Practice Paper - Atomic Radius

MASTERS Periodic Table 1 C

1. The correct order of atomic size of C, N, P, S 6. Arrange in the increasing order of atomic radii
follows the order - of the following elements O, C, F, Cl, Br -
(A) N < C < S < P (A) F < O < C < Cl < Br
(B) N < C < P < S (B) F < C < O < Cl < Br
(C) C < N < S < P (C) F < Cl < Br < O < C
(D) C < N < P < S (D) C < O < F < Cl < Br
2. Match list-I with list-II and select the correct 7. The correct order of size would be -
answer using the codes given below - (A) Ni < Pd ~ Pt
List-I List-II (B) Pd < Pt < Ni
Ion Radius (in pm) (C) Pt > Ni > Pd
(I) Li+ (a) 216 (D) Pd > Pt > Ni
(II) Na+ (b) 195 8. Which group of atoms have nearly same atomic
(III) Br– (c) 60 radius
(IV) I– (d) 95 (A) Na, K, Rb, Cs
Codes : (B) Li, Be, B, C
I II III IV (C) Fe, Co, Ni
(A) a b d c (D) F, Cl, Br, I
(B) b c a d 9. In the ions P3–, S2– and Cl– the increasing order
(C) c d b a of size is -
(D) d c b a (A) Cl– < S2– < P3–
3. The ionic radii of N 3–, O 2– and F – are (B) P3– < S2– < Cl–
respectively given by - (C) S2– < Cl– < P3–
(A) 1.36, 1.40, 1.71 (D) S2– < P3– < Cl–
(B) 1.36, 1.71, 1.40 10. Atomic radii of Fluorine and Neon in Angstrom
(C) 1.71, 1.40, 1.36 units are given by -
(D) 1.71, 1.36, 1.40 (A) 0.72, 1.60
4. The screening effect of d-electrons is - (B) 1.60, 1.60
(A) Equal to the p-electrons (C) 0.72, 0.72
(B) Much more than p-electrons (D) None of these
(C) Same as f-electrons 11. Which of the following has largest radius -
(D) Less than p-electrons (A) 1s2, 2s2, 2p6, 3s2
5. In which of the following compounds manganese (B) 1s2, 2s2, 2p6, 3s2, 3p1
show maximum radius - (C) 1s2, 2s2, 2p6, 3s2, 3p3
(A) MnO2 (D) 1s2, 2s2, 2p6, 3s2, 3p5
(B) KMnO4 12. Arrange the elements in increasing order of
(C) MnO atomic radius Na, Rb, K, Mg -
(D) K3[Mn(CN)6] (A) Na < K < Mg < Rb
(B) K < Na < Mg < Rb
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 MASTERS Periodic Table 2 C
(C) Mg < Na < K < Rb 16. Consider the isoelectronic series :
(D) Rb < K < Mg < Na K+, S2–, Cl– and Ca2+, the radii of the ions
13. Which of the following sequences is correct for decrease as -
decreasing order of ionic radius - (A) Ca2+ > K+ > Cl– > S2–
(A) Se–2 > I– > Br– > O–2 > F– (B) Cl– > S2– > K+ > Ca2+
(B) I– > Se–2 > O–2 > Br– > F– (C) S2– > Cl– > K+ > Ca2+
(C) Se–2 > I– > Br– > F– > O–2 (D) K+ > Ca2+ > S2– > Cl–
(D) I– > Se–2 > Br– > O–2 > F– 17. Which of the following is not isoelectronic
14. The order of size is - series-
(A) S–2 > Cl– > O–2 > F– (A) Cl–, P3–, Ar
(B) Cl– > S–2 > O–2 > F– (B) N3–, Ne, Mg+2
(C) S–2 > O–2 > Cl– > F– (C) B+3, He, Li+
(D) S–2 > O–2 > F– > Cl– (D) N3–, S2–, Cl–
15. Arrange the following in order of increasing 18. In the isoelectronic species the ionic radii (Å)
atomic radii Na, Si, Al, Ar - of N3–, Ne and Al+3 are respectively given by
(A) Na < Si < Al < Ar (A) 1.36, 1.40, 1.71
(B) Si < Al < Na < Ar (B) 1.36, 1.71, 1.40
(C) Ar < Al < Si < Na (C) 1.71, 1.40, 1.36
(D) Na < Al < Si < Ar (D) 1.71, 1.36, 1.40

Atomic Radius
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18
A C C D C A A C A A A C D A B C D C

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