Revision Mid-Term 2019
Revision Mid-Term 2019
Manufacturing definition
It is the application of physical and chemical processes to alter the geometry, properties of a given material to
make product.
Importance of manufacturing
Material Types
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Metals
A metal is a category of materials generally characterized by properties of ductility, malleability, luster, and high
electrical and thermal conductivity.
Metals
Ferrous Non-Ferrous
based of iron steel all other metals
ex: Cast iron, Steel Aluminum, Magnesium, Copper
Steel: an iron-carbon alloy containing from 0.02% to 2.1% carbon.
Cast iron: an iron-carbon alloy containing from 2.1% to about 4% or 5% carbon.
Parameter Low carbon steels Medium carbon steels High carbon steels
Carbon contain less than 0.20% range between 0.20% and contain carbon in amounts
content C 0.50% C greater than 0.50%
automobile sheet metal machinery components and springs, cutting tools and
Applications parts, plate steel for engine parts such as crankshafts blades, wear-resistant parts
fabrication, railroad rails and connecting rods
Classification of Manufacturing processes
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Shaping processes
Solidification
Heating material → becomes liquid → Pouring → Solidification
Ex: casting
Particulate
Powdered material → applying pressure → product
Ex: any powdered material
Deforming
Material → force exceeds the yield → deformed material
Ex: extrusion and forging
Material removal
Ex: turning, drilling, and milling
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Lecture 2
Physical and mechanical properties
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Tensile properties
a force is applied that pulls the material, tending to elongate it and reduce its diameter.
Curve
𝐹 𝐹
𝜎= 𝜎=
𝐴0 𝐴
Stress F: Applied tension force. F: Applied tension force.
A0: Original cross-section area. A: Instantaneous cross-section area
Stress unit is: N/mm2 (MPa.) Stress unit is: N/mm2 (MPa.)
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Parameter Engineering stress-strain True stress-strain
𝐿 − 𝐿0 𝐿
𝜖= 𝜖 = ln ( )
𝐿0 𝐿0
L: Specimen length at certain L: Specimen length at certain section.
Strain
section. L0: Original length (Gage length).
L0: Original length (Gage
length).
𝐿𝑓 − 𝐿0 𝐿𝑓 − 𝐿0
𝜖𝑡𝑜𝑡 = × 100 𝜖𝑡𝑜𝑡 = × 100
𝐿0 𝐿0
Elongation % It measures ductility Lf: Length at fracture (Final length).
Note: it is applicable only in elastic
region.
Area reduction does not be 𝐴0 − 𝐴𝑓
accounted in engineering stress- 𝐴𝑅 = × 100
Area 𝐴0
reduction % strain. Af: Area at fracture, A0: Original area.
It measures ductility also.
Hooke’s Law
𝜎 = 𝐸𝜖
It is applied only in elastic region where the stress is directly proportional to the strain.
The relation between stress and strain is straight line has modulus of elasticity, which measures the stiffness of
the material, as a slope.
Stiffness
It is the rigidity of an object.
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Ductility
The ability of a material to plastically strain without fracture.
smaller toughness-
unreinforced
polymers
Ex
A tensile test specimen has a starting gage length = 50 mm and a cross-section area = 200mm2. During the test,
the specimen yields under a load of 32000 N (this is the 0.2% offset) at a gage length of 50.2 mm. The maximum
load of 65000 N is reached at a gage length of 57.7mm just necking begins, Final fracture occurs at a gage length
of 63.5mm.
Determine:
a. Yield strength b. Modulus of elasticity
c. Tensile strength d. Engineering strain at max. load
e. Elongation percent
Given 𝐿0 = 50 𝑚𝑚
𝐴0 = 200 𝑚𝑚2
𝐹𝑦 = 32000 𝑁
𝐿𝑦 = 50.2 𝑚𝑚
𝐹𝑚𝑎𝑥 = 65000 𝑁
𝐿𝑚𝑎𝑥 = 57.7 𝑚𝑚
𝐿𝑓 = 63.5 𝑚𝑚
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Required 𝜎𝑦 , 𝐸 , 𝜎𝑚𝑎𝑥 , 𝜖 @ 𝐹𝑚𝑎𝑥 , 𝑒 (%)
Solution 𝐹𝑦 32000 𝑁
𝜎𝑦 = = = 160 N/mm2 = 160 𝑀𝑃𝑎 (Ans. a)
𝐴0 200 𝑚𝑚2
Δ𝜎 𝜎𝑦 −0 𝜎𝑦 −0 160
𝐸= =𝜖 = 𝐿𝑦 −𝐿0 = 50.2−50 = 80000 𝑀𝑃𝑎 =
Δ𝜖 𝑦 −0.002 ( )−0.002 ( )−0.002
𝐿0 50
80 𝐺𝑃𝑎 (Ans.b)
𝐹𝑚𝑎𝑥 65000 𝑁
𝜎𝑚𝑎𝑥 = = 200 𝑚𝑚2 = 325 𝑀𝑃𝑎 (Ans. c)
𝐴0
𝐿𝑚𝑎𝑥 −𝐿0 57.7−50
𝜖𝑚𝑎𝑥 = = = 0.154 (Ans. d)
𝐿0 50
𝐿𝑓 −𝐿0 63.5−50
𝑒= × 100 = × 100 = 27 % (Ans. e)
𝐿0 50
Hardness
It is resistance to permanent indentation. Good hardness generally means that the material is resistant to scratching
and wear.
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Lecture 3
Metals can be classified as illustrated in lecture 1
Reasons of importance of metals
• High stiffness and strength.
• More tough than other classes of materials.
• Good electrical conductivity.
• Good thermal conductivity.
• Low cost compared with other materials.
Alloy
A mixture or compound of two or more elements, at least one of which is metallic using to improve the mechanical
properties like toughness, strength and hardness.
Solid Solutions:
A solid solution is an alloy in which one element is dissolved in another to form a single-phase structure. In a
solid solution, the solvent or base element is metallic, and the dissolved element can be either metallic or
nonmetallic
Phase:
Any homogeneous mass of material, such as a metal in which the grains all have the same crystal lattice structure.
Phase Diagram: a phase diagram is a graphical means of representing the phases of a metal alloy system as a
function of composition and temperature.
Binary phase diagram: phase diagram of an alloy Consists of 2 elements
Copper-Nickel Phase Diagram
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Determining Chemical Compositions of Phases
Ex:
Determine the proportions of liquid and solid phases for the 50% nickel composition of the copper–nickel system
at the temperature of 1260 oC (2300 oF).
Solution
The proportion of liquid phase present is given by:
Using the same horizontal line in the Figure, the distances CS and CL are measured as 10 mm and 12 mm,
respectively. Thus, the proportion of the liquid phase is 10=22 ¼ 0.45 (45%), and the proportion of solid phase is
12=22 ¼ 0.55 (55%).
Plain Carbon Steels
▪ Strength of plain carbon steels increases with carbon content, but ductility is reduced
▪ High carbon steels can be heat treated to form martensite, making the steel very hard and strong
Parameter Low carbon steels Medium carbon steels High carbon steels
contain less than 0.20% range between 0.20% and contain carbon in
Carbon content C 0.50% C amounts greater than
0.50%
automobile sheetmetal machinery components springs, cutting tools and
parts, plate steel for and engine parts such as blades, wear-resistant
Applications
fabrication, railroad crankshafts and parts
rails connecting rods
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Properties and Applications
1. High electrical and thermal conductivity
2. Excellent corrosion resistance due to formation of a hard-thin oxide surface film
Aluminum 3. Very ductile metal, noted for its formability
4. Pure aluminum is relatively low in strength, but it can be alloyed and heat treated to compete
with some steels, especially when weight is taken into consideration
1. Low electrical resistivity - commercially pure copper is widely used as an electrical conductor
2. Also, an excellent thermal conductor
3. One of the noble metals (gold and silver are also noble metals), so it is corrosion resistant
Its Alloys:
Copper
Bronze - alloy of copper and tin (typical 90% Cu, 10% Sn)
Brass - alloy of copper and zinc (typical 65% Cu, 35% Zn).
Highest strength alloy is beryllium-copper (only about 2% Be), which can be heat treated to high
strengths and used for springs
1. Coefficient of thermal expansion is relatively low among metals
2. Stiffer and stronger than Al
3. Retains good strength at elevated temperatures
Titanium
Used for:
aerospace applications where its light weight and good strength-to-weight ratio
used for corrosion resistant components, such as marine components and prosthetic implants
dense, low melting point; low strength, low hardness, high ductility, good corrosion resistance
Lead Applications: solder, bearings, ammunition, type metals, x-ray shielding, storage batteries, and
vibration damping
lower melting point than lead; low strength, low hardness, good ductility
Tin
Applications: solder, bronze, "tin cans" for storing food
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Lecture 4
Sand casting mold
Gating system
Channel through which molten metal flows into cavity from outside of mold.
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Solution
Here, illustrative schematic sketch for the sprue and the molten metal flow
𝑚3
𝑄 = 0.01 60 𝑠 → 1.66667 × 10−4 𝑚3 /𝑠
Let’s denote the sprue top and the sprue down with 1 & 2 respectively.
1.66667×10−4
From continuity equation: 𝑄 = 𝐴𝑉 → 𝐴1 𝑉1 = 𝐴2 𝑉2 → 𝑉1 = 𝜋
(20×10−3 )2
= 0.530516 𝑚/𝑠 → (1)
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𝜋
Since 𝐴 = 𝑑2
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Then, we have 2 unknows (𝑉2 & 𝐴2 ), so we need one more extra equation which is “Bernoulli’s Eqn”
𝑃1 𝑉12 𝑃2 𝑉22
+ + ℎ1 = + + ℎ2 + 𝑓𝑟𝑖𝑐𝑡𝑖𝑜𝑛
𝜌𝑔 2𝑔 𝜌𝑔 2𝑔
Assume that 𝑃1 ≅ 𝑃2 and neglect the friction and the datum of h is at h2.
𝑄 4𝑄
∴ 𝐴2 = 𝑉 → 𝑑2 = √𝜋𝑉 = 0.018 𝑚 →≅ 18 𝑚𝑚 (the diameter to avoid the aspiration)
2 2
Solidification of metals
Solidification of alloys (a) and of pure metals (b)
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Solidification time
It is a time required for the casting to solidify after pouring and it is calculated form Chovernov’s rule
𝑉 𝑛
𝑇𝑆𝑇 = 𝐶𝑚 ( )
𝐴
V: mold volume.
A: casting surface area.
n: empirical exponent (~ 2)
Cm: mold constant depends on: mold material – casting thermal properties – how far pouring temperature from
milting point.
Shrinkage in solidification and cooling
Shrinkage of a cylindrical casting during solidification and cooling: (0) starting level of molten metal immediately
after pouring; (1) reduction in level caused by liquid contraction during cooling; (2) reduction in height and
formation of shrinkage cavity caused by solidification shrinkage; and (3) further reduction in height and diameter
due to thermal contraction during cooling of the solid metal. For clarity, dimensional reductions are exaggerated
in our sketches.
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Riser
Reservoir in the mold which is a source of liquid metal to compensate for shrinkage of the part during
solidification
▪ The riser must be designed to freeze after the main casting in order to satisfy its function.
▪ Since the geometry of the riser is normally selected to maximize the V/A ratio, this allows riser volume
to be reduced to the minimum possible value
Core vs pattern
Core
Buoyancy in casting
During pouring, buoyancy of the molten metal tends to displace the core, which can cause casting to be
defective.
Fb = Wm – Wc
Fb: Buoyancy force.
Wm: weight of molten metal displaced
Wc: weight of the core.
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Lecture 5
Metal Casting
Cycle in cold-chamber casting: (1) with die closed and ram withdrawn, molten metal is poured into the chamber.
(2) ram forces metal to flow into die, maintaining pressure during cooling and solidification.
Advantages Limitations
Economical for large production quantities Generally limited to metals with low metal
points
Rapid cooling provides small grain size and Part geometry must allow removal from die
good strength to casting
Good accuracy and surface finish
Thin sections are possible
Centrifugal Casting:
A family of casting processes in which the mold is rotated at high speed so centrifugal force distributes molten
metal to outer regions of die cavity
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Lecture 6
Metal Forming
Metal forming processes are deformation processes in which applied loads cause plastic (permanent) strains. The
ability to form metals increases with the increase of its ductility.
True Stress-Strain Curve
True stress-strain curve for a typical metallic material is shown
Strain hardening means that the metal is becoming stronger as strain increases.
Material Behavior in Metal Forming
In plastic region, metal's behavior is expressed by the flow curve
𝜎 = 𝑘 𝜖𝑛
k = strength coefficient; and n = strain hardening exponent
Flow Stress: Instantaneous value of stress required to continue deforming the material
𝑌𝑓 = 𝑘 𝜖 𝑛
where Yf = flow stress, that is, the yield strength as a function of strain
Average Flow Stress:
𝑘 𝜖𝑛 𝑌𝑓
𝑌̅𝑓 = =
𝑛+1 𝑛+1
Where 𝑌̅𝑓 = average flow stress; and = maximum strain during deformation process.
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Hot Working vs. Cold Forming
Rolling Extrusion
Deformation process in which work thickness is Compression forming process in which work metal
reduced by compressive forces exerted by two is forced to flow through a die opening to produce a
opposing rolls desired cross-sectional shape
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Rolling Extrusion
Direct
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Rolling Extrusion
2. Grain structure and strength enhanced in cold
and warm extrusion
3. Close tolerances possible, especially in cold
extrusion
4. In some operations, little or no waste of material
Ao
Extrusion ratio rx = Af
Ao = initial cross-section area of the billet.
Af = final cross-section area of the billet.
Draft= D=t0-tf
Reduction=r=D/ t0
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