Uploaded by

Jerome Azañes
Copyright
© © All Rights Reserved
We take content rights seriously. If you suspect this is your content, claim it here.
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VIEW CENTER ae “STRESSES & MACHINE ELEMENTS PROBLEM SET #4 erect enna oyu or INSTRUCTION: MULTIPLE Gros" the later hat coesponds - ir find the smeter of rivers 10 inches, * Seperate canteen A15in between cy B. 10in c.25in o20h Dit? De la ee Een Dees Da = Di (ae rs ia Ce) (eee : ; ciameters 2 Two cylinders ring ite sae reconnect? Sender dtc of60.n,Findte a ofthe larger Asn o.16887 p.6867in BAe Da as Get Die. Ds 3 Lon = 65.6163 cares ads Wee c7emx te = 65.610in aude ferro 330 3. Four cylinders roling in opposite drecsons hes a speed rao of AB:C:D = 53:14, IFoerter distance aynder A and Cie YO inches, fd he ameter of pnd , 02 A 1875in . Botg—ns 0 Ditty © Dee > Bydia: Bully 3 pe aes 756 052030) [Orta a | Do= Zs a % 2o20 / 7) oy 2 on () E°SEI=7E ci = 2 (%)| ds = v2(3) aif ob, eBfg J V9 OD = ERE ‘4. Apulley has a tangential velocity of75 fpm. If puley ameter is 10 inches, find the speed ofthe speed, A 24.34 pm "2885 1pm c. u2imm D. 8234 pm 28.65 x9m) in xtZ)CN) ja FMP in ae Shaft A with 12 inches diameter pulley running at 250 rpm is connected to shaft B by means of 26 inches. Bl, ple on bY re ann = cod Os Gre a noe he @ we! pm 8. 29480.5m ©. 17945 pm 0. 197.44.mn = Bers a) Eva = Ws.38 4 Gl vpm 6. Asteel te rod on bridge must be withstand a pull of 6200, Saley of 4 and utimate sess of 6,000 psi Ie. Find he camer of the rod assuming @ factor of A 0234in B. 0.634in ©oee1in ro * Sa pe Set |p oa) FS ae uP 7 Noein soa sera etl 45.0 wt re necesay neg in pues plate using 2 factor of safety of Pincha oi © 63617 bs 8. 61587 bs ©. 653788 é Sin cameter hole See 68.345 tbs aoe i sooo = . » wOM6Sin 7 B05) Fe canoe A25 in diam through a single Y 1.8 i, 320 rpm using ole ap ot long jc fing is to Cat 15000 Ib load at A 4111.44 pole at ag, 5 puna! beni my the bearing pressure. 1. 197.34 psi Bae pel ©. 123.94 Ps Sect OO = wt Bo A journal bea cl ami) Wi c z i '0. A cable steel has = 16200 mt? ie at both ends. If tensile stress 'S SO raters ng aS won He 7 i” : 100,000 pet onsty of soa Gp H000088 D. 130,000 psi 18s 56 yh ut ~ sen = SP yom 7 ee Some W000 ee Sern Fuiem De i tr of 1.25 inches and yield stress of 63,000 psi, a wnoge toraue varies from 2200 10 6400 ib Ithas a diameter A 6524.48 pol 1 aoa8.66 pel ©. 5476.95 psi D, 7834556 pst g- Me Quins, YoComettl gy ge. 95 pe! aa be an ¢ +12. How many 1/2-inch diameter hole that can be punch in one motion of @ 1/-nch-thick plate using a force of 50 tons. The ultimate shear stress is 52 ks! and factor of safety of 3 = AT 8.9 C8 D_i0\ 5 Wat oe Vo ore = 0 ens& ooolh . = js0000 MS sooo Te av 1407 ep cna = Gus S288 gts S200 Migr WojD+ sat STR We 42 ).220a7 202 ine te iia ameter paeesormaoope eee ir 18 ago iib. The shaft diameter is 1.5 aches andhas a stress of 20,000 ps apodeme Ys "A. 0,252 in Beh ©. O62in D. 0.826in =9.3=10 it row Ty 720.0" 4 pee wow te, ~ ete tio We Ty ° u = 1000 Wo ‘termine the® Useq 10stud * sa Pe eon on tmnt te ogee fone S he cinder bt see Lo Bee may Dzaee se © SBT ©. 4828 Kpa De= Kew of Ha Aco 5 wy 185 : B.zeim pears Ez 0. ON My + A20 mm diam ee SIT, Ber Se a ta Termenvonenig wenn ISR pp ect ne hes me cp A. 28.35 KN B. 28.42 KN B@xI0? = 2S tt ean fo ee ee ata mee nang * Far WOXIO pa “WOoNGos) = UB en 3 KL torque, Find the sess shafts subjected to 20. 42.5 inches shat 8 ane ©. S067 Mee D. 3864 Mpg e S=ve » te MesaBL TS SIGN. GY eR ing TOT He se rteaun be Sete Sesto up parm Sa Ree _ "A123 KNm © 184m et 35x gy jen — S Taw z fe 2 pow 01 Vo \ a radius of 600 lever, has a pul of 200 Nat ; Sued 08 50 mm (d= 10 mm), has 8 ull Tm tga Te Working ares Sat by a sat pared (6 = 10M Na 8 A at "o*tesson ne pint, Come Sa D. 4 ) wen VAT C200) (9 PTs ay ss ~ 1} Fe . me D xa? sonm™ (\0) beam is 110 Mpe, Lean, 2 pled tee ond. tthe allowable tess ingction moduius, ~ Mtn weight i D. 24.2810? 23. In a20m cantievereg determine the : A 1854 L=am, M i 4 B. 2u77iny ome th PR 5 Ln = BAM ENO gasaz sen m7 xeon ecm 2a ne % 103 yn n> we Lai0c xo-cerai] a 39 24 Gpa, find the | 3) >, 24, julus of elasticity is 200 teed pps 68m ong and stretches tem ur agen trmodt nes ATKN B.akN ©. 9KN EWAE eit 2 Fm) YL oom FEM = OM Ke 7 opel Ceexe) TS Aun] 25. A steel wire 10 m tong ing the weight of wire, determine Fang Vertcaly supports a tensile oad of 2 KN. Neglecting the: 7 Asam ES Sameer cess en aa eal? Nene wh fw, deen S A 2mm— 8. 3mm c. 4mm . (B smm © ee Fl 2-2 BANCO = 5x0? YR Bim = Boor fox’) Smm 28. tomodaas chee OREN ros econ rees 1mm wen aessc225 4g hanged on Compute re Ren Seay ten 176.58 GPa B. 169.81 Gpa ©. 160.41 GPa D. 180.28 Gpa 0-00 1ya> (2220-0023) ki) (4) Re = 1% 58 hip os en a? E ork 27. A200 radi sveenes oa erin of 000. Osamne he - deflection ofthe rod, 20mm B. 25mm ©. 30mm D. 35mm Ye AS, pre © Stay L oe 207 ; Y= 009m A giana confit fer om 118 1% ncaa hen at Ain Determine the strain. jh when heated fom A 204x104 5 05x10. Lg 40szane D278 | You (haw L Yor cate) =(v Ox?) Eseq* ary), =f9 ONE] 29 ean foramen no a gy = 11.7 x 10 mim°c, temperature of 15°C Use k an mise ches Seen tm tity eet D. S064 Y - VK) CO} Tavg 9 90% ) Tre 40-Gy ed Ac MRE ey, A 4512 x 190 ak an : sg, mano cantons Determine the polar moment of Om == c. gs2x10%m! =D. 7.125 104 mt rDy no 08) I= Coot a 32 = 6.2.200e INF. TaN oy of A08.3°F (78, a pryete OF Stel material so thet the o a Sec) teat aa mati 0 thatthe sighity amar le of son busting of Fe Don eraee bushing 8 aesstY 988 Heating = 245%, Cooing med one yo va bolng pst ‘A 0.000793." Shing hae bai? es pag Boting pont 000073 Deon teal earancebebween & YIMEGAA) me Ete Sela crte eta a no in ©. 0.000750 in , 0.0000 in So068 agg Maly fey fF Beene a at wee ely @ drag 4, eo a0? ye <0 -00073 (2) + ~0-2 046 G) othe 2 eaesea 32. What mod a mer ulus of. “L999 393. 3 gaan -Longe sug {2-00083] a.unit tensile stress, ini lene 1h 42,300. pa eon unt dfn F010 mn tom ad rotons S Manx torpe —c. aso1xicrps (Diy 905210 ps » yyeoo = Yr. TOB¥IO’ pi 33, the weight of 6 diam 3108 WS Ny SAE S4t6 of same act YS MUSAE 120 hata 174814 what wil be the weigh of chvmium 5 al 2 26.4ibs D. 465.1 ibs eT 34. Compute the maximum unt sharin a3 nees ameter soul sang at vanamits 2400 no tava 99 om, eet (482.7 ps 8 es70ps 6, 90850581 se let wy 7 sine Wick wns pars 61st tes egress Hn 35. Ifthe utimate shear stress of@ a ee Nm ag Ks Hooalg 2700 eaCiTT Ter 7 2000 to E000 ins has 1% ncn ameter and 60000 ply! strength 38. The shaft whose torque ares FoR, efor re shot meat VO Ao et cstezps S860 pa jones eal as! 0902 ) Sx A — yT ¢ sac odor of 060. Te axtace oor is 099 an the endurance sera 2 naam wate seen te Sates et nme ao 's 28000 psi. Cor cay a 1090 @)ass 7260 ast 25000 9539.97 = 2S ‘A178 e Bay, $8,000 into ata shear stress of 10,000 ps. Compt the ameter of cs Gy» S= eT oy n lovee = Ie (3@ 000 in 1H) 30. Asst pits 10 be shear ate —————_ 9 2-64 4 uate shearing stregg tt 815 Ww 03 Re rE ne Te ate "ELPA, Fd ine ate i aches 2 hub toa shat 1S inches in ater and chin Din 40./A steel 0.5 inch x 4 / wid if poison's ratio ie 8S 200 k ‘A. 0.000007 in S225; Bag tiie a sons esos Find the deformation along its 90000697 in ©. 0.000016 n . 0.000067 in | = elon Ee ms & By = Bez” = me ee Eee \ ‘corded 0-23 “Sayre & sab 41. Asteel rods stretched betwee ignotto exceed 130 MNim? at “ayer 94 walls and caries a tensile load of 5000 N at 20°0. ithe allowable stess © 7™" “S5;,¢ 20 am * whats te minimum mettre? Aasurok= HAT umMIMACE= 122mm ©. 12.22mm D. 1322mm os ANSWER KEY a ze 3A 48 5A ne ee se eee ee ~ te 12.8 43.8 48 16.8 ae 16.A 17.0 18.4 19.0 20.0 yw 20a 2A 23.8 24.6 26.0 26.8 aA 28.¢ 20.8 20.8 3A 32.0 aac 34a 25.0 36.A 37.¢ 38. 20.8 40.8 41.0 uy.

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