Name: G R O U P 2 ABE 111 Date:
Course/Year/Section: BS ABE III AB STRUCTURES ENGINEERING Rating:
Time Frame: 3 hours 2nd Sem 2023 – 2024
Mango Orchard
Row Spacing 9m
Tree Spacing 4m
2
2030 m
2
=56.39∨56 trees
36 m /tree
Calamansi
Planting distance 5m
5m x 5m = 25m^2
2
2000 m
2
=80 trees
25 m /tree
Banana
Planting distance 4m x 4m
4m x 4m = 16m2
2
504 m
2
=31.5∨31trees
16 m /tree
Moringa
Planting distance of 3m x 3m
3m x 3m = 9m2
2
1182m
2
=131.33∨131trees
9 m /tree
Dragon fruit
Fruit pole spacing 3m
Cold Storage
A cavan of onion in the Philippines is typically around 44 kilograms. The volume of a cavan can vary, but if we consider the density of
chopped onions as approximately 169 grams per cup1, we can estimate the volume of a cavan of onions.
First, let’s convert 44 kilograms to grams: 44 kg = 44,000 grams
Next, we divide this by the density of chopped onions to get the volume in cups: 44,000 grams ÷ 169 grams/cup ≈ 260 cups
Since there are approximately 4 cups in a liter, this is equivalent to: 260 cups ÷ 4 ≈ 65 liters
So, one cavan of onions is approximately 65 liters.
Now, let’s calculate the volume of your 7m by 5m storage facility. Assuming it’s a rectangular prism (a box shape), the volume is
calculated by multiplying the length, width, and height. If we assume a reasonable height for a storage facility, say 3m, the volume would
be:
Volume = Length x Width x Height = 7m x 5m x 3m = 105 cubic meters
Since 1 cubic meter is equal to 1,000 liters, the volume of the storage facility is 105,000 liters.
Finally, we can calculate how many cavans the storage facility can accommodate by dividing the total volume of the storage facility by the
volume of one cavan:
Number of cavans = Total volume ÷ Volume of one cavan = 105,000 liters ÷ 65 liters/cavan = Approximately 1,615 cavans
So, a 7m by 5m by 3m cold storage facility could accommodate approximately 1,615 cavans of onions.
1,500 x 5 rooms (7mx5m)
Capacity= approx. 7,500 cavans
Rice/Corn Field
According to the Philippine Rice Research Institute, the average yield for irrigated rice fields in the Philippines is about 4.51 metric tons
per hectare1. Other sources suggest that the average yield of rice per hectare can range from 3 to 6 tons2.
To convert this to a per square meter basis, we need to know that 1 hectare is equal to 10,000 square meters. So, the yield per square
meter is:
4.51 metric tons 2
2
=0.000451 metric tons per m
10,000 m
calculate the yield for a 5,200 m² rice field:
0.000451 metric tons per m2 ×5,200 m2 = 2.3452 metric tons
So, a 5,200 m² rice field could yield approximately 2.35 metric tons of rice, assuming average yield rates.
Pavement Drying
According to the Department of Agriculture in the Philippines, a multi-crop drying pavement (MCDP) with an area of 600 square meters
can dry up to 170 bags of palay per batch1. If we assume that each bag of palay weighs approximately 50 kilograms (a common weight for
a bag of palay in the Philippines), this means that 170 bags would weigh 8,500 kilograms, or 8.5 metric tons.
So, if 600 square meters can accommodate 8.5 metric tons of rice, we can calculate the area required for 2.3452 metric tons of rice:
Area = (2.3452 metric tons / 8.5 metric tons) * 600 square meters = Approximately 165.7 square meters
So, you would need approximately 165.7 square meters of pavement drying area for 2.3452 metric tons of rice.
Silo
Cylindrical Part:
The formula for the surface area of a cylinder (excluding the bases) is 2πrh, where r is the radius and h is the height. Given that the
diameter of the cylindrical part is 2.5 m (which makes the radius 1.25 m) and the height is 2 m, the surface area of the cylindrical part is:
2π(1.25m)(2m)=5πm2
Conical Part:
The formula for the lateral surface area of a cone is πrl, where r is the radius and l is the slant height. Given that the diameter of the
conical part is also 2.5 m (which makes the radius 1.25 m) and the slant height is approximately 1.6 m, the surface area of the conical part
is:
π(1.25m)(1.6m)=2πm2
5πm2 + 2πm2 = 7πm2 or 22m2
Farm Machinery
Tractor:
width=2.3m
length=3.7m
Farm Machinery Shed Dimes:
L= 10.1m
W= 5m
Area= 50.5m2
Space between the vehicles= 0.8m
Farm Workshop
Length= 6.6m
Width= 5.3m
Area= 34.98m2
