Lesson 29
Lesson 29
1 for x > 0 .
(a) Find
1 =
(2x +
3)
a= (21 +
3)
2y
.
x = +
)
1-3 y
=
-
2
f (m) / :
- [3]
19
[1]
[Total: 4]
Find an expression for g(x)-1 and state its domain and range.
1
=
(x 4) -
+
domain 1)
4)
(y
+
x = -
g"(n)
=
x
-
1 =
(y
-
4) range
= 4
y
-
x -
1 =
4=
y 1
=
x
-
[4]
4
y
=
x -
1
[Total: 4]
.
g(x) 4
/
=
=
n -
2
9 -
=
9
9
g(n)a
-
[1]
177
[1]
3
g(5x 2) 45
-
4(5x -
2) 9 45 =
4(5x -
2) =
54
54
(5x 2)2 -
:
54 2
=
-
5x 2
c
= +
x =
j2 +
[3]
[Total: 5]
for ,
.
4
(a) ,
+
y
=
eY -
2
=
[2]
(b) ,
g(i
+ 1) =
m 1)
+ + 2
[2]
(c) .
f(x) 2)
+ =
y
+
2
+
[2]
5
+ (i
: x + 2
1)
+ 3
+ =
- +
1 2 +
x
x))
2
3x +
2 = 1)(2 x) +
= T
2 +
1 3x + 2 = 2(n + (2
Ch
x + 2x -
x
-
2 =
21) 2 + 3)
- +
2 + 1) 2 + 1) x 1 -
2 =
0
2x) 2 + 1)
2)(x 1) 0
+
- (x - + =
2 + 1)
1= 2 Ch = -
34 + 2
(reg)
=
2 +
1)
[4]
[Total: 10]
3 ) a(b)
+ +
+
b = ( (1) + + al -
1) b + = 2
2 +
9 +
3a + b =
-
+
1 -
a +
b =
20
[4]
3a + b =
-
3) -
1
-
a + b =
20 - 2
1 -
2 3a -
( a)- = -
36 -
20
4a = -
5) -
( 14) b
- +
= 20
a =
-
1 b : 20 -
14
b =
6
6
(b) Using your value of a and taking b as 6, find the non-integer roots of the equation
in the form ,where p and q are integers.
f(x) 1 =
+ 1 -
141+ 6
( + 4x) -
2
x + 4x -
2 =
0
x -
)(o
( +
y -
14x +
6
43 - 3) -
45 4" -
4(11) 2) -
7) = .
2()
*
44 -
141
4x2 -
121
47/16
-
= +
8
-
21 +
6
2
-
2x + 6
41 24
-
-
.
= - 41 216
2
= -
27 6
.
[5]
[Total: 9]
2 :
a(l)) 15(1)" b(1)
-
+ -
2 =
15 b2 5
i 3
a
8
+ :
-
+ -
2 :
a + b =
22 2
xj
a -
30 +
4616 :
a+ 46 46 = I
1 -
24b -
b 4) : -
22 a
+
8 =
2)
3b : 2 a = k
b =
0
7
[4]
(b) Using the values of a and b from part (a), express in the form , where is a
quadratic factor to be found.
f(x) =
4x3 -
151 + 0x -
2
L
x -
4x7 + 2
29 -
141" -
15a" + Bi-2 (2x) -
1)(7x -
4x + 2)
14123 7x2
-
8x +
01
-
8x + 41)
4x
-
2
4x -
2
[2]
(c) Show that the equation has only one real root.
(21-19779" 41 2) -
+
=
2x- 1 :
0 79 -
412 + 2 =
Cl =
! b 4a =
( 4) 4(7)(2)
=
1656 [2]
= -
40
[Total: 8]
b" 4al
-
2 k(2)"
+ -
0(2) 0 - =
0 +
41 16 - 8 =
4k =
16
k=
[2]
(b) Using your value of k, find the non-integer roots of the equation f(x) = 0 in the
form , where a and b are integers.
1 44 8n -0
+
=
" +
6114 x 6x
+ +
4 =
x -
2/a t
4, 0x8
"21"
-
6= 6 -
4(1)(4)
=
61x2 -
81 2(1)
6x" -
121)
=
-
61 20
.
4x -
8 2
41 -
8
-
=
-
6= 2/5
=
-
3 = [5
[5]
[Total: 7]
9
[4]
[2]
[2]
[Total: 8]
10
9
The line intersects the curve at the points A and B. The x-coordinate of
A is less than the x-coordinate of B. Given that the point C lies on the line AB such that
AC : CB = 1 : 2, find the coordinates of C.
4 8
16 41
y
= -
=
3 16-412
= 4
4 2
=
4
x)" x
-
((4 -
4(4-1) 21 =
K(4-1
16 -
41217 413-4 :
12 101 +
16 =
I 81(1-2) :
x =
8 1 =
2
1 =
16 4(8)
-
y
:
16 -
4(2)
=
16 32 =
16-8
2)
-
(1
16
,
j
= -
=
& 2
A(2 8) ,
B(8 - 16) ,
2(2) +
1(8) 2(8) 1( 16) +
-
x
y
= =
1 +
2
1 + 2
4 +8
=
=
16-16
3 J
12
I
8
I
=
3 3
14, 0)
[8]
11
[Total: 8]
10 Find the coordinates of the points of intersection of the curve and the line .
5 3
4 + +
-
(5x + 18 3
+j
↓ 3
4 + + =
311+ 2 1
x(3x +
2)
1x(3x 2)1()13(3x 2)
+ + =
124084 +
11941J =
124 1 1813 :
6 0 =
2x + 3x + 1 =
(2x +
1((x +
1) :
a=
21 =
y 1572) 15) 1) 18
=
1
y
+ =
-
+
2 =
=
-
5
(2 2) ( 1 5
-
-
,
,
[6]
[Total: 6]
12
11 Find the coordinates of the points of intersection of the curve and the line .
8 10 x= 9 -
1
=
-
q
Y
-
-
y(9 y)8
-
1019 1) (9 1) 9 ( 15) 6
=
9
-
-
.
x = - -
x =
-
90 9-1 24 S
By
=
101
+ =
=
(24 15) (3 6)
By 9y 10y
90
-
,
1 + -
+ - ,
y 19 90
= :
.
153)y6) 6
4 + :
151
y
: - =
[6]
[Total: 6]
13
12 The line cuts the curve at the points A and B. Find the
length of the line AB.
[7]
[Total: 7]
14
13 (a) On the axes below, sketch the graph of showing the coordinates of the points
where the graph meets the coordinate axes.
1
y
= =
141 -
5 :
y
-
= -
(3x +
1((x -
5) =
=
j
1: -
'y 1 :
5
I
-
5
-
3 + 5
a
=
2 3
: 373) 14(5) -
-
5 :
64
[4]
15
13 (b) Find the exact value of k such that has 3 solutions only.
64
k =
[3]
[Total: 7]
14 (a) Sketch the graph of on the axes below, showing the coordinates of the points where the
graph meets the coordinate axes.
( =
y
=
i =
5(0) -
] [1 3
= -
=
3 51 -
3 =
3
=
j 3
[3]
16
593 = 2() 52 =
(2(
5x2 + 1 = 2+ ) 51 -
3 = 2 + 1)
61 = 5 x 3
(2 - = -
2 +
5
x =
4)) =
6
a= 1
[3]
[Total: 6]
15 (a) Sketch the graph of on the axes below, showing the coordinates of the points where the
graph meets the axes.
1) = 0
y
=
y
4x 2 :
4(0)
-
2
y
= -
43 = 2
=
2 2
17 :
4
1
↳
=
O I x
2
[3]
17
41 -
2 : 1) 4x - 2 =
1)
3 2
2
=
2
1=
3
[3]
[Total: 6]
18
16 Solve .
loge
I
10)
(y
-
=
2
< 1
Y
-
by 2)
2y
10 = - +
1
2.
3y
- 10 : -
4. + 2
"+
4y
-
12 :
(16)(y -
2) =
Yi
[5]
[Total: 5]
19
1) 2
(g(x 192
2)
(g(3x
+ + + =
-
2((x + ) 2
g2(3x
-
=
2(3x 2((x - +
1) :
(3x 2((k 1)
-
+
=
5
3 1312x 2 -
-
50 =
3x + x) -
52 :
(3x +
1)((x -
4) =
= -
1 =
<
[5]
Crej)
[Total: 5]
20
2
(294-15) J
oga
E
&
loga
(29-15)
2og
" 3
ogc
=
logull"
(29-15 3
g
· -
=
.
194-15
:2
ogs ,
291) -
15
= 2
12
29x -
15 =
84
89 29x +
15 0=
(8x -
j((x -
3) =
a =
% () 3
=
[5]
[Total: 5]
21
19
Q
5 cm
0.8 rad P
O R
x cm
The diagram shows a sector OPQ of a circle with centre O and radius x cm. Angle POQ is
0.8 radians. The point S lies on OQ such that OS = 5 cm. The point R lies on OP such that
angle ORS is a right angle. Given that the area of triangle ORS is one-fifth of the area of
sector OPQ, find
(a) the area of sector OPQ in terms of x and hence show that the value of x is 8.837 correct to
4 significant figures,
1030 .
8 =
OR
:
247
50 44)
J 6 .
.
OR 5 COS Dij
=
-
Or =
3 .
48 x
= 6 .
247(5)
0 .
4
6 247(5)
a = .
-0 .
4
1= 8 .
83
[5]
22
[3]
[2]
[Total: 10]
20 The diagram shows a sector, AOB, of a circle centre O, radius 12 cm. Angle AOB = 0.9 radians. The point C
lies on OA such that OC = CB.
23
0.9 rad
O 12 cm B
[2]
[3]
24
[3]
[Total: 8]
21 The number of combinations of n items taken 3 at a time is 6 times the number of combinations of n items
taken 2 at a time. Find the value of the constant n.
[4]
[Total: 4]
25
22 The number of combinations of n items taken 3 at a time is 92n. Find the value of the constant n.
[4]
[Total: 4]
23 Jess wants to arrange 9 different books on a shelf. There are 4 mathematics books, 3 physics books and
2 chemistry books. Find the number of different possible arrangements of the books if
[1]
[2]
26
(c) all the mathematics books are kept together and all the physics books are kept together.
[3]
[Total: 6]
24 Jack has won 7 trophies for sport and wants to arrange them on a shelf. He has 2 trophies for cricket, 4 trophies
for football and 1 trophy for swimming. Find the number of different arrangements if
[1]
27
[3]
(c) the football trophies are to be kept together and the cricket trophies are to be kept together.
[3]
[Total: 7]
28
[4]
[Total: 4]