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P2 Memo June 2024-2

The document provides marking guidelines for a Physical Sciences exam consisting of multiple choice and long answer questions on topics of chemistry. It includes the exam questions, expected answers, and number of marks allocated to each part. The marking guidelines contain the full exam paper and scoring rubric.

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0% found this document useful (0 votes)
817 views5 pages

P2 Memo June 2024-2

The document provides marking guidelines for a Physical Sciences exam consisting of multiple choice and long answer questions on topics of chemistry. It includes the exam questions, expected answers, and number of marks allocated to each part. The marking guidelines contain the full exam paper and scoring rubric.

Uploaded by

rinaemudau50
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© © All Rights Reserved
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Physical Sciences/P2 Marking guidelines Grade 10 LDoE June 2024

NSC EXAMINATION

GRADE 10

PHYSICAL SCIENCES: CHEMISTRY (P2)


JUNE EXAM 2024
MARKING GUIDELINES

MARKS: 100

This marking guidelines consists of 5 pages.

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Physical Sciences/P2 Marking guidelines Grade 10 LDoE June 2024

QUESTION 1 (MULTIPLE CHOICE QUESTIONS)

1.1 C  (2)
1.2 A  (2)
1.3 B  (2)
1.4 D  (2)
1.5 D  (2)
1.6 B  (2)
1.7 D  (2)
1.8 C  (2)
1.9 B  (2)
1.10 C  (2)
[20]

QUESTION 2

2.1 An element is a pure substance consisting of only one type of atoms.


 (2)

2.2.1 Sodium chloride  (1)


2.2.2 Copper wire  (1)
2.2.3 Iron  (1)
2.2.4 Glass/table salt  (1)
2.2.5 Air/Brass  (1)
[7]

QUESTION 3

3.1 Temperature is the measure of the average kinetic energy of the


particles in a substance.  (2)
3.2 30 ⁰C  (1)
3.3.1 30 – 40 minutes  (1)
3.3.2 0 – 5 minutes  (1)
3.3.3 5 – 10  and 20 – 30 minutes  (2)
3.3.4 During a phase change heat energy supplied is used to
overcome the intermolecular forces.  Therefore the average
kinetic energy of the particles remains the same. (1)
[8]

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Physical Sciences/P2 Marking guidelines Grade 10 LDoE June 2024

QUESTION 4
4.1.1 Atoms of the same element having the same number of protons but
different number of neutrons. 
OR
Atoms have the same atomic number but different mass numbers. (2)

4.1.2 Relative atomic mass = (69.5252 x 60.4)  + (70.9249 x 39.6) 
100
= 70.08  (3)
4.1.3 Ga  (1)
4.2 4.2.1 13  (1)
4.2.2 13  (1)
4.2.3 13  (1)
4.2.4 10  (1)
4.2.5 27  (1)
4.3.1 8  (1)
4.3.2 Period 3  (1)
4.3.3 3  (1)
4.3.4 Ar  (1)
4.4 Ionic  (1)
4.5

(3)
4.6

(4)

4.7 Electronegativity is the tendency of an atom in a molecule  to attract (2)


electrons towards itself 
4.8 Electronegativity of Al = 1,5  (3)
Electronegativity of C = 3,0 
Difference in electronegativity = 3,0 – 2,5 = 1,5 
[28]

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Physical Sciences/P2 Marking guidelines Grade 10 LDoE June 2024

QUESTION 5

5.1 5.1.1 Sharing of electrons between atoms to form molecules.  (2)


5.1.2 CH4(g) + 2O2(g) → 2H2O(l) + CO2(g)  balancing  (3)
5.2 5.2.1 NaCl  (Correct ratio) (2)
5.2.2 Transfer of electrons to form cations (positive ions) and
anions (negative ions) that attract each other to form a
formula unit.  (2)
5.2.3 Carbon dioxide.  (1)
[9]

QUESTION 6

6.1 Chemical change  (1)


6.2 • Change in which new substances are formed.  ( The bond
between H and O in H2O2 are broken and new bonds
between H and O to form H2O and between O and O are
formed to form O2) 
• Energy change are much larger than those of physical
change. 
• Mass and atoms are conserved, but the number of molecules
is not. 
ANY TWO (2)
6.3 2H2O2  → 2H2O + O2  balancing  (3)
6.4 It was a catalyst.  (1)
6.5 2H2O2 → 2H2O + O2
2[(1 x 2) + (2 x 16)]  : 2[(2 + 16) + (2 x 16)] 
68 g : 68 g
68 g = 68 g  (3)
6.6 Decomposition  (1)
[11]

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Physical Sciences/P2 Marking guidelines Grade 10 LDoE June 2024

QUESTION 7
7.1 7.1.1 The amount of substance having the same number of (2)
particles as there are atoms in 12 g carbon-12. 
7.1.2 Calcium chloride.  (1)
7.1.3 Number of atoms = n x NA 
= 3 x 6,022 x 1023 
= 1.81 x 1024 atoms  (3)
7.2 7.2.1
2Na + C2  →2NaC  (2)

7.2.2 Ratio:
2n(NaC) = 6
6
n(NaC) = 2
n(NaC) = 3 mol 
𝑚 (4)
n(NaC) = 𝑀 
𝑚
3= 
58,5
m = 175,5 g 

7.2.3 Ratio:
2n(C) = 3
3
2n(C) = 2
2n(C) = 1,5 mol 
𝑉 (4)
n(C) = 𝑉 
𝑚
𝑉
1,5 = 22,4 
V = 33,6 dm3 
[16]
TOTAL = 100

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