GRADE 8 2nd Quarter
GRADE 8 2nd Quarter
Department of Education
PUBLIC TECHNICAL - VOCATIONAL
HIGH SCHOOLS
GRADE 8
ELECTRICAL INSTALLATION AND MAINTENANCE NC II
MODULE TITLE:
LEARNING O
ANALYZES SIGNS, SYMBOLS, AND DATA
7
At the end of
MODULE NO.:
DEFINITION OF TERMS
Ampere (I) - the unit of electrical current (coulombs per second)
Caution - indicates some precautionary measures against potential hazardous situation which, if not
avoided, may result to a minor or moderate injury
Danger - specifies hazardous situation which, if not avoided, will result to a serious injury or even death
Joule (J) - a metric unit of energy: watt per second. 1 Kw hr = 2,655,000 ft-lb = 1.341 hp-hr = 3413 Btu
= 3,600,000 joules
Orthographic - a drawing which shows the front top and side view of the object
Volt (E) - the unit of electric pressure or electromotive force which will produce a current of 1
ampere through a resistance of 1 ohm Watts (W) and kilowatts (KW) - are units of electric power.
Electrical Symbols are small drawings or pictograms used to represent various electrical devices in a
diagram or plan of an electrical circuit. These symbols are used in sketching schematic diagrams and electrical
plans for numerous types of electrical works. Practically any electrical fixture found in a house has a symbol that
coincides to said fixture on an electrical wiring diagram. These are very useful guide for an electrician or electrical
contractor, thus, making the wiring easier to install as well.
The following are common electrical symbols used in sketching wiring plan and diagram.
Conductor/Wire Ammeter
Terminal Voltmeter
Switch Galvanometer
Fuse Wattmeter
Battery Buzzer
Resistor Speaker
Capacitor Antenna
ELECTRICAL SIGNS
Your power tool with its manual may contain "WARNING ICONS" (a picture symbol intended to alert you to,
and/or to instruct you how to avoid a potentially hazardous condition). Knowing and understanding these symbols
will help you operate your tool better and more safely.
Electrical signs and stickers alert students, workers, and visitors to electrical hazards in the area. Alerting
workers to high voltage areas, electrical hazards, power lines and other electrical equipment in the area, can help
prevent fires and injuries. Proper electrical signs can inform workers of the dangers in the area.
The flow of current in a conductor or wire can be represented by diagram. There are two types of
diagram: pictorial diagram and schematic diagram.
A. Pictorial diagram is a sketch of electrical circuit that shows the external appearance of each
component. It is much like a photograph of the circuit and uses simple images of parts.
Sample Pictorial diagram of one bulb controlled by single pole switch using 9 volt battery source.
B. Schematic diagram is a sketch showing the components of the circuit using standard electrical
symbols. It shows the actual number of components and how the wiring is routed but not the actual
location.
Diagram A Diagram B
Sample schematic diagrams of one bulb controlled by single pole switch using direct current (Diagram
A) and alternating current (Diagram B) source.
Schematic diagram of three bulbs connected in parallel circuit controlled
by a single pole switch.
C. Types of Circuit
1. Series Circuit is a circuit in which lamps are arranged in a chain, so that the current has only one
path to take. The current is the same through each load. Example of this is the Christmas lights. It
consists of a number of bulbs that are connected side by side to meet the voltage requirement
which is 220 volts for alternating current.
Pictorial diagram of Christmas light in series circuit
2. Parallel Circuit is a circuit in which lamps are connected across the wires. The voltage across
each load on parallel circuit is the same. The advantage of using parallel circuit is that even if one
of the lamps fails, still the remaining lamps will function.
Pictorial diagram of two bulbs connected in parallel circuit controlled by a single pole switch.
ELECTRICAL PLAN
These units and symbols for electrical quantities will become very
important to know as we begin to explore the relationships
between them in circuits.
The Ohm’s Law Equation
Ohm’s principal discovery was that the amount of electric current
through a metal conductor in a circuit is directly proportional to the
voltage impressed across it, for any given temperature. Ohm
expressed his discovery in the form of a simple equation, describing
how voltage, current, and resistance interrelate:
In this algebraic expression, voltage (E) is equal to current (I)
multiplied by resistance (R). Using algebra techniques, we can
manipulate this equation into two variations, solving for I and for R,
respectively:
Analyzing Simple Circuits with Ohm’s
Law
Let’s see how these equations might work to help us analyze simple
circuits:
In the above circuit, there is only one source of voltage (the battery,
on the left) and only one source of resistance to current (the lamp,
on the right). This makes it very easy to apply Ohm’s Law. If we
know the values of any two of the three quantities (voltage, current,
and resistance) in this circuit, we can use Ohm’s Law to determine
the third.
In this first example, we will calculate the amount of current (I) in a
circuit, given values of voltage (E) and resistance (R):
What is the amount of current (I) in this circuit?
REVIEW:
MATTER
Anything that occupies space and has weight is called matter. All liquids, gases, and
solids are examples of matter in different forms. Matter is made up of smaller units called
atoms.
ATOMS
An atom resembles the solar system with the sun as the center around which a
series of planets revolve, as shown in Figure 2-1. In the atom, there is a relatively large
mass at the center called the nucleus. Electrons revolve in orbital patterns around the
nucleus.
Figure 2-1 Atomic structure
of Helium.
ELECTRONS
ELECTRON
ORBITS PROTONS
AND NUCLEUS
NEUTRONS
7
Unit 2 Electron Theory and Ohm’s Law 50
ELECTRICAL CHARGE
A material is said to have an electrical charge when it attracts or repels another
charged material. A material may have either a positive or a negative electrical charge.
Two objects with positive charges repel each other. Two objects with negative charges
also repel each other. Two objects with unlike charges attract each other.
ELECTRONS
One or more electrons revolve continuously around the nucleus of an atom (just as
the planets revolve about the sun). Electrons possess a negative electrical charge and are
very much lighter in weight than protons. All electrons are alike regardless of the atoms of
which they are a part. An atom contains the same number of electrons as protons. For
example, the aluminum atom has thirteen electrons and thirteen protons.
CURRENT
Electrons in motion result in an electrical current. Copper wire is often used to carry
electrical current (moving electrons). For each atom of copper in the wire, electrons are
revolving around the nucleus. When electrical pressure (voltage) from a battery or
generator is applied, it is possible to force these electrons out of their circular paths and
cause them to pass from atom to atom along the length of the wire (conductor).
Unit 2 Electron Theory and Ohm’s Law 52
The greater the number of electrons passing a given point in a circuit, the greater the
intensity of the current. The intensity of an electrical current is measured in amperes (A).
The instrument used to measure current is called an ammeter as shown in Figure 2-2. An
ammeter must be connected in series with other devices in a circuit. The letter “I” is used
to represent the amount of current in a circuit.
Current Types
0 0 0
TIME TIME TIME
VOLTAGE
obtained from many sources. Generators are widely used for high-powered AC and DC
installations. Storage batteries are used extensively for DC power in automobiles and
aircraft. Photoelectric cells convert light energy into electrical energy. These cells are used
as voltage sources in light-operated devices. A thermocouple, which consists of a junction
of two unlike metals, generates a low voltage when heated. Of all the voltage sources
mentioned, the generator is most commonly used because of its suitability for commercial
and residential applications.
The letter “E” is used to represent a voltage. The volt (V) is the unit used to express
the quantity of electrical pressure. The instrument used to measure voltage is the
voltmeter. The voltmeter must be connected in parallel with the load to be measured.
Unit 2 Electron Theory and Ohm’s Law 56
ELECTRICAL POLARITY
All DC sources of electrical pressure have two terminals to which electrical devices
are connected. These terminals have electrical polarity. One terminal is the positive
terminal, whereas the other is the negative terminal. Electrons flow through the device
from the negative terminal of the source to the positive terminal of the source. The
source maintains a supply of electrons on its negative terminal.
RESISTANCE
Resistance is measured in ohms. The symbol for ohms is the Greek letter omega, Ω.
This symbol, representing ohms, and the letter “R,” representing resistance, are used in
formulas. The instrument used to measure resistance is called an ohmmeter. Electrical
power must be disconnected in a circuit when using an ohmmeter. The meter shown in
Figure 2-4 is commonly used to measure resistance, voltage, and current.
Unit 2 Electron Theory and Ohm’s Law 58
Unit 2 Electron Theory and Ohm’s Law 59
According to Ohm’s law, when the resistance of a circuit is constant, the current can
be changed by changing the voltage: current will increase when the voltage is increased,
and current will decrease when the voltage is decreased. Similarly, when the voltage is
constant, current will increase when the resistance is decreased, and current will decrease
when resistance is increased.
Unit 2 Electron Theory and Ohm’s Law 60
I=E
R
E
E =IRand R =
Unit 2 Electron Theory and Ohm’s Law 61
I
Example: If a voltage of 24 volts appears across a resistance of 4 ohms, find the
current through the resistance.
I = E = 24 volts = 6 amperes
R 4Ω
Example: Find the voltage that appears across an 8-ohm resistance if the current
through it is 10 amperes.
SUMMARY
Ohm’s law is the basic formula for understanding electrical fundamentals. The
relationships among current, voltage, and resistance provide a foundation for
understanding various types of electrical circuits and systems. Current is the movement of
electrons.
Voltage is the electrical pressure that causes the electrons to move. Resistance is a
property of all materials that tends to prevent electrons from moving. The lower the
resistance, the greater the current.
ACHIEVEMENT REVIEW
1. Name the particles that revolve in orbital patterns around the nucleus of an atom.
Unit 2 Electron Theory and Ohm’s Law 63
___________________________________________________________________
___________________________________________________________________
3. A current that changes direction and intensity at a regular interval of time is called:
___________________________________________________________________
___________________________________________________________________
5. State Ohm’s law, and write three forms of Ohm’s law using equations.
___________________________________________________________________
___________________________________________________________________
___________________________________________________________________
___________________________________________________________________
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6. What instruments are used to measure voltage, current, and resistance? ________
___________________________________________________________________
___________________________________________________________________
Unit 2 Electron Theory and Ohm’s Law 65
___________________________________________________________________
___________________________________________________________________
7. What units of measure are used for voltage, current, and resistance? __________
___________________________________________________________________
___________________________________________________________________
___________________________________________________________________
___________________________________________________________________
10. Determine the resistance of a lamp that draws 3 amperes when connected to a
120-volt supply. __________________________________________________
___________________________________________________________________
11. If the lamp in problem 10 is connected to a 240-volt supply, what is the new value of
current? (Assume there is no change in resistance as the temperature of the lamp
changes.) __________________________________________________
___________________________________________________________________
___________________________________________________________________
12. An 8-ohm resistor is connected to a 120-volt circuit. What current will it draw?
___________________________________________________________________
Unit 2 Electron Theory and Ohm’s Law 67
13. If 60 volts are applied to an 8-ohm resistor, what is the value of current through the
resistor? _______________________________________________________
___________________________________________________________________
14. A toaster is connected to a 120-volt supply and it draws 8 amperes. Find the
resistance. ________________________________________________________
___________________________________________________________________
15. A 5-ohm heater draws 9 amperes from a power supply. What is the voltage of the
power supply? _______________________________________________________
___________________________________________________________________
___________________________________________________________________
16. If the 5-ohm heater in problem 15 is replaced with a 15-ohm heater, what current
will the 15-ohm heater draw from the same power supply? _________________
Unit 2 Electron Theory and Ohm’s Law 68
___________________________________________________________________
17. What voltage must be applied to a 6.4-ohm lamp filament to develop 20 amperes of
current? ________________________________________________________
___________________________________________________________________
___________________________________________________________________
18. An ammeter placed in a lighting circuit registers a current of 3 amperes. If a
24-volt source has been applied, what is the circuit resistance? ______________
___________________________________________________________________
19. If an ohmmeter measures the resistance of a load as 7 ohms, and a source of
28 volts is applied, what is the current? _________________________________
___________________________________________________________________
Unit 2 Electron Theory and Ohm’s Law 69
20. If the resistance in a circuit remains constant, what will happen to the current if the
voltage increases? _______________________________________________
___________________________________________________________________
21. If the voltage of a circuit remains constant, what will happen to the current if the
resistance increases? ________________________________________________
___________________________________________________________________
22. What is the term given to anything that has weight and occupies space? _______
___________________________________________________________________
U•N•I•T 3
SERIES CIRCUITS
OBJECTIVES
• describe the basic relationships of voltage, current, and resistance in a series circuit.
• apply Ohm’s law to determine unknown quantities.
Knowing certain basic rules in the operation of series, parallel, and series-parallel
circuits is important in developing a facility for locating faults in electrical equipment.
Unit 3 Series Circuits 71
Understanding electrical problems is, in VOLTAGE
fact, impossible without this knowledge.
The total voltage applied to a series
A series circuit is one in which devices circuit is distributed across the various
are connected so that there is only one components of the circuit in a series of
path for current. The direction of the voltage drops.
current in the wire is the same as the
The three equal resistors shown in
direction of electron movement. Figure 3-1
Figure 3-2 are connected in series. The
illustrates three lamps connected in a
voltage across each component is equal to
series with a voltage source.
onethird of the total voltage. In Figure 3-3,
the voltage across each resistor is
proportional to the resistance. The higher
the resistance, the greater the voltage drop
in a series circuit.
Unit 3 Series Circuits 72
L1 L2 L3
1 2 3
1 2 3
I
E
– +
A B
15
Unit 3 Series Circuits 73
3V 9V
1 2
R1 R2
4 12
12 16
Therefore,
I = 0.75 ampere
Figure 3-3 Voltage and current distribution: Figure 3-4 Digital multimeter. resistors of
unequal value in series. (Courtesy of Advanced Test Products)
Unit 3 Series Circuits 74
As shown in the previous figures, the sum of the voltages across the individual
devices is equal to the total applied voltage. This leads to the following important rule for
a series circuit:
CURRENT
Because only one path for current exists, the current through all components in the
circuit is the same. This statement can be expressed as
I T = Il = I2 = I3 = In
The total resistance of a series circuit is equal to the sum of resistances of all
resistors in the circuit. The total resistance in Figure 3-1 is the resistance from terminal A
to terminal B with the voltage source disconnected.
In equation form,
R T = Rl + R2 + R3 + . . . + Rn
R3 = resistance of resistor 3
= resistance of nth
Rn
resistor
Unit 3 Series Circuits 77
Example: The total resistance for Figure 3-3 is RT = R1 + R2.
RT = 4 Ω + 12 Ω = 16 Ω
An alternate path of very low resistance in a circuit is called a short circuit (Figure 3-
6). For example, if the two wires leading to a lamp come in contact with each
R T = R1 + R2 + R3 2
R2
= 2 Ω + 3 Ω + 7 Ω = 12 Ω
3
R1 R3
ET 240 V 1 3
IT = = = 20 amperes 2 7
RT 12 Ω
ET = 240 V
I T = I1 = I2 = I3
Unit 3 Series Circuits 79
El = ITR1 = (20)(2) = 40 volts
E l + E2 + E3 = ET
40 + 60 + 140 = 240 volts
Example: Find the total current for the circuit shown in Figure 3-8.
R T = R1 + R2 + R3 I 1
=2+6+2 2
2
= 10 Ω 120E V 6
R3
2
Unit 3 Series Circuits 80
IT = ET = 120 V = 12 amperes
RT 10 Ω
SUMMARY
A series circuit means that the resistive loads are connected one after another. In
this type of circuit, the current is the same in all parts of the circuit. To determine the
current, the total resistance must first be calculated. The total resistance is the sum of all
the resistances in the circuit. The current is then the supplied voltage divided by the total
resistance.
E T = El + E2 + E3 + . . . + En
I T = Il = I2 = I3 = In
Unit 3 Series Circuits 81
R T = Rl + R2 + R3 + . . . + Rn
ACHIEVEMENT REVIEW
1. Four loads are connected in series across 110 volts DC. The loads fail to operate. A
voltmeter connected in succession across each device reads 0 across the first three
loads and 110 volts across the fourth load. What circuit fault is indicated at the
fourth load?_____________________________________________________
___________________________________________________________________
2. Four loads are connected in series across 120 volts and a 3-ampere current exists.
One load fails to operate. The voltage across each of the other devices is 40 volts.
4. Find the voltage drop across a 10-ohm resistor, if the current through the resistor is
1.7 amperes. _____________________________________________________
___________________________________________________________________
5. Find the resistance of a resistor if the voltage drop across it is 51 volts, and the
current through it is 3 amperes. ________________________________________
___________________________________________________________________
E1 = ________________
Unit 3 Series Circuits 83
E2 = ________________ 150 V
R1 = 4 R 2 = ___
E1 = ________________
EG = ________________
EG
R2 = ________________
E 2
6
I = 3A R3
12
Unit 3 Series Circuits 85
10. If E2 = 54 volts, find E1 in Figure 3-13.
R2
9
R1
1 R3
3
ET
Figure 3-13 Finding voltage.
11. Using the circuit in problem 10, find E2 if E1 = 6 V.
12. Find E1 and E3 in Figure 3-14.
Unit 3 Series Circuits 86
R2
I = 4A
R2
E1 R1 R3
E3
2 5
ET
VOLTAGE
E T = E1 = E2 = E3 = En
E2 = voltage across
component 2
E3
= voltage across
En component 3
RESISTANCE
It is apparent from studying the previous equation that adding more parallel
branches to the circuit will increase the total current. Ohm’s law (R T = ET/IT) shows that the
total circuit resistance decreases as current increases in parallel circuits. Therefore, adding
parallel branches results in a decrease in total resistance.
Equal Resistors
ET 15 15 15
R 15
RT = = = 5 ohms
N 3
Where= total RT resistance in ohms
= resistance R of one of the equal valued resistors in ohms
N = number of parallel resistors
Unequal Resistance
In practice, parallel circuits with resistors that have unequal values are more
frequently used than parallel circuits with resistors that have equal values. No simple rule
Unit 4 Parallel Circuits 96
applies in this case because each resistor takes a different value of current for the same
applied voltage.
To find the total resistance of a parallel circuit, apply a known source voltage to the
circuit and determine the total current. Ohm’s law is then used to find the total
resistance.
RT = ET
IT
Where= total circuit resistance RT in ohms
= total voltage in volts ET
IT = total current in
amperes
Unit 4 Parallel Circuits 97
The total circuit resistance also can be found by using the following formula. This
formula may be applied to any parallel circuit with any number of parallel branches.
1 = 1 + 1 + 1 . . . + 1 Rn
RT R1 R2 R3
Unit 4 Parallel Circuits 98
1=1+1+1
RT 3 6 8
Lowest common 1=8+4+3
denominator is 24 RT 24 24 24
Unit 4 Parallel Circuits 99
1 = 8 + 4 +3 = 15
RT 24 24
1 15
= (cross multiply)
RT 24
Solving for RT 15RT = 24
Unit 4 Parallel Circuits 100
24
RT = == 1.6 ohms
15
An alternate solution to this problem is as follows:
1
RT =
1/3 + 1/6 + 1/8
RT = 1
0.333 + 0.167 + 0.125
1
RT = 1
0.625
RT =1.6 ohms
Unit 4 Parallel Circuits 101
A simple method of solving circuits consisting of only two resistors in parallel (with
either equal or unequal values) is called the “product over the sum” method.
Example: A 3-ohm resistor and a 6-ohm resistor are connected in parallel.
Determine their combined resistance.
RT = R1 × R2 = 3 × 6 = 18 = 2 ohms
R 1 + R2 3+ 6 9
Example: For the circuit in Figure 4-4, find the total current and the current in R 2.
E R1
I1 I2 R2
24 V 6Ω
4Ω
IT
Unit 4 Parallel Circuits 102
IT = ET = 24 = 10 amperes
RT 2.4
E T = E1 = E2
E2 24
I2 = = = 6 amperes
R2 4
Note: IT may also be found by adding the currents I1 and I2.
Unit 4 Parallel Circuits 103
E1 24
Find I1: I1 = = = 4 amperes
R2 6
Therefore, IT = I1 + I2 = 4 + 6 = 10 amperes.
E
R1 R2 R3
120 V
6Ω 12 Ω 16 Ω
1=1+1+1
RT R1 R2 R3
1
1 = ++
RT 6
=
denominator is 48 ++
Cross 1 = 15
Unit 4 Parallel Circuits 105
RT 48
multiply
15RT = 48
Unit 4 Parallel Circuits 106
RT = = 3.2 Ω
IT = ET = 120 = 37.5 A
RT 3.2
SUMMARY
A parallel circuit has branches of resistance. The voltage is the same across each
branch, but the current may not be the same in each branch. The current is determined
by the amount of resistance in the branch. If the branch currents are added together, the
sum is the total current.
ET = E1 = E2 = E3 . . . = En
I T = I 1 + I 2 + I 3 . . . + In
1=1+1+1...+1
RT R1 R2 R3 Rn
ACHIEVEMENT REVIEW
1. Four 12-ohm resistors are connected in parallel. Calculate the total circuit resistance.
_______________________________________________________
___________________________________________________________________
2. Four resistors are connected in parallel. The resistance values are 4 ohms, 8 ohms, 12
ohms, and 16 ohms. Calculate the total circuit resistance.
___________________________________________________________________
___________________________________________________________________
___________________________________________________________________
Unit 4 Parallel Circuits 107
4. Determine the total resistance of a 10-ohm resistor and a 30-ohm resistor connected
in parallel. ________________________________________________________
___________________________________________________________________
5. If the circuit in problem 4 is connected to a 150-volt supply, find the current through
each resistor. ________________________________________________________
___________________________________________________________________
6. Find the total voltage, ET, for the circuit shown in Figure 4-6.
total voltages.
40
3A
___________________________________________________________________
___________________________________________________________________
___________________________________________________________________
___________________________________________________________________
7. Find the current through R3 in the circuit shown in Figure 4-7.
___________________________________________________________________
Unit 4 Parallel Circuits 108
15 A
Figure 4-7 Finding current.
3A 6A ?
R1 R2 R3
E
10 Ω 5Ω
___________________________________________________________________
___________________________________________________________________
8. For the circuit in problem 7, what is the value of R 3? _______________________
___________________________________________________________________
9. Find the value of R2 for the circuit shown in Figure 4-8 if the total circuit resistance is
7.5 ohms.
Figure 4-8
Finding resistance. E
75 volts
R1 R2 = _
10
___________________________________________________________________
___________________________________________________________________
___________________________________________________________________
11. The ammeters in the circuit in Figure 4-9 are indicating 4 amperes and 9 amperes as
shown. Find the values of R3 and RT.
___________________________________________________________________
Unit 4 Parallel Circuits 109
Figure 4-9 9A
Finding resistance.
E 4A
R = Ω R2 = 60 Ω R3 = Ω
R1 = 30 Ω
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___________________________________________________________________
___________________________________________________________________
___________________________________________________________________
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Unit 4 Parallel Circuits 110
13. Find IT for the circuit shown in Figure 4-10.
10
Figure 4-10 Ω
Finding current.
100 V ET 20 Ω 20 Ω
IT
_____________________________________________________________________________
_
_____________________________________________________________________________
_
_____________________________________________________________________________
_
_____________________________________________________________________________
_ 14. Using the circuit in Figure 4-10, what is the current through the 10-ohm resistor?
_____________________________________________________________________________
_
_____________________________________________________________________________
_
15. In Figure 4-10, if the 10-ohm resistor is changed to 20-ohms, and E T is changed to 120
volts, find IT.
_____________________________________________________________________________
_
_____________________________________________________________________________
_
16. In Figure 4-10, if there is a break in the 10-ohm resistor causing an “open circuit”to
occur in the 10-ohm branch, what will be the total current, IT?
_____________________________________________________________________________
_
_____________________________________________________________________________
_
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U•N•I•T 5
SERIES-PARALLEL CIRCUITS
OBJECTIVES
The circuit shown in Figure 5-1 is In Figure 5-3, the resistors are
an example of a series-parallel circuit. In grouped in another type of series-
this circuit, lamps L1 and L2 constitute a parallel
parallel circuit. The rheostat R, used to
control the current in this circuit, is in
series with L1 and L2 as a group.
R1 R3
R
3 6
E
L1 L2 R2 R4
9 12
circuit. In this circuit, R1 and R3 are in series, and R2 and R4 are in series. The two series
branches are then in parallel.
EQUIVALENT CIRCUITS
The methods used to determine current, voltage, and resistance for series and
parallel circuits apply to combination circuits as well. Solving problems in series-parallel
circuits is made easier by resolving these circuits into equivalent circuits.
Figure 5-4 is equivalent to Figure 5-3. In this case, R1 and R3 are combined as a single
resistance RA, equal in value to the sum of R1 and R3. Similarly, RB replaces R2 and R4. RA and
RB then may be combined into one resistor, RC, to result in the final equivalent circuit of
Figure 5-5. The total current in the original series parallel circuit, Figure 5-3, is equal to the
current in the simple series circuit of Figure 5-5.
Unit 5 Series-Parallel Circuits 117
RA
R
9 C
6.3
RB
21
E E
CIRCUIT SOLUTION
After the total resistance of a circuit is found, the total current, as well as the current
in other parts of the circuit, can be determined according to Ohm’s law. In Figure 5-6, the
equivalent resistance of the parallel resistors R2 and R3 is 12 ohms.
Unit 5 Series-Parallel Circuits 118
Therefore, Figure 5-7 is the series circuit equivalent of Figure 5-6, and the total
R1 R1
8 8
E
E 120 V
R2 R3 R 2, 3
120 V
20 30 I 12
T
6A
R T = R 1 + R 2× R 3
R 2+ R 3
Unit 5 Series-Parallel Circuits 119
RT = 8+ 20 × 30
20 + 30
RT = 8+ = 8 12+
RT = 20 Ω
120 volts
The total current is IT = = 6 amperes 20 ohms
The voltage across R2,3 is IT × R2,3 = 6 amperes × 12 ohms = 72 volts. Because R2,3 is the
equivalent resistance of the parallel combination of R2 and R3, the voltage across these
resistors is 72 volts, as shown in Figure 5-8. Finally, the current through
R2 is R1
8 I3
I
T
E 6A
120 V I2 R2 R3
72 V
20 30
Unit 5 Series-Parallel Circuits 120
Example: Find the total current (IT) in the circuit shown in Figure 5-9.
Figure 5-9 Sample problem. 8 12
8 12
120 V
2
Unit 5 Series-Parallel Circuits 121
RT = 2+ 8×8 + 12 ×12
8+8 12+12
RT = 2 + 4 + 6 = 12 Ω
IT = ET = 120 = 10 A
RT 12
SUMMARY
In a simple series-parallel circuit, the total currrent is equal to the sum of the branch
currents. This current passes through the resistances that are in series with the voltage
source. The total current may also be computed by changing the series-parallel circuit into
a series circuit. The resistances of the branches may be converted into a single resistance.
Unit 5 Series-Parallel Circuits 122
This resistance is then in series with the other resistances in the circuit, and the total
resistance is the sum. By using Ohm’s law, the total current can be calculated.
ACHIEVEMENT REVIEW
1. a. In Figure 5-6, what circuit components are connected in series?
____________________________________________________________________
____________________________________________________________________
b.What circuit components are in parallel with each other?
____________________________________________________________________
____________________________________________________________________
Unit 5 Series-Parallel Circuits 123
2. Assume that each resistor shown in Figure 5-2 has a resistance of 100 ohms. Findthe
total circuit resistance. _____________________________________________
____________________________________________________________________
____________________________________________________________________
____________________________________________________________________ 3.
a. In Figure 5-10, what circuit components are connected in series?
____________________________________________________________________
____________________________________________________________________
Figure 5-10 R1 R2
Unit 5 Series-Parallel Circuits 124
R3 R4
EG
Series and parallel.
Unit 5 Series-Parallel Circuits 125
____________________________________________________________________
____________________________________________________________________
____________________________________________________________________
Figure 5-11
8 3
Finding total current.
120 V
6
5. Find the current through the 6-ohm resistor for the circuit used in problem 4.
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6. Determine the total resistance of the circuit in Figure 5-12 between points A and B.
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Figure 5-12 B
10
Finding total resistance.
5 7
4 12
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Unit 5 Series-Parallel Circuits 126
7. If 120 volts are connected across points A and B in the circuit shown in problem
6,what is the current through the 4-ohm resistor?
8. Five 4-ohm resistors are connected so that their combined resistance will equal5
ohms. Draw the circuit diagram.
9. The two resistors in branch A-B of the circuit in Figure 5-13 are of equal value.
Figure 5-13A 8A
Finding resistance.
R
240 V 120
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Unit 5 Series-Parallel Circuits 127
Eg 45 V 15 9
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Unit 5 Series-Parallel Circuits 128
12. For the circuit in problem 11 (Figure 5-14), if the voltage across the parallelbranches
is changed from 45 volts to 90 volts, find the total current, IT.
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13. Draw the series equivalent circuit diagram for the circuit in problem 11 (Figure 5-14).
14. Find the total current for the circuit shown in Figure 5-15.
Figure 5-15 6 8
Finding total current.
4 12
72 V
IT
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Unit 5 Series-Parallel Circuits 129
15. Using the circuit in problem 14 (Figure 5-15), find the voltage across the 4-
ohmresistor. ___________________________________________________________
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16. What is the value of the voltage across the 8-ohm resistor in problem 14?
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Unit 5 Series-Parallel Circuits
130
17. Find the current through the 6-ohm resistor in the circuit in problem 14.
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18. What is the value of current through the 12-ohm resistor in the problem 14
circuit diagram?
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Unit 5 Series-Parallel Circuits
131
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