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MUZAMAL TARIQ
 IN SHED

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 Area Needed for Shed
No. of Fans, Pads, Vents, Feeding and Drinking System
Water Tank Construction
Light Bulbs and Light Intensity
Water and Chemicals for Shed Cleaning and Disinfection
Litter Placement and Water for Litter Disinfection
Temperature and Relative Humidity
Water for Medicine, vaccine and Sugar Solution
Static Pressure
Air Velocity and Air Exchange Time
Timer Calculation of Fans and Pads
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MUZAMAL TARIQ
 1- Area Needed for Shed

• According to Shed Dimensions and No. of Sheds

• If One shed with dimensions (450×50×10)ft then Area required is

450ft×50ft = 22500ft²
• As we know that
1 canal = 272.25×20 = 5445ft² (⸫1marla=272.25ft²)

• Required Area for Shed = 22500ft²/5445ft² = 4.13 canal

• So,
4.5 canal Land will be sufficient.
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 2- No. of Fans, Pads, Vents, Feeding & Drinking
System

For the same shed dimensions;

Volume (V) = L × w × h = 450×50×10 = 225000ft³
Area (A)= L × w = 450×50 = 22500ft²
Cross section (CS) = w × h = 50×10 = 500ft²
Fan Capacity = V × 10% = 225000ft³ × 10% = 22500ft³
No. of Birds = 22500/0.75 = 30,000 (⸫Space/bird = 0.75ft²)
Max. BW = 30,000 × 2.2 kg = 66,000 kg

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 Conti…
A- Front Fans

1- No. of Front Fans = Volume/Fan Capacity = 225000ft³/22500ft³/m = 10

2- No. of Front Fans = (Max. BW × Required Cfm per kg live wt.)/Fan Capacity
= (66,000kg × 6cfm)/22500ft³/m = 18 (⸫Cfm/kg in summer = 6cfm)
3- No. of Front Fans = (Desired Velocity × C.S)/Fan Capacity
= (550ft/m × 500ft²)/22500ft³/m = 12 (⸫DV = L+100)
4- No. of Front Fans = (Required Cfm per ft² × Total Area)/Fan Capacity
= (8cfm×22500ft²)/22500ft³/m = 8 (8 cfm is required per ft²)

Average No. of Front Fans = (10+18+12+8)/4 = 12 Front Fans

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 Conti…

B- Side Fans

No. of Side Fans = (Max. BW ×Required Cfm/kg Live wt.)/Fan Capacity

= (66,000kg×0.58ft³)/9000ft³/m (⸫Side Fan Capacity = 9000cfm)
= 4 Side Fans (⸫Required cfm/kg live wt. in winter = 0.58cfm)

• Fans should be installed at 30% of wall from the floor. It means that
= 10ft(H)×30% = 3ft above from the floor.

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 Conti…
C- Cooling Pads

1- No. of Cooling Pads = Area for Pads/Area per pad

= 740ft²/13ft² = 57 Cooling pads (⸫Area/pad = 13ft²)
As; Area for Pads = (FF × F.C)/Face Velocity
= (12×22500ft³/m)/365ft/m = 740ft²
2- No. of Cooling Pads = Total Area required by FFs/Area per pad
= (80ft²×12)/13ft² = 960ft²/13ft² = 74 Cooling Pads
(⸫80ft²/FF is required)
3- No. of Cooling Pads = No. of FF × Cooling Pads required by 1 FF
= 12×7 = 84 Cooling pads (⸫7 cooling pads required by 1 FF)
Average No. of Cooling Pads = (57+74+84)/3 = 72
• Cooling Pads will be installed on width and lengthwise also.
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 Conti…
D- Air Inlets/Vents

No. of Vents = (Total Required cfm/4)/Area for 1 vent (⸫1sq.inch sufficient for 4cfm)
= (38280cfm/4)/144˝ = 9570˝/144˝ (⸫Area for 1 vent = 1ft² = 144˝)
= 66 Vents
As, Total Required cfm = Total BW × Required cfm/kg live wt.
= 66,000kg×0.58cfm/kg = 38280ft³/m

• If Fabricated vents available the area for 1 vent = 1.5ft²

• Vents should be installed at 60% of the height of wall from floor. So,
= 10ft(H)×60% = 6ft above from the floor.
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 Conti…
E- Feeding System

• For 50ft wide house, 3 feeding lines will be ideal.

No. of Feeders in Automatic system = Total Birds/Birds on 1 feeder

= 30,000/60 = 500 feeders
(⸫1 Feeder for 60 birds)
No. of Feeders in one line = Total feeders/Total lines = 500/3 = 167F/line

Total lengths of feeders in one line = Total length/Length of 1 feeder length

= 420ft/10ft = 42 lengths/line
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 Conti…
Conti… (Feeding System)

Feed Storage Bins Capacity

• It should be as enough to store 5 days feed.

So, we have to know the # of feed bags on 35th day.

No. of Feed Bags = (Age × 5 × No. of Birds in Thousands)/50 (⸫1Feed Bag = 50kg
= (35×5×30)/50 = 105 Bags

So, the 5 days feed bags will be = 5×105 = 525bags = 26,250kg

= 26,250kg/3 = 8,750kg each bin
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 Conti…

F- Drinking System

• For 50ft wide house, 4 drinking lines will be ideal with 3 feeding lines.

No. of Nipples in Shed = Total Birds/Birds on 1 nipple

= 30,000/12 = 2500 Nipples (⸫1 nipple/12 birds)

No. of Nipples in one line = Total nipples/Total lines

= 2500/4 = 625N/line

Total lengths of nipples in one line = 42 lengths like for feeding line
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 3- Water Tank Construction
A- Drinking Water Tank

• Drinking water, at least 48 hrs. water need should be stored.

• At 35th d of age 175g/bird feed is normal then water consumption will be double,
350ml/bird.
So,
Total Water Needed = 30,000×350
= 10,500ltr/d×2 = 21,000Ltrs

Plastic Tank Capacity = 21,000ltr/3.78ltr

= 5555Gallon capacity (⸫1Gallon = 3.78ltr)

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 Conti…
• A- Drinking Water Tank (Conti…)

Cemented Tank Dimensions = (10×8×10)ft

Tank Capacity = Volume/(Water storage capacity/ft³) (⸫V = (10×8×10)ft = 800ft³)
= 800ft³/28.3ltr = 22,640Ltrs (⸫water storage capacity/ft³ = 28.3liters)

Water stored per ft = Total water/height of tank

= 22,640Ltrs/10ft = 2264Ltrs/ft

Water stored per inch = water stored per ft/inches in a ft

= 2264Ltrs/12 = 189Ltrs/inch

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 Conti…
B- Water Storage Tank for Cooling Pads

• At 50%RH and 35℃ temp., 10 l/m water is required for 1,00,000cfm to evaporate.
(⸫Total cfm in the house = total FF × FC = 12×22500cfm = 270,000cfm)
So, For 270,000cfm
Total water required/m = 27Ltr×2 = 54 l/m
(2 = water evaporated & present in pads)
As Timer setting 4min ON/20min; then 12min/hr.×24 = 288min/day
Total water required/day = Total water required per min/total time per day
= 54 L./m×288min/d = 15,552Ltrs
= 15,552Ltrs ×2 = 31,104Ltrs capacity tank required
(2 = days for which store water)

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 Conti…

So,
For 31,104 liters capacity water tank’s dimensions will be as
= (12×8×12)ft
(⸫V = (12×8×12)ft = 1152ft³)
Tank Capacity = 1152ft³×28.3 L/ft³ (⸫water storage capacity/ft³ = 28.3liters)
= 32,601 Liters will be stored in that tank.

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 4- Light Bulbs and Light Intensity
A- Light Bulbs

No. of Light Bulbs = #of watts/Available watts

= (L × w/4)/Avail. watts (⸫4W/ft² are required)
= ((450×50)/4)/25W = 225Bulbs

• Each Bulb line will be on top of the feeding line.

So, No. of Bulbs in one line = 225/3 = 75bulbs/line (As 3 feeding lines)

Distance between bulbs in a line = Shed Length/# of bulbs

= 450ft/75 = 6ft apart

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 Conti…
B- Light Intensity

Total Lux Required = Recommended Lux ×Area(m²) (⸫1m² = 10.76ft²)

= 40lux×2091m² = 83640lux required
(⸫A = 22500ft² = 2091m²)
As, 100W bulb = 1600lux. It means 1W = 16lux So,
25W bulb = 25×16 = 400lux
According to No. of Bulbs;
Total Lux = Total Bulbs × Lux of available watt bulb
= 225×400 = 90,000lux or
= 90,000/10.76 = 8364fc (⸫1fc = 10.76lux)

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 5-Water and Chemicals for Shed Cleaning and
Disinfection
For Disinfectant

Total area of the shed = Area of (walls(L)+walls(w)+floor & roof)ft²

= 18000ft² + 2000ft² + 45000ft² = 65,000ft²
Area of walls(L) = L × h × # of walls = 450×10×4 = 18000ft²
Area of walls(w) = w × h × # of walls = 50×10×4 = 2000ft²
Area of floor & roof = L × w × # of surfaces = 450×50×2 = 45000ft²

Total water required = Total area × water required/ft²

= 65,000ft²×30ml = 19,50,000ml
= 19,50,000ml/1000 = 1950liters

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 Conti…
For Disinfectant (Conti…)

No. of drums of water = Total water/drum capacity

= 1,950 L/220L = 9 drums
Inside the shed = 8 drums & Outside the shed = 1 drum

• If Chemical dose used 0.5% then

Amount of chemical = Total water × Chemical dose
= 1950 l × 0.5% = 98liters

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 Conti…
For Detergent

Total area of the shed = Area of (walls(L)+walls(w)+floor)ft²

= 18000ft² + 2000ft² + 45000ft² = 65,000ft²
Area of walls(L) = L × h × # of walls = 450×10×2 = 9000ft²
Area of walls(w) = w × h × # of walls = 50×10×2 = 1000ft²
Area of floor = L × w × # of surfaces = 450×50×1 = 22500ft²

Total water required = Total area × water required/ft²

= 32,500ft²×30ml = 975liters
• Amount of detergent will be according to dose and water
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 6- Litter Placement and Water for Litter Disinfection

Litter Placement

Litter quantity = (L × w × depth (ft) × litter/ft³)/40kg (⸫1ft³ holds 2.5kg)

= (450ft×50ft×0.25ft×2.5kg)/40kg (⸫3inch = 0.25ft)
= 352 Mann

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 Conti…
Litter Disinfection

Amount of Disinfectant = L × w/Area covered by 1liter disinfectant

= (450×50)ft/500ft² = 45liter
(⸫1liter disinfectant used for 500ft²)
Water Required for Disinfectant = Disinfectant × water for 1liter disinfectant
= 45L×37L = 1,665liter water
(⸫1 liter of disinfectant uses 37 L water)
No. of drums of water = Total water/drum capacity
= 1,665L/220L = 8 drums

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 7- Temperature and Humidity

(A)- Temperature
T = 32°C – (Age × 0.32)
At 10th day T = 32°C – (10× 0.32) = 28.8°C
(B)- Relative Humidity
RH% = (WBT – (DBT – WBT)/DBT) × 100
RH% = (25°C- (28°C-25°C)/25°C×100 (If DBT = 28°C & WBT = 25°C)
RH% = 78%
(C)- THI
THI = T + H = 28.8°C + 78 = 107 (It should be >100)

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 8-Water for Vaccination, Medication & Sugar Solution

(A)
1- Water for DW vaccine = No. of birds(T) × Age(d) × water required/Thousand birds
Water = 30×18×1.25ltr = 675Ltrs.

2- Water for ED vaccine = No. of birds(T) × water required/Thousand birds

Water = 30×35ml = 1050ml/1000 = 1.05L
3- Water for Spray vaccine = No. of birds(T) × water required/Thousand birds
Water = 30×350ml = 10,500ml/1000 = 10.5L
(B)
Water for medicine = Calculated acc. to % or Dose recommended of medicine
• It will be according to the condition.
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 Conti…

(C)- Water for Sugar Solution

• At 1st day, if 10ml/bird sugar solution will be sufficient.

Water = (No. of birds × water needed for 1 bird)/1000
= (30,000×10ml)/1000 = 300Ltrs
Now
Sugar quantity (5% soln.) = water required × % of solution
= 300×5% = 15kg.

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 9- Static Pressure Calculation

Static Pressure of Shed = width of house (m) (‫؞‬w = 50ft/3.28ft = 15m)

= 15Pa
249Pa = 1 inches of water column
15 Pa = (1/249)×15 = 0.060 inches of water column

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 10- Air Velocity & Air Exchange Time

Velocity = Total running cfm/Cross Section (if 5 fans are running)

= 112,500/500 = 225 fpm

Air Exchange Time = Shed Length/Air Velocity at that time

= 450ft/225fpm = 2min

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 11- Timer Calculation for Fans & Pads

(A)- For Fans

Fans ON time = % of fan × 60

= 2.4×60 = 144s
If 5min cycle then 144s ON & 156s OFF.

% of fan = total cfm required/cfm of running fan

= 54000cfm/22500cfm = 2.4min

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 Conti.…

(B)- For Pads

• Timer will be set according to pads wet and dry time.

• If wet time is 4-5 min and dry time is 15 min then
in 20 min cycle, 4 min will be ON time.

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