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Seatwork 2

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0% found this document useful (0 votes)
322 views6 pages

Seatwork 2

Uploaded by

Alex Yumul
Copyright
© © All Rights Reserved
We take content rights seriously. If you suspect this is your content, claim it here.
Available Formats
Download as DOC, PDF, TXT or read online on Scribd
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SEATWORK 1

Directions: Create a C++ program that follows the given program specifications, paste your source code
and the screenshot of the sample output in the space provided.

1. Write a program to check if the number is positive and how many digits the number has using if
statement. If the inputted number is zero or a negative number, it should display, “It is a non-
positive number”. The maximum digits of the number that can be entered by the user should be
four only.

Program

#include <iostream>

using namespace std;

int main () {
float num;

cout << "Enter number: ";


cin >> num;

if(num <= 9999 && num > 0){


cout << num << " is a positive number.";
}

else if (num <= 0 && num > -9999) {


cout << "It is a non-positive number.";
}

else {
cout << "The maximum digit of the number that can only be 4.";
}

return 0;
}
Sample Output

Note: Take screenshot of the output given that the input is a one-,two-,three-,four-digit number and a
non-positive number.

CCS0003-Computer Programming 1 Page 2 of


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2. Write a program that allows the user to select an arithmetic operator to be applied to the two
floating numbers inputted by the user using a switch statement.

Sample Output:

Program
#include <iostream>

using namespace std;

int main()
{
char op;
float num1;
float num2;
float result;

std::cout << "Enter your operator either (+ - * /): ";


std::cin >> op;

std::cout << "Enter your first number: ";


std::cin >> num1;

std::cout << "Enter your second number: ";


std::cin >> num2;

switch (op){
case '+':
result = num1 + num2;
cout << "Result: " << result << '\n';
break;

case '-':
result = num1 - num2;

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cout << "Result: " << result << '\n';
break;

case '*':
result = num1 * num2;
cout << "Result: " << result << '\n';
break;

case '/':
result = num1 / num2;
cout << "Result: " << result << '\n';
break;

default:
cout << "Please only enter one of the 4 math operators" << '\n';

return 0;
}

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Sample Output

Note: Take screenshot of the output when choosing each of the operators in the option.

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