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Lab No 8

The document describes an experiment to verify the torsion formula and modulus of rigidity experimentally by testing a member with a circular cross-section. The experiment involves applying torque to a specimen, measuring the angle of twist, and using the results to calculate the maximum torsional stress and modulus of rigidity.

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0% found this document useful (0 votes)
23 views4 pages

Lab No 8

The document describes an experiment to verify the torsion formula and modulus of rigidity experimentally by testing a member with a circular cross-section. The experiment involves applying torque to a specimen, measuring the angle of twist, and using the results to calculate the maximum torsional stress and modulus of rigidity.

Uploaded by

Zohaib Stylish
Copyright
© © All Rights Reserved
We take content rights seriously. If you suspect this is your content, claim it here.
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Download as DOCX, PDF, TXT or read online on Scribd
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EXPERIMENT # 08

TO VERIFY EXPERIMENTALLY TORSION FORMULA


AND MODULUS OF RIGIDITY BY TESTING A
MEMBER WITH CIRCULAR CROSS SECTION

OBJECTIVE:

 To verify torsional formula


 To verify modulus of rigidity

THEORY:

TORSION:
Torsion is the twisting of an object caused by a moment acting about the
object’s longitudinal axis. Torsion is the deformation that a torque tends
to produce when applied in the along the longitudinal axis of an object.
Transmission shafts, like drive shaft in axle, are used to transmit power
by rotation.


τ=
J

WHERE:
τ = TORSIONAL STRESS

T = TORQUE
J = POLOR MOMENT OF INERTIA
ρ = DISTANCE FROM THE CENTRE

The maximum torsional stress in a circular cross section is given by:


TR
(τ) max= WHERE R = d/2
J

Moreover, for circular shaft the moment of inertia is given by:


J = π D4 / 32
So the value of max-torsion will become:
(τ) max = 16T / πD^3

MODULUS OF RIGIDITY:

Shear modulus also known as Modulus of rigidity is the measure of the


rigidity of the body, given by the ratio of shear stress to shear strain.
Often denoted by G
G = 𝜏/ γ
σ = -K ε
Where,
K=proportionality constant
σ = stress
ε =strain
Moreover, from above equation it can also be written as:
G = TL / G φ

POLAR MOMENT OF INERTIA:

Polar Moment of Inertia is a measure of an object's capacity to oppose or


resist torsion when some amount of torque is applied to it on a specified
axis. If the polar moment of inertia is of higher magnitude then the
torsional resistance of the object will also be greater.
ANGLE OF TWIST:

Angle of twist: For a shaft under torsional loading, the angle through
which fixed end of a shaft rotates with respect to the free end is called the
angle of twist.. As the torque is increased, the outer region of the shaft
behaves like a plastic material while the inner core is still linear elastic.
φ = TL/JG
Where the angle is always in radians.

APPARATUS AND EQUIPMENT:

 Torsion Testing Machine


 Dial Gauge
 Vernier Calliper
 Ruler
 Weight
PROCEDURE:

FOR TORSIONAL FORMULA


 Measure the length of the specimen by measuring tape
 Measure the diameter of the specimen by Vernier caliper
 Calculate the polar moment of inertia of the sample
 Insert the specimen into the jaws of the torsion testing machine
 Apply the torque and increase it by appropriate increments
 Record the applied torque and the angle of twist
 Plot the torque versus angle graph
GJ T
 Calculate the value of L and θ
 Compute the percentage error

FOR MODULUS OF RIGIDITY


 Measure the diameter of test specimen using vernier callipers.
 Measure the gauge length of the specimen.
 Hold the specimen in between the plates with a dog holder.
 Adjust the circular scale with zero of the vernier scale.
 Torque reading show the value in digital indicator.
 Fracture occurs.
 Plot a graph of torque vs angle of twist and determine the Modulus
of Rigidity.

OBSERVATION:
S.no length diameter torque Angle of
twist
ft in Kip/ft degree
1 3 4 15 1.23

L = 36in d = 4in T = 150 kip-in τ = 0.02 rad

CALCULATIONS:
Maximum torsion stress is given by = 16T / πD^3
= 14.33 ksi

Modulus of rigidity is given by = G = TL / G φ


By putting the values in above equation, we get
G = 12903.5 ksi RESULTS:
S NO (τ)max G (ksi)
1 14.33 12903.5

CONCLUSION:
The above results shows the required values of torsional stress and modulus of
rigidity.

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