NSET
Past Year Question Bank
NSET 2023 Solved Questions
Section 1- Mathematics
Question 1
The average score of a class in a math test is 75. If ten new students, who scored an
average of 80, join the class, the average score of the entire class becomes 77. How
many students were there in the class initially?
Answer:
Let n be the total number of students in class initially.
Total class score for Math = 75*n
Total score for 10 new students = 10*80
New Total class(n+10) score = 800+75*n = 77*(n+10)
=> 75n +800 = 77n +770
=> 77n-75n = 800-770
=> 2n = 30
=> n =15
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Question 2
In a survey conducted among 250 IPL fans, 120 students support CSK, 80 students
support RCB, and 30 students support both CSK and RCB.
If a student is selected at random, what is the probability that the selected student
neither supports CSK, nor RCB?
Answer:
n(T1) = number of student supporters for team T1
n(CSK) = 120
n(RCB) = 80
n(CSK & RCB) = 30
n(CSK or RCB) = 120 + 80 - 30 = 170
n(neither CSK nor RCB) = Total number of student fans - n(CSK or RCB) = 250-170 =
80
p(neither CSK nor RCB) = 80/250 = 0.32
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Section 2- Learnability
Question 1
Given a recursive equation,
F(N) = F(floor(N/3)) + 1
F(1) = 1
Calculate the value of F(2187).
Where floor(x) gives the greatest integer less than or equal to x.
floor(3.14) = 3
floor(1.9) = 1
floor(5) = 5
Answer:
F(2187)= F(floor(2187/3))+1 = F (729)+1 = F(floor(729))+2= F(243)+2 = F(81)+3 = F(27)+4 =
F(9)+5 = F(3)+6 = F(1)+7 = 8
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Question 2
Given a recursive equation,
F(N) = F(N-1) + N
F(1) = 1
Calculate the value of F(600).
Answer:
F(600) = 600 + F(599) = 600 + 599 + F(598) = …… = 600+599+598+....+2+1 = 600/2
*(600+1) = 601*300 = 180300
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Section 3- Aptitude
Question 1
The selling price of x articles is the same as the cost price of 12 articles. If the profit is
20%, then what is the value of x?
Answer:
S.P. of x articles = C.P. of 12 articles
Profit = 20% => S.P. = 1.2 * C.P.
1.2 * C.P. * x = 12 * C.P.
=> 1.2 x = 12
=> x = 10
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Question 2
In an alien language, surprisingly, they also use English lowercase letters, but in a
different order given as
"w o r l d a b c e f g h i j k m n p q s t u v x y z"
Arrange the following words in dictionary order as per the given order of alphabets:
["awde", "bwld", "wol", "ozceg", "wrd", "bwdl"]
Answer:
Words starting with w comes first, then word starting with o & then words starting
with a & then b.
wol & wrd < ozceg < awde < bwld & bwdl
wol < wrd < ozceg < awde < bwld < bwdl
wol-wrd-ozceg-awde-bwld-bwdl
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