1
Contents
• Capacitors
• Series and Parallel Capacitors
• Inductors
• Series and Parallel Inductors
Capacitors
• The capacitor consists of two parallel plates
separated by the insulator or known as dielectric.
The symbol of the basic capacitor is shown in
Figure 5.1
Figure 5.1
• The capacitance is defined as the value of capacitor when the
potential difference across the capacitor is one volt and is charged
by one coulomb of electricity.
Q
C=
V
3
Capacitors
• A capacitor consists of two conducting plates
separated by an insulator (or dielectric).
• The energy is stored in its electric field.
q = Cv
A
C=
d
Unit = farad (F)
I-V Characteristic of Capacitor
q = Cv
dq dv
i= =C
dt dt
1 t
v = idt
C −
Power and Energy in Capacitor
The instantaneous power delivered to the capacitor is
dv dv
p = vi = v C = Cv
dt dt
The energy stored in the capacitor is
t t dv t
w = pdt = C v dt = C vdv
− − dt −
1 2t
t = −
1
(
= Cv | = Cv t − Cv − )2 1
( )2
2 2 2
where v(− ) = 0 because the capacitor was uncharged at t = -.
1 2 q2
w = Cv =
2 2C
Cont’d
+ i + i
IS v IS v
_ _
v Energy absorbed
Charging Discharging
during charging mode
= Energy supplied
t during discharging mode
i
IS
t
−I S
Properties of Capacitor
• A capacitor is an open circuit to dc.
dv(t )
i =C = 0 (no dc current)
dt
Capacitors
replaced by
open circuits
Parallel Capacitors
Applying KCL gives
i = i1 + i2 + i3 + + iN
dv dv dv dv
i = C1 + C2 + C3 + + CN
dt dt dt dt
N dv dv
= Ck = Ceq
k =1 dt dt
where Ceq = C1 + C2 + C3 + + C N
Series Capacitors
Applying KVL gives
v = v1 + v2 + v3 + + v N
v = i (t )dt + v1 (t0 ) + i(t )dt + v (t )
1 t 1 t
2 0
C1 t0 C2 t0
i(t )dt + v (t )
1 t
+ + N 0
CN t0
N 1 t
i (t )dt + vk (t0 )
N
k =1 C t 0
=
k =1
k
i (t )dt + v(t0 )
1 t
=
Ceq 0 t
1 1 1 1 1
where = + + + +
Ceq C1 C2 C3 CN
v(t0 ) = vk (t0 )
N
k =1
Example 1
Find Ceq.
Example 2
Find v1, v2, v3. 1
=
1
+
1
+
1
Ceq 20m 30m 60m
Ceq = 10mF
q = Ceq v = 10 10 −3 30 = 0.3 C
Because q = C1v1 = C2 v2 = C3v3 ,
q q
v1 = = 15 V, v2 = = 10 V
C1 C2
q
v3 = =5V
C3
Example
Find the equivalent capacitance seen at the
terminal of the circuit.
Ans: 40 µF
Inductors
• An inductor consists of a coil of conducting wire.
• The energy is stored in its magnetic field.
di
v=L
dt
Unit = henry (H)
N 2 A
L=
l
I-V Characteristic of Inductor
di 1
v = L , di = vdt
dt L
1 t 1 t
i = v ( t ) dt = v ( t ) dt + i ( t0 )
L − L t0
Power and Energy in Inductor
The power delivered to the inductor is
di di
p = vi = L i = Li
dt dt
The energy stored in the inductor is
t t di t
w = pdt = Li dt = L idi
− − dt −
= Li(t ) − Li(− )
1 2t 1 1
= Li |
2 2
2 t = − 2 2
1 2 0
w = Li
2
Series Inductors
Applying KVL gives
v = v1 + v2 + v3 + + v N
di di di di
v = L1 + L2 + L3 + + LN
dt dt dt dt
N di di
= Lk = Leq
k =1 dt dt
where Leq = L1 + L2 + L3 + + LN
Parallel Inductors
Applying KCL gives
i = i1 + i2 + i3 + + iN
i = v(t )dt + i1 (t0 ) + v(t )dt + i (t )
1 t 1 t
2 0
L1 t0 L2 t0
v(t )dt + i (t )
1 t
+ + N 0
LN t0
N 1 t
v(t )dt + ik (t0 )
N
k =1 L t 0
=
k =1
k
v(t )dt + i (t0 )
1 t
=
Leq 0 t
1 1 1 1 1
where = + + + +
Leq L1 L2 L3 LN
i (t0 ) = ik (t0 )
N
k =1
Example 1
Find Leq.
Example
• A capacitor is open circuit to dc.
• An Inductor is short circuit to dc.
Find i, iL, vC.
v 12
i = iL = = =2A
R 1+ 5
vC = 5i = 10 V
Summary
Series connections Parallel connections
1 1 1 1 1
Req = R1 + R2 + R3 + + RN = + + + +
Req R1 R2 R3 RN
1 1 1 1 1
= + + + + Ceq = C1 + C2 + C3 + + C N
Ceq C1 C2 C3 CN
1 1 1 1 1
Leq = L1 + L2 + L3 + + LN = + + + +
Leq L1 L2 L3 LN