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0% found this document useful (0 votes)
61 views5 pages

Quize PDF

assignment
Copyright
© © All Rights Reserved
We take content rights seriously. If you suspect this is your content, claim it here.
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MASD1021 – Mathematics

Test 3 – Angles, Triangles and Trigonometry

Student Name: _____Ali Manoor Hoessini_________________________________

Student Number: ____4609400________________________________

Total: /32

Instructions:

 Please print clearly – I cannot mark what I cannot read.


 Show all your work, including all formulae, steps, logic and calculations used to
obtain your solutions.
 Do not round values in the middle of your calculations.
 Show all answers as unrounded values.
 Only round final answers when required by the question.
 All final answers must include units where possible.

1. Solve for the missing angle x.

56º x 85º

𝑥 = 1800 − (850 + 560 ) = 390

2. Solve for angles a, b, and c.

b
45º
a
c
2700
𝑎 = 450 𝑏 = 𝑐 = 3600 − (450 + 450 ) = 2700 = = 1350
2
3. Are the following angles complimentary? YES / NO (circle one)

60º 21º

4. Determine the missing angles and side lengths in the following triangle. Round
side lengths to 2 decimal places if necessary.

c a

42º

b
a=_420______________ A= 42º

b=_480_______________ B=_1800-(420+900)=480___________

c=__900______________ C= 90º

5. Determine the missing angles and side lengths in the following triangle. Round
side lengths to 2 decimal places if necessary.
b

a= 13 ft A=_____________
b=_15.19________ B=_____________

c= 20 ft C= 90º

𝑏 2 = 𝑐 2 − 𝑎2 ⇒ 𝑏 = √𝑐 2 − 𝑎2 = √202 − 132 = √400 − 169 = √231 = 15.19


15.19 13
𝐶 = 900 𝑏 = 𝑎𝑟𝑐𝑡𝑔 ( ) = 49.440 𝑎 = 𝑎𝑟𝑐𝑡𝑔 ( ) = 40.550
13 15.19
𝑎 + 𝑏 + 𝑐 = 900 + 49.440 + 40.550 ≈ 1800

6. A roof has a roof pitch of 5/12 and a run of 15 ft 6 in. What is the height of the
roof, the length of the roof and the slope? Give your length answers (x & y) as
measurable quantities to the nearest 16th of an inch and roof slope (RS) to 1
decimal place. (there are 3 values to calculate)

X 12

Y 5

RS

15’ 6”

𝑐 2 = √52 + 122 = √25 + 144 = √169 = 13

15′6" 𝑦 ′
15′ 6" ∗ 5 1"
= ⇒ (𝑦 ∗ 12 = 15 6*5 ) /12⇒ y = = 77.5=77
12 5 12 2
2
2 2
1"
𝑅𝑆 = 15′6" + 77 ⇒ 𝑅𝑆 = √1862 + 77.52 = √40602.25 = 201.5"
2
7. Find the stud lengths a and b expressed as a measurable quantity, based on the
following diagram:

12
4

76-1/2” a b

16” 16”

𝑎 16" 4 ∗ 16" 1" 7"


= ⇒𝑎= = 5.33 ⇒ 𝑎 = 76 − + 5.33=81.83 = 81
4 12" 12 2 8
𝑏 16" 4 ∗ 16" 1"
= ⇒𝑏= = 5.33" ⇒ 𝑏 = 76 − + 5.33" + 5.33" = 87.16"
4 12" 12 2
8. Determine the missing angles and side lengths of the following triangle. Round
all answers to 2 decimal places if necessary.

5 ft

according the triangle if the side is equal so a^ = b^

𝑎^ + 𝑏 ^ = 1802 𝑎=𝑏 ⇒ 𝑎 + 𝑎 + 90 = 1800 2𝑎 + 90 = 1800 2𝑎 = 180 − 90

90
𝑎= ⇒ 𝑎 = 450 ⇒ 𝑎 = 𝑏 = 450 𝑎 = 450 𝑏 = 452
2

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