Ch1 Electrical
Ch1 Electrical
General Overview
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Details on the Electric Drives Course
Electric Drives course details :
• Session 1 (2h): Introduction & Overview
• Session 2 (2h): DC Drives
• Session 3 (2h): AC Drives: Basics & Scalar Control
• Session 4 (2h): Field Oriented Control
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Table of Contents
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Concept of Electric Drives - Basics
𝑽𝑽 𝝎𝝎
PWM 𝝎𝝎𝒎𝒎𝒎𝒎𝒎𝒎𝒎𝒎
𝑪𝑪𝑪𝑪𝑪𝑪𝑪𝑪𝑪𝑪𝑪𝑪𝑪𝑪𝑪𝑪𝑪𝑪
𝑽𝑽𝒎𝒎𝒎𝒎𝒎𝒎𝒎𝒎
Objectives
• Controlling the dynamics of the machine: Speed, Position, Voltage, Current, Torque…
• Providing Electronic Commutation
• Motors Starting and Protection Circuitry
• Adjusting the input (Source) to meet the Output (Load) requirements
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Concept of Electric Drives – Basic Methodology
I use power
I want to electronic to obtain
change variable voltage or
the motor excitation
speed… I use control and feedback
to accurately change the
values and control the PE
I can change its
components, in compliance
armature voltage
with the specs
or its excitation
current
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Concept of Electric Drives – More into it
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Power Electronics Overview
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Power electronics Overview
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Power electronics Overview – Single Phase AC-DC Drives
SP FW Converter
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Power electronics Overview – Single Phase AC-DC Drives
Single-Phase FW Converter Drives
DC
2Vm
VA = cos α A
π
2Vm
VF = cos α F
π AC
Applications limited to 15 kW
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Power electronics Overview – Three Phase AC-DC Drives
3φ
Supply AC/DC Va
3 3Vm
Va = cos α a 0 ≤ αa ≤ π
π
3 3Vm
Vf = cos α f 0 ≤αf ≤π
π
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Power electronics Overview – DC-DC Drives
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Power electronics Overview – DC-DC Drives
Power Control (Acceleration control)
Ripple-free Armature Current
DC
DC
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Power electronics Overview – DC-DC Drives
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Power electronics Overview – DC-DC Drives
Regenerative Brake Control
Variable voltage into constant voltage
DC
DC
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Power electronics Overview – DC-DC Drives
Vav
• Turn the transistor on
• Armature current rises
-
• Turn the transistor off
• Diode turns on, current flows into the supply
Average voltage:
Vav = (1 − k )Vs
Regenerated power:
Pg = I aVs (1 − k )
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Power electronics Overview – DC-DC Drives
E g = K vωmin I f = Ra I a K vωmax I f − Ra I a = Vs
RI Vs Ra I a
ωmin = a a ωmax = +
Kv I f Minimum Maximum Kv I f Kv I f
Braking Braking
ω ≥ ωmin ω ≤ ωmax
Speed Speed
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Review on Electric Machines
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Electric Machines Overview
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Electric Machines Overview - Separately Excited DC Motor
dia
va = Ra ia + La + ea
dt
di f
v f = Rf if + Lf
Field circuit
dt
ea = K vω i f
Armature circuit
Td = K t iF i A
Pconv ea ia K vωia i f
Td = = = = K v ia i f = K t ia i f
ω ω ω
dω
Td = J + Bω + TL
dt
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Electric Machines Overview - Separately Excited DC Motor
d
At steady state: =0 At rated load, IA = cst, Td≡If
dt
Va = Ra I a + Ea = Ra I a + K vωI f
Td = K t I a I f
ω ∝ Va
Va − Ra I a
So, ω = 1
Kv I f ω∝
If
VA Control ωrated IF Control
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Electric Machines Overview – Induction Motors
Principle: Interaction of 2 magnetic fields: Tind=kBRxBS
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Electric Machines Overview – IM Model
120 f
ns =
P
n − nm ω s − ωm
s= s = ≡ slip
ns ωs
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Electric Machines Overview – IM Equations
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Electric Machines Overview – Terminal Characteristic
Tmm
Vs
: I r' = 1
Rr'
2
2
(
Rs + + X s + X r
s
) ' 2
sm s=0
1<s<2 s=1
2 '
' Rr s<0
Pg 3I r s 3Rr' Vs2
Td = = =
ωs ωs Rr'
2
(
sω s Rs + + X s + X r'
s
)
2
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Electric Machines Overview – Terminal Characteristic
The starting torque is found by replacing s=1
The maximum torque Tm is found by replacing s=sm where sm is found by calculating
the derivative dTd/ds=0
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Thank you for your attention
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Extras….
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What we need to know ? Understand the behaviour
(electrical model, speed,
Machines Control rotor position in AC…)
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Control Overview - Generalities
Voltage control
DC-DC converter
Switched ON-OFF on high frequency (>10 KHz)
Based on MOSFET, IGBT, GTO
DC output is controlled by the duty cycle
AC control
By varying the pulse width, the amplitude of the sine wave can change - PWM
By varying the pulse magnitude - PAM
By varying the pulse repetition frequency - PFM
DC outputs from choppers and PWM circuits are full of harmonics that may be eliminated due
to the inductive nature of the DC machine
Since current flows only when switches are ON, these techniques are relatively lossless
For continuous control, the inverter can be incorporated in feedback loops
As speed changes, the control maintains the voltage constant
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Control Overview - Generalities
Speed Control
Speed changes with load variations
• Open loop: Manual
• Closed loop: Automatic
DC machines
• If load changes, speed changes, and the machine has to deliver a different torque: current changes
• Speed is controlled by voltage control (outer feedback)
• Torque is controlled by current control (inner feedback)
• Voltage may deliver more current but without overriding current control, which must be controlled by the current loop
AC machines
• Speed control depends on the supply frequency and voltage
• Variable frequency drives allow control for speed by varying these two parameters
• In case of Induction motor, V/F method is used with V/F constant to control the flux
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Control Overview - Generalities
Torque and current control
Use only current loop and omit speed loop
Current is important at starting, transient and load changes
Use methods such as (mainly important for Induction motors):
• Vector controllers VC
Iref
ωref +
Speed + Current
M
Control Control
_ _ I
ωm
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Control Overview - Compensators
If the error is too large or the transient response is too fast, the system may be
unstable and a compensation (controller in the feedback) is required
Though this may change the overall transfer function of the system, it will allow to
rectify one of the following situations:
Basically, the
Compensator is in the
feedback (F4)
For simplicity purposes,
the compensator can be
instead inserted in the
main line (F1)
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Control Overview - Compensators
1- Proportional controller (P): How far from set point? Response proportional with
offset
2- Integral controller (I):How long from set point? Adds time component to response
3- Derivative controller (D): How fast towards set point? Adds compensating element
for speed of response, e.g. It slows down the response and prevents overshooting
Vc Vc k i Vc
= kp = = s kd
Eω Eω s Eω
Paramete Settling Steady
Rise Time Overshoot Design Requirements
r Time State Error
Small Steady-state error of the
Kp Decrease Decrease change Decrease
(Indefinite) motor should be less than 1%
Ki Decrease Increase Increase Eliminate
Settling time of 2 seconds
Small
Decrease Decrease
Kd change No effect Overshoot less than 5%
(Indefinite)
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Control Overview - PWM
Case of chopper control
High frequency carrier
Vref
“Saw tooth”
triangular carrier
u(t)
With this
0 kT T comparison, we
could generate the
- Output magnitude is defined by the input magnitude control pulses of
- Output frequency defined by the HF carrier frequency the chopper.
- The reference & the carrier are continuously compared
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Control Overview - PWM
Case of three-phase inverter control
We compare the triangle signal to the three sine waves. When the sine is over the triangle, we control K1 and
when it is under, we control K1’ and so on for the other sine waves.
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Power Semiconductor Components
Power Diode Thyristor
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Power Semiconductor Components
Power Mosfet IGBT
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Power electronics Overview – DC-AC Drives
- VFI: Voltage Fed Inverter: The input DC voltage is constant independent from the load
- CFI: Current Fed Inverter: The input DC current is constant independent from the load
- Variable DC link Inverter: The input DC voltage is controllable
- Resonant Pulse Inverter: The output is forced to pass to ‘0’ creating an LC resonant
circuit
- Multilevel inverter: Further switching combination and switching devices can be used
in order to minimize output harmonics
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Power electronics Overview – SP DC-AC Drives
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Power electronics Overview – 3P DC-AC Drives
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Power electronics Overview – General AC Drives
Diode Rectifier Based Converter
DC power
PMSG
WRSG
uncontrolled controlled
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Power electronics Overview – General AC Drives
Back 2 Back Converter
Control the active
Reduces the input current and reactive power
harmonics and harmonic flow to the grid
losses Bidirectional power flow
PMSG
SCIG
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Electric Machines Overview - DC Motors Comparison
Separated Series Shunt
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Electric Machines Overview – Terminal Characteristic
1. Motor : As the slip s↑, torque ↑, while the air-gap flux is constant. Torque
reacts at maximum at s=sm, then starts to decrease due to the reduction
of air-gap flux.
0 ≤ s ≤1 0 ≤ nm ≤ ns
2. Generator: Slip s<0, and the rotor reluctance is negative: Power is fed
back from the shaft into the rotor circuit as the torque becomes negative.
s0 nm ns
3. Braking region (Plugging): Developed torque opposes the speed and acts
as a braking torque. Also, s>0, I’r>> but Td<<: Energy due to excessive
current dissipates through the machine, produces heating: Not
recommended 1≤ s ≤ 2 n 0
m
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Insights through Examples
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First Example (Waste Sorting Plant)
I am the boss of a waste sorting plant, I want to redo
my entire installation :
I want 3 units of conveyors at 3 different speeds, I want to be able to
easily change the speed of the chains.
I want the plant to run continuously
I want reduced maintenance and purchasing costs
I don't need to have precise trash scrolling speed
My factory is supplied with three-phase 400V / 50Hz by EDF.
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First Example (Waste Sorting Plant)
I want 3 units of convoyors at 3 different speeds, I want to be able to
easily change the speed of the chains.
• 3 motors controlled by 3 conversion systems for variable speed
I want the plant to run continuously
I want reduced maintenance and purchasing costs
• Brushless motors (PMSM or ASM), PMSM remains more expensive and
needs an auxiliary motor to start => Best solution : the cage ASM
I don't need to have precise trash scrolling speed
• No need for precise speed, we can limit ourselves to a scalar control
because the factory owner does not care if the speed is shifted due to the
slip.
My factory is supplied with three-phase 400V / 50Hz by EDF.
• I will be able to use frequency converters directly connected to the network
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First Example (Waste Sorting Plant) Gear Box
Schematic diagram :
80V/10Hz
112V/14Hz
Power network ASM2
Variator 2 GB2 Conveyor 2
400V/50Hz
Three phase
240V/30Hz
poweer supply
Variator 3 ASM3 GB3 Conveyor 3
Speed variator
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Second Example : Powering a lighthouse
I am the mayor of a seaside town, I want to supply the city's
lighthouse with a hydrokinetic turbine to rotate the lighthouse lamp
and make it light up.
• The rotation speed of the lamp is variable according to the messages to be
transmitted to the sailors and it must be precise.
• The brightness of the lamp is always the same.
• I don't want to have interruptions in the operation of the lighthouse
Which solution are we going
to offer to this mayor ?
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Second Example : Powering a lighthouse
First solution : with a DC motor
Battery (48V) with its Control of the
electronic charge chopper with a
Permanent Magnet
Synchronous Generator
management system PWM changing the
conduction duty
cycle k of the IGBTs
4 quadrants
PMSG Rectifier Fixed voltage DC output (48V)
chopper
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Second Example : Powering a lighthouse
Second solution : with an ASM
Boost chopper
48V-230V
Single Three phase
Lighthouse
phase inverter with
lamp with
inverter Fixed voltage DC output (230V) variable
its switch
230V/50Hz Voltage/Frequency
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