Differential Equations 2019/20
MA 209
Extra questions from class 5, with partial answers
Question
Suppose the 1-dimensional ODE x0 = f (x) has the following phase portrait:
P
t P
t
P t P
0 x -
(a) Sketch the phase portrait of the ODE x0 = xf (x).
(b) Sketch the phase portrait of the ODE x0 = x2 f (x).
(c) Find a 1-dimensional ODE x0 = g(x) that has an infinite number of stationary points,
and where all stationary points are attractors or repellors.
(d) Find a 1-dimensional ODE x0 = h(x) that has an infinite number of stationary points,
and where all stationary points are shunts.
(e) Find a 1-dimensional ODE x0 = j(x) that has two stationary points, and where both
stationary points are attractors.
Answers/hints:
(a) We have an additional stationary point at x = 0. For x > 0, the sign of xf (x) is the
same as the sign of f (x); for x < 0, the sign of xf (x) is the opposite of the sign of f (x).
So we get the following phase portrait:
P t
P t P
t
P t P
0 x -
(b) We have an additional stationary point at x = 0. But now for all x 6= 0, the sign of
x2 f (x) is the same as the sign of f (x). Hence we get the following phase portrait:
P
t P
t P
t
P t P
0 x -
(c) Many options are possible. The most important observation is that we need a function
f (x) with an infinite number of x for which f (x) = 0, and then make sure it has the right
properties. One option is f (x) = sin(x). Hence taking the ODE x0 = sin(x).
c London School of Economics, 2019
MA 209 Differential Equations Extra questions from class 5, with partial answers — Page 2
(d) Many options are again possible. The most important observation is that we need a
function f (x) with an infinite number of x for which f (x) = 0, and then make sure it
has the right properties. In particular we must make sure that the sign of f (x) is the
same for all non-stationary points. Possibilities are x0 = |sin(x)|, or x0 = sin2 (x), or
x0 = sin(x) + 1.
(e) This is a trick question: such an ODE is not possible. If you try to make a phase portrait
with this property, it is easy to see that you just can’t make it.