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Blood Sample Oxygen Saturation Analysis

The document contains fractional saturation data measured from a blood sample. It describes plotting the data to calculate the Hill constant and determine cooperative ligand binding. It also shows calculating the P50 value of the blood sample as 2.449kPa.

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14 views2 pages

Blood Sample Oxygen Saturation Analysis

The document contains fractional saturation data measured from a blood sample. It describes plotting the data to calculate the Hill constant and determine cooperative ligand binding. It also shows calculating the P50 value of the blood sample as 2.449kPa.

Uploaded by

ameigemechu
Copyright
© © All Rights Reserved
We take content rights seriously. If you suspect this is your content, claim it here.
Available Formats
Download as DOCX, PDF, TXT or read online on Scribd
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1.

The following fractional saturation data has been measured for a certain blood sample:

pO2 ,kPa θ

20 0.14

30 0.26

40 0.39

50 0.50

60 0.59

70 0.66

80 0.72

90 0 .76

θ
a. By plotting the graph of log( ) versus log[pO2] , put [pO2] on the x-axis
1−θ
while θ on the y-axis, Calculate the Hill constant, n, and state the cooperativity
type
b. Calculate P50 of this blood sample

Solution

θ
First Find the values of log(pO2) and log( ¿
1−θ
θ
pO2 ,kPa log(pO2) θ log( ¿
1−θ

20 1.301 0.14 -0.788

30 1.477 0.26 -0.454

40 1.602 0.39 -0.194

50 1.699 0.50 0.000

60 1.778 0.59 0.158

70 1.845 0.66 0.288

80 1.903 0.72 0.410

Page 1 of 2
90 1.954 0 .76 0.501

a.

Chart Title
0.6

0.4

0.2

0
1.2 1.3 1.4 1.5 1.6 1.7 1.8 1.9 2
-0.2

-0.4

-0.6

-0.8

-1

Using linear regression or calculating the slope by ΔX/ΔY the Hill


constant, nH, is 1.991. This implies that the ligand binding is positively
cooperative.
θ
b. Log( ) = nLog(pO2)- LogKd
1−θ
θ
LogKd = nLog(pO2) - Log( )
1−θ
=1.991 *1.954-0.501
=3.389
Kd=Anti log 10^3.389 = 2.449kPa

Page 2 of 2

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