Ionic Bonding Bingo Fillers
You will be using these formulas for your bingo cards in class. Just take these compounds and write their
formulas in the bingo cards. Each square on the bingo card will have one of these formulas written in it.
The trick, however, is that some of these compounds exist and some don’t. If you want, you may just randomly
fill in blanks with these formulas. A better choice would be to determine which compounds exist and which
don’t. Then, cross off the ones that are covalent or don’t exist and use the rest to fill in your card (because I
won’t call those).
Here’s an example…
If BaOH and Ba(OH)2 were both on the list, then you would have to figure out the formula of the correct
one. Barium has a +2 charge and hydroxide has a -1 charge. To get the correct formula, you have to use
two hydroxides. The correct formula would be Ba(OH)2. Before filling in the bingo card, you would
cross off the BaOH.
Hint: When you’re done eliminating formulas, you should have twenty-four correct ones left.
KMnO4 Al4(SO4)3 Rb(MnO4)3
ICl Al2(SO4)3 SrAr
Na(NO3)2 Mg(NO2)2 BePO4
NaNO3 MgNO2 N2S4
Co(CN)2 CuHe ZnCrO4
CoCN SnBr4 NeAr
K2O Sn3(PO4)4 NiF2
SrClO32 Rb(OH)2 FePO4
Fe(OH)3 RbOH Fe3(PO4)2
FeOH O2 CuS
Fe(OH)2 Sr(C2H3O2)4 Cu2S
Fe2O3 CF4 KCrO4
PI3 BaSO4 K2CrO4
CuSO4 BaS2 NaS2
Sr(ClO3)2 Ba3SO3 (NH4)4PO4
NH4Br (NH)4Br (NH4)3PO4
Al2S (NH4)Rn
Free
Now, use the
formulas that you
have left to fill in
these two cards.
Remember, one
formula for every
box and don’t
repeat the
formulas
anywhere.
Make sure the two
cards are different
so we can play
different games.
Free