Practice Paper-3
Practice Paper-3
Mathematics 9. The ratio of cost price and selling price is 17. Om, Jai and Jagdish rented a field for the
5 : 4, then find the loss percentage. whole year in ` 500 for grazing cow. Om
1. The sum and the difference of two put to graze 15 cows for 6 months and Jai
numbers are 45 and 15 respectively, then (A) 20% (B) 25% 12 cows for 5 months. If Jagdish put to
find the smaller number. (C) 40% (D) 50% graze 25 cows for 4 months, then what
rent should Jagdish have to pay ?
(A) 13 (B) 14 10. If the cost price of 18 articles is equal to
(A) ` 200 (B) ` 250
(C) 17 (D) 15 the selling price of 15 articles, then find
(C) ` 220 (D) ` 240
the profit percent.
2. The ratio of two numbers is 4 : 5 and sum 18. Calculate the amount on ` 20,000 for 2
of these numbers is 90. Find their H.C.F.: (A) 15% (B) 20% years at 10% rate of interest compounded
(A) 10 (B) 4 (C) 25% (D) 18% annually.
11. The volume of a cubical dice is 8 cubic (A) ` 42,200 (B) ` 24,200
(C) 5 (D) 9 (C) ` 22,400 (D) ` 24,100
cm. What will be the measure of the
3. The average income of 40 persons is diagonal of that die ?
Direction (Q. No. 19 to 20)
` 4200 and the average income of other 35
(A) 2 3 cm (B) 3 2 cm
persons is ` 4000. The average income of Study the pie chart give below and answer
the questions :
whole group is : (C) 2 cm (D) 3 cm
1 12. A can do one-third of a work in 5 days
(A) ` 4100 (B) ` 4106 and B can do 40% of work in 10 days,
3
then in how many days will A and B
2 1
(C) ` 4106 (D) ` 4108 together complete the work ?
3 3
81 29
(A) days (B) days
4. If side of a square is increased by 10%, 7 4
then what percent will area of square be
increased ? 75 19. If the miscellaneous expense is ` 6,000,
(C) days (D) 10 days
(A) 20 (B) 11 8 then what will be the advertising ex-
13. A person walks the first part of distance at pense ?
(C) 121 (D) 21 a speed of 64 km@hr and second part at a (A) `9,000 (B) `27,000
5. In how many years an amount will give speed of 80 km@hr. What is his average (C) `1,33,333 (D) `15,000
the double interest of the amount at 5% speed ? 20. If the cost of printing is ` 17,500, then
interest per annum ? what will be the royalty ?
(A) 72 km@hr (B) 71 km@hr
(A) 25 years (B) 40 years (A) `7,500 (B) `15,000
(C) 71.11 km@hr (D) 70 km@hr (C) `3,500 (D) `750
(C) 30 years (D) 45 years 14. If 272n–1 3
= (243) , then find the value of 21. If 2 is a zero of the polynomial p(x) = 4x2
6. The value of 2 − [3 − (4 − 2 − 3)] will be : n: + 2x – 5a, then value of a is :
(A) 2 (B) 6 (A) 3 (B) 6 (A) 5 (B) 4
(C) 7 (D) 9 (C) 5/4 (D) – 4
(C) 1 (D) 4
15. A milkman professes to sell his milk at 22. Two straight lines AB and CD cut each
7. If product of two numbers is 320 and
cost price but he mixes it with water and other at point O. If ∠AOC = 50º, then
their ratio is in 1 : 5, then what will be ∠BOC = ?
thereby gains 10%. Now, what will be the
difference of their squares ?
ratio of milk and water in that mixture ?
(A) 1356 (B) 1024
(A) 1 : 9 (B) 9 : 1
(C) 635 (D) 1536 (C) 1 : 10 (D) 10 : 1
8. By which smallest number should 5808 16. A coin is tossed twice, the probability of
be multiplied so that it becomes a perfect getting head both times is :
square ?
(A) 12 (B)
1
4
(A) 40º (B) 50º
(A) 2 (B) 7
1 3 (C) 140º (D) 130º
(C) 11 (D) 3 (C) (D)
3 4
440 CUET General Test Final Revision
23. In fig. below, ABCD is a parallelogram Statement : Luck always favours the
Answer Figures
in which ∠DAB = 75° and ∠DBC = 60°, brave people.
then ∠BDC is equal to : Conclusions :
D C I. People who take risk in their life get
many opportunity to become successful.
II. Timid people are never lucky.
75º 60º 37. If – denotes +, + denotes ×, ÷ denotes –,
(A) only I follows
A B × denotes ÷, then 27 + 3 ÷ 6 + 9 – 8 = ?
(B) only II follows
(A) 15 (B) 14·5
(A) 75º (B) 60º (C) Both I and II follow
(C) 35 (D) 3·5
(C) 45º (D) 55º (D) Neither I nor II follows
31. Arrange the following words as per order 38. Read the following information carefully
24. If the circumference of a circle is equal to in the English dictionary : and answer the questions given below :
the perimeter of square, then what is the
ratio of their areas ? 1. Range 2. Rain
Eight persons A, B, C, D, E, F, G and H
3. Rein 4. Ranger are sitting in the circular table all facing
(A) 22 : 7
(B) 7 : 22
(A) 2, 1, 4, 3 (B) 2, 4, 3, 1 the centre of the table. All the people are
(C) 14 : 11 (D) 11 : 7 (C) 2, 3, 4, 1 (D) 2, 1, 3, 4 not necessary to be in the same order.
25. From a cube of side 6 cm, a sphere of 32. From the given Answer Figures, select A sits second to the left of B. Only two
maximum volume is cut out. Find the the figure in which the Question Figure people sit between G and F, who is an
volume of the remainder. is embedded. immediate neighbour of B. More than
Question Figure two persons sit between H and D in both
(A) 216 – 12π
clockwise and anticlockwise direction.
(B) [27 – (2π/3) × 6)] D is not an immediate neighbour of A.
E is not an immediate neighbour of G. A
(C) 216 – 18π does not face E. E does not sit second to
(D) 36 – (3π/2)
Answer Figures the right of F.
Solutions
Mathematics 4. (D) Let, side of square = x m. 7. (D) Let that two numbers are x and 5x
Area of square = x2 sq. m. respectively.
1. (D) By Mean Method,
Sum New side on increasing the length
According to the question,
Mean of numbers = x × 5x = 320
2 by 10%
110 x 5x2 = 320
45 =
= 22.5 100 x2 = 64
= 2
11x x=8
15 =
Mean of difference = = 7.5 10 Difference of squares of numbers,
2
So, larger number = 22.5 + 7.5 = 30 Area =
11x 11x
× = (5x)2 – x2
and smaller number = 22.5 – 7.5
10 10 = 24x2
= 15 121x 2 = 24 × 82
=
2. (A) Let, the two numbers be 4x and 5x. 100 = 1536
According to the question, 121x 2 8. (D) 5808 = 2 × 2 × 2 × 2 × 3 × 11 × 11
4x + 5x = 90 − x2 So, the required number to make
100
9x = 90 Increment % = × 100
perfect square = 3
x2
x = 10 9. (A) Let, that
21
Required numbers = 4 × 10, 5 × 10 = × 100 = 21%
100 S.P. = 5x
= 40 and 50 and C.P. = 4x
5. (B) Here,
10 40, 50 5x − 4x
Let, principal = P Loss % = × 100
4, 5 5x
S.I. = 2P
H.C.F. =10
According to the question, 1
= × 100 = 20%
3. (C) According to the question, 5
P×5×T
40 × 4200 + 35 × 4000 100 = 2P
10. (B)
Required profit %
40 + 35 200
T= = 40 years 18 − 15
5 = × 100
168000 + 140000 15
= 6. (D) 2 − [3 − (4 − 2 − 3)]
75 3
308000 = 2 – [3 – (4 – (– 1))] = × 100
= 15
= 2 – [3 – (4 + 1)]
75
= 2 – [3 – 5] = 20%
2
= ` 4106 = 2 – (– 2) = 2 + 2 = 4 11. (A) A.T.Q.,
3