Acoba, Kenneth Jay B.: Educational Background: Tertiary Divine Word College of Laoag
Acoba, Kenneth Jay B.: Educational Background: Tertiary Divine Word College of Laoag
Citizenship: Filipino
Sex: Male
EDUCATIONAL BACKGROUND:
2017-2019
                      2013-2017
Primary   Elementary
          2007-2013
GALICINAO , JET NEIL PATRICK G.
Citizenship: Filipino
Sex: Male
EDUCATIONAL BACKGROUND:
2017-2019
2013-2017
Primary Elementary
          2007-2013
SUMMARY OF REACTIONS FROM ROOF BEAMS FOR SECOND FLOOR COLUMNS
                          A                                     B B                     C                                        D                         E
                               58.63        kN                        133.54   kN           144.75     kN                             60.04       kN
     1                +        61.44        kN                  +     114.39   kN   +       114.39     kN                    +        54.82       kN   +
                              120.07        kN                        247.93   kN           259.14     kN                            114.86       kN           1
                              108.94        kN                        253.72   kN           266.77     kN                            136.09       kN           1
     2                +       122.58        kN                  +     228.78   kN   +       228.78     kN                    +       175.83       kN   +       1
                              231.52        kN                        482.50   kN           495.55     kN                            311.92       kN           3
                               54.48        kN                        136.48   kN             140.23   kN                                 92.71   kN
     3                +        61.44        kN                  +     114.39   kN   +       114.39     kN                    +       121.01       kN   +       1
                              115.92        kN                        250.87   kN           254.62     kN                            213.72       kN           2
                                                                                                       LEGENDS:
                                                                                                       HORIZONTAL FRAME REACTION
                                                                                                       VERTICAL FRAME REACTION
                                                                                                       TOTAL REACTION
SUMMARY OF REACTIONS FROM 2ND FLOOR BEAMS FOR GROUND FLOOR COLUMNS                                                                                                    10
                         A                                     B                       C                                       D                       E
                                                                                                                                                               0
                              56.86         kN                     133.32     kN           151.85     kN                            70.72     kN            64.20          kN
    1                +        59.73         kN             +       110.28     kN   +       118.44     kN                   +        61.57     kN   +        52.39          kN
                             116.59         kN                     243.60     kN           270.29     kN                           132.29     kN           116.59          kN
                             115.93         kN                     279.19     kN           293.58     kN                           124.61     kN           511.13          kN
    2                +       119.46         kN             +       220.56     kN   +       236.88     kN                   +       186.33     kN   +       178.17          kN
                             235.39         kN                     499.75     kN           530.46     kN                           310.94     kN                           kN
                                    70.01   kN                       171.41   kN             155.15   kN                             124.54   kN             132.20        kN
    3                +        59.73         kN             +       110.28     kN   +       118.44     kN                   +       124.76     kN   +       125.78          kN
                             129.74         kN                     281.69     kN           273.59     kN                           249.30     kN           257.98          kN
                                                                                                      LEGENDS:
                                                                                                      HORIZONTAL FRAME REACTION
                                                                                                      VERTICAL FRAME REACTION
                                                                                                      TOTAL REACTION
DESIGN OF AXIALLY LOADED COLUMNS
    Ast =                   8            x               201.06
                                    2
    Ast =        1608.495411 mm
    An = Ag - Ast
    An =            400                  x                400                -               1,608.50
                                    2
    An =         158,391.50 mm
    Po = 0.85f'cAn +Ast fy
    Po = 0.85 x 20.7 x       158,391.50                      +             1,608.50          x            275
    Po =     3,229,234.76 N
    Po =         3,229.23 kN
     Pu = ΦαPo
     Pu =       0.65                     x                   0.8             x            3,229,234.76    ∴
     Pu =    1,679,202.08 N
     Pu =        1,679.20 kN                                 >               270.47 kN                        SAFE!
CHECK SLENDERNESS
      r=            0.3                  x                   0.4
      r=                  0.12
                                                                       ∴
   Lu/r =          2.6                  /                 0.12
   Lu/r =         21.67                 <                  34               SAFE!
                                                         ∴
     ρg = Ast /Ag
     ρg =        1608.495411             /                   160000
     ρg =        0.010053096                                 SAFE!
    Ast =                   8            x               201.06
                                    2
    Ast =        1608.495411 mm
    An = Ag - Ast
    An =            400                  x                400                -                1,608.50
                                    2
    An =         158,391.50 mm
    Po = 0.85f'cAn +Ast fy
    Po = 0.85 x 20.7 x       158,391.50                      +             1,608.50          x            275
    Po =     3,229,234.76 N
    Po =         3,229.23 kN
     Pu = ΦαPo
     Pu =       0.65                     x                   0.8             x            3,229,234.76    ∴
     Pu =    1,679,202.08 N
     Pu =        1,679.20 kN                                 >               506.88 kN                        SAFE!
CHECK SLENDERNESS
      r=            0.3                  x                   0.4
      r=                  0.12
                                                                       ∴
   Lu/r =          2.6                   /                0.12
   Lu/r =         21.67                  <                 34               SAFE!
                                                         ∴
     ρg = Ast /Ag
     ρg =        1608.495411             /                   160000
     ρg =        0.010053096                                 SAFE!
           Ast =                  8           x            201.06
                                          2
           Ast =   1608.495411 mm
           An = Ag - Ast
           An =         400                   x                400              -           #######
                                          2
           An =     158,391.50 mm
           Po = 0.85f'cAn +Ast fy
           Po = 0.85 x 20.7 x #########                         +               1,608.50          x    275
           Po = 3,229,234.76 N
           Po =        3,229.23 kN
           Pu = ΦαPo
           Pu =      0.65                     x                0.8              x           #######    ∴
           Pu = 1,679,202.08 N
           Pu =      1,679.20 kN                                >                    265.95 kN             SAFE!
CHECK SLENDERNESS
            r=            0.3                 x                0.4
            r=                  0.12
                                                                          ∴
         Lu/r =          2.6                  /                0.12
         Lu/r =         21.67                 <                 34            SAFE!
                                                           ∴
           ρg = Ast /Ag
           ρg =    1608.495411                 /                160000
           ρg =    0.010053096                                 SAFE!
                                                                                                                                     ∴
    P = 552.84       kN                                 REBAR CROSS SECTION AREA                                                       SAFE!
                                                                                  2
   f'c = 20.7        Mpa                                          Ø 20 = 314.16 mm                                                     SAFE!
                                                                                                                        2
     fy = 275                      Mpa                                                         Ø 16 =   201.06 mm                     SAFE!
                                                                                                                        2
     Φ = 0.65                      (Rectangular)                                               Ø 12 =   113.10 mm
     α = 0.8                       (Rectangular)
    Ast =                     8            x             201.06
                                      2
    Ast =       1608.495411 mm
    An = Ag - Ast
    An =            400                    x              400           -                   1,608.50
                                      2
    An =            158,391.50 mm
    Po = 0.85f'cAn +Ast fy
    Po = 0.85 x 20.7 x         158,391.50                  +           1,608.50            x            275
    Po =     3,229,234.76 N
    Po =           3,229.23 kN
     Pu = ΦαPo
     Pu =       0.65                       x              0.8           x               3,229,234.76    ∴
     Pu =    1,679,202.08 N
     Pu =         1,679.20 kN                              >                552.84 kN                       SAFE!
CHECK SLENDERNESS
      r=             0.3                   x              0.4
      r=                    0.12
                                                                   ∴
   Lu/r =            2.8                  /               0.12
   Lu/r =           23.33                 <                34          SAFE!
                                                         ∴
     ρg = Ast /Ag
     ρg =       1608.495411                /             160000
     ρg =       0.010053096                                SAFE!
                                                                                                                                     ∴
    P = 1049.42      kN                                 REBAR CROSS SECTION AREA                                                       SAFE!
                                                                                  2
   f'c = 20.7        Mpa                                          Ø 20 = 314.16 mm                                                     SAFE!
                                                                                                                        2
     fy = 275                      Mpa                                                         Ø 16 =   201.06 mm                     SAFE!
                                                                                                                        2
     Φ = 0.65                      (Rectangular)                                               Ø 12 =   113.10 mm
     α = 0.8                       (Rectangular)
    Ast =                     8            x             201.06
                                      2
    Ast =       1608.495411 mm
    An = Ag - Ast
    An =            400                    x              400           -                   1,608.50
                                      2
    An =            158,391.50 mm
    Po = 0.85f'cAn +Ast fy
    Po = 0.85 x 20.7 x         158,391.50                  +           1,608.50            x            275
    Po =     3,229,234.76 N
    Po =           3,229.23 kN
     Pu = ΦαPo
     Pu =       0.65                       x              0.8           x               3,229,234.76    ∴
     Pu =    1,679,202.08 N
     Pu =         1,679.20 kN                              >             1049.42 kN                         SAFE!
CHECK SLENDERNESS
      r=             0.3                   x              0.4
      r=                    0.12
                                                                   ∴
   Lu/r =            2.8                  /               0.12
   Lu/r =           23.33                 <                34          SAFE!
                                                         ∴
     ρg = Ast /Ag
     ρg =       1608.495411                /             160000
     ρg =       0.010053096                                SAFE!
                                                                                                                                      ∴
         P = 559.72     kN                                                                REBAR CROSS SECTION AREA                      SAFE!
                                                                                                                         2
           f'c = 20.7                   Mpa                                                     Ø 20 =   314.16 mm                      SAFE!
                                                                                                                         2
            fy = 275                    Mpa                                                     Ø 16 =   201.06 mm                     SAFE!
                                                                                                                         2
            Φ = 0.65                    (Rectangular)                                           Ø 12 =   113.10 mm
            α = 0.8                     (Rectangular)
           Ast =                   8           x            201.06
                                           2
           Ast =    1608.495411 mm
           An = Ag - Ast
           An =            400                 x             400               -           #######
                                           2
           An =        158,391.50 mm
           Po = 0.85f'cAn +Ast fy
           Po = 0.85 x 20.7 x     #######                     +                1,608.50          x       275
           Po = 3,229,234.76 N
           Po =        3,229.23 kN
            Pu = ΦαPo
            Pu =      0.65        x                          0.8               x           #######       ∴
            Pu = 1,679,202.08 N
            Pu =      1,679.20 kN                             >                     559.72 kN                SAFE!
CHECK SLENDERNESS
             r=            0.3                 x             0.4
             r=                  0.12
                                                                         ∴
          Lu/r =         2.8                   /             0.12
          Lu/r =        23.33                  <              34             SAFE!
                                                        ∴
            ρg = Ast /Ag
            ρg =    1608.495411                /               160000
            ρg =    0.010053096                             SAFE!
                            2        2
                Vu = qu [ L - (d + c) ]
                                        2       2         2
                Vu = 100.13(1000/1000 ) [ 2500 - (d + 400) ]
               bo d = (d+c)(4)d
             Vc = Vn             ; Φ = 0.85 (Shear)
                                                                                                       2         2             2
                             Vu                                                100.13(1000/1000 ) [ 2500 - (d + 400) ]
                 Vc =                     =>                 1.52      =
                            Φbo d                                                          (0.85)(d+400)(4)d
                  d=            192.79 mm            say                200.00 mm
  Check "d" from beam shear
                           L=    2500           mm
                                                                                                    x
                                                                                                             d
                           c = 400 mm                                      L=b
                                           d=              200 mm
                           x=        850        mm
                       Vn = Vu / (Φbo d)           (Actual)
                      Where:       Vu = quLx                 ; Φ = 0.85 (Shear)
                                   Vu =      88.45        x             2.5                         x            0.85
                                   Vu =     187.97 kN
                   Vu                                      187.97        (                         1000           )
      Vn =                       =>          =
                  Φbd                                 0.85 x           2500                          x           200
      Vn =             0.44 Mpa (Actual)
  Compare to allowable
      Vc = (1/6) √f'c                                                 ∴
      Vc = (1/6) √20.7
      Vc =             0.76 Mpa              >               0.44       SAFE!
  Compute ρ
  From Bending
      Mu = quLx(x/2)
      Mu =           88.45      x                    2.5               x              0.85          x                    0.43
      Mu =           79.89 kN - m
                   2
      Mu = Φf’cbd ω(1-0.59ω)                    ; Φ = 0.90 (bending)
         6                            2
94.74 x10 = (0.90)(20.7)(2100)(230) ω(1-0.59ω)
        ω=             0.047
        Try        20           mm       bar
         n=       As / A
                                                                                                                                    2
        n=         2,545.45   / [ (                3.1416              /               4           ) (               20         )        ]
        n=             8.10 pcs ,               say                        9.00 pcs
                                           ∅
  Check Weight of Footing
           Total Thickness = d + 70 + 1.5 ( bar )
           Total Thickness =     200          +              70                       + (       1.5                  x              20       )
           Total Thickness =         300 mm,          say                             300.00 mm
   Actual Weight of Footing =    2.5          x              2.5                       x            0.30             x          23.6
   Actual Weight of Footing =     44.25 kN
                 Total WT. =      44.25       +               394.89
                                                                                                                 ∴
                 Total WT. =     439.14
            Required Area = Total Load / Allowable Soil Pressure                       =            439.14           /          100.00
                                                      2                                              2
              Required Area =         4.39           m                 <              6.25          m                OK!
DESIGN OF FOOTING @FRAME 2 (GRID B-2)
                                                                                                                                    1049.42 kN
                 Pu =      1,049.42    kN
Service Load DL = LL =     1,049.42                /               2.8
Service Load DL = LL =      374.79 kN
Service Load DL + LL =      749.59 kN
          Checking = 1.2 DL + 1.6 LL
                           1.2          x                    ∴  374.79
                +          1.6          x                       374.79
                          1,049.42 kN = Pu                    OK!
                            2          2
                 Vu = qu [ L - (d + c) ]
                                               2         2                2
                Vu = 100.13(1000/1000 ) [ 3100 - (d + 350) ]
               bod = (d+c)(4)d
             Vc = Vn           ; Φ = 0.85 (Shear)
                                                                                                                 2         2              2
                            Vu                                                           100.13(1000/1000 ) [3100 - (d + 400) ]
                 Vc =                  =>                               1.52      =
                           Φbod                                                                      (0.85)(d+400)(4)d
                  d=         192.79 mm                       say                  200.00 mm
    Check "d" from beam shear
                            L=        3100          mm
                                                                                                        x
                                                                                                                d
                            c = 400 mm                                          L=b
                                               d=              200 mm
                            x=        1150          mm
                        Vn = Vu / (Φbod)             (Actual)
                     Where:           Vu = quLx               ; Φ = 0.85 (Shear)
                                      Vu =    109.20        x            3.1                            x               1.15
                                      Vu =    389.30 kN
                    Vu                                     389.30         (                            1000              )
       Vn =                        =>           =
                   Φbd                                  0.85 x          3100                            x               200
       Vn =            0.74 Mpa (Actual)
    Compare to allowable
       Vc = (1/6) √f'c                                                 ∴
       Vc = (1/6) √20.7
       Vc =            0.76 Mpa                 >             0.74       SAFE!
    Compute ρ
    From Bending
        Mu = quLx(x/2)
        Mu =       109.20       x                        3.1               x               1.15         x                    0.58
        Mu =       223.85 kN - m
                     2
        Mu = Φf’cbd ω(1-0.59ω)                      ; Φ = 0.90 (bending)
          6                                2
223.85 x 10 = (0.90)(20.7)(3100)(290) ω(1-0.59ω)
          ω=           0.047
         Try        20           mm    bar
          n=       As / A
                                                                                                                                        2
          n=       3,156.36    / [ (                  3.1416               /                4          ) (              20          )        ]
          n=          10.05 pcs ,                   say                        11.00 pcs
                                           ∅
   Check Weight of Footing
           Total Thickness = d + 70 + 1.5 ( bar )
           Total Thickness =      200           +              70                          + (       1.5                 x              20       )
           Total Thickness =           300 mm,           say                               300.00 mm
   Actual Weight of Footing =     3.1           x             3.1                           x           0.30             x          23.6
   Actual Weight of Footing =       68.04 kN
                 Total WT. =        68.04       +              749.59
                                                                                                                    ∴
                 Total WT. =       817.62
            Required Area = Total Load / Allowable Soil Pressure                            =          817.62            /          100.00
                                                          2                                              2
              Required Area =              8.18          m              <                  9.61        m                OK!
DESIGN OF FOOTING @FRAME 3 (GRID B-3)
                                                                                                                                       559.62 kN
                 Pu =           559.62       kN
Service Load DL = LL =          559.62            /               2.8
Service Load DL = LL =          199.86 kN
Service Load DL + LL =     399.73 kN
          Checking = 1.2 DL + 1.6 LL
                          1.2           x                   ∴   199.86
                +         1.6           x                       199.86
                           559.62 kN = Pu                    OK!
                            2            2
                Vu = qu [ L - (d + c) ]
                                         2       2        2
                Vu = 100.13(1000/1000 ) [ 2500 - (d + 300) ]
               bo d = (d+c)(4)d
             Vc = Vn            ; Φ = 0.85 (Shear)
                                                                                                                 2            2             2
                            Vu                                                          100.13(1000/1000 ) [ 2500 - (d + 400) ]
                 Vc =                  =>                             1.52      =
                           Φbo d                                                                     (0.85)(d+400)(4)d
                  d=         192.79 mm                      say                  200.00 mm
 Check "d" from beam shear
                             L=         2500         mm
                                                                                                        x
                                  400 mm
                                                                                                                 d
                             c=                                                 L=b
                                               d=                  200 mm
                             x=         850          mm
                      Vn = Vu / (Φbod)               (Actual)
                  Where:            Vu = quLx                  ; Φ = 0.85 (Shear)
                                    Vu =       89.54        x             2.5                           x            0.85
                                    Vu =      190.27 kN
                 Vu                                          190.27        (                           1000           )
    Vn =                         =>           =
                 Φbd                                    0.85 x           2500                           x            200
    Vn =             0.45 Mpa (Actual)
 Compare to allowable
    Vc = (1/6) √f'c                                                     ∴
    Vc = (1/6) √20.7
    Vc =             0.76 Mpa                 >                0.45       SAFE!
 Compute ρ
 From Bending
     Mu = quLx(x/2)
     Mu =         89.54       x                             2.5             x              0.85         x                    0.43
     Mu =         80.87 kN - m
                       2
      Mu = Φf’cbd ω(1-0.59ω)                         ; Φ = 0.90 (bending)
           6                              2
80.87x10 = (0.90)(20.7)(2500)(230) ω(1-0.59ω)
       ω=             0.03
       Try           20           mm     bar
        n=          As / A
                                                                                                                                        2
           n=        2,545.45    / [ (                     3.1416           /               4          ) (               20         )        ]
           n=            8.10 pcs ,                  say                        9.00 pcs
                                         ∅
 Check Weight of Footing
         Total Thickness = d + 70 + 1.5 ( bar )
         Total Thickness =      200             +              70                          + (        1.5                x              20       )
         Total Thickness =            300 mm,            say                                300.00 mm
 Actual Weight of Footing =      2.5            x              2.5                           x           0.30            x          23.6
 Actual Weight of Footing =        44.25 kN
               Total WT. =         44.25        +               399.73
                                                                                                                     ∴
               Total WT. =        443.98
          Required Area = Total Load / Allowable Soil Pressure                              =           443.98           /          100.00
                                                              2                                          2
                Required Area =               4.44          m               <              6.25        m                 OK!
               DIVINE WORD COLLEGE OF LAOAG
                School of Engineering & Architecture
                   Gen. Segundo Ave. Laoag City