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Gravitation

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Gravitation

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Textbook

Chapter No.

05 Gravitation
Subtopics Centripetal Acceleration

5.1 Introduction
Gravitational Orbit
Force Velocity
5.2 Kepler's Laws
S.3 Universal Law of Gravitation
RadiuS
5.4 of Earth
Measurement of the Gravitational Constant (G)
Alritude Radius of Orbit
5.5 Acceleration due to Gravity
5.6 Variation in the Acceleration due to gravity
with Altitude, Depth, Latitude and Shape
$.7 Gravitational Potential and Potential Energy
5.8 Earth Satellites

For asatellite in circular orbit around


the earth, the gravitational force
provides the necessary centripetal force.

Formulae 3. Gravitational constant: G= Fr?


m,m,
1. Kepler's formula for planetary motion: 4. Measurement of G using Cavendish balance:
i. Kepler's law of equal areas:
Kestoring torque. t= GM -L=K0
Areal velocity, AA L
= constant
At 2m Where, r=initial distance of separation between
the centres of the large (with mass M) and the
Kepler's law of periods:
neighbouring small (with mass m) sphere,
T°«r' or = Constant K=restoring torque per unit angle and
9 = the angle of twist.
b Ratio of time periods of two planets,
5.
\3/2 Acceleration due to gravity:
On the surface of the earth, g= GM
T,
Where, r = average distance of planet ii
from the Sun. In terms of density, g= pGR
2
Gravitational force:
Variation in acceleration due to gravity:
i. Scalar form: F = Gm,m, i At a height above the earth,
GM GM
Gravitational force between two equal masses, (R +h)
where r=R+h
Gm
F=
ii.
R+h.
iii Vector form: Fx=G"(-,)
iii.
where, i,, =the unit vector from m, to m: ...(For h<<R)
and
force F is directed from m, to m,. iv. Ala depth below the earth,
40
Chapter 05: Gravitation
1 A latitde . g
At cquator,
Hence g- Ro VR+h
Alpoles, e 0° (if g, is not known)
Hence g'g In terms of density of earth (only close to the
Ifcarth stops rotating. then the value of g Surface of earth).
at equator increases by Ro
v.- 2R G
Gravitational potential encrgy of a body:
For body stationary on the carth: where p Density of earth
-GMm
-mgR iv. In terms of escape velocity, v. =É
R
For body revolving around the earth:
11. Weightlessness:
GMm
i. W = m(g+ a)
when lift moves upward with acceleration 'a"
8 Gravitational Potential: ii. W =m(g - a)
1. In terms of potential energy: V=
U when lift moves downward with acceleration 'a
Im iii. W =0

On surface of the earth: V= GM when lift moves as free fall.


R where, W= Weight of the body in the lift
iii. At certain height above the surface of the earth:
12. Time Period of a satellite:
GM
V
At height h from surface of earth,
4n'
9 Escape Velocity: i. T= (R+h)
VGM
For abody stationary on the earth's surface
|2GM (R+h'
a. V =
R
b. ii.
T= 2r GM

R+h
Ve =R 8npG iii. T=2r
V3
For a body revolving around the Earth's surface R
iv. Close to surface of earth, T = 2
at a height h Vg
a b Ve= 2gr
V. Ratio of time periods of two satellites at
different radius of orbits ,
3/2 3/2

R +h,
C
R+h,

10. Critical (orbital) velocity: 13. Binding energy:


J. a When satellite is orbiting close to the i For a body stationary on the Earth,
surface of earth, v, = GM B.E. =
GMm
VR R
b When salellite is orbiting at height h' ii. For a body revolving around the Earth at a
fromthe surface of earth, GMm GMm
|GM
height h, B.E. =
2(R +h) 2
VR h
GM
,rradius of orbit.
14 Potential energy of a body on the Earth's
surface:
In terms of acceleration due to gravity, For a body on the carth's surtace,
-GMm
v, = VgR (whensatellite is orbiting close PE. -mgR
to the surlace of carth)
b. V. = gh (R +h) where For a body revolving around the Earth,
-GMm
P.E. =
g, acceleration due to graviy at height h.
41
of the thenearth to thewhich is
cosmic on compared near satellite
because the in itself orbit the requires
between of height
lts about
essentialwithlie circular.the revolution of
value surfuce surface, orbital
of moon direction. revolving alwavs uroundvelocity velociy
experienced. force
depends
upon
weight sphere,
the
ofcentre from
second depends satellite about complete stationary called
orbits.
parking
the the planet are is zero.same
as molecules.
from moon earth force They
in earth/planet the of orbitalearth
change uctual solid of less s in
north-south
a km
keeping
arerotating
a
orbits revolves is
periodkms ungular
earthhaveorbit.
body called surface for in
the aroundprovides earth.
thegravitational
is velocity on too 7.92 They are 3.08
u the
n) weight projected. atmosphere
gus velocity satelliteto their
lts
The the
w.r.t.
same
masses
no a is is close on satellite relative
us at is dissipated
be is
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planet.
earth only. satellites
and
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hours.
eust. is of
the
will assumed
apparent
of on velocity
orbits
orbital a required satellite
centripetal
very satellite
revolving
satellite also satellite Saltellite
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being of the a as becauseforce.
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is velocity radius velocity velocity are km.
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infinity around
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to Jupiter at will
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their the given h) angular
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it types between to + of It
of of compared R 3RT why mass
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to sum two satellite
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torque velocity
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satellite = Escape
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3. 4. 5. 6. 7. 1.
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29. 30. 31. 33 34. 35. 36. 37. 38 39. 40.
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velocity satellite in north earth. its the from the the Jupiterorbital
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fall in continuethe orbital orbital
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5.8 44. 45. 46. 47. 48. 54
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Gravitation
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going. JK, at assumed 55
path decrease. column in both to of
watch. is earthcentre from by
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and infinity
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Find
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kinetic
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to minimum
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planet,
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radius by by
quantities by by earth,
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inversely
gravity decreases increases v;.
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increases radius
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speed m maximizes
of earth's
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orbit. pendulum
twice 2s
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two m/M 2 force
distance.
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Suppose and and and R. vt then the circular
the are (B) (D) acceleration and
is 10 speed (B) (D) (B) (D)
be keeping 10 into between gravitational
times.
in diameter
second K.E 2% 4% 4% 4% m of (A)
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decreases decreases
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Suppose R"
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70. 71. 72. 73. 74.
R h. is the velocity
planet. under
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is Then of of surlace times
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velocity moremore
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Physics R R R it of height finite the
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R 2 maximum from ol speed
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66. 67. 68 69. 56
05:
Chapter
Gravitation
velocity
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required
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around a same
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Assertion
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explanation57
in is x 10*rad/s
10rad/s
6.7 earth. Assertion with maximum
1.414
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moves a r R
to not Assertion
gravitational True. Assertion True.
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in satellite escape proportional doesremains with is
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explanation
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initial
of explanation
(B)(D) to (D) (B) (D) it the
satellite explanation
aroundadditional km (B)
axis 6400
is gravitational but objectits but
x kinetic the
satellite circular is to then, necessary the weight
influencing the above star
artificial by the True, True, False then is
True, True, True, True,False
3.84
x rad/s planet
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7.4
even theprovided
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is
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the ASsertion Assertion
Assertion Assertion poleWhen Assertion Assertion
Assertion Assertion
I
The
km/s. should but The a then a
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T. R? R2 fuel Reason: earth
required is is physical Reason:
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circular rotation period
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massive between at
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79. 80. 81. 82. 83. 84.
a andthe m mB r. periods of the a centre
mass
can
undergo a surface,
it of of as point
transverse
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thatpathcentre
+)
force andand
r of
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areC.M. (,+)
)
m, MA ratimes
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orbits gravitational
m,G + radii then, gravitational influence
from R
velocity
are the (m, masses
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from
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Its <r<o) in above ellipse diametrically
point
are particles. (D)
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of of TB T) density initialan focus,
measured stars symmetric h
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circular > under (0 height of be
mg rA>m, or r +r)
r(R
mass binary mass minimum would
surfacefarther
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system. (5+r,)
is m,m,G
respectively, in If m
and (if (if
T3 TB a
r<R
for
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spherically a is
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R
particle
a
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of Them, m,G respectively.
of moving > TA>T has r gravitational
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the as
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T: A of of
7$. 76. 77. 78.
A side.thegravitational
Farth.
reaches 10. 20.(D)
(C) (C)30. (C)
40. 50.
(D)(C)
60. (B)
70. (C)(D)
10. 20.30.
(A)(C) (C)60.
40.50. (C)(A)
70. 80.
(B)
one
GM
3) V7.lgR
thefrom R
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when
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(C)29.
(C)39. 49.59.
(D)(B) (B)69.
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29. 39.
(C) (D) (C)(A)
49. 59. 69. (C)
79.
=
Earth (B) (D)
dug
ball, 9. 9.
is the is of
intotheEarthcentre
tunnel (C)18.
(A)(B) (B)(B)
28.38. 58. (C)
48. (D) 68. (A)18. (C)38.
(B)28. (B)(A)
48.58.
(B)68.
(B)78.
(A)
of
dropped
the the
diametrical
velocity /2.5gR 8. 8.
of at VR
potential (B)17.
(A)(C) (D)(B)
27. 37.47. 57.
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67. (C)
7. 17. 27.37.
(B)(D) (C)(B) (B) 67.
47. 57. (A)77.
(C)
is centre
ballThe (A) (C) 7.
A
Answer
Key 16. (B)
(C)(C) 26. 36.
(C) 46. (C)(A)
(B)56. 66. (D)16.
(D)(A) (B)46.
26. 36. (D)56. (D)76.
(B)66. (D)86.
(B)
86.
6. 6.
The
moon).
month
thesatellite
about 5.(A)15. 25.35.
(B)(A) (A)(B)
45. (D)
55. 65.
(C) (A)
5. 15. 25. (A)(D)(D)
(C)(B) (C) 75.
55. 65. (A)85.
(A)
of
35.45.
orbitradius(lunar
the
circularof month
2-2
(D) (A) 14. 24. (B)(A)(A)(A)
(B)(D) (A)14. 24.(D)(A)(A)
(B)(B) 54. (B)(A) 84.
64.74. (B)
the the 32
rotation 34. 44.
(MCQs)half of (B) 34. 44. 54.(B)
63.
64.
4.
revolution 4.
a to lunar 23. (D)
33. (B)(C) (A) 13.
(A)(B) 33.(C) (B)(A)
43. 53. 63. 73.
(B)83.
(A)
in of
cqual (B)(D)
(B)13. 23. (D)
Physics
placcdPeriod
the
3. 43. 53. 3.
radius of of
(A)12.
(C)(B)
Triumph
is orbit. thatperiod
ofn
is (D)(B)
(B)12.22. (B)
32. (B) (B) 62.
42. 52. (C) 22. (B) 42. (A)
32. (B) 52. (B)
62. (C)
72. 82.
(C)
satellite
with times 3/2
moon's the 2. 2.
Homework
MHT-CETFarth n value Classwork
(A) (C)11. (C)S1. (C)71.
(B)61. (A) 21.31.
(D)(B) 51. (C)
61. 71.
A is is (A)21.
(C) (D)
31.41. (D)11.
(D)(B) 41.(C) (C)81.
(C)
1.

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